Crack IBPS Exam 2017 – Quantitative Aptitude Scoring Part (Day-16)

    Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-1)

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    Direction (1-10): What value should come in place of question mark (?) in the following questions?
    1). 3 2/5 × 7 5/8 ÷ 2 1/3 × 3 1/2 × 3 1/5 = ?

    121.32
    122.82
    123.74
    124.44
    125.5

    1). Answer: d)
    ? = 17/5 × 61/8 ÷ 7/3 × 7/2 × 16/5
    ? = 17 × 61 × 3 × 16 / (5 × 8 × 2 × 5)
    ? = 3111 / 25 = 124.44

    2. 77.8 × 0.8 × ? = 964.72

    13.5
    14.5
    15.5
    16.5
    17.5
    2). Answer: c)
    ? = 964.72 / (77.8 × 0.8) = 15.5

    3. √17.64 × √14.0625 = √0.0225 × ?

    105
    115
    125
    135
    145
    3). Answer: a)
    ? = 4.2 × 3.75 / 0.15 = 15.75 / 0.15
    ? = 105


    4. 7/15 of 5/27 of 45% of 1593 = 2.1 × ?

    29.5
    28.5
    27.5
    26.5
    25.5
    4). Answer: a)
    ? = 7 × 5 × 45 × 1593 / (12 × 27 × 100 × 2.1)
    ? = 29.5


    5). (357.911)^(2/3) × (50.41)^(3/2) = (7.1)^?

    5
    4
    3
    2
    1
    5). Answer: a)
    (7.1)^? = {(7.1)^3}^(2/3) × {(7.1)2}^(3/2)
    or, (7.1)^? = (7.1)^2 × (7.1)^3
    or, (7.1)^? = (7.1)^5
    ? = 5


    6. 4003 × 77 - 21015 = ? × 116

    2477
    2478
    2467
    2476
    None of these
    6). Answer: d)
    ? × 116 = 4003 × 77 - 21015
    ? × 116 = 308231 - 21015 = 287216
    ? = 287216 / 116
    ? = 2476


    7. [(5 √7 + √7) × (4 √7 + 8 √7)] - (19)^2 = ?

    143
    72 √7
    134
    70 √7
    None of these
    7). Answer: a)
    [(5 √7 + √7) × (4 √7 + 8 √7)] - (19)^2 = ?
    ? = [20 × 7 + 4 × 7 + 8 × 7 + 40 × 7] - 361
    ? = [140 + 28 + 56 + 280] - 361
    ? = 504 - 361 = 143


    8. (4444 ÷ 40) + (645 ÷ 25) + (3991 ÷ 26) = ?

    280.4
    290.4
    295.4
    285.4
    None of these
    8). Answer: b)
    ? = (4444 ÷ 40) + (645 ÷ 25) + (3991 + 26)
    ? = 4440 / 40 + 645 / 25 + 3991 / 26
    ? = 111.1 + 25.8 + 153.5 = 290.4

    9. √33124 × √2601 - (83)^2 = (?)^2 + (37)^2

    37
    33
    34
    28
    None of these
    9). Answer: e)
    (?)^2 + (37)^2 = √33124 × √2601 - (83)^2
    or, (?)^2 + (37)^2 = 182 × 51 - (83)^2
    or, (?)^2 + 1369 = 9282 - 6889 = 2393
    or, (?)^2 = 2393 - 1369 = 1024
    ? = √1024 = 32

    10. 5 17/37 × 4 51/52 × 11 1/7 + 2 3/4 = ?

    303.75
    305.75
    303 3/4
    305 1/4
    None of these
    10). Answer: b)
    ? = 5 17/37 × 4 51/52 × 11 1/7 + 2 3/4
    ? = 202 / 37 × 259 / 52 × 78 / 7 + 11/4
    ? = 202/37 × 259 / 7 × 3/2 + 11 / 4
    ? = 101 × 3 + 11 / 4
    ? = 303 + 11/4 = (1212 + 11) / 4
    ? = 1223/4 = 305.75

    Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
    11. 1144.98 × 5.85 × 3.2 ÷ 12 = ?

    1600
    1790
    1800
    2200
    2400
    11). Answer: b)
    ? ≈ 1145 × 5.85 × 3.2 ÷ 12
    ? = 1786.2 ≈ 1790

    12. 112.21 × 132.52 × 4.793 ÷ 17.998 = ?

    3720
    3780
    3840
    3900
    3960
    12). Answer: e)
    ? ≈ 112.2 × 132.5 × 4.8 ÷ 18
    ? = 3964.4 ≈ 3960

    13. 27.77 × 35.012 × 4.88 ÷ 24.985 + √35 = ?

    180
    200
    220
    240
    260
    13). Answer: b)
    ? ≈ 27.8 × 35 × 5 / 25 + 6
    ? ≈ 194.6 + 6 = 200.6 ≈ 200

    14. 27% of 5678 - 37% of 2345 = ?

    620
    635
    650
    665
    680
    14). Answer: d)
    ? = 27 × 5678 /100 – 37 × 2345 / 100
    ? = 1533.06 - 867.65 = 665.41 ≈ 665

    15. 648% of √429020 = ?

    4050
    4150
    4250
    4350
    4450
    15). Answer: c)
    √429020 ≈ 655
    ? ≈ 648 × 655 /100 = 4244.4 ≈ 4250

    16. 148% of 13785 = ?

