2 Jul 2017

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-19)

Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-1)



00:00:00

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). 7.8% of 275 + 3.2% of 155 = 1% of?
2640
2641
2642
2643
2644
1). Answer: b)
1 × ? / 100 = 21.45 + 4.96 = 26.41
? = 2641
2. 12/19 of 7/5 of 45% of 8075 = ?
3194
3199
3207
3213
3228
2). Answer: d)
? = 12/19 × 7/5 × 45/100 × 8075 = 3213
3. 4/13 of 2379 + 2/15 of 2265 = 20% of ?
5150
5160
5170
5180
5190
3). Answer: c)
20 × ?/100 = 732 + 302 = 1034
? = 5 × 1034 = 5170

4. (4913)^(2/3) × (2197)^(2/3) = 221 × ?
1
221
(221)^2
(221)^3
None of these
4). Answer: b)
4913 = 17 × 17 × 17 and
2197 = 13 × 13 × 13
? = (17^3)^(2/3) × (13^3)^(2/3) / 221
? = (17)^2 × (13)^2 / 221
? = 221

5). 65% of 132 + 12.5% of 57.6 = ? × 3
30
31
32
33
34
5). Answer: b)
3 × ? = 65 × 132/100 + 12.5 × 57.6/100
3 × ? = 85.8 + 7.2 = 93
? = 93/3 = 31

6. (√5 - √10)^2 + (√2 + 5)^2 = (?)^3 – 22
2
12
16
8
None of these
6). Answer: e)
(?)^3 -22= (√5 - √10)2 + (√2 + 5)^2
(?)^3 -22 = 5 - 2√50 + 10 + 2 + 10 √2 + 25
(?)^3 -22 = 5 -10√2 +10 + 2 +10 √2 + 25
(?)^3 -22 = 42
or, (?)^3 = 42 + 22 = 64
? = ³√64 = 4

7. 55% of √2116 ÷ 0.01 = ? × 20
126.5
126.6
124.6
125.4
None of these
7). Answer: a)
55 ×√2116 /100 ÷ 0.01 = ? × 20
Wkt, √2116 = √(46 × 46) = 46
or, ? × 20 = 55 × 46 / (100 × 0.01) = 55 × 46 / 1 = 2530
? = 2530 / 20 = 126.5

8. √(12^2 × 16 ÷ 24 +193 + 7 × 5) = (?)^2
3 √2
4 √2
5 √2
18
32
8). Answer: a)
?2 = √(12^2 × 16 ÷ 24 +193 + 7 × 5)
?2 = √(144 × 16 / 24 + 193 + 35)
=√(96 + 193 + 35) = √324
or, (?)^2 = √324 =18
? = √18 = √(3 × 3 × 2)
? = 3 √2
9. √31.36 ÷ √0.64 × 252 = (?)^2 × 36
81
64
-8
-7
9
9). Answer: d)
(?)2 = √31.36 ÷√0.64 ×252 / 36
= 5.6 / 0.8 × 252 / 36
= 7 × 252 / 36 = 49
? = √49 = ±7
Hence, - 7

10. (1.69)^4 ÷ (2197 ÷ 1000)^3 × (0.13 × 10)^3 = (1.3)^(?-2)
6
2
4
0
None of these
10). Answer: c)
(1.69)^4 ÷ (2197/1000)^3 × 1.3^3 = 1.3^(? – 2)
or, (1.3)^8 ÷ (1.3)^(3×3) × 1.3^3 = 1.3^(?–2)
or, 1.3^(8-9+3) = 1.3^(?-2)
or, 1.32 = 1.3?-2
or, ? - 2 = 2
? = 2 + 2 = 4

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11. √164 × ³√ 615 = ?
70
90
110
130
150
11). Answer: c)
? ≈ 12.8 × 8.5 = 108.8 ≈ 110

12. (√485 × 3.48) × 12.08 = ?
900
925
950
975
1000
12). Answer: b)
? ≈ (22 × 3.5) × 12 = 924 ≈ 925
13. 29.03 × 24.96 – 7.98 × ³√3370 = ?
450
500
550
600
650
13). Answer: d)
? ≈ 29 × 25 - 8 × 15 = 725 - 120 = 605 ≈ 600
14. 245% of 49.962 – 115.03% of 41.89 = ?
75
125
175
225
275
14). Answer: a)
? ≈ 245 × 50 /100 – 115 × 42/100
? = 122.5 - 48.3 = 74.2 ≈ 75
15. √5930 × ³√43 = ?
250
260
270
280
290
15). Answer: c)
? = √5930 × ³√43 ≈ 77 × 3.5
= 269.5 ≈ 270
16. { √2300 ÷11.98 / 8.51} × 7.48 = ?
225
235
245
255
265
16). Answer: d)
? ≈ {48 ÷ 12/8.5} × 7.5 = 34 × 7.5 = 255
17.{10.71% of 1984.96 + 3.89% of 1451} ÷ ( 12.49)^(–1) = ?
3120
3360
3540
3780
3900
17). Answer: b)
? ≈ (212.395 + 56.55) × 12.5
= 268.945 × 12.5
? = 3361.8 ≈ 3360
18.{ √33850 × ³√91100} ÷ 8.98 = ?
720
820
920
1020
1120
18). Answer: c)
? ≈ (184 × 45) ÷ 9 = 184 × 5 = 920

