4 Jul 2017

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-21)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-1)



00:00:00

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). (17)^8.8 × (289)^(–1.4) ÷ 1/(17)^-1 = 17 × (17)^?
2
3
4
5
6
1). Answer: c)
17 × 17^? = (17)^8.8 × (17^2)^(–1.4) ÷ (17)^1
17 × 17^? = (17)^8.8 × (17)^(–2.8) ÷ 17 = (17)^(8.8 – 2.8 – 1) = (17)^5
17^? = 17^(5 – 1) = 17^4
? = 4
2. 2.4% of 775 + 8.4% of 525 = 30% of?
201
203
205
207
209
2). Answer: e)
30 × ? / 100 = 2.4 × 775 / 100 + 8.4 × 525 / 100
30 × ? / 100 = 18.6 + 44.1 = 62.7
? = 62.7 × 100 / 30 = 627/3 = 209
3. {0.00102 ÷ 0.000017} × 17.75 = ?
1045
1055
1065
1075
1085
3). Answer: c)
? = 0.00102 / 0.000017 × 17.75
? = 1020 / 17 × 17.75
? = 60 × 17.75 = 1065

4. (1728)^(2/3) ÷ 1/(5832)^(2/3) = ? × 9
5184
7776
3888
11664
10368
4). Answer: a)
9 × ? = (12^3)^(2/3) ÷ 1/(18^3)^(2/3) =(12)^2 ÷ (18)^(-2)
9 × ? = (12)^2 × (18)^2
? = 12 × 12 × 18 × 18 / 9
? = 5184

5).(1260 ÷ 28) × 6.4 = 45% of?
320
640
960
1280
1510
5). Answer: b)
45 × ? / 100 = 1260 / 28 × 6.4 = 45 × 6.4
? = 6.4 × 100 = 640

6. 85% of 4/7 of 6755 = ? + 1687
1586
1592
1594
1582
None of these
6). Answer: c)
? = 85 × 4 × 6755 / (100 × 7) – 1687 = 17 × 193 - 1687
? = 3281 - 1687 = 1594

7. (5568 ÷ 87)^(1/3) + (72 × 2)^(1/2) = (?)^(1/2)
256
4
2
16
None of these
7). Answer: a)
(?)^(1/2) = (5568 / 87)^(1/3) + (144)^(1/2)
(?)^(1/2) = (64)^(1/3) + (12^2)^(1/2) = (4^3)^(1/3) + (122)^(1/2)
(?)^1/2 = 4 + 12 = 16
? = 256

8. √(13^2 + 28 ÷ 4 - (3)^3 +107) = (?)^2
2
16
256
4
(256)^2
8). Answer: d)
(?)^2 = √(13^2 + 28 ÷ 4 - (3)^3 +107)
= √(169 + 7 - 27 +107)
= √(283 – 27) = √256 = 16
? = √16 = 4
9). Answer: b)
(0.7)^(?+3) = (0.7)^(2 × 4) × (0.7)^(3 × 4) ÷ (0.7)^(4 × 4)
(0.7)^(?+3) = (0.7)^(8 + 12 – 16) = (0.7)^4
? = 4 – 3 = 1
9. (0.49)^4 × (0.343)^4 ÷ (0.2401)^4 = (70 ÷ 100)^(? + 3)
3
1
4
7
None of these
9). Answer: b)
(?)^2 = 1224 × 306 = (18 × 17 × 4) × (18 × 17)
(?)^2 = (18 × 17 × 2)^2
? = 18 × 17 × 2 = 612

10. 45% of √2025 ÷ 0.01 = (?)^2 ÷ 25
3
(81)^2
81
9
None of these
10). Answer: e)
√2025 = 45
Now, 45 × 45 / (0.01 × 100) = (?)^2 ÷ 25
2025 = (?)^2 / 25
or. (?)^2 = 50625
? = √50625 = 225

