20 Jun 2017

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-8)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-1)
Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-8):
Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.

Here in Scoring Part we are providing 10 Questions in simplification, 10 Questions in Approximation, 5 Questions in number Series and 5 Questions in Quadratic Equations, total 30 questions in 20 Minutes. By practicing these questions regularly you can increase your calculation speed and it will help you to increase your score.





00:00:00

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1.4950 ÷ 6 + 112 × 1.75 = ? × 2
495.5
510.5
530
560.5
None of these
1). Answer: b)
? = 1/2 [(4950 / 6) + (112 × 1.75)]
? = 1/2 (825 + 196)
? = 1021 / 2 = 510.5
2. ³√166.375 = ?
11.5
8.5
6.5
5.5
7.5
2). Answer: d)
³√166.375 = ?
? = 5.5
3. 84.25 × 144 - 512 × 7 = ? % of 1068.5
620
840
780
750
None of these
3). Answer: e)
? × 1068.5 / 100 = 12132 - 3584
? = 8548 × 100 / 1068.5 = 800

4. √4096 + √13456 = 75 × ?
2.4
3.8
4.2
5.5
6
4). Answer: a)
75 × ? = 64 + 116 = 180
? = 180 / 75 = 2.4

5. 157% of 360 + 66% of 275 = 30% of ?
2210
2348
2489
2520
None of these
5).Answer: c)
30 × ? /100 = 157 × 360 /100 + 66 × 275 / 100
or, 30 × ? = 56520 + 18150 = 74670
? = 74670 / 30 = 2489

6.[(3024 ÷ 189)^1/2 + (684 ÷ 19)^2] = (?)^2 + 459
± 27
± 29
31
841
1089
6). Answer: b)
(16)1/2 + (36)^2 = ?^2 + 459
or, ?^2 = 4 + 1296 - 459 = 841
or, ? = ±29

7. 4.4 times of 5/16 of 30% of 216 = ?
81.9
83.7
87.3
89.1
None of these
7). Answer: d)
? = 4.4 × 5/16 × 30/100 × 216
? = 4.4 × 5/16 × 64.8 = 89.1

8. (0.0729 ÷ 0.1)^3 ÷ (0.081 × 10)^5 × (0.3 × 3)^5 = (0.9)^(?+3)
1
2
4
7
None of these
8). Answer: a)
(0.729)^3 ÷ (0.81)^5 × (0.9)^5 = (0.9)^(? + 3)
or, [(0.9)^3]^3 ÷ [(0.9)^2]^5 × (0.9)^5 = (0.9)^(?+3)
or, (0.9)9 ÷ (0.9)^10 × (0.9)^5 = (0.9)?+3
or, (0.9)^(9-10+5) = (0.9)^(?+3)
or, (0.9)^4 = (0.9)^(?+3)
:. ? = 1
9. (√(?%) of √1764 × 5) = 149.8 -112
18
18
324
24
None of these
9). Answer: e)
√(?/100) of 42 × 5 = 37.8
or, √? / 10 of 42 × 5 = 37.8
or, 4.2 √? × 5 = 37.8
or, 21 √? = 37.8
or, √? = 1.8
or, ? = 3.24

10.(27)^2 × 6 ÷ 9 + (7)^3 + 71 =(?)^3 - 431
11
(13)^3
13
(11)^2
None of these
10). Answer: a)
(729 × 6 ÷ 9) + 343 + 71 + 431 = ?3
or, 486 + 343 + 71 + 431 = ?3
or, ?^3 = 1331 = (11)3
:. ? = 11

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. √(√29585 + √23100) = ?
18
20
16
22
24
11).Answer: a) ≈
? ≈ √(172 +152) = √324 = 18

12. 48.5% of 7842 + ? % of 1318 = 4515
42
48
54
57
60
12).Answer: c)
1320 × ? /100 = 4515 – (48.5 × 7840 / 100)
1320 × ? /100 ≈ 4515 - 3800 = 715
? = 71500 / 1320
? = 54.16 ≈ 54
13.118.257 × 289.92 + 43.54 × 171.37 = ?
41500
41700
41900
42100
42300
13). Answer: b)
? ≈ 118.25 × 290 + 43.5 × 170
? = 34292.5 + 7395
? = 41687.5 ≈ 41700
14. ³√226980 = ?
59
61
63
65
67
14). Answer: b)
? = ³√226980 ≈ 61
15. 8847256 ÷ 4446 = ?
1930
1950
1970
1990
2010
15). Answer: d)
? ≈ 8847256 / 4446
? = 1989.936 ≈ 1990
16. (838 ÷ 14.95) × 17.85 = ?
900
1000
1100
1200
1300
16).Answer: b)
? ≈ 840 / 15 × 18 = 1008 ≈ 1000
17. ³√29790 × √1760 = ?
1200
1250
1300
1350
1400
17).Answer: c)
? ≈ 31 × 42 = 1302 ≈ 1300
18. {555.05 ÷ 3.001 × 11.968} × 4.99 = ?
11100
12100
13100
14100
15100
18).Answer: a)
? ≈ {555 / 3 × 12} × 5
? = 185 × 12 × 5
? = 11100

