23 Jun 2017

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-11)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-11):
Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.

Here in Scoring Part we are providing 10 Questions in simplification, 10 Questions in Approximation, 5 Questions in number Series and 5 Questions in Quadratic Equations, total 30 questions in 20 Minutes. By practicing these questions regularly you can increase your calculation speed and it will help you to increase your score.

00:00:00

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). [(23.65)^2 - (48.35)^2 ] / 0.9 = ?
-1976
-1864
-1724
-1684
None of these
1). Answer: a)
? = [(23.65 + 48.35)(23.65 – 48.35)] / 0.9
? = 72 × (– 24.7) / 0.9
or, ? = - 1976
2. 76% of 960 - 45% of 148 = ?% of 5525
15
20
24
30
None of these
2). Answer: e)
? / 100 × 5525 = 76 × 960 /100 – 45 × 148 /100
? / 100 × 5525 = 729.6 - 66.6 = 663
? = 663 × 100 / 5525 = 12
3. (4096)^3.7 ÷ (256)^4.3 × (64)^5 ÷ (16)^-4 = (4)?
22
24
26
28
None of these
3). Answer: d)
(4^6)^3.7 ÷ (4^4)^4.3 × (4^3)^5 ÷ (4^2)^-4 = (4)^?
(4)^? = (4)^22.2 ÷ (4)^17.2 × (4)^15 ÷ (4)^-8
(4)^? = (4)^(22.2 -17.2 + 15 + 8) = (4)^28
? = 28

4. 3 2/7 of 4 5/11 of 3/35 of 3080 = ?
3864
3948
4014
4124
None of these
4). Answer: a)
? = 3 2/7 of 4 5/11 of 3/35 of 3080
? = 23/7 × 49/11 × 3/35 × 3080
? = 3864

5). [5√(2√38416)]^(5/2) = ?
14
196
2744
38416
None of these
5). Answer: a)
[5√(2√38416)]^(5/2) = ?
? = [5√196]^(5/2)
? = 196^(1/2) = 14

6. 4/7 of 3/11 of 24/13 of 15015 = ?
4280
4320
4480
4550
None of these
6). Answer: b)
? = 4/7 × 3/11 × 24/13 × 15015
? = 4320

7. 984 + 3.75 × 440 - 1.25 × 248 = ?
2148
2264
2324
2420
None of these
7). Answer: c)
? = 984 + 1650 - 310
= 2634 - 310 = 2324

8. [3√(2√20736)]^(3/2) = ?
18
16
14
12
8
8). Answer: d)
? = [3√(2√20736)]^(3/2)
? = [3√(144)]^(3/2)
? = 144^(1/2) = 12
9. (?% of 664) ÷ 0.8 = 332
80
75
60
50
40
9). Answer: e)
? / 100 × 664 = 332 × 0.8 = 265.6
? = 265.6 × 100 / 664 = 40

10.18.5 % of 7200 + 27.8% of 1800 + 16.6 = (?)^2
37
39
43
47
None of these
10). Answer: c)
(?)^2 = 18.5 × 7200 /100 + 27.8 × 1800 /100 + 16.6
(?)^2 = 1332 + 500.4 + 16.6 = 1849 = (43)2
? = 43

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11.379.87 × 44.12 - 78.89 × 84.15 + 373 = ?
10240
10460
10450
10580
10720
11). Answer: b)
? ≈ (380 × 44) - (79 × 84) + 373
? = 16720 - 6636 + 373 = 10457 ≈ 10460

12. (2.38% of 743) × (1.84% of 588) = ?
190
290
390
490
590
12). Answer: a)
? ≈ 2.4 × 740 /100 × 1.8 × 590 / 100
? = 17.76 × 10.62 = 188.6112 ≈ 190
13. 182.06 × 17.987 + 172% of 785 = ?
4175
4225
4450
4505
4625
13). Answer: e)
? ≈ 182 × 18 + 172 × 785 /100
? = 3276 + 1350.2 = 4626.2 ≈ 4625
14. 17.99 × 155.05 + 1245 ÷ 32 = ?
2230
2430
2630
2830
3030
14).Answer: d)
? = 18 × 155 + 1245 / 32
? = 2790 + 38.9 = 2828.9 ≈ 2830
15. 77.003 × 13.998 + 18.04 × 14.996 = ?
1150
1250
1350
1450
1550
15). Answer: c)
? ≈ 77 × 14 + 18 × 15
? = 1078 + 270 = 1348 ≈ 1350
16. 22% of 164.4 + 13.89 % of 65 = ?
40
45
49
54
58
16). Answer: b)
? ≈ 22 × 164.4/100 + 14 × 65 / 100
? ≈ 36 + 9 = 45
17. [(1.29)^2 + (3.05)^2] / 0.198 = ?
25
6
66
54
42
17). Answer: d)
? ≈ [(1.3)^2 + (3)^2 ] / 0.2
? = (1.69 + 9) / 0.2
? = 10.7 / 0.2 = 53.5 ≈ 54
18. (48.84)^2 × 7.079 = ?
16200
16400
16600
16800
16990
18). Answer: d)
? ≈ 7 × 49^2
? = 16807 ≈ 16800

19. √ 2020 + √320 + √1330 = ?
80
100
120
140
160
19). Answer: b)
√2020 ≈ 45, √320 ≈ 18, √1330 ≈ 36.5
? = 45 + 18 + 36.5 = 99.5 ≈ 100

