## 6 Jul 2017

### Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-23)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-23):
Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.

00:00:00

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1).√(46656)^(1/3) + √462.25 = √(?)
702.25
812.25
756.25
746.25
None of these
√? =√(46656)^(1/3)+√462.25
=√(36)^(3×(1/3))+ √(21.5)^2
or, √? =√36 + 21.5 = 6 + 21.5 = 27.5
? = 27.5 × 27.5 = 756.25
2. 1/6 of 42 6/7% of 71 3/7% of 4116 = ?
245
210
205
215
None of these
? = 1/6 × 300/700 × 500/700 × 4116
? = 1/6 × 3/7 × 5/7 × 4116
= 42 × 5 = 210
3. 88% of 1500 + 75% of 340 = ?% of 630
205
250
235
225
215
?× 630 / 100 = 88 ×1500/100 + 75× 340 / 100
= 1320 + 255 = 1575
or, ? × 630 = 1575 × 100
? = 157500 / 630 = 250

4. {6^(3.6)÷ (36)^(-4.2)}^(1/4) = √?
46566
46626
46256
46656
46216
{(6)^(3.6)÷ (36)^(-4.2)}^(1/4) = √?
or, {66(3.6) ÷ (6)^(2 × (-4.2))}^(1/ 4) =√?
or, {(6)^(3.6 + 8.4)}^(1/4 )=√?
or, 6^(12/4)=√?
or, 6^3=√?
? = 216 × 216 = 46656

5). √32041 ×√3364 - (56)^2 = 387 + (?)^3
27
17
19
13
14
(?^3=√32041×√3364 - (56^2- 387
= 179 × 58 - 3136 - 387
= 10382 - 3523 = 6859
? =∛(19×19×19) = 19

6. 3749.3409 - 2959.9987 - 1350.009 + 2309.9413 + 13.0405 = ? + 113.45
1738.865
1638.865
1648.865
1638.785
1783.7769
? = (3749.3409 + 2309.9413 + 13.0405) -(2959.9987 + 1350.009 + 113.45)
= 6072.3227 - 4423.4577 = 1648.865

7. 137.5% of 3375 - 4352% of 73.5 = ? – 3/11 of 14641
3744.905
5443.905
5472.905
5437.905
5434.905
? = 137.5 × 33.75 - 43.52 × 73.5 +3/11 × 14641
= 4640.625 - 3198.72 + 3 × 1331
= 1441.905 + 3993 = 5434.905

8. 67620 ÷ 345 × 14 + 3584 ÷ 14 = ? - 4158 ÷ 297
1994
3173
2174
3014
2054
196 × 14 + 256 = ? - 14
or, ? = 2744 + 256 + 14 = 3014
9. ? - 115.94 ÷ 3.41 = 0.006 × 0.36 ÷ 0.012 + 1.0034
35.0214
35.0184
35.1834
34.1834
36.1834
0.006 × 30 + 1.0034 = ? - 34
or, ? = 0.18 + 1.0034 + 34 = 35.1834

10. 5.8 × 2.5 + 0.6 × 6.75 + 139.25 = ?
157.30
157.80
158.40
160.30
None of these
14.5 + 4.05 + 139.25 = 157.80

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. √795664 × 3√5832 – √675.9932 = ?
16230
16334
16030
14030
17030
? = √795664 ×∛5832 -√676.9932
≈ 892 × 18 - 26
= 16056 - 26 = 16030

12. 1325 × √16.0123 + 25% of 161.043 – 3/4 of 84.31 = ?
5201
5400
5537
5280
5013
? = 1325 ×√16.0123 + 25%of 161.043 – 3/4 of 84.31
≈ 1325 × 4 +1/4 × 160 – 3/4 × 84
= 5300 + 40 - 63
= 5300 - 23 = 5277 ≈ 5280
13. 0.5% of 449.93 ×8% of 674 = ?
122
110
146
152
190
? = 0.5% × 449.93 × 8% of 674
≈1/2 × 4.5 × 8 × 6.75 = 2.25 × 54 = 121.5 ≈ 122
14. 2/5 of ∛91125 × √324.0013 ÷ 2/5 of 44.9934 = ?
13
24
35
18
29
? = 2/5 of ∛91125 ×√324.0013 ÷2/5 of 44.9934
≈2/5 × 45× 18÷ 2/5 of 45
= 2/5 × 45 ×18 ÷18 = 18
15. 85% of 225 + 43.012 × 42.9873 - 40% of 149.90 = ?
1909
1980
1849
1921
1995
? = 85% of 225 + 43.012 × 42.9873 - 40% of 149.9
? ≈85× 225/100 + 43 ×43 - 40 ×150 / 100
= 85 × 2.25 + 43 × 43 – 2/5 × 150
≈ 191 + 1849- 60 = 1980
16.512.01 × 412.99 ÷ 119 = ?
1720
1740
1820
1845
1775
? = 512.01 ×412.99/119
≈ 510× 413 / (17 × 7) = 30× 59
= 1770 ≈1775
17. 1699.99 × 299.88 ÷ 59.9 - 1498 + 3745 = ?
10980
11700
11000
10750
9800
?≈ 1700 ×300 / 600 – 1498 + 3745
= 510000 / 600 - 1498 + 3745
= 8500 - 1498 + 3745
= 12245 - 1498 = 10747 ≈ 10750
18.(13.96)^2 + (16.23)^2 + (17.26)^2 - 32.95 = ?
790
720
840
780
680
? ≈ (14^2 + (16.2^2 + (17.25^2 - 33
≈ 196 + 262.44 + 297.56 – 33
≈ 756 - 33 = 723 ≈ 720 (approximate)

