11 Nov 2016

IBPS Clerk/RRB 2016- Practice Reasoning Questions [Answers Updated]

IBPS Clerk 2016- Practice Reasoning Questions
IBPS Clerk/RRB 2016- Practice Reasoning Questions Set-32:
Dear Readers, Important Practice Reasoning Questions with explanation for Upcoming IBPS RRB/Clerk Exams was given here with explanation, candidates those who are preparing for those exams can use this practice questions.

Directions (Q.1-4): In each question below are given three statements followed by four conclusions numbered I, II,. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements, disregarding commonly known facts.

a)    If only conclusion I follow
b)    If only conclusion II follow
c)    If either conclusion I or II follow
d)    If neither conclusion I nor II follow
e)    If both conclusion I and II follow
1). Statement: Some boards are clocks.
All boards are boxes
No box is a wall
Conclusion: I. Some boxes are clocks
II. All clocks being boxes is a possibility.

2). Statement: No home is a hut.
Some huts are houses.
Some houses are table.
Conclusion: I. Some houses are not homes.
II. All tables being huts is a possibility.

3). Statement: Some cats are rats.
Some rats are fishes.
All fishes are birds.
Conclusion: I. Some fishes are rats.
II. All cats being birds is a possibility.

4). Statement: Some flowers are roses.
No rose is red.
All red are leaves.
Conclusion: I. Some flowers are definitely not red.
II. Some leaves are definitely not roses.

Directions (Q. 5-8): In each of the following questions, assuming the given statements to be true, find which of the given two conclusions numbered I, II and II is/are definitely true and give your answer accordingly .
a)    Only conclusion I is true.
b)    Only conclusion II is true.
c)    Either conclusion I or II is true
d)    Both Conclusion I and II is true
e)    Neither Conclusion I and  II is true.

5). Statement: L = I ≥ N < E; N ≥ S
Conclusion: I. S < E
II. E > L

6). Statement: V < E > B = H ≥ N; B ≤ T
Conclusion: I. T > V
II. N ≤T

7). Statement: L = I ≥ N < E; N ≥ S
Conclusion: I. S = L
II. L > S

8). Statement: B > E ≥ A < L; T ≥ A > S
Conclusion: I. B > S
II. L > S

Directions (Q. 9-10): Study the following information and answer the questions given below.
‘A + B’ means ‘A’ is father of ‘B’
‘A ÷ B’ means ‘B’ is brother of ‘A’
‘A × B’ means ‘A’ is husband of ‘B’
‘A - B’ means ‘A’ is sister of ‘B’
9). In the expression A + B × C – D ÷ E, how is D related to B?
a)    Brother in law
b)    Sister in law
c)    Nephew
d)    Brother
e)    Cannot be determined

10). Which of the following expressions shows that ‘R is sister of Q’?
a)    P + Q – R + Z
b)    T × Q + Z – R
c)    P + Q – R × Z
d)    None of these
e)    Cannot be determined

1).e)   2).e)  3).e)  4).e)  5).a)  6).b)  7).c)  8).d)  9).e)  10).d)

5). Given Statements:
L = I ≥ N < E;
N ≥ S
Combining above both we get
 S ≤N , E
Thus S < E is true.
Hence I is true.
Again from I we can’t compare L and E
hence II (E > L) is not true
Answer: a)
6). Given Statements:
V < E > B = H ≥ N;
B ≤ T
Combining above both we get
V < E > B ≤ T
thus, we can’t compare V and T.
hence I (T > V) is not true.
Again, from (I) and (ii), we get
T ≥ B = H ≥ N
thus, T ≥ N or N ≤ T is true
hence II is true
Answer: b)
7). Given Statements
L = I ≥ N < E;
N ≥ S
Combining above both we get
L = I ≥ N ≥ S
thus, L ≥ S or S ≤ L is true
it means L > S may be true or L = S may be true.
Hence conclusion I and II make a complementary pair.
so, either I or II is true
Answer: c)
8). Given statements:
B > E ≥ A < L; T ≥ A > S
Combining above we get
B > E ≥ A < L
thus B > S is true
hence I is true
Again S < A < L
So, S < L or L > S is true
hence both I and II is true
Answer: d)
9). hence D may be either male or female so, we cannot be determined.
Answer: e)

Answer: d)


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