20. (8/3 × 13/5) + (7/2 × 5/3) + (18/7 × 28/16) = ?
11.5
14.5
17.5
21.5
27.5
20). Answer: c)
? = 104 / 15 + 35 / 6 + 9 / 2
? ≈ 7 + 6 + 4.5 = 17.5
Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number. 21. 18.3, 20.6 , 16, 22.9 , 13.7, 22.2, 11.4
22.2
18.3
13.7
22.9
20.6
21). Answer: a)
The series is,
18.3 + 2.3 = 20.6
20.6 - 4.6 = 16
16 + 6.9 = 22.9
22.9 - 9.2 = 13.7
13.7 +11.5 = 25.2 ≠ 22.2
25.2 - 13.8 = 11.4

22. 9 , 5 , 6 , 10.5 , 23 , 61, 183
183
10.5
61
5
9
22). Answer: c)
The sequence in the series is,
9 x 0.5 + 0.5 = 5
5 x 1 + 1 = 6
6 x 1.5 + 1.5 = 10.5
10.5 x 2 + 2 = 23
23 x 2.5 + 2.5 = 60 ≠ 61
60 x 3 + 3 = 183

23. 188, 154, 140, 132 ,128, 126 , 125
125
188
132
126
154
23). Answer: e)
The series is,
188 - 32 = 156 ≠ 154
156 - 16 = 140
140 - 8 = 132
132 - 4 = 128
128 - 2 = 126
126 - 1 = 125
24. 2, 4 , 11 , 37 , 151 , 771 , 4633
11
4633
771
151
2
24). Answer: d)
The sequence in the series is,
2 x 1 + 2 = 4
4 x 2 + 3 = 11
11 x 3 + 4 = 37
37 x 4 + 5 = 153 ≠ 151
153 x 5 + 6 = 771
771 x 6 + 7 = 4633

25. 391 , 394 , 399 , 411 , 431 , 461, 503
503
394
399
431
391
25). Answer: b)
The series is,
391 + 2 = 393 ≠ 394
393 + 6 = 399
399 + 12 = 411
411+ 20 = 431
431 + 30 = 461
461 +42 = 503

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) if x > y
b) if x < y
c) if x ≥ y
d) if x ≤ y
e) if x =y, or no relation can be established between x and y.
26. I. 5x^2 – 87x + 378 = 0
II. 3y^2 – 49y + 200 = 0

a)
b)
c)
d)
e)
26). Answer: a)
I. 5x^2 - 45x - 42x + 378 = 0
or,5x(x - 9) - 42(x- 9) = 0
or. (5x - 42)(x -9) = 0
x = 9, 42/5
II. 3y^2 - 24y - 25y + 200=0
or, 3y(y - 8) -25(y - 8) = 0 or, (y - 8)(3y-25)=0
y = 8, 25/3
Hence, x>y

27.I. 10x^2 – x – 24 = 0
II. y^2 – 2y = 0

a)
b)
c)
d)
e)
27). Answer: e)
I. 10x^2 -16x + 15x – 24 = 0
or, 2x(5x -8) + 3(5x - 8)=0
or,(2x + 3)(5x -8) = 0
x = -3/2, 8/5
II. y^2 – 2y = 0
or, y(y -2) = 0
y = 0, 2
i.e. no relationship between x and y.
28. I. x^2 – 5x + 6 = 0
II. 2y^2 – 15y + 27 = 0

a)
b)
c)
d)
e)
28). Answer: d)
I. x^2 - 2x - 3x + 6 =0
or, x(x -2) - 3(x -2) = 0
or, (x -2) (x -3) = 0
x =2, 3
II. 2y^2 - 6y - 9y + 27 = 0
or, 2y(y - 3)-9(y -3) = 0
or, (y- 3) (2y -9) = 0
y = 3, 9/2
hence, x ≤ y
29. I. 3x + 2y = 301
II. 7x – 5y = 74

a)
b)
c)
d)
e)
29). Answer: b)
I. eqn (I) × 5 + eqn (II) × 2
[15x + 10y = 1505] + [14x – 10y = 148] = 29x = 1653
x = (1653/29) = 57
and y = 65
hence, x< y
30. I. 14x^2 – 37x + 24 = 0
II. 28y^2 – 53y + 24 = 0

a)
b)
c)
d)
e)
30). Answer: c)
14x^2 - 37x + 24 = 0
or, 14x^2 - 21x- 16x + 24 = 0
or, 7x(2x -3) -8(2x -3) = 0
or, (2x - 3)(7x - 8) = 0
x = (3/2), (8/7)
II. 28y^2 - 53y + 24 = 0
or, 28y^2 -21y - 32y + 24 =0
or, 7y(4y - 3) -8(4y - 3) = 0
or, (7y - 8) (4y - 3) = 0
y = 8/7, 3/4
x ≥ y

Do you feel that you are weak in English Section?
Here we are creating a pathway to win the English Section in upcoming IBPS Exams 2017
 English Learning Session :– (Day-1) English Learning Session :– (Day-2) English Learning Session :– (Day-3) English Learning Session :– (Day-4) English Learning Session :– (Day-5) English Learning Session :– (Day-6) English Learning Session :– (Day-7)