13 May 2017

Practice Quantitative Aptitude Questions For NICL AO Prelims 2017

Practice Quantitative Aptitude Questions For NICL AO Prelims 2017
[Dated: 13th May] Practice Quantitative Aptitude Questions For NICL AO Prelims 2017 (Quadratic Equation):
Dear Readers, Important Practice Aptitude Questions for  Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the Bank Examination and other Competitive Examination can use this.

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Directions (Q. 1-10): in each question two equations numbered I and II are given. You have to solve both the equations and mark the answer.
a)   If x > y
b)   If x ≥ y
c)   If x < y
d)   If x ≤ y
e)   If x = y or no relation can be established between x and y.
1).
I. x2 + 18x + 72 = 0
II. y2 + 6y + 8 =0

2).
I. 8x2 – 22x + 15 = 0
II. 3y2 – 13y + 14 = 0

3).
I. 9x2 – 26x + 16 = 0
II. 3y2 – 16y + 20 = 0

4).
I. 10x2 – 17x + 7 = 0
II. 15y2 – 19y + 6 = 0

5).
I. 12x2 + 19x + 5 = 0
II. 5y2 + 16y + 3 = 0

6).
I. x2 – 8x + 15 = 0
II. 2y2 – 11y + 14 = 0
a)   x > y
b)   x = y or relationship can’t be established
c)   x ≤ y
d)   x ≥ y
e)   x < y

7).
I. x = √2916
II. y2 = 2916
a)   x < y
b)   x > y
c)   x ≤ y
d)   x ≥ y
e)   x = y or relationship can’t be established

8).
I. 3x2 + 35x + 88 = 0
II. y2 + 787 = 1316
a)   x > y
b)   x ≤ y
c)   x = y or relationship can’t be established
d)   x ≥ y
e)   x < y

9).
I. x2 – 14x + 45 = 0
II. y2 – 9y + 20 = 0
a)   x < y
b)   x > y
c)   x ≤ y
d)   x ≥ y
e)   x = y or relationship can’t be established

10).
I. x2 – 54 = 3x
II. y2 = 36
a)   x > y
b)   x ≤ y
c)   x ≥ y
d)   x > y
e)   x = y or relationship can’t be established

Explanation With Answer Key:
1). C)
I. x2 + 18x + 72 = 0
or, x2 + 12x + 6x + 72 =0
or, x(x + 12) + 6(x + 12) = 0
x = -9, -12
II. y2 + 6y + 8 =0
or, y2 + 4y + 2y + 8 =0
or, y(y + 4) + 2(y + 4) = 0
y = -2, -4
Hence x < y

2). C)
I. 8x2 – 22x + 15 = 0
or, 8x2 - 12x - 10x + 15 = 0
or, 4x(2x - 3) - 5(2x - 3) = 0
or, (4x - 5) (2x - 3) = 0
x = 5/4, 3/2
II. 3y2 – 13y + 14 = 0
or, 3y2 - 6y - 7y + 14 =0
or, 3y(y - 2) - 7(y - 2) = 0
or, (3y - 7) (y - 2) = 0
y = 7/3, 2
Hence x < y

3). D)
I. 9x2 – 26x + 16 = 0
or, 9x2 - 18x - 8x + 16 = 0
or, 9x(x - 2) - 8(x - 2) = 0
or, (9x - 8) (x - 2) = 0
x = 8/9, 2
II. 3y2 – 16y + 20 = 0
or, 3y2 - 6y - 10y + 20 =0
or, 3y(y - 2) - 10(y - 2) = 0
or, (3y - 10) (y - 2) = 0
y = 2, 10/3
Hence x ≤ y

4). A)
I. 10x2 – 17x + 7 = 0
or, 10x2 - 10x - 7x + 7 = 0
or, 10x(x - 1) - 7(x - 1) = 0
or, (10x - 7) (x - 1) = 0
x = 7/10, 1
II. 15y2 – 19y + 6 = 0
or, 15y2 - 10y - 9y + 6 =0
or, 5y(3y - 2) – (3y - 2) = 0
or, (3y - 2) (5y - 3) = 0
y = 3/5, 2/3
Hence x > y

5). E)
I. 12x2 + 19x + 5 = 0
or, 12x2 + 4x + 15x + 5 =0
or, 4x(3x + 1) + 5(3x + 1) = 0
or, (4x + 5) (3x + 1) = 0
x = -5/4, -1/3
II. 5y2 + 16y + 3 = 0
or,5y2 + 15y + y + 3 =0
or, 5y(y + 3) + 1(y + 3) = 0
or, (5y + 1) (y + 3) = 0
y = -1/5, -3
Hence no relationship can be established.

6). B)
I. x2 – 8x + 15 = 0
or, x2 - 5x - 3x + 15 =0
or, x(x - 5) - 3(x - 5) = 0
or, (x - 5) (x - 3) = 0
x = 3, 5
II. 2y2 – 11y + 14 = 0
or, 2y2 – 7y – 4y + 14 =0
or, 2y(y - 2) - 7(y - 2) = 0
or, (2y - 7) (y - 2) = 0
y = 7/2, 2
Hence no relationship can be established.

7). D)
I. x = √2916 = 54
II. y2 = 2916
y = ± 54
hence x ≥ y

8). C)
I. 3x2 + 35x + 88 = 0
or, 3x2 + 24x + 11x + 88 =0
or, 3x(x + 8) +11(x + 8) = 0
or, (3x + 11) (x + 8) = 0
x = -11/3, -8
II. y2 + 787 = 1316
y2 = 1316 – 787 = 529
y = √529 = ±23
Hence no relationship can be established.

9). D)
I. x2 – 14x + 45 = 0
or, x2 - 9x - 5x + 45 =0
or, x(x - 9) -5(x - 9) = 0
or, (x - 5) (x - 9) = 0
x = 5, 9
II. y2 – 9y + 20 = 0
or, y(y - 5) – 4 (y - 5) = 0
y = 5, 4
Hence x ≥ y

10). E)
I. x2 – 54 = 3x
Or, x2 – 9x + 6x – 54 = 0
Or, x (x - 9) +6 (x - 9) = 0
x = 9, -6
II. y2 = 36
y = ± 6

Hence no relationship can be established.



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