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. 78.99% of 9875.99 - 38.09% of 6785.05 = 2479.05 + ? of 4895.99
56
50
48
60
None of these
11). Answer: a)
? × 4896 / 100 ≈ 79 × 9876 /100 - 38 × 6785 / 100 - 2479
= 0.79 × 9876 - 0.38 × 6785 - 2479
≈ 7802 - 2578 - 2479
= 7802 - 5057 = 2745
? = 2745 / 4896 × 100 = 56.06 ≈ 56

12. √((4095.99)^(1/3)) × √65535.89 = (?)^2
24
11
16
64
32
12). Answer: e)
(?)^2 ≈ √(4096)^(1/3) × √65536
= √16^(3 ×(1/3)) × √16^4
= 4 × 16 × 16 = 256 × 4 = 1024
? = √1024 = 32
13.5030.05 ÷ 42.93 + 24.49% of 5049.93 ÷ 100 = ?
150
170
130
90
None of these
13). Answer: c)
5030.05 ÷ 42.93 + 24.49% of 5049.93 ÷ 100 = ?
? ≈ 5030 ÷ 43 + 24.5% of 5050 ÷ 100
? = 116.9764 + 1237.25 ÷ 100
? ≈ 117 + 13
? = 130
14. 52920 ÷ 3214.05 × 514.13 + 5231.92 = ?
13617
13695
13823
13511
None of these
14). Answer: b)
? ≈ 52920 ÷ 3214 × 514 + 5232
? = 16.46 × 514 + 5232
? = 8460.44 + 5232 = 13692.44 ≈ 13695
15. ³√ 6850 × √12540 = ? × 52
41
39
38
43
None of these
15). Answer: a)
³√6850 × √12540 = ? × 52
or, ? ≈ 19 × 112 / 52
? = 40.92 ≈ 41
16.√6398.99 ÷ ³√4099.99 × 24.89 = (?)^³
4
5
7
6
3
16). Answer: b)
(?)^3 = √6398.99 ÷ ³√4099.99 × 24.89
or, (?)^3 ≈ 80 ÷ √(16 ×16 × 16) × 25
or, (?)^3 = 80 ÷ 16 × 25
or, (?)^3 = 125 = 53
? = 5
17. (87.65% of 7159.89 - 68.99% of 8939.89) × 6.06 = (?)^2
20
22
21
28
30
17). Answer: d)
(?)^2 ≈ (88 × 7160 / 100 - 69 × 8940 /100) × 6
= (88 × 71.60 - 69 × 89.40) × 6
≈ (6300 - 6168) × 6
= 132 × 6 = 792
? = √792 = 28.14 ≈ 28
18). Answer: b)
40 × ? / 100 ≈ 449 × 346 / 64
or,? = 449 × 346 × 100 / (64 × 40)
? = 6068.5 ≈ 6065
18.449.03 × 345.88 ÷ 64 = 40.02% of ?
6232
6065
6512
5831
5932
18). Answer: b)
(50243408)^(1/3) ≈ (50243409)^(1/3) = 369
and, (48627124)^(1/3) ≈ (48627125)^(1/3) = 365
Again, (7529535)^(1/3) ≈ (7529536)^(1/3) =196
So, ? = 369 - 365 + 196
? = 200

19. 37.9% of 638.05 + 25.25% of 4401.9 = ?
1320
1415
1270
1345
None of these
19). Answer: d)
37.9% of 638.05 + 25.25% of 4401.9 = ?
or, ? ≈ 38% of 638 + 25% of 4402
= 242.44 + 1100.5 = 1342.94
? ≈ 1345

20. 833.956 - 543.005 - 108.98 = 19.8% of ?
940
890
880
910
None of these
20). Answer: d)
? × 20 / 100 ≈ 834 - 543 - 109 = 182
? = 182 × 5 = 910
Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number. 21. 2, 10, 30, 68, ?
126
130
140
150
None of these
21). Answer: b)
The series is 1^3 + 1, 2^3 + 2, 3^3 + 3, 4^3 + 4, 5^3 + 5, …

22. 33, 321, 465, 537, 573, ?
600
591
585
498
None of these
22). Answer: b)
The difference between the numbers is + 288, + 144, + 72, + 36, +18, ..