19. 1873 ÷ 84.85 + 40.81 × 16.96 = ?
700
720
740
760
780
19). Answer: b)
? ≈ 1870 / 85 + 41 × 17
? = 22 + 697
? = 719 ≈ 720

20. 79.99% of 873 + 18.08% of 255.05 = ?
720
750
790
850
890
20). Answer: b)
? ≈ 80 × 875 /100 + 18 × 255 / 100
? = 700 + 45.9
? = 745.9 ≈ 750
Direction (21 – 25): What value should come in place of the question mark (?) in the following number series? 21. 28, 32, 23, 39, 14, ?
30
50
55
6
14
21). Answer: b)
First series 28, 23, 14
28 – 5 =23;
23 – 9 = 14, ….
i.e. The difference between the no. is -5, -9, -13, ….
Second series 32, 37, ?
32 +7 = 39;
39 + 11 = 50
i.e. The difference between the no. is +7, +11, +15, ….

22. 5, 12, 33, 136, 675, ?
5569
4426
5046
4065
4056
22). Answer: e)
The series is,
5 x 2 + 2 = 12;
12 x 3 - 3 = 33;
33 x 4 + 4 = 136;
136 x 5 - 5 = 675;
675 x 6 + 6 = 4056

23. 2, 4, 12, 4, 240, ?
960
1440
1080
1920
None of these
23). Answer: b)
The series is
2 × (2 + 0) = 4
4 × (2 + 1) = 12
12 × (2 + 2) = 48
48 × (2 + 3) = 240
240 × (2 + 4) = 240 × 6 = 1440
24. 2, 5, 9, 19, 37, ?
76
74
75
73
None of these
24). Answer: c)
The series is,
2 × 2 + 1 = 5
5 × 2 - 1 = 9
9 × 2 + 1 = 19
19 × 2 – 1 = 37
37 × 2 + 1 = 75

25. 4, -8, 16, -32, 64, ? .
128
-128
192
-192
None of these
25).Answer: b)
First series 4, 16, 64
4 × 4 = 16
16 × 4 = 64
i.e. The sequence of the series is × 4, × 4 ….
Second series -8, -32, ?
-8 × 4 = -32
-32 × 4 = - 128
i.e. The sequence of the series is × 4, × 4 ….

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) if x < y
b) if x > y
c) if x ≤ y
d) if x ≥ y
e) if x = y, or relationship between x and y can't be established.

26. I. 7x^2 - 33x + 20 = 0
II. 7y^2 + 9y – 10 = 0

a)
b)
c)
d)
e)
26). Answer: d)
I. 7x^2 - 33x + 20 = 0
or, 7x^2 - 28x - 5x + 20 = 0
or, 7x(x - 4) - 5(x —4)= 0
or (7x - 5) (x - 4) = 0
or, x = 4, (5/7)
II. 7y^2 + 9y -10 = 0
or, 7y^2 + 14y - 5y – 10 = 0
or, 7y(y + 2) - 5(y + 2) = 0
or, (7y - 5)(y + 2) = 0
or, y = 5/7, -2
Hence, x ≥ y

27. I. 7x + 3y = 8
II. 3x + 2y = 12

a)
b)
c)
d)
e)
27).Answer: a)
I. 7x + 3y = 8
II. 3x + 2y = 12
Now, solving both the eqns, we get
eqn (i) x 2 - eqn (ii) x 3
(14x+ 6y=16) – (9x + 6y = 36)
5x = -20
x = -4 and y = 12
Hence, x
28. I. x^2 = 289
II. y = 3√2197

a)
b)
c)
d)
e)
28). Answer: e)
I. x^2 = 289
or x = ±17
II. y = 3√2197
y = 13
Hence, we can’t find a relationship between x and y.
29. I. 8x^2 - 11x + 3 = 0
II. y^2 - 8y + 7 = 0

a)
b)
c)
d)
e)
29).Answer: c)
8x^2 -11x + 3 = 0
or, 8x^2 - 8x - 3x +3 = 0
or, 8x(x - 1) - 3(x - 1) = 0
or, (8x -3)(x - 1) = 0
or, x =1, 3/8
II. y^2 - 8y + 7 = 0
or, y^2 - y - 7y + 7 = 0
or, y(y - 1) - 7(y - 1) = 0
or, (y - 1) (y - 7) = 0
or, y = 1, 7
Hence, x ≤ y
30. I. x = √1089
II. y + y – 756 = 0

a)
b)
c)
d)
e)
30).Answer: b)
I. x = √1089
or, x = 33
II. y^2 + y - 756 =0
or, y^2 + 28y - 27y - 756 = 0
or, y(y +28) - 27(y + 28) = 0
or, (y - 27)(y + 28) = 0
or, y= 27, -28
Hence, x > y



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