Dear Aspirants, Our IBPS Guide team is providing new series of Quants Questions for IBPS Clerk Mains 2022 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
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1) A, B and C can do a piece of work in 14, 28 and 32 days respectively. They all begin to working together. A work continuously till it is finished, B leaves the work 3 days before its completion and C leaves the work 2 days before its completion. In what time is the work finished?
A.7(20/31) days
B.8(14/31) days
C.9(14/31) days
D.7(20/31) days
E.none of these
2) A and B together can complete the job in 16 days, B and C together can complete the job in 20 days. First A did the job for 6 days, B did the job for 9 days and C completed the remaining job in 22 days. Find the number of days in which C alone can complete the job?
A.40 days
B.48 days
C.30 days
D.36 days
E.None of these
3) A and B together can complete 33(1/3) % of the work in 10 days, C and D together can complete 85% of the work in 17 days and A, B and C together can complete half of the work in 7.5 days. A and D together can complete 66(2/3) % of the work in 16 days. In how many days B alone complete 40% of the work?
A.32 days
B.36 days
C.45 days
D.48 days
E.None of these
4) A can complete the 75% of the work in 9 days and A and B together can complete 60% of the work in 4.8 days. If A got Rs. 5000 for doing the whole work and then what is the difference between the amount received by A and B?
A.Rs.2000
B.Rs.2500
C.Rs.3000
D.Rs.1500
E.None of these
5) A alone complete four – ninth of the work in 20 days, B alone complete half of the work in 15 days and C alone complete four – fifth of the work in 36 days. A and B started the work and after 5 days C joined with them, in how many days the work will be completed?
A.13(2/7) days
B.14(2/7) days
C.15(2/7) days
D.16(2/7) days
E.None of these
6) A can complete 75% of the work in 15 days and B alone complete 60% of the work in 18 days. If A and B works alternatively starting from A and then B so on, in how many days half of the total work in completed?
A.5 days
B.6 days
C.4 days
D.8 days
E.None of these
7) A and B together can complete 60% of the work in 8(16/25) days and B and C together can complete 80% of the work in 7(1/5) days. If B and C started the work and after 4 days they left the work, then A complete the remaining work in 13(1/3) days, in how many days A, B and C alone complete the work respectively?
A.24, 36, 10
B.36, 24, 12
C.10, 12, 24
D.24, 12, 36
E.24, 36, 12
8) 18 men can complete a work in (x – 6) days. 20 women can complete the same work in (x – 2) days. 10 men can complete the same work in (y + 2) days and 16 women can complete the same work in (y + 4) days. Find the value of x – y?
A.65/22
B.40/11
C.95/22
D.50/11
E.70/11
9) Â (x – 5) person can do a work in x days and (x + 10) person can do the same work in (x – 10) days. Then in how many days can (x + 5) person finish the work?
A.14 days
B.9 days
C.10 days
D.12 days
E.None of these
10) A, B and C together can complete the work in 9 days. If ratio of efficiency of B to A is 3: 2, C and D together can complete 75% of the work in 6 days the efficiency of C is x% of D, then find the value of x?
From the statement given in the above question which of the following can be determined.
a)Â Value of x
b)Â Time taken by A alone complete the work.
c)Â Time taken by C and B together can complete work.
