## 6 Jun 2017

### Practice Aptitude Questions For NICL AO & RBI Grade B 2017 (Data Interpretation - Caselets)

Practice Aptitude Questions For NICL AO & RBI Grade B 2017 (Data Interpretation - Caselets):
Dear Readers, Important Practice Aptitude Questions for NICL AO & RBI Grade B 2017 Exams was given here with Solutions. Aspirants those who are preparing for Bank exams & all other Competitive examination can use this material.

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### 6. How many students are there who have cleared at most one exam conducted by these three organisations? 560 605 579 632 592 6). X + K = 260 – (72 + 60) = 128 –––––– (I) Y + K = 340 – (72 + 48) = 220 ––––––– (II) Z + K = 436 – (48 + 60) = 328 –––––––(III) X + Y + Z + K = 800 – (72 + 60 + 48) = 800 – 180 = 620 Now, equation (I) + (II) + (III) – equation (IV) gives K = 28 2K = 56, X = 100 Y = 192 Z = 300 Required number of students = 100+ 192 + 300 = 592 Answer is: E 7. How many students cleared all three banks examination? 23 28 30 20 40 7). X + K = 260 – (72 + 60) = 128 –––––– (I) Y + K = 340 – (72 + 48) = 220 ––––––– (II) Z + K = 436 – (48 + 60) = 328 –––––––(III) X + Y + Z + K = 800 – (72 + 60 + 48) = 800 – 180 = 620 Now, equation (I) + (II) + (III) – equation (IV) gives K = 28 2K = 56, X = 100 Y = 192 Z = 300 Number of students who cleared all the three bank exams = 28 Answer is: B 8. What is the percentage of students who cleared the exam conducted by SBI but couldn't clear the exam conducted by RBI? 28 % 30 % 37.5 % 33 % 22.5 % 8). X + K = 260 – (72 + 60) = 128 –––––– (I) Y + K = 340 – (72 + 48) = 220 ––––––– (II) Z + K = 436 – (48 + 60) = 328 –––––––(III) X + Y + Z + K = 800 – (72 + 60 + 48) = 800 – 180 = 620 Now, equation (I) + (II) + (III) – equation (IV) gives K = 28 2K = 56, X = 100 Y = 192 Z = 300 Required % = 264/800 × 100 = 33% Answer is: D 9. What is the percentage of students who cleared the only examination conducted by IBPS? 10 % 17.5 % 12.5 % 7.5 % 14.5 % 9). X + K = 260 – (72 + 60) = 128 –––––– (I) Y + K = 340 – (72 + 48) = 220 ––––––– (II) Z + K = 436 – (48 + 60) = 328 –––––––(III) X + Y + Z + K = 800 – (72 + 60 + 48) = 800 – 180 = 620 Now, equation (I) + (II) + (III) – equation (IV) gives K = 28 2K = 56, X = 100 Y = 192 Z = 300 Required % = 100/800 × 100 = 12.5% Answer is: C 10.How many students are there who cleared examinations conducted by at least two organisations? 208 193 222 201 217 10). X + K = 260 – (72 + 60) = 128 –––––– (I) Y + K = 340 – (72 + 48) = 220 ––––––– (II) Z + K = 436 – (48 + 60) = 328 –––––––(III) X + Y + Z + K = 800 – (72 + 60 + 48) = 800 – 180 = 620 Now, equation (I) + (II) + (III) – equation (IV) gives K = 28 2K = 56, X = 100 Y = 192 Z = 300 Required number of students = 72 + 48 + 60 + 28 = 208 Answer is: A

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