17 Jun 2017

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-5)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-1)
Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-5):
Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.

Here in Scoring Part we are providing 10 Questions in simplification, 10 Questions in Approximation, 5 Questions in number Series and 5 Questions in Quadratic Equations, total 30 questions in 20 Minutes. By practicing these questions regularly you can increase your calculation speed and it will help you to increase your score.



00:00:00

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). 1/6 of (92)% of 1 1/23 of (650) = 85 + ?
18
21
19
28
None of these
1). Answer: c)
650 × 24/23 × 92/100 × 1/6 = 85 + ?
or, ? = 104 - 85 = 19
2. 92 × 576 ÷ (2 × √1296) = (?)^3 + √49
3
9^2
9
27
None of these
2). Answer: c)
92 × 576 ÷ (2 × √1296) = (?)^3 + √49
or, 92 × 576 / 72 = (?)^3 + 7
or, 736 - 7 = ?^3
?3 = 729
? = ³√729 = 9
3. 3 1/4 + 2 1/2 – 1 5/6 = (?)^2 /10 + 1 5/12
25
√5
625
15
5
3). Answer: e)
(3 + 2 – 1 – 1) + (1/4 + 1/2 – 5/6 – 5/12) = ?^2 / 10
3 + ((3 + 6 – 10 – 5) / 12) = ?^2 / 10
3 - 6/12 = ?^2 / 10
3 – 1 /2 = ?^2 / 10
?2 = 5/2 × 10 = 25
? = 5.

4. (√8 × √8)^(1/2) + (9)^(1/2) = (?)^3 + √8 – 340
7
19
18
9
None of these
4). Answer: a)
(√8 × √8)^(1/2) + (9)^(1/2) = (?)^3 + √8 – 340
√8 + 3 = (?)^3 + √8 – 340
(?)^3 = 340 + 3
(?)^3 = 343
? = 7

5. (15 × 0.40)^4 ÷ (1080 ÷ 30)^4 × (27 × 8)^4 = (3 × 2)^(?+5)
8
3
12
16
None of these
5). Answer: b)
(15 × 0.40)^4 ÷ (1080 ÷ 30)^4 × (27 × 8)^4 = (3 × 2)^(? + 5)
6^4 ÷ (36)^ 4 × (216)^ 4 = (6)^(? + 5)
6^4 ÷ (6^2)^4 × (6^3)^ 4 = (6)^ (? + 5)
6^(4 + 12 – 8) = (6)^(? + 5)
(6)^ 8 = (6)^(? + 5)
? + 5 = 8
? = 3

6. 1664 × 1.75 + 1008 × 1.25 - 1220 × 0.65 = ?
3147
3287
3379
3432
3548
6). Answer: c)
? = 2912 + 1260 - 793 = 3379

7. (?% of 999) ÷ 0.9 = 166.5
12
15
18
21
24
7). Answer: b)
? × 999 / 100 = 166.5 × 0.9
? = 14985 / 999 = 15

8. {(157.8)^2 - (117.2)^2} × 0.008 = ?
89.32
92.34
94.86
96.12
98.5
8). Answer: a)
? = {(157.8 + 117.2) × (157.8 - 117.2)} × 0.008
? = (275 × 40.6) × 0.008 = 11165 × 0.008
= 89.32
9. 82992 ÷ ? = 76 × 42
22
24
26
28
32
9). Answer: c)
? = 82992 / (76 × 42) = 26

10. [{(486)^2 ÷ (27)^2} × 15] ÷ 12 = ?
365
375
385
395
405
10). Answer: e)
? = {[(486 × 486) / (27 × 27)] × 15} ÷ 12
? = 324 × 15 / 12 = 405

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. (24/9)^2 × 399 / 39 ÷ 41 / 899 = ?
1600
1650
1700
1550
1750
11). Answer: a)
(24/9)^2 × (399/39) ÷ (41/899) = ?
? ≈ (576 / 81) × (400/40) ÷ (40/900)
? = 1600

12. 67.99% of 1401 - 13.99% of 1299 = ?
700
720
770
800
740
12). Answer: c)
68% of 1400 - 14% of 1300
= 952 - 182 = 770
13. 5466.97 - 3245.01 + 1122.99 = ? + 2309.99
1130
1000
1100
1030
1060
13). Answer: d)
5467 - 3245 + 1123 - 2310 = ?
? = 1035
14. 5998 ÷ 9.98 + 670.99 - 139.99 = ?
1080
1280
1180
1130
1230
14). Answer: d)
5998 ÷ 9.98 + 670.99 - 139.99 = ?
? ≈ 6000/10 + 670 – 140
? = 600 + 670 – 140
? = 1130
15.– (4.99)^3 + (29.98)^2 - (3.01)^4 = ?
550
590
620
650
690
15). Answer: e)
? = – (4.99)^3 + (29.98)^2 - (3.01)^4
? ≈ - 5^3 + 30^2 - 3^4
? = – 125 + 900 – 81
? = 694 ≈ 690
16. 2874.78% of 124.06 ÷ √26 = ?
650
680
710
740
780
16). Answer: c)
? ≈ (2875 × 124 / 100) ÷ 5
? = 3565 / 5
? = 713 ≈ 710
17. 44.4 × 4.44 ÷ 7.98 + √24000 = ?
180
210
260
320
350
17). Answer: a)
? = 44.4 × 4.44 / 8 + √24000
? ≈ 197 / 8 + 154.9
? ≈ 25 + 155 = 180
18. 134.9% of 127.89 + 115.05% of 23.94 = ?
140
160
180
200
220
18). Answer: d)
? = 135 × 128 / 100 + 115 × 24 / 100
? = 172.8 + 27.6 = 200.4 ≈ 200

