9 Jul 2017

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-26)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-1)



00:00:00

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). (609)^2 + 25% of 200 – 3/4 of 1976 = ?
369439
369429
369419
369449
379449
1). Answer: d)
370881 + 50 - 494 × 3
= 370881 + 50 - 1482 = 369449
2. √17161 × 18 + 92 × 94 + 2/5 of 125 = ?
11054
11354
11056
12346
10156
2). Answer: c)
? = √17161 × 18 + 92 × 94 + 2/5 of 125
= 131 × 18 + 8648 + 50
= 2358 + 8648 + 50 = 11056
3. ?% of 650 + 40% of 525 = 275
12
15
10
13
8
3). Answer: c)
?% of 650 + 40% of 525 = 275
?/100 × 650 + 210 = 275
6.5 × ? = 275 - 210 = 65
? = 650/65 = 10

4. 3√12167 ×√11881 + 70% of 6210=?
6823
7853
6854
9231
8454
4). Answer: c)
? = 3√12167 ×√11881 + 70%of 6210
= 23 x 109 + 70/100 × 6210
= 2507 + 4347 = 6854

5). ∛35937 ×∛1331 ÷ √121 + 60% of 1295 = ?
895
890
610
810
980
5). Answer: d)
? = 3√35937 × 3√1331 ÷√121 + 60% of 1295
= 33 × 11 ÷ 11 + 3/5 × 1295
= 33 + 777 = 810

6. 15% of 240 + √11449 - 25% of 160 = ?
109
112
116
103
None of these
6). Answer: d)
? = 15/100 × 240 + 107 – 25/100 × 160
= 36 + 107 - 40 = 103

7. (64)^4.5 × (4096)^3.4 ÷ (16)^1.5 × (4)^3 = ?
4^(43.8 )
4^(42.9 )
4^(40.8 )
4^(33.9)
None of these
7). Answer: d)
? = (64)^4.5 × (4096)^3.4 ÷ (16)^1.5 × (4)³
= (4³)^4.5 × (4^6)^3.4 ÷ (42)^1.5 × 4^3
= (4)^13.5 × (4)^20.4 ÷ (4)^3 × 4^3
= (4)^(13.5) × (4)^(20.4 – 3) × 4^3
= (4)^(13.5 + 17.4 + 3)
= (4)^(33.9)

8. (207)^2 + 20% of 200 × √1225 - 25% of 160 = ?
46409
49409
44209
35409
None of these
8). Answer: c)
? = (207)² + 20% of 200 × √1225 - 25.1% of 160
= 42849 + 1/5 × 200 × 35 – 1/4 × 160
= 42849 + 40 × 35 - 40 = 44209
9. √9216 ×∛1728 - 40%of 1200 = ?
685
772
840
672
None of these
9). Answer: d)
? = √9216 × ³√1728 - 40% of 1200
= 96 × 12 – 2/5 × 1200
= 1152 - 480 = 672

10. 2/5 of 1/4 of 5/3 of ∛46656 = ?
12
9
6
15
None of these
10). Answer: c)
? = 2/5 × 1/4 × 5/3 ×3√46656 =1/6 × 36 = 6

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. (871% of 752) ÷ 251 = ?
26
38
45
66
75
11). Answer: a)
? = (871% of 752) + 251
= (870 / 100) × 750 × (1 / 250) = 26.1 ≈ 26

12. 0.5% of 349 × 8.2% of 574 = ?
80.5
84.5
89.5
95.5
None of these
12). Answer: a)
?= (0.5% of 349) × (8.2% of 574)
= (0.5% of 350) × 8% of 575
= [( 0.5 / 100) × 350] × [( 8 / 100) × 575]
= (1.75 × 46) = 80.5
13. 29.99% of 155.012 + 12.98% of 164.99 = ?
54
58
64
66
68
13). Answer: e)
? = 29.99% of 155.012 + 12.98% of 164.99
= (30% of 155) + (13% of 165)
= [ (30 / 100) × 155 ] + [ (13 / 100) × 165 ]
= 46.5 + 21.45 = 67.95 ≈ 68
14. 57% of 394 – 2.5% of 996 = ?
215
175
200
180
205
14). Answer: c)
? = (57% of 394) – (2.5% of 996) = ?
? ≈ [(57 × 400) / 100] – [(25 × 1000) / 1000]
(actual answer less than this)
= 228 – 25 = 203 = 200
15. (1.65% of 5471) – (0.61% of 8336) = ?
20.15
26.25
31.45
38.85
40.35
15). Answer: e)
? = (1.65% of 5471) – (0.61% of 8336) = ?
≈ (1.5% of 5470) – (0.5% of 8340)
= [(1.5 / 100) × 5470] – [(0.5 / 100) × 8340]
= 82.05 – 41.7 ≈ 40.35
16. 74.75% of 240 + 151% of 180 = ?
390
415
425
450
465
16). Answer: d)
(74.75% of 240) + (151% of 180) = ?
= (75% of 240) + (150% of 180)
= [(75 / 100) × 240] – [(150 / 100) ×180]
= (180 + 270) = 450
17. 49% of 2647 + 27% of 7589 = ?
4133.5
3222.5
2111.5
1000.5
None of these
17). Answer: b)
? = (49% of 2647) + (27% of 7589)
≈ (50% of 2650) + (25% of 7590)
= [(50 / 100) × 2650] – [(25 / 100) × 7590]
= (1325 + 1897.5) ≈ 3222.5
18. 23.5% of 4924.2 + ? % of 4324.4 = 1849.091
16
18.5
36.5
46.5
52.5
18). Answer: a)
23.5% of 4924.2 + ? % of 4324.4 = 1849.091
(? / 100) × 4325 ≈ 1850 – 4925 × (23.5 / 100)
? ≈ (693 × 100) / 4325
? = 16

