## 2 Sep 2016

### IBPS Clerk 2016 - Practice Quantitative Aptitude Questions

IBPS Clerk 2016 - Practice Quantitative Aptitude Questions Set-1:
Dear Readers, Important Practice Aptitude Questions for IBPS Clerk and Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the examination can use this.

Directions (Q. 1-5): Study the table and pie-chart carefully to answer the following questions:

Total area = 50000 sq km

1). What is the difference between the total area of Udaipur and Jaipur?
a)   7500 km2
b)   4500 km2
c)   3500 km2
d)   2500 km2
e)   5000 km2

2). The industrial area in all five districts is what per cent of the total area of Dholpur?
a)   12%
b)   8%
c)   10%
d)   11%
e)   7%

3). In which district is the percentage of Green Belt the maximum?
a)   Dholpur
b)   Bikaner
c)   Ajmer
d)   Jaipur
e)   Udaipur

4). In which district is the percentage of Industrial Belt the maximum?
a)   Ajmer
b)   Jaipur
c)   Bikaner
d)   Udaipur
e)   Dholpur

5). The area of Green belt and Industrial belt together in Bikaner is what percentage of the total area of Bikaner?
a)   5%
b)   7%
c)   10%
d)   12%
e)   15%
6). P sells an article to Q at 15% profit. Q sells it to C at 10% loss. If R pays Rs. 517.50/-  for it then P purchased it at
a)   Rs. 500/-
b)   Rs. 750/-
c)   Rs. 1,000/-
d)   Rs. 1, 250/-
e)   None of these

7). Two pipes A and B can fill a tank in 36 min. and 45 min. respectively. A water pipe C can       empty the tank in 30 min. First A and B are opened. After 7 min, C is also opened. In how much time, the tank is full?
a)   39 min
b)   40 min
c)   42 min
d)   38 min
e)   36 min

8). Mohan bought a jute bag @ 30% discount on the list price. He then sold it at a price which is 160% of the list price thereby making a profit of `81. What is the list price of the bag?
a)   180
b)   100
c)   90
d)   200
e)   None of these

9). A sum is lent at 18% pa compound interest. What is the ratio of increase in the amount of 6th year to that in the 7th year?
a)   11:16
b)   20:23
c)   18:31
d)   15:27
e)   25:27

10). A bus started its journey from Allahabad and reached Lucknow in 1 hour 30 minutes at its average speed of 75 kmph. If the average speed of the bus is decreased by 21 kmph, how much time will it take to cover the same distance?
a)   2 hours 45 min
b)   2 hour 22 min
c)   2 hour 5 min
d)   2 hour 18 min
e)   1 hour 55 min

1. e) 2. c) 3. d) 4. b) 5. a) 6. a) 7. a) 8. c) 9. e) 10. c)

Solution:
1). Difference between the total area of Udaipur and Jaipur
= 7500 – 2500
= 5000 sq km

2).  Industrial area in all 5 districts
= 200 + 300 + 500 + 350 + 400
= 1750 km2
Required % = 1750 / 17500 × 100%
= 10% of the total area of Dholpur.

3). Total area of Ajmer = = 50000 × 25 / 100   = 12500 sq km
Percentage of Green Belt in Ajmer = 400 / 12500 × 100% = 16 / 5 % = 3.2%
Total area of Bikaner = 50000 × 20 / 100 = 10000 sq km
Percentage of Green Belt in Bikaner = 200 / 10000 × 100% = 2%
Total area of Dholpur = 50000 × 35 / 100 = 17500 sq km
Percentage of Green Belt in Dholpur = 300 / 17500 × 100% = 12 / 7 % = 1.714%
Total area of Jaipur = 50000 × 5 / 100 = 2500 sq km
Percentage of Green Belt in Jaipur = 500 / 2500 × 100% = 20%
Total area of Udaipur = 50000 × 15 / 100 = 7500 sq km
Percentage of Green Belt in Udaipur = 350 / 7500 × 100% =  4.66%
In Jaipur the percentage of Green Belt is the maximum.

4). Percentage of Industrial Belt in Ajmer = 200 × 100 / 12500 = 8 / 5 = 1.6%
Percentage of Industrial Belt in Bikaner = 300 × 100 / 10000 = 3%
Percentage of Industrial Belt in Dholpur = 500 × 100 / 17500 = 20 / 7 = 2.85%
Percentage of Industrial Belt in Jaipur = 350 × 100 / 2500 = 14%
Percentage of Industrial Belt in Udaipur = 400 × 100 / 7500 = 16 / 3 = 5.35%
In Jaipur the percentage of Industrial Belt is the maximum.

5). Area  of  Green  Belt  and Industrial Belt  together  in  Bikaner  =  200  + 300 =  500 km2
Area of Green Belt and Industrial   Belt together in Bikaner = 500 × 100 / 10000
= 5% of the total area of Bikaner

6). Let CP of P be x Rs
=115x/100 * 90/100 = 517.5
x  = 500

7). Part filled in 7 min. = 7*((1/36)+(1/45))=(7/20).
Remaining part=(1-(7/20))=(13/20).
Net part filled in 1min. when A,B and C are opened=(1/36)+(1/45)-(1/30)=(1/60).
Now,(1/60) part is filled in one minute.
(13/20) part is filled in (60*(13/20))=39 minutes.

8). Let the LP be 100
So, cost price = 100 × 70% = 70
SP = 100 × 160% = 160
Profit = 160 – 70 = 90
When profit is 90, LP = 100
When profit is 81 LP = 100 * 81 / 90 = 90

9). P[(1+r/100)]6/[(1+r/100)]7 = 1/[1+(r/100)] = 100/(100+r)
Now, 100/(100+18) = 100/118 = 25/27
Required ratio = 25:27

10). Distance = 75×(90/60)
Now, new average speed = 75-21 = 54 kmph
Now, let the time taken by the new average be x hours
(75×90)/60 = (54×x)/60
X = (75×90)/54 = 125 minutes
Time = 2 hours 5 minutes