19. 1624.98 × 29.92 + 468.75 = ?
49290
48220
49220
47220
46365
? ≈ 1625 × 30 + 469
= 48750 + 469 = 49219 ≈ 49220

20. 8499.99 ÷ 375.002 × 14.996 = ?
360
290
480
380
340
?≈ 8500 /375 ×15 =340
Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.
21. 2, 11, 38, 197, 1172, 8227, 65806
11
38
197
1172
8227
The series is based on the following pattern:
2 × 3 + 5 = 11
11 × 4 – 6 = 38
38 × 5 + 7 = 197
197 × 6 – 8 = 1174 ≠ 1172
1172 is wrong and it should be replaced by 197 × 6 - 8 = 1174

22. 16, 19, 21, 30, 46, 71, 107
19
21
30
46
71
The series is based on the following pattern:
107 - 71 = 36
71 - 46 = 25
46 - 30 = 16
30 - 21 = 9
21 - 19 = 2≠4
19 should be replaced by 17 for which 21 - 17 = 4

23. 7, 9, 16, 25, 41, 68, 107, 173
107
16
41
68
25
The series is based on the following pattern:
9 + 7 = 16
16 + 9 = 25
25 + 16 = 41
41 + 25 = 66 ≠ 68
68 should be replaced by 66.
24. 4, 2, 3.5, 7.5, 26.25, 118.125
118.125
26.25
3.5
2
7.5
The series is based on the following pattern: ×0.5,×1.5,×2.5,×3.5,×4.5
Obviously, 3.5 Is the wrong number which should be replaced by 3.

25. 16, 4, 2, 1.5, 1.75, 1.875
1.875
1.75
1.5
2
4
The series is based on the following pattern: ×0.25,×0.5,×0.75,×1,×1.25
Obviously, 1.75 is the wrong number which should be replaced by 1.5.

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) if x > y
b) if x ≥ y
c) if x < y
d) if x ≤ y
e) if x =y, or no relation can be established between x and y.
26. I. x^2 – 1200 = 244.
II. y + 122 = 159

a)
b)
c)
d)
e)
I. ^2 = 1200 + 244
X^2 = 1444
x = √(1444) = ± 38
II. y = 159 – 122 = 37
Clearly, x > y or x < y
Hence, the relationship cannot be established.
27. I. 14x – 25 = 59 – 7x.
II. √(y + 222) - √(36) = √(81)

a)
b)
c)
d)
e)
I. 14x + 7x = 59 + 25
21x = 84; x = 4
II. √(y + 222) = √(36) + √(81)
√(y + 222) = ± 6 ±9
√(y + 222) = ± 15
Taking (+ve) sign,
√(y + 222) = 15
y + 222 = 225
y = 225 – 222 = 3
Taking (-ve) sign,
√(y + 222) = -15
(y + 222) = 225
Y = 225 – 222 = 3
Clearly, x > y
28. I. 144x^2 – 16 = 9.
II. 12y + √4 = √(49)

a)
b)
c)
d)
e)
I. 144x^2 = 16 + 9
144x^2 = 25 ax^2 = 25 / 144
x = ± 5 / 12
II. 12y = √49 - √4
12y = ± 7 – (± 2)
12y = ± 5
y = ± 5 / 12
clearly, x = y
29. I. x^2 – 9x + 20 = 0.
II. y^2 – 13y + 42 = 0

a)
b)
c)
d)
e)
I. x^2 – 9x + 20 = 0
x^2 – 5x -4x +20 = 0
x(x - 5) – 4 (x - 5) = 0
(x - 5) (x - 4) = 0
x = 5 or 4
II. y^2 – 13y + 42 = 0
Y^2 – 7y – 6y + 42 = 0
y(y - 7) – 6 (y - 7) = 0
(y - 7) (y - 6) = 0
Y = 6 (or) 7
Clearly, x < y
30. I. (√(x) / 5) + (3 √(x) / 10) = (1 / √(x)) .
II. (10 / √(y)) – (2 / √(y)) = 4√(y)

a)
b)
c)
d)
e)
I. (2√x + 3√x) / 10 = 1 / √x
2x + 3x = 10
5x = 10
x = 2
II. (10 - 2) / √y = 4 √y
8 = 4y
y = 8 / 4 = 2
Clearly, x = y

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