## 27 May 2017

### Practice Reasoning Questions For NICL AO Prelims 2017 (Puzzle & Inequality) Answers Updated

[Dated: 27th May] Practice Reasoning Questions For NICL AO Prelims 2017 (Puzzle & Inequality):
Dear Readers, Important Practice Reasoning Questions with explanation for Upcoming Exams was given here with explanation, candidates those who are preparing for Banking and all other Competitive exams can use this practice questions.

Directions (Q. 1-5): Study the following information and answer the given questions.
Seven people, namely, Pavi, Panav, Pavin, Punit, Poorna, Prithvi and Prajin like seven different cartoon characters, namely Tweety, Wiene. Superman, Garfield, Jerry, Ariel and Popeye. Each of them studies in one of the three standards, viz IV, VIII and XI with at least two of them in a standard.
(Note: None of the information given is necessarily in the same order.)
Only one person studies with Punit in XI standard. Panav studies with the one who likes Ariel. Punit does not like Ariel. Prajin studies only with the one who likes Garfield. Neither Panav nor Punit likes Garfield. Pavi likes Popeye. Pavi does not study with Panav. The one who likes Tweety studies with Pavi. Poorna studies with the one who likes Jerry. Poorna does not study in IV standard. Neither Panav nor Prithvi likes Jerry. The one who likes Superman studies with Poorna.

1). Who among the-following likes Wiene?
a)   Poorna
b)   Prithvi
c)   Punit
d)   Prajin
e)   Panav

2). Which of the following cartoon characters does Pavin like?
a)   Superman
b)   Ariel
c)   Tweety
d)   Jerry
e)   Garfield

3). Which of the following statements is true?
a)   Both Punit and Pavi study in the same standard.
b)   Panav studies in IV standard.
c)   Pavi studies with the one who likes Wiene
d)   More than two people study in the standard in which Prithvi studies.
e)   None of the given statements is true

4). Which of the following combinations represents the combination of people studying in VIII standard?
a)   Poorna and the one who likes Wiene
b)   Pavi, Prithvi
c)   Panav, Pavin, Poorna
d)   Panav and the one who likes Tweety
e)   None of these

5). Four of the following five are alike in a certain way based on the given arrangement and hence form a group. Which of the following does not belong to that group?
a)   Prajin, Punit
b)   Pavin, Panav
c)   Panav, Poorna
d)   Pavin, Poorna
e)   Prithvi, Prajin

6). Which of the following combinations represents the standard in which Prithvi studies and the cartoon character she likes'?
a)   VIII - Garfield
b)   VIII - Superman
c)   XI - Tweety
d)   IV - Ariel
e)   IV - Garfield

Directions (Q. 7-11): In these questions, a relationship between different elements is shown in the statements. The statements are followed by two conclusions. Give answer
a)   If only conclusion I is true.
b)   If only conclusion II is true.
c)   If either conclusion I or II is true.
d)   If neither conclusion I nor H is true.
e)   If both conclusion I and II are true.
7). Statements: N ≤ C > T = Q; P < E ≤ T
Conclusions:
I. C > P
II.Q ≥ E

(8-9):
Statements: B  > A = N ≥ L > R; E < D > C; B ≥ G > E
8). Conclusions:
I.C>E
II.B>E

9). Conclusions:
I. A ≥ L
II. C ≤ N

(10-11):
Statements: R = T > P < Q = S; T ≥ K > U; N = W > U
10). Conclusions:
I. S > P
II. K ≤ R
1
1). Conclusions:
I. S =N
II. K ≥ Q

1)d   2)d   3)a   4)e   5)a   6)e   7)e   8)b   9)a   10)e   11)d

Explanation:
Directions (Q. 1-6):

7). E)
Given statements:
N ≤ C > T=Q     ..(i)
P < E ≤ T        ..(ii)
Combining both statements, we get
N ≤ C > Q = T ≥ E > P
Thus, C > P is true. Again, Q ≥ T is true

(8-9): Given statements:
B > A = N ≥ L > R       …(i)
E < D > C                   …(ii)
B ≥ G > E                  ….(iii)
Combining all these statements, we get
C < D > E < G ≤ B > A = N ≥ L > R         ...(iv)

8). B) Check for conclusion I.
From (iv), we can't compare C and E. Hence I (C > E) is not true.
Check for conclusion II. From (iv), E < B or B > E is true. Hence II follows.

9). A) Check for conclusion I. From (iv), A ≥ L, is true.
check for conclusion II. From (iv), we can't compare C and N. Hence II (C ≤ N) is not true.

(10-11): Given statements:
R=T>P<Q=S         ..(i)
T ≥ K > U               ...(ii)
N = W > U             ...(iii)
Combining all these statements, we get
N=W>U<K≤T=R>P<Q=S             ..(iv)

10). E) From (iv), S > P is true. K ≤ R is true.

11). D) From (iv), S = N is not true. K ≥ Q is not true.