19. (296% of 112) ÷ 73.92 = ?
9.86
8.42
6.15
5.24
4.48
19). Answer: e)
(296% of 112) ÷ 73.92 = ?
= (296% of 112) ÷ 74
= (296 / 100) × 112 × (1 / 74) ≈ 4.48

20.(37% of 1222 – 13% of 1211) ÷ 61 = ?
18
24
28
34
None of these
20). Answer: e)
? = (37% of 1222 – 13% of 1211) ÷ 61 = ?
= [(37 / 100) × 1200] – [(13 / 100) × 1200] × (1 / 60)
= [1200 / (100 × 60) ] × (37 – 13) = 4.8 ≈ 5
Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.
21. 2, 6, 18, 54, 162, ?, 1458
274
486
1236
1032
None of these
21). Answer: b)
The series is ×3, ×3, ×3, ×3,…..

22. 0, 3, 8, 15, 24, 35, 48, ?
60
62
63
64
None of these
22). Answer: c)
The series is 1² – 1, 2² – 1, 3² – 1, 4² – 1, 5² – 1, …..

23. 0, 7, 26, 63, 124, ?, 342
128
300
240
215
None of these
23). Answer: d)
The series is 1³ – 1, 2³ – 1, 3³ – 1, 4³ – 1, 5³ – 1,…..
24. 9, 11, 16, 26, ?, 69
29
34
45
57
None of these
24).Answer: e)
The difference of difference of the series is, 3, 5, 7, 9,..

25. 3, 4, 10, 33, 136, ?
685
447
366
586
None of these
25). Answer: a)
The series is,
3 x 1 + 1 = 4
4 x 2 + 2 = 10
10 x 3 + 3 = 33
33 x 4 + 4 = 136
136 x 5 + 5 = 685

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) if x > y
b) if x ≥ y
c) if x < y < br > d) if x ≤ y
e) if x = y or no relation can be established between x and y.
26). I. x² – 11x + 30 = 0
II. 2y² – 9y + 10 =0

a)
b)
c)
d)
e)
26). Answer: a)
I.x² – 6x – 5x + 30 = 0
x (x-6) -5 (x- 6) = 0
(x-6) (x-5) = 0
=> x = 6, 5.
II. 2y² – 9y + 10 =0
2y² – 4y – 5y + 10 =0
2y (y-2) -5 (y-2) =0
=> y = 2, 5/2.
Therefore, x > y
27). I. 15x² + 8x + 1 =0
II. 3y² + 14y + 8 = 0

a)
b)
c)
d)
e)
27). Answer: a)
I.15x² + 8x + 1 =0
15x² + 5x + 3x + 1 =0
5x (3x+1) + 1(3x+1)) = 0
(5x+1) (3x+1) = 0
=> x = -1/5, -1/3.
II. 3y² + 14y + 8 = 0
3y² + 12y +2y + 8 = 0
3y (y+4) +2(y+4) =0
=> y = -4, -2/3.
Therefore, x > y
28). I. 4x² – 17x+ 18 = 0
II. 2y² – 21y + 40 = 0

a)
b)
c)
d)
e)
28). Answer: c)
I.4x² – 17x+ 18 = 0
4x² -8x -9x + 18 =0
4x (x-2)-9(x-2)) = 0
(x-2)(4x-9) = 0
=> x = 2, 9/4
II. 2y² – 21y + 40 = 0
2y² – 16y-5y + 40 = 0
2y(y-8)-5(y-8) =0
=> y = 8, 5/2.
Therefore, x < y
29). I. 6x² – 25x + 14 =0
II. 9y² -9y + 2 =0

a)
b)
c)
d)
e)
29). Answer: b)
I. 6x² – 25x + 14 =0
6x² – 4x -21x + 14 =0
2x (3x-2)-7(3x-2)) = 0
(2x-7)(3x-2) = 0
=> x = 7/2, 2/3
II. 9y² -9y + 2 =0
9y² -6y -3y + 2 =0
3y(3y-2)-1(3y-2) =0
=> y = 2/3, 1/3.
Therefore, x ≥ y
30). I.8x² + 25x + 3 =0
II. 2y² + 17y + 30 = 0

a)
b)
c)
d)
e)
30). Answer: e)
I. 8x² + 25x + 3 =0
8x² + 24x + x + 3 =0
8x (x+3)+1(x+3)) = 0
(8x+1)(x+3) = 0
=> x = -1/8, -3
II. 2y² + 17y + 30 = 0
2y² + 12y +5y + 30 = 0
2y (y+6) +5(y+6) =0
(2y+5) (y+6) =0
=> y = -5/2, -6.
Therefore, the relationship cannot be established.




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