Crack IBPS Exam 2017 – Quantitative Aptitude Scoring Part (Day-21)

    Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-1)


     

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    Direction (1-10): What value should come in place of question mark (?) in the following questions?
    1). (17)^8.8 × (289)^(–1.4) ÷ 1/(17)^-1 = 17 × (17)^?

    2
    3
    4
    5
    6

    1). Answer: c)
    17 × 17^? = (17)^8.8 × (17^2)^(–1.4) ÷ (17)^1
    17 × 17^? = (17)^8.8 × (17)^(–2.8) ÷ 17 = (17)^(8.8 – 2.8 – 1) = (17)^5
    17^? = 17^(5 – 1) = 17^4
    ? = 4

    2. 2.4% of 775 + 8.4% of 525 = 30% of?

    201
    203
    205
    207
    209
    2). Answer: e)
    30 × ? / 100 = 2.4 × 775 / 100 + 8.4 × 525 / 100
    30 × ? / 100 = 18.6 + 44.1 = 62.7
    ? = 62.7 × 100 / 30 = 627/3 = 209

    3. {0.00102 ÷ 0.000017} × 17.75 = ?

    1045
    1055
    1065
    1075
    1085
    3). Answer: c)
    ? = 0.00102 / 0.000017 × 17.75
    ? = 1020 / 17 × 17.75
    ? = 60 × 17.75 = 1065


    4. (1728)^(2/3) ÷ 1/(5832)^(2/3) = ? × 9

    5184
    7776
    3888
    11664
    10368
    4). Answer: a)
    9 × ? = (12^3)^(2/3) ÷ 1/(18^3)^(2/3) =(12)^2 ÷ (18)^(-2)
    9 × ? = (12)^2 × (18)^2
    ? = 12 × 12 × 18 × 18 / 9
    ? = 5184


    5).(1260 ÷ 28) × 6.4 = 45% of?

    320
    640
    960
    1280
    1510
    5). Answer: b)
    45 × ? / 100 = 1260 / 28 × 6.4 = 45 × 6.4
    ? = 6.4 × 100 = 640


    6. 85% of 4/7 of 6755 = ? + 1687

    1586
    1592
    1594
    1582
    None of these
    6). Answer: c)
    ? = 85 × 4 × 6755 / (100 × 7) – 1687 = 17 × 193 - 1687
    ? = 3281 - 1687 = 1594


    7. (5568 ÷ 87)^(1/3) + (72 × 2)^(1/2) = (?)^(1/2)

    256
    4
    2
    16
    None of these
    7). Answer: a)
    (?)^(1/2) = (5568 / 87)^(1/3) + (144)^(1/2)
    (?)^(1/2) = (64)^(1/3) + (12^2)^(1/2) = (4^3)^(1/3) + (122)^(1/2)
    (?)^1/2 = 4 + 12 = 16
    ? = 256


    8. √(13^2 + 28 ÷ 4 - (3)^3 +107) = (?)^2

    2
    16
    256
    4
    (256)^2
    8). Answer: d)
    (?)^2 = √(13^2 + 28 ÷ 4 - (3)^3 +107)
    = √(169 + 7 - 27 +107)
    = √(283 – 27) = √256 = 16
    ? = √16 = 4
    9). Answer: b)
    (0.7)^(?+3) = (0.7)^(2 × 4) × (0.7)^(3 × 4) ÷ (0.7)^(4 × 4)
    (0.7)^(?+3) = (0.7)^(8 + 12 – 16) = (0.7)^4
    ? = 4 – 3 = 1

    9. (0.49)^4 × (0.343)^4 ÷ (0.2401)^4 = (70 ÷ 100)^(? + 3)

    3
    1
    4
    7
    None of these
    9). Answer: b)
    (?)^2 = 1224 × 306 = (18 × 17 × 4) × (18 × 17)
    (?)^2 = (18 × 17 × 2)^2
    ? = 18 × 17 × 2 = 612

    10. 45% of √2025 ÷ 0.01 = (?)^2 ÷ 25

    3
    (81)^2
    81
    9
    None of these
    10). Answer: e)
    √2025 = 45
    Now, 45 × 45 / (0.01 × 100) = (?)^2 ÷ 25
    2025 = (?)^2 / 25
    or. (?)^2 = 50625
    ? = √50625 = 225

    Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
    11. 78.99% of 9875.99 - 38.09% of 6785.05 = 2479.05 + ? of 4895.99

    56
    50
    48
    60
    None of these
    11). Answer: a)
    ? × 4896 / 100 ≈ 79 × 9876 /100 - 38 × 6785 / 100 - 2479
    = 0.79 × 9876 - 0.38 × 6785 - 2479
    ≈ 7802 - 2578 - 2479
    = 7802 - 5057 = 2745
    ? = 2745 / 4896 × 100 = 56.06 ≈ 56

    12. √((4095.99)^(1/3)) × √65535.89 = (?)^2

    24
    11
    16
    64
    32
    12). Answer: e)
    (?)^2 ≈ √(4096)^(1/3) × √65536
    = √16^(3 ×(1/3)) × √16^4
    = 4 × 16 × 16 = 256 × 4 = 1024
    ? = √1024 = 32

    13.5030.05 ÷ 42.93 + 24.49% of 5049.93 ÷ 100 = ?

    150
    170
    130
    90
    None of these
    13). Answer: c)
    5030.05 ÷ 42.93 + 24.49% of 5049.93 ÷ 100 = ?
    ? ≈ 5030 ÷ 43 + 24.5% of 5050 ÷ 100
    ? = 116.9764 + 1237.25 ÷ 100
    ? ≈ 117 + 13
    ? = 130

    14. 52920 ÷ 3214.05 × 514.13 + 5231.92 = ?

    13617
    13695
    13823
    13511
    None of these
    14). Answer: b)
    ? ≈ 52920 ÷ 3214 × 514 + 5232
    ? = 16.46 × 514 + 5232
    ? = 8460.44 + 5232 = 13692.44 ≈ 13695

    15. ³√ 6850 × √12540 = ? × 52

    41
    39
    38
    43
    None of these
    15). Answer: a)
    ³√6850 × √12540 = ? × 52
    or, ? ≈ 19 × 112 / 52
    ? = 40.92 ≈ 41

    16.√6398.99 ÷ ³√4099.99 × 24.89 = (?)^³

    4
    5
    7
    6
    3

    16). Answer: b)
    (?)^3 = √6398.99 ÷ ³√4099.99 × 24.89
    or, (?)^3 ≈ 80 ÷ √(16 ×16 × 16) × 25
    or, (?)^3 = 80 ÷ 16 × 25
    or, (?)^3 = 125 = 53
    ? = 5

    17. (87.65% of 7159.89 - 68.99% of 8939.89) × 6.06 = (?)^2

    20
    22
    21
    28
    30
    17). Answer: d)
    (?)^2 ≈ (88 × 7160 / 100 - 69 × 8940 /100) × 6
    = (88 × 71.60 - 69 × 89.40) × 6
    ≈ (6300 - 6168) × 6
    = 132 × 6 = 792
    ? = √792 = 28.14 ≈ 28
    18). Answer: b)
    40 × ? / 100 ≈ 449 × 346 / 64
    or,? = 449 × 346 × 100 / (64 × 40)
    ? = 6068.5 ≈ 6065

    18.449.03 × 345.88 ÷ 64 = 40.02% of ?

    6232
    6065
    6512
    5831
    5932
    18). Answer: b)
    (50243408)^(1/3) ≈ (50243409)^(1/3) = 369
    and, (48627124)^(1/3) ≈ (48627125)^(1/3) = 365
    Again, (7529535)^(1/3) ≈ (7529536)^(1/3) =196
    So, ? = 369 - 365 + 196
    ? = 200


    19. 37.9% of 638.05 + 25.25% of 4401.9 = ?

    1320
    1415
    1270
    1345
    None of these
    19). Answer: d)
    37.9% of 638.05 + 25.25% of 4401.9 = ?
    or, ? ≈ 38% of 638 + 25% of 4402
    = 242.44 + 1100.5 = 1342.94
    ? ≈ 1345


    20. 833.956 - 543.005 - 108.98 = 19.8% of ?

    940
    890
    880
    910
    None of these
    20). Answer: d)
    ? × 20 / 100 ≈ 834 - 543 - 109 = 182
    ? = 182 × 5 = 910

    Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.21. 2, 10, 30, 68, ?

