## 28 Sep 2016

### Mission IBPS PO 2016 - Practice Quantitative Aptitude Questions with Detailed Solutions

Mission IBPS PO 2016 - Practice Quantitative Aptitude Questions:
Dear Readers, Important Practice Aptitude Questions for IBPS PO and Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the examination can use this.

1). Is X divisible by 12?
a. X leaves a remainder 2 when divided by 8
b. X is divisible by 3.
c. X is divisible by 6.
a)    If the data in statement a is sufficient to answer the question, while the data in statement b and c are not required to answer the question.
b)    If the data in statement b is sufficient to answer the question, while the data in statement a and c are not required to answer the question
c)    If the data in statement a and b are sufficient to answer the question, while the data in statement c is not required to answer the question.
d)    If the data in statement a, b and c together are necessary to answer the question.
e)    If the data in statement a, b and c together are not sufficient to answer the question.

2). What is the average score in an exam taken by 500 students where the minimum score is 200?
a. Half the students scored above 700.
b. Half the students scored below 700.
c. The maximum score in the exam was 850, scored by exactly 42 students.
a)    If the data in statement a is sufficient to answer the question, while the data in statement b and c are not required to answer the question
b)    If the data in statement b is sufficient to answer the question, while the data in statement a and c are not required to answer the question
c)    If the data in statement a and b are sufficient to answer the question, while the data in statement c is not required to answer the question
d)    If the data in statement a, b and c together are necessary to answer the question.
e)    If the data in statement a, b and c together are not sufficient to answer the question.

3). What is the wholesale cost of a dress?
a. The dress was listed at a price that would have given the store a profit of 20 percent of the wholesale cost.
b. After as 10% discount on the list price, the dress sold for a net profit of 10 Rupees.
c. The dress sold for 50 Rupees more than the wholesale cost.
a)    If the data in statement a is sufficient to answer the question, while the data in statement b and c are not required to answer the question
b)    If the data in statement b is sufficient to answer the question, while the data in statement a and c are not required to answer the question
c)    If the data in statement a and b are sufficient to answer the question, while the data in statement c is not required to answer the question
d)    If the data in statement a, b and c together are necessary to answer the question.
e)    If the data in statement a, b and c together are not sufficient to answer the question.

4). Is p>q?
(A) 0<p<0.5
(B) q>0.4
a)    If statement (A) alone is sufficient to answer the question but statement (B) alone is not sufficient.
b)    If statement (B) alone is sufficient to answer the question but statement (A) alone is not sufficient.
c)    If the two statements taken together are sufficient to answer the question, but neither statement alone is sufficient
d)    If each statement alone is sufficient to answer the question
e)    If the two statements taken together are still not sufficient to answer the question.

5). What is the remainder when positive integer ‘p’ is divided by 3?
(A) ‘p’ is an even number
(B) ‘p’ is a perfect square
a)    If statement (A) alone is sufficient to answer the question but statement (B) alone is not sufficient.
b)    If statement (B) alone is sufficient to answer the question but statement (A) alone is not sufficient.
c)    If the two statements taken together are sufficient to answer the question, but neither statement alone is sufficient
d)    If each statement alone is sufficient to answer the question
e)    If the two statements taken together are still not sufficient to answer the question.

Directions (Q. 6-10): In the following questions three equations numbered I, II and III are given. Solve the equations and choose the correct option that gives the relation between the variables.
a)    x > y = z
b)    x ≥ y ≥ z
c)    x < y > z
d)    x > y < z
e)    None of these
6). I. 3x + y = 30
II. 2y + 5z = 48
III. 5x – 4z = 11

7). I. 2x + 5y = 19.6
II. y = √(7.84)
III. 10x – 7z = 8.4

8). I. z – 3x = -6
II. 5x + 2y = 22.5
III. 3y + 2z = 16.5

9). I. x + 3y – 7z = -7
II. 3y + 2z = 15
III. 3z – x = 4

10). I. x2 - 11x + 28 = 0
II. y2 – 7y + 12 = 0
III. z2 – 4z + 3 = 0

1)a  2)e  3)c  4)e  5)e  6)c  7)e  8)d  9)a  10)b

Solution:
1). From (a), we notice that the number is of the form 8n+2, which means it also leaves a remainder 2 on being divided by 4. So, its not divisible by 12.
From (b) and (c) together, the number can be any multiple of 6, from which we cant conclusively say if number is divisible by 12.

2). The fact that half scored above 700, and other half less than 700 does not tell the actual distribution of scores to calculate the average. Statement (c) also does not help us determine the average.

3). Let C be the wholesale price, listed Price be P. from (a), P = 1.2C
From (b), 0.9P = C + 10. Using statement (a), 1.2C = C + 10, from this we can determine C.
From (C), we have sales price = C + 50. From this we cant determine C, even if we combine information from other statements.
So (a) and (b) together are sufficient to answer the question.

4). We can have p = 0.45, and q = 0.41. here p>q
We can also have p = 0.45,and q = 10. Here p<q
So, we cant determine using both statements if p>q.

5). Using (A), we can have ‘p’ as 2/4/6/8 etc. we cant determine remainder when divided by 3.
Using (B), we can have ‘p’ as 1/4/9/16 etc. we cant determine remainder when divided by 3.
Using both ‘p’ is the square of an even number. So ‘p’ can be 4/16/36 etc.
We see that remainder can again be 1/0 (4/16 leave remainder 1, 36 remainder 0).
So, we cant determine using both statements.

6). 2xI – II = 6x – 5z = 12(IV)
IV – III = x – z = 1 or x = z + 1
Substituting in III, we get x = 7, z = 6
Putting x = 7 in I, we get y = 9
Hence x < y > z

7). From II, y = 2.8
Putting in I, we get 2x + 14 = 19.6
= 2x = 5.6 or x = 2.8
Putting x = 2.8 in III, we get 28 – 7z = 8.4
= 7z = 19.6 or z = 2.8
Hence x = y = z

8). III – 2xI = 3y + 6x = 28.5 or 2y + 4x = 19(IV)
II – IV = x = 3.5
Putting in I, z – 10.5 = -6
Z = 4.5
Putting in II, 17.5 + 2y = 22.5
Y = 2.5
Hence x > y < z

9). From II, 3y = -2z + 15
From III, x = 3z -4
Putting in I, 3z – 4 – 2z + 15 – 7z = -7
= -6z + 11 = -7
z = 3
Substituting in II and III, we get
x = 5, y =3
hence x > y = z

10). From I, (x-7) (x-4) = 0
x = 7,4
From II, (y-4) (y-3) = 0
y = 4, 3
From III, (z-3) (z-1) = 0
z = 3, 1
hence x ≥ y ≥ z