19. (83.98)^2 ÷ 13.49 = ?
500
525
550
575
600
19). Answer: b)
? = (83.98)^2 / 13.49
? = (84)^2 / 13.5
? = 522.66 ≈ 525

20. (2904 ÷ 34.95 - 12.99) × 5.96 = ?
380
400
420
440
460
20). Answer: c)
? = (2900/35 – 13) × 6
? ≈ (83 – 13) × 6
? = 70 × 6 = 420
Direction (21 – 25): What value should come in place of the question mark (?) in the following number series? 21. 19 , 16 , 44 , 107 , ?
108
156
215
151
251
21). Answer: c)
The difference of difference between numbers is + 25, +35, +45, ….

22. 11 , 14 , 23 , 50, ?
111
121
151
131
141
22). Answer: d)
The series is,
11 + 3^1 = 11 + 3 = 14;
14 + 3^2 = 14 + 9 = 23;
23 + 3^3 = 23 + 27 = 50;
50 + 3^4 = 50 + 81 = 131

23. 19 , 25 , 42 ,71 , 113 , ?
169
153
186
196
269
23). Answer: a)
The difference of difference between numbers is +11, +12, +13, +14, …
24. 21 , 35 , 30 , 44 , 39 ,?
59
53
55
45
46
24). Answer: b)
The series is,
21 + 14 = 35;
35 – 5 = 30;
30 + 14 = 44;
44 – 5 = 39;
39 + 14 = 53

25. 7, 14, 30, 56 , 93 , ?
142
403
124
96
124
25). Answer: a)
The difference of difference between the numbers is, +9, +10, +11, +12, …..

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) P < Q
b) P ≤ Q
c) P ≥ Q
d) P = Q or no relation can be established between P and Q
e) P > Q
26. Ⅰ. 9P^2 – 9P + 2 = 0
Ⅱ. 18Q^2 + 3Q = 1

a)
b)
c)
d)
e)
26). Answer: e)
Ⅰ. 9P^2 – 9P + 2 = 0
Or, 9P^2 – 6P – 3P + 2 = 0
Or, (3P – 1)(3P – 2) = 0
∴ P = (1 / 3), (2 / 3)
Ⅱ. 18Q^2 + 3Q – 1 = 0
Or, 18Q^2 + 6Q – 3Q – 1 = 0
Or, (6Q – 1)(3Q + 1) = 0
∴ Q = - (1 / 3), (1 / 6)
Hence , P > Q

27. Ⅰ. P^2 + 13P + 42 = 0
Ⅱ. 2Q^2 + 22Q + 60 = 0

a)
b)
c)
d)
e)
27). Answer: b)
Ⅰ. P^2 + 13P + 42 = 0
Or, P^2 + 7P + 6P + 42 = 0
Or, (P + 7)(P + 6) = 0
∴ P = -7, -6
Ⅱ. 2Q^2 + 22Q + 60 = 0
Or, Q^2 + 11Q + 30 = 0
Or, (Q + 5)(Q + 6) = 0
∴ Q = -5, -6
Hence , Q ≥ P
28. Ⅰ. 6P + 7Q = 45
Ⅱ. 2P + 3Q = 17

a)
b)
c)
d)
e)
28). Answer: e)
P = 4 and Q = 3
Hence P > Q
29. Ⅰ. 3P^2 + 192 = - 48P
Ⅱ. Q^2 + 16Q + 64 = 0

a)
b)
c)
d)
e)
29). Answer: d)
Ⅰ. 3P^2 + 48P + 192 = 0
Or, P^2 + 16P + 64 = 0
Or, (P + 8)^2 = 0
∴ P = -8 , -8
Ⅱ. Q^2 + 16Q + 64 = 0
Or, (Q + 8)^2 = 0
∴ Q = -8, -8
Hence , P = Q
30.Ⅰ. 15P^2 - 8P + 1 = 0
Ⅱ. 45Q^2 + 21Q = 6

a)
b)
c)
d)
e)
30). Answer: c)
Ⅰ. 15P^2 – 8P + 1 = 0
Or, 15P^2 – 3P – 5P + 1 = 0
Or, (3P – 1)(5P – 1) = 0
∴ P = (1 / 3), (1 / 5)
Ⅱ. 45Q^2 + 21Q – 6 = 0
15Q^2 + 7Q – 2 = 0
Or, 15Q^2 + 10Q – 3Q – 2 = 0
Or, (5Q – 1)(3Q + 2) = 0
∴ Q = (1 / 5), - (2 / 3)
Hence , P ≥ Q




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