30 Sep 2016

IBPS PO/Clerk/RRB Exam 2016 – Section wise Full Test-60

IBPS PO/Clerk/RRB Exam 2016 – Section wise Full Test-60:
Dear Readers, IBPS PO/Clerk 2016 was approaching, for that we have given the Section wise Full Test which consist of all the three sections such as, Aptitude, Reasoning, and English. This Section wise Full Test will be provided on daily basis kindly make use of it.


QUANTITATIVE APTITUDE
Directions (1 – 5): In these, questions two equations numbered I and II are given. You have to solve both the equations and give answer:
a) if x > y
b) if x ≥ y
c) if x <y
d) if x ≤ y
e) if x = y or the relationship between x and y cannot be established.
1). I. 2x2 − x − 10 = 0 II. 2y2 − y − 21 = 0
2). I. 2x2 + 11x + 15 = 0 II. 4y2 + 22y + 24 = 0
3). I. 3x2 − 22x + 40 = 0 II. 2y2 −19y + 44 = 0
4). I. x2 − 4x − 12 = 0 II. y2 − 5y − 14 = 0
5). I. 25x2 + 35x + 12 = 0 II. 10y2 + 9y + 2 = 0

REASONING
Directions (6 – 10): In these questions, the relationship between different elements is shown in the statements. Give answer:
a) If only conclusion I follows
b) If only conclusion II follows
c) If either conclusion I or II follows
d) If neither conclusion I nor II follows
e) If both conclusion I and II follow
6). Statements: A = B ≠ E > T
Conclusions: I. A ≥ T II. A < T
7). Statements: S > O ≥ F ≤ T
Conclusions: I. O > T II. O ≤ T
8). Statements: C = A ≠ P
Conclusions: I. P > C II. P < C
9). Statements: D ≥ A ≥ Y, S = Y
Conclusions: I. D > S II. D = Y
10). Statements: I > D > E ≠ A = L
Conclusions: I. I ≥ L II. I < L

ENGLISH
Directions (Q. 11-15): Read each sentence to find out whether there is any error in it. The error, if any, will be in one part of the sentence. The number of that part is the answer. If there is no error, the answer is (e). (Ignore errors of punctuation, if any)

11). Various employees, whom a)/ we met, echoed b)/ the sentiments expressed c)/ by the CEO of the company. d)/ No error e)

12). The challenge for us a)/ is to engage with a potential b)/ customer early so we can c)/ sell him the entire range. d)/ No error e)

13). This situation probably  a)/ contributing to a b)/ greater lack of protection c)/ for children in the households. d)/ No error e)

14). The amount at a minimum  a)/ payment is determined b)/ by management and varies  c)/ from firm to firm. d)/ No error e)

15). It is difficult to assume that  a)/ a increase in the number of health institutions b)/ would automatically enhance  c)/ utilization of health services. d)/ No error e)

Answers:
1)e    2)e   3)d   4)d   5)c   6)c   7)c   8)c   9)c   10)c  11)e   12)c   13)b   14)a   15)b

Solutions:
1). e)
I. 2x2 − x − 10 = 0 => 2x2 – 5x + 4x – 10 = 0 => x = -2 or 5/2
II. 2y2 − y − 21 = 0 => 2y2 – 7y + 6y – 21 = 0 => y = -3 or 7/2
Clearly relation between x and y cannot be established.

2). e)
I. 2x2 + 11x + 15 = 0 => 2x2 + 6x + 5x + 15 = 0 => x = -5/2 or -3
II. 4y2 + 22y + 24 = 0 => 2y2 + 11y + 12 = 0 => y = -4, -3/2
Clearly relation between x and y cannot be established.

3). d)
I. 3x2 − 22x + 40 = 0 => 3x2 − 10x − 12x + 40 = 0 => x = 4 or 10/3
II. 2y2 −19y + 44 = 0 => 2y2 −11y − 8y + 44 = 0 => y = 4 or 11/2
Clearly x ≤ y

4). d)
I. x2 − 4x − 12 = 0 => x2 − 6x + 2x − 12 = 0 => x = -2 or 6
II. y2 − 5y − 14 = 0 => y2 − 7y + 2y − 14 = 0 => y = 7 or -2
Clearly x ≤ y

5). c)
I. 25x2 + 35x + 12 = 0 => 25x2 + 15x + 20x + 12 = 0 => x = -4/5 or -3/5
II. 10y2 + 9y + 2 = 0 => 10y2 + 5y + 4y + 2 = 0 => y = -1/2 or -2/5
Clearly x < y

6). c)
‘B ≠ E’ means that B > E or B < E. So a > T or A < T or A = T.
Hence, either I or II follows

7). c)
O ≥ F ≥ T, as > and < are there between O and T, the relationship between cannot be compared.
Hence O > T or O ≤ T

8). c)
As C = A ≠ P, C > P or C < P
So either I or II follows

9). c)
D ≥ A ≥ Y = S; Either D > Y (or S) or D = Y (or S)

10). c)
I > L or I < L or I = L

Hence, either I or II follows.



 


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