23. 2, 9, ?, 105, 436, 2195
25
27
30
33
None of The Above
23). Answer: c)
The sequence of the series is ×1 + (1×7), ×2 + (2×6), ×3 + (3×5), ×4 +(4×4),…
24. 4, 6, 14, 44, ?, 892
176
172
178
182
None of The Above
24). Answer: c)
The series is ×1 + 2, ×2 +2, ×3 + 2, ×4 + 2, ×5 + 2,

25.126, 64, 34, 20, 14, ?
12
14
16
18
None of The Above
25). Answer: a)
The sequence of the series is ÷2 + 1, ÷2 + 2, ÷2 +3, ÷2 +4, ÷2+5,..

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or no relation can be established between x and y.
26. I. x2 – 16 = 0
II. y^4 – {[(8 x 2)^(9/4)] / √y } = 0

a)
b)
c)
d)
e)
26). Answer: d)
I. x^2 – 16 = 0
X^2 = 16
x = ±4
II. y^4 – {[(8 x 2)^(9/4)] / √y } = 0
Y^4 √y – [(4^2)^(9/4)] = 0
y ^(4+(1/2)) – (4)9/2 = 0
y^(9/2) – 4^(9/2) = 0
y = 4
Hence x ≤ y
27.I. x^2 - 2√3x – 72 = 0
II. y^2 + 9√3x + 60 = 0

a)
b)
c)
d)
e)
27). Answer: b)
I. x^2 - 2√3x – 72 = 0
X^2 - 6√3x + 4√3x – 72 = 0
x (x - 6√3) + 4√3 (x - 6√3) = 0
x = -4√3, 6√3
II. y^2 + 9√3y + 60 = 0
Y^2 + 4√3y + 5√3y + 60 = 0
y(y + 4√3) + 5√3 (y + 4√3) = 0
y = -4√3, -5√3
Hence x ≥ y
28.I. x^6 – [(√(54 × 6))^6.5 / √x] = 0
II. y – (36 × 81)^(1/2) = 0

a)
b)
c)
d)
e)
28). Answer: c)
I. x^6 – [(√(54×6))^6.5 / √x] = 0
X^(6+(1/2)) – (18)^(6.5) = 0
X^(6.5) = 18^(6.5)
x = 18
II. y – (36 × 81)^(1/2) = 0
y – (6 × 9) = 0
y – 54 = 0
y = 54
Hence x < y

29. I. x^2 – 17x – 234 = 0
II. 4y^2 + 32y – 192 = 0

a)
b)
c)
d)
e)
29). Answer: e)
I. x^2 – 17x – 234 = 0
X^2 – 26x + 9x – 234 = 0
x(x - 26) + 9 (x – 26) = 0
(x + 9) (x - 26) = 0
x = -9, 26
II. 4y^2 + 32y – 192 = 0
Y^2 + 8y – 48 = 0
y^2 + 12y – 4y – 48 = 0
y (y + 12) – 4 (y + 12)
y = - 12, 4
Hence relation cannot be determined
30. I. x^2 = 784
II. y^2 – 11y – 102 = 0

a)
b)
c)
d)
e)
30). Answer: e)
I. x^2 = 784
x = ± 28
II. y^2 – 11y – 102 = 0
y^2 – 17y + 6y – 102 = 0
y (y - 17) +6 (y - 17) = 0
y = 17, -6
Hence Relation cannot be determined




Do you feel that you are weak in English Section?
Here we are creating a pathway to win the English Section in upcoming IBPS Exams 2017
English Learning Session :– (Day-1)
English Learning Session :– (Day-2)
English Learning Session :– (Day-3)
English Learning Session :– (Day-4)
English Learning Session :– (Day-5)
English Learning Session :– (Day-6)
English Learning Session :– (Day-7)