19. {(219.06 × 24.98) - (23.84 × 55.05)} × 8.49 = ?
31500
32500
33500
34500
35500
19). Answer: e)
? ≈ {(220 × 25) - (24 × 55)} × 8.5
= (5500 - 1320) × 8.5 = 4180 × 8.5
? = 35530 ≈ 35500

20.(√1120 × 183.98) + 465.02% of 171.95 = ?
6960
6760
6560
6360
6160
20). Answer: a)
? ≈ (33.5 × 184) + 465 × 172 / 100
≈ 6164 + 800
? = 6964 ≈ 6960
Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number. 21. 8, 125, 1331, 4913, ?
14847
13427
12167
11067
None of these
21). Answer: c)
The series is, alternate prime number cube
i.e., 2^3 , 5^3 , 11^3 , 17^3 , 23^3

22. 5, 25, 7, ?, 9, 19
23
22
25
32
None of these
22). Answer: b)
The first series is, 5, 7, 9
The difference between the numbers is +2, +2, ..
The second series is 25, ?, 19
The difference between the numbers is -3, -3, ..

23. 980, 392, 156.8, ?, 25.088, 10.0352
62.72
63.85
65.04
60.28
None of these
23). Answer: a)
The sequence of the series is ×2/5, ×2/5, ×2/5, ….
24. 5, 9, 21, 37, 81, ?
163
153
181
203
None of these
24). Answer: b)
The sequence of the series is, ×2 -1, × 2 +3, × 2 – 5, × 2 + 7, × 2 – 9

25. 45, 46, 70, 141, ?, 1061.5
353
353.5
352.5
352
None of these
25). Answer: b)
The sequence of the series is, ×1 +1, × 1.5 + 1, × 2 + 1, × 2.5 + 1, × 3 + 1

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) If x < y
b) If x ≥ y
c) If x ≤ y
d) If x = y or no relationship can be established
e) If x > y
26. I. 3x^2 + 11x + 6 = 0
II. 3y^2 + 10y + 8 = 0

a)
b)
c)
d)
e)
26). Answer: d)
I. 3x^2 + 11x + 6 = 0
or, 3x^2 + 9x + 2x + 6 = 0
or, 3x (x +3 ) + 2 (x + 3) = 0
or, (3x + 2) (x + 3) = 0
x = -2/3, - 3
II. 3y^2 + 10y + 8 = 0
or, 3y^2 + 6y + 4y + 8 = 0
or, 3y (y +2) + 4 (y + 2) = 0
or, (3y + 4) (y + 2) = 0
y = -4/3, - 2
Hence, no relationship can be established.

27.I. 3x^2 - 7x + 2 = 0
II. 2y^2 - 9y + 10 = 0

a)
b)
c)
d)
e)
27). Answer: c)
I. 3x^2 - 7x + 2 = 0
or, 3x^2 - 6x - x + 2 = 0
or, 3x (x -2) - 1 (x - 2) = 0
or, (3x - 1) (x - 2) = 0
x = 1/3, 2
II. 2y^2 - 9y + 10 = 0
or, 2y^2 – 5y - 4y + 10 = 0
or, y (2y - 5) -2 (2y - 5) = 0
or, (2y - 5) (y - 2) = 0
y = 5/2, 2
Hence x ≤ y
28. I. x^2 = 9
II. 2y^2 - 19y + 44 = 0

a)
b)
c)
d)
e)
28). Answer: a)
I. x^2 = 9
x = ±3
II. 2y^2 - 19y + 44 = 0
or, 2y^2 – 11y - 8y + 44 = 0
or, y (2y - 11) -4 (2y - 11) = 0
or, (2y - 11) (y - 4) = 0
y = 11/2, 4
Hence x < y
29. I. 2x^2 - 15x + 28 = 0
II. 4y^2 - 23y + 30 = 0

a)
b)
c)
d)
e)
29). Answer: d)
I. 2x^2 - 15x + 28 = 0
or, 2x^2 - 7x - 8x + 28 = 0
or, x (2x -7) - 4 (2x - 7) = 0
or, (2x - 7) (x - 4) = 0
x = 7/2, 4
II. 4y^2 - 23y + 30 = 0
or, 4y^2 – 15y - 8y + 30 = 0
or, y (4y - 15) -2 (4y - 15) = 0
or, (4y - 15) (y - 2) = 0
y = 15/4, 2
Hence no relationship can be established.
30. I. 2x^2 - 15x + 27 = 0
II. 5y^2 - 26y + 33 = 0

a)
b)
c)
d)
e)
30). Answer: b)
I. 2x^2 - 15x + 27 = 0
or, 2x^2 - 9x - 6x + 27 = 0
or, x (2x -9) - 3 (2x - 9) = 0
or, (2x - 9) (x - 3) = 0
x = 9/2, 3
II. 5y^2 - 26y + 33 = 0
or, 5y^2 – 15y - 11y + 33 = 0
or, 5y (y - 3) -11 (y - 3) = 0
or, (5y - 11) (y - 3) = 0
y = 11/5, 3
Hence x ≥ y




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