    20100
    20200
    20300
    20400
    20500

    16). Answer: d)
    ? = 148 × 13785 / 100
    ? = 20401.8 ≈ 20400

    17. √1445 + 8.01 / 6.994 × 168.08 = ?

    210
    220
    230
    240
    250
    17). Answer: c)
    √1445 ≈ 38
    ? ≈ 38 + 8/7 × 168
    ? = 38 + 192 = 230

    18. √24000 × 36.06 +174.98 × 3.99 = ?

    6180
    6280
    6380
    6480
    6580
    18). Answer: b)
    √24000 ≈ 155
    ? ≈ 155 × 36 + 175 × 4
    ? = 5580 + 700 = 6280


    19. 4488 ÷ √1935 + 171.991 ÷ 3.998 = ?

    105
    125
    145
    165
    185
    19). Answer: c)
    √1935 ≈ 44
    ? ≈ 4488 / 44 + 172 / 4
    ? = 102 + 43 = 145


    20. (1884% of 73) ÷ 25.05 = ?

    35
    45
    55
    65
    75
    20). Answer: c)
    ? = 1884 × 73 /100 ÷ 25
    ? ≈ 1375 / 25 = 55

    Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.21. 4500, 5400, 5488, 4608, ?

    4836
    1786
    2916
    3866
    5896
    21). Answer: c)
    The series is,
    5^3 × 62 = 4500
    6^3 × 52 = 5400
    7^3 × 42 = 5488
    8^3 × 32 = 4608
    9^3 × 22 = 2916


    22. 3, 6, 17, 48, ?, 248

    154
    169
    214
    117
    135
    22). Answer: d)
    The difference between numbers is + 1^3 + 2 , + 2^3 + 3, + 3^3 +4 , + 4^3 + 5 , + 5^3 + 6


    23. 13, 24, 42, 79, 153,?

    198
    248
    288
    328
    378
    23). Answer: c)
    The difference between numbers is + 1^3 + 10, + 2^3 +10, + 3^3 + 10, + 4^3 + 10, + 5^3 +10

    24. 2, 4, 20, 74, ?, 452

    316
    202
    348
    184
    396
    24). Answer: b)
    The difference between numbers is +1³+1³ , +2³+2³ ,+3³+3³ , +4³+4³ , +5³+5³

    25. 122, 131, 203, 446,?

    1022
    878
    1246
    1132
    984
    25). Answer: a)
    The difference between numbers is +1³+2³ , +2³+4³ ,+3³+6³ , +4³+8³

    Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
    a) if x< y
    b) if x ≤ y
    c) if x = y
    d) if x> y
    e) if x ≥ y

    26. I. 4x^2 – 8x + 3 = 0
    II. 2y^2 – 7y + 6 = 0

    a)
    b)
    c)
    d)
    e)
    26). Answer: b)
    From equation I:
    4x^2 -8x+3 = 0
    or, 4x^2-6x-2x+3=0
    or, 2x(2x -3)-1(2x -3) = 0
    or, (2x -1)(2x -3) = 0
    x =1/2 or 3/2
    From equation II:
    2y^2 - 7y +6 = 0
    or,2y^2-4y-3y+6 = 0
    or, (2y-3) (y-2)=0
    y =3/2 or 2
    Hence, x ≤ y

    27.I. x^2 + x - 6 = 0
    II. 2y^2 – 13y + 21 = 0

    a)
    b)
    c)
    d)
    e)
    27). Answer: a)
    From equation I:
    x^2+ x - 6 = 0
    or, x^2 – 2x + 3x – 6 = 0
    or, x(x -2) +3(x - 2) = 0
    (x - 2) (x + 3) = 0
    x = -3 or 2
    From equation II:
    2y^2 – 13y + 21 = 0
    or, 2y^2 – 6y – 7y + 21 = 0
    or, 2y(y-3) -7(y-3) = 0
    or, (2y - 7) (y - 3) = 0
    y = 3 or 7/2
    Hence, x

    28. I. x^2 – x - 6 = 0
    II. 2y^2 + 13y + 21 = 0

    a)
    b)
    c)
    d)
    e)
    28). Answer: d)
    From equation I:
    x^2 – x – 6 = 0
    or, x^2 – 3x + 2x – 6 = 0
    or, x(x-3) + 2(x-3) = 0
    or, (x-3)(x+2) = 0
    x = -2 or 3
    From equation II:
    2y^2 +13y+21=0
    or, 2y^2 +6y+7y+21 = 0
    or,2y(y+3)+7(y+3)=0
    or, (2y+7)(y+3) = 0
    y = - 3 or - 7/2
    Hence x> y

    29. I. x^2 = 4
    II. y^2 + 6y + 9 = 0

    a)
    b)
    c)
    d)
    e)
    29). Answer: d)
    From equation I:
    x^2 = 4
    x = √4
    x = ± 2
    from equation II:
    y^2 + 6y + 9 = 0
    or, y^2 + 3y + 3y + 9 = 0
    or,y (y + 3)+3(y+3) = 0
    or, (y+3) (y+3)=0
    or, y = -3, -3
    Hence x> y

    30. I. 2x + 3y = 4
    II. 3x + 2y = 11

    a)
    b)
    c)
    d)
    e)
    30). Answer: d)
    From I and II we get y = - 2 and x = 5
    x> y


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