    126
    130
    140
    150
    None of these
    21). Answer: b)
    The series is 1^3 + 1, 2^3 + 2, 3^3 + 3, 4^3 + 4, 5^3 + 5, …


    22. 33, 321, 465, 537, 573, ?

    600
    591
    585
    498
    None of these
    22). Answer: b)
    The difference between the numbers is + 288, + 144, + 72, + 36, +18, ..


    23. 2, 9, ?, 105, 436, 2195

    25
    27
    30
    33
    None of The Above
    23). Answer: c)
    The sequence of the series is ×1 + (1×7), ×2 + (2×6), ×3 + (3×5), ×4 +(4×4),…

    24. 4, 6, 14, 44, ?, 892

    176
    172
    178
    182
    None of The Above
    24). Answer: c)
    The series is ×1 + 2, ×2 +2, ×3 + 2, ×4 + 2, ×5 + 2,

    25.126, 64, 34, 20, 14, ?

    12
    14
    16
    18
    None of The Above
    25). Answer: a)
    The sequence of the series is ÷2 + 1, ÷2 + 2, ÷2 +3, ÷2 +4, ÷2+5,..

    Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
    a) If x> y
    b) If x ≥ y
    c) If x< y
    d) If x ≤ y
    e) If x = y or no relation can be established between x and y.

    26. I. x2 – 16 = 0
    II. y^4 – {[(8 x 2)^(9/4)] / √y } = 0

    a)
    b)
    c)
    d)
    e)
    26). Answer: d)
    I. x^2 – 16 = 0
    X^2 = 16
    x = ±4
    II. y^4 – {[(8 x 2)^(9/4)] / √y } = 0
    Y^4 √y – [(4^2)^(9/4)] = 0
    y ^(4+(1/2)) – (4)9/2 = 0
    y^(9/2) – 4^(9/2) = 0
    y = 4
    Hence x ≤ y

    27.I. x^2 - 2√3x – 72 = 0
    II. y^2 + 9√3x + 60 = 0

    a)
    b)
    c)
    d)
    e)
    27). Answer: b)
    I. x^2 - 2√3x – 72 = 0
    X^2 - 6√3x + 4√3x – 72 = 0
    x (x - 6√3) + 4√3 (x - 6√3) = 0
    x = -4√3, 6√3
    II. y^2 + 9√3y + 60 = 0
    Y^2 + 4√3y + 5√3y + 60 = 0
    y(y + 4√3) + 5√3 (y + 4√3) = 0
    y = -4√3, -5√3
    Hence x ≥ y

    28.I. x^6 – [(√(54 × 6))^6.5 / √x] = 0
    II. y – (36 × 81)^(1/2) = 0

    a)
    b)
    c)
    d)
    e)
    28). Answer: c)
    I. x^6 – [(√(54×6))^6.5 / √x] = 0
    X^(6+(1/2)) – (18)^(6.5) = 0
    X^(6.5) = 18^(6.5)
    x = 18
    II. y – (36 × 81)^(1/2) = 0
    y – (6 × 9) = 0
    y – 54 = 0
    y = 54
    Hence x< y

    29. I. x^2 – 17x – 234 = 0
    II. 4y^2 + 32y – 192 = 0

    a)
    b)
    c)
    d)
    e)
    29). Answer: e)
    I. x^2 – 17x – 234 = 0
    X^2 – 26x + 9x – 234 = 0
    x(x - 26) + 9 (x – 26) = 0
    (x + 9) (x - 26) = 0
    x = -9, 26
    II. 4y^2 + 32y – 192 = 0
    Y^2 + 8y – 48 = 0
    y^2 + 12y – 4y – 48 = 0
    y (y + 12) – 4 (y + 12)
    y = - 12, 4
    Hence relation cannot be determined

    30. I. x^2 = 784
    II. y^2 – 11y – 102 = 0

    a)
    b)
    c)
    d)
    e)
    30). Answer: e)
    I. x^2 = 784
    x = ± 28
    II. y^2 – 11y – 102 = 0
    y^2 – 17y + 6y – 102 = 0
    y (y - 17) +6 (y - 17) = 0
    y = 17, -6
    Hence Relation cannot be determined

     


     
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