## 7 Jun 2017

### Practice Quantitative Aptitude Questions For SBI Clerk 2017 & IBPS 2017 Exams (Data Interpretation & Caselets)

Practice Quantitative Aptitude Questions For SBI Clerk 2017 & IBPS 2017 Exams (Data Interpretation - Pie Chart & Caselets):

Dear Readers, Important Practice Aptitude Questions for SBI Clerk & IBPS Exams 2017 was given here with Solutions. Aspirants those who are preparing for the Bank Examination and other Competitive Examination can use this material.

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### 1.What will be the percentage of total number of males in U.P., M.P. and Goa together to the total population of all the given states? 25% 27.5% 28.5% 31.5% None of these 1). Let N = 3276000. Number of males in U.P =(3/5) of (15% of N)= (3/5) × (15/100) × N = 9×(N/100) Number of males in M.P = [3/4 of (20% of N)] = (3/4) × (20/100)×N = 15×(N/100) Number of males in Goa = [(3/8) of (12% of N)] = (3/8) × (12/100) ×N = 4.5×(N/100) Total number of males in these three states = (9+15+4.5) × (N/100) = 28.5 × (N/100) Required Percentage = {[28.5 × (N/100)] / N × 100}% = 28.5% Answer: C 2. What is the ratio of the number of females in Tamilnadu to the number of females in Delhi?

7 : 5
9 : 7
13 : 11
15 : 14
None of these
2). Required ratio = [(4/7)of (9% of 3276000)] / [(3/5) of (8% of 3276000)]
= [(4/7) × 9] / [(3/5) × 8] = (4/7) × 9 × (5/3) × (1/8)
= 15/14 = 15:14

3.What was the total number of illiterate people in A.P. and M.P. in 2001?
876040
932170
981550
1161160
None of these
3).No. of illiterate people in A.P. = [(7/9) of (25% of 3276000)] = 637000
No. of illiterate people in M.P. = [(4/5) of (20% of 3276000)] = 524160
Total number = 637000 + 524160 = 1161160

4.What was the number of males in U.P. in the year 2001?
254650
294800
321470
341200
None of these
4). Number of males in U.P. = [(3/5) of (15% of 3276000)]
= (3/5) × (15/100) × 3726000 = 294840.

5.If in the year 2001, there was an increase of 10% in the population of U.P. and 12% in the population of M.P. compared to the previous year, and then what was the ratio of populations of U.P. and M.P. in 2000?
42 : 55
48 : 55
7 : 11
4 : 5
None of these
5).Let X be the population of U.P. in 2000. Then,
Population of U.P. in 2001 = 110% of X = (110/100) × X
Also, let Y be the population of M.P. in 2000. Then,
Population of M.P. in 2001 = 112% of Y = (112/100) × Y
Ratio of populations of U.P. and M.P. in 2001 = [(110/100) × X] / [(112/100) × Y] = 110X / 112Y
From the pie-chart, this ratio is (15/20).
110X/112Y = 15/20 = X/Y = (15/20) × (112/110) = 42/55
Thus, ratio of populations of U.P. and M.P. in 2000 = X :Y = 42:55

### 6.What percentages of students are enrolled in all three departments? 3.3% 7.2% 8.5% 9.32% None of these 6). Directions (6-10): Boys = (7/15)×150 = 70 Girls = 150 – 70 =80 Required percentage= (5/150) ×100 = 10/3 = 3 1/3%=3.3% Answer: A 7.What is the respective ratio of boys and girls only in Information technology department? 13 : 9 9 : 13 9 : 11 11 : 9 None of these 7).Required ratio = 18 : 26 = 9 : 13 Answer: B 8.What is the ratio of number of boys in Information technology and Network management both and that of girls in and Network management only? 5 : 3 3 : 5 5 : 4 4 : 7 None of these 8). Required ratio = 5 : 4 Answer: C

9.By what percent is the number of boys in Information technology more than the number of girls in software engineering department?
13 1/3 %
33 1/3%
14 2/3%
16 2/3%
None of these
9).Required percentage = [(28-24)/24] × 100 = (4/24) × 100
= (50/3) = 16 2/3%

10.What is the ratio of boys and girls enrolled in Software engineering department only?
10 : 11
9 : 10
7 : 5
5 : 7
None of these
10). Required ratio = 10 : 11