## 4 Jul 2017

### Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-21)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-21):
Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.

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Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). (17)^8.8 × (289)^(–1.4) ÷ 1/(17)^-1 = 17 × (17)^?
2
3
4
5
6
17 × 17^? = (17)^8.8 × (17^2)^(–1.4) ÷ (17)^1
17 × 17^? = (17)^8.8 × (17)^(–2.8) ÷ 17 = (17)^(8.8 – 2.8 – 1) = (17)^5
17^? = 17^(5 – 1) = 17^4
? = 4
2. 2.4% of 775 + 8.4% of 525 = 30% of?
201
203
205
207
209
30 × ? / 100 = 2.4 × 775 / 100 + 8.4 × 525 / 100
30 × ? / 100 = 18.6 + 44.1 = 62.7
? = 62.7 × 100 / 30 = 627/3 = 209
3. {0.00102 ÷ 0.000017} × 17.75 = ?
1045
1055
1065
1075
1085
? = 0.00102 / 0.000017 × 17.75
? = 1020 / 17 × 17.75
? = 60 × 17.75 = 1065

4. (1728)^(2/3) ÷ 1/(5832)^(2/3) = ? × 9
5184
7776
3888
11664
10368
9 × ? = (12^3)^(2/3) ÷ 1/(18^3)^(2/3) =(12)^2 ÷ (18)^(-2)
9 × ? = (12)^2 × (18)^2
? = 12 × 12 × 18 × 18 / 9
? = 5184

5).(1260 ÷ 28) × 6.4 = 45% of?
320
640
960
1280
1510
45 × ? / 100 = 1260 / 28 × 6.4 = 45 × 6.4
? = 6.4 × 100 = 640

6. 85% of 4/7 of 6755 = ? + 1687
1586
1592
1594
1582
None of these
? = 85 × 4 × 6755 / (100 × 7) – 1687 = 17 × 193 - 1687
? = 3281 - 1687 = 1594

7. (5568 ÷ 87)^(1/3) + (72 × 2)^(1/2) = (?)^(1/2)
256
4
2
16
None of these
(?)^(1/2) = (5568 / 87)^(1/3) + (144)^(1/2)
(?)^(1/2) = (64)^(1/3) + (12^2)^(1/2) = (4^3)^(1/3) + (122)^(1/2)
(?)^1/2 = 4 + 12 = 16
? = 256

8. √(13^2 + 28 ÷ 4 - (3)^3 +107) = (?)^2
2
16
256
4
(256)^2
(?)^2 = √(13^2 + 28 ÷ 4 - (3)^3 +107)
= √(169 + 7 - 27 +107)
= √(283 – 27) = √256 = 16
? = √16 = 4
(0.7)^(?+3) = (0.7)^(2 × 4) × (0.7)^(3 × 4) ÷ (0.7)^(4 × 4)
(0.7)^(?+3) = (0.7)^(8 + 12 – 16) = (0.7)^4
? = 4 – 3 = 1
9. (0.49)^4 × (0.343)^4 ÷ (0.2401)^4 = (70 ÷ 100)^(? + 3)
3
1
4
7
None of these
(?)^2 = 1224 × 306 = (18 × 17 × 4) × (18 × 17)
(?)^2 = (18 × 17 × 2)^2
? = 18 × 17 × 2 = 612

10. 45% of √2025 ÷ 0.01 = (?)^2 ÷ 25
3
(81)^2
81
9
None of these
√2025 = 45
Now, 45 × 45 / (0.01 × 100) = (?)^2 ÷ 25
2025 = (?)^2 / 25
or. (?)^2 = 50625
? = √50625 = 225

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. 78.99% of 9875.99 - 38.09% of 6785.05 = 2479.05 + ? of 4895.99
56
50
48
60
None of these
? × 4896 / 100 ≈ 79 × 9876 /100 - 38 × 6785 / 100 - 2479
= 0.79 × 9876 - 0.38 × 6785 - 2479
≈ 7802 - 2578 - 2479
= 7802 - 5057 = 2745
? = 2745 / 4896 × 100 = 56.06 ≈ 56

12. √((4095.99)^(1/3)) × √65535.89 = (?)^2
24
11
16
64
32
(?)^2 ≈ √(4096)^(1/3) × √65536
= √16^(3 ×(1/3)) × √16^4
= 4 × 16 × 16 = 256 × 4 = 1024
? = √1024 = 32
13.5030.05 ÷ 42.93 + 24.49% of 5049.93 ÷ 100 = ?
150
170
130
90
None of these
5030.05 ÷ 42.93 + 24.49% of 5049.93 ÷ 100 = ?
? ≈ 5030 ÷ 43 + 24.5% of 5050 ÷ 100
? = 116.9764 + 1237.25 ÷ 100
? ≈ 117 + 13
? = 130
14. 52920 ÷ 3214.05 × 514.13 + 5231.92 = ?
13617
13695
13823
13511
None of these
? ≈ 52920 ÷ 3214 × 514 + 5232
? = 16.46 × 514 + 5232
? = 8460.44 + 5232 = 13692.44 ≈ 13695
15. ³√ 6850 × √12540 = ? × 52
41
39
38
43
None of these
³√6850 × √12540 = ? × 52
or, ? ≈ 19 × 112 / 52
? = 40.92 ≈ 41
16.√6398.99 ÷ ³√4099.99 × 24.89 = (?)^³
4
5
7
6
3
(?)^3 = √6398.99 ÷ ³√4099.99 × 24.89
or, (?)^3 ≈ 80 ÷ √(16 ×16 × 16) × 25
or, (?)^3 = 80 ÷ 16 × 25
or, (?)^3 = 125 = 53
? = 5
17. (87.65% of 7159.89 - 68.99% of 8939.89) × 6.06 = (?)^2
20
22
21
28
30
(?)^2 ≈ (88 × 7160 / 100 - 69 × 8940 /100) × 6
= (88 × 71.60 - 69 × 89.40) × 6
≈ (6300 - 6168) × 6
= 132 × 6 = 792
? = √792 = 28.14 ≈ 28
40 × ? / 100 ≈ 449 × 346 / 64
or,? = 449 × 346 × 100 / (64 × 40)
? = 6068.5 ≈ 6065
18.449.03 × 345.88 ÷ 64 = 40.02% of ?
6232
6065
6512
5831
5932
(50243408)^(1/3) ≈ (50243409)^(1/3) = 369
and, (48627124)^(1/3) ≈ (48627125)^(1/3) = 365
Again, (7529535)^(1/3) ≈ (7529536)^(1/3) =196
So, ? = 369 - 365 + 196
? = 200