d)Â If the efficiency of B and C is equal, then in how many days D alone complete the work
A.All A, B, C and D
B.Only D
C.Only B
D.Only A, B and D
E.Only B and C
Time and Work Questions For Online Mock Test
Answers :
1) Answer: B
Let the work finished in x days
A’s one day work = 1/14
B’s one day work = 1/28
C’s one day work = 1/32
x/14 + (x-3)/28 + (x-2)/32 = 1
=> (16x + 8x – 24 + 7x – 14)/224 = 1
=> 31x = 224 + 38
=> x = 262/31
=> x = 8 (14/31) days
2) Answer: A
LCM of 16 and 20 = 80 units
(A + B)’s one day work = 5 units
(B + C)’s one day work = 4 units
A’s 6 days work + B’s 9 days work + C’s 22 days work = 80
(A + B)’s 6 days work + (B + C)’s 3 days work + C’s 19 days work = 80
(5*6) + (4*3) + C’s 19 days work = 80
C’s 19 days work = 80 – 30 – 12 = 38
C’s one day work = 38/19 = 2 units
C alone can complete the work in, (80/2) = 40 days
3) Answer: D
A + B = 300/100 * 10 = 30 days
C + D = 100/85 * 17 = 20 days
A + B + C = 2/1 * 7.5 = 15 days
C = 1/15 – 1/30 = 1/30
D = 1/20 – 1/30 = 1/60
A + D = 300/200 * 16 = 24 days
A = 1/24 – 1/60 = (5 – 2)/120 = 1/40
B = 1/30 – 1/40 = 1/120
B complete 40% of the work = 40/100 * 120 = 48 days
4) Answer: B
A = 4/3 * 9 = 12 days
A + B = 100/60 * 4.8 = 8 days
B = 1/8 – 1/12 = 3 – 1/24 = 1/24
Ratio of the amount received by A and B = 1/12:1/24 = 2:1
Required difference = 1/2 * 5000 = 2500
5) Answer: B
A = 9/4 * 20 = 45
B = 2/1 * 15 = 30
C = 5/4 * 36 = 45
(x + 5/45) + (x + 5/30) + (x/45) = 1
2x + 10 + 3x + 15 + 2x = 90
7x = 65
x = 65/7 = 9(2/7)
Total time = 5 + 9(2/7) = 14(2/7) days
6) Answer: E
A = 100/75 * 15 = 20 days
B = 100/60 * 18 = 30 days
First 2 days complete the work = 1/20 + 1/30 = 5/60 = 1/12
After 6 times of 2 days = 6/12 = 1/2
After 6 * 2 = 12 days half of the work is completed.
7) Answer: E
A + B complete the whole work = 100/60 * 216/25 = 14(2/5) days
B + C complete whole work = 100/80 * 36/5 = 9 days
B + C complete the work in 4 days = 4/9
Remaining work = 5/9
A alone complete the whole work = (40/3)/(5/9) = 24 days
B = 5/72 – 1/24 = 2/72 = 1/36
C = 1/9 – 1/36 = 3/36 = 1/12
8) Answer: B
18 men can complete the work in (x – 6) days
One man can complete the work in 18 * (x – 6) days
10 men can complete the same work in (y + 2) days
One man can complete the same work in 10 * (y + 2) days
Since, the work is same
18 * (x – 6) = 10 * (y + 2)
9 * (x – 6) = 5 * (y + 2)
9x – 54 = 5y + 10
9x – 5y = 64 (equation 1)
Also, 20 women can complete the work in (x – 2) days
1 women can complete the work in 20 * (x – 2) days
16 women can complete the work in (y + 4) days
One woman can complete the work in 16 * (y + 4) days
Since, the work is same
20 * (x – 2) = 16 * (y + 4)
5 * (x – 2) = 4 * (y + 4)
5x – 10 = 4y + 16
5x – 4y = 26 (equation 2)
Solving equation 1 and equation 2, we get
x = 126/11 and y = 86/11
Therefore,
x – y = (126/11) – (86/11)
x – y = 40/11
9) Answer: D
(x – 5) person can do the work in = x days
(x – 5)*x = (x + 10) (x – 10)
x2 – 5x = x2 – 100
5x = 100
x = 20
Person        days
15Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 20
25Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ?
(15 * 20) = 25*y
y = 300/25 = 12 days
10) Answer: B
A + B + C = 1/9
C + D = 100/75 * 6 = 8
d) 1/3y + 1/2y + 1/2y= 1/9
(2 + 3 + 3)/6y = 1/9
8/6y = 1/9
1/y = 1/12
C alone complete the work = 2 * 12 = 24 days
D = 1/8 – 1/24 = 2/24 = 1/12
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