19. 37.9% of 638.05 + 25.25% of 4401.9 = ?
1320
1415
1270
1345
None of these
37.9% of 638.05 + 25.25% of 4401.9 = ?
or, ? ≈ 38% of 638 + 25% of 4402
= 242.44 + 1100.5 = 1342.94
? ≈ 1345

20. 833.956 - 543.005 - 108.98 = 19.8% of ?
940
890
880
910
None of these
? × 20 / 100 ≈ 834 - 543 - 109 = 182
? = 182 × 5 = 910
Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number. 21. 2, 10, 30, 68, ?
126
130
140
150
None of these
The series is 1^3 + 1, 2^3 + 2, 3^3 + 3, 4^3 + 4, 5^3 + 5, …

22. 33, 321, 465, 537, 573, ?
600
591
585
498
None of these
The difference between the numbers is + 288, + 144, + 72, + 36, +18, ..

23. 2, 9, ?, 105, 436, 2195
25
27
30
33
None of The Above
The sequence of the series is ×1 + (1×7), ×2 + (2×6), ×3 + (3×5), ×4 +(4×4),…
24. 4, 6, 14, 44, ?, 892
176
172
178
182
None of The Above
The series is ×1 + 2, ×2 +2, ×3 + 2, ×4 + 2, ×5 + 2,

25.126, 64, 34, 20, 14, ?
12
14
16
18
None of The Above
The sequence of the series is ÷2 + 1, ÷2 + 2, ÷2 +3, ÷2 +4, ÷2+5,..

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or no relation can be established between x and y.
26. I. x2 – 16 = 0
II. y^4 – {[(8 x 2)^(9/4)] / √y } = 0

a)
b)
c)
d)
e)
I. x^2 – 16 = 0
X^2 = 16
x = ±4
II. y^4 – {[(8 x 2)^(9/4)] / √y } = 0
Y^4 √y – [(4^2)^(9/4)] = 0
y ^(4+(1/2)) – (4)9/2 = 0
y^(9/2) – 4^(9/2) = 0
y = 4
Hence x ≤ y
27.I. x^2 - 2√3x – 72 = 0
II. y^2 + 9√3x + 60 = 0

a)
b)
c)
d)
e)
I. x^2 - 2√3x – 72 = 0
X^2 - 6√3x + 4√3x – 72 = 0
x (x - 6√3) + 4√3 (x - 6√3) = 0
x = -4√3, 6√3
II. y^2 + 9√3y + 60 = 0
Y^2 + 4√3y + 5√3y + 60 = 0
y(y + 4√3) + 5√3 (y + 4√3) = 0
y = -4√3, -5√3
Hence x ≥ y
28.I. x^6 – [(√(54 × 6))^6.5 / √x] = 0
II. y – (36 × 81)^(1/2) = 0

a)
b)
c)
d)
e)
I. x^6 – [(√(54×6))^6.5 / √x] = 0
X^(6+(1/2)) – (18)^(6.5) = 0
X^(6.5) = 18^(6.5)
x = 18
II. y – (36 × 81)^(1/2) = 0
y – (6 × 9) = 0
y – 54 = 0
y = 54
Hence x < y

29. I. x^2 – 17x – 234 = 0
II. 4y^2 + 32y – 192 = 0

a)
b)
c)
d)
e)
I. x^2 – 17x – 234 = 0
X^2 – 26x + 9x – 234 = 0
x(x - 26) + 9 (x – 26) = 0
(x + 9) (x - 26) = 0
x = -9, 26
II. 4y^2 + 32y – 192 = 0
Y^2 + 8y – 48 = 0
y^2 + 12y – 4y – 48 = 0
y (y + 12) – 4 (y + 12)
y = - 12, 4
Hence relation cannot be determined
30. I. x^2 = 784
II. y^2 – 11y – 102 = 0

a)
b)
c)
d)
e)
I. x^2 = 784
x = ± 28
II. y^2 – 11y – 102 = 0
y^2 – 17y + 6y – 102 = 0
y (y - 17) +6 (y - 17) = 0
y = 17, -6
Hence Relation cannot be determined

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