Crack IBPS Exam 2017 – Quantitative Aptitude Scoring Part (Day-26)

    Crack IBPS Exam 2017 - Quantitative Aptitude Scoring Part (Day-1)


     

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    Direction (1-10): What value should come in place of question mark (?) in the following questions?
    1). (609)^2 + 25% of 200 – 3/4 of 1976 = ?

    369439
    369429
    369419
    369449
    379449

    1). Answer: d)
    370881 + 50 - 494 × 3
    = 370881 + 50 - 1482 = 369449

    2. √17161 × 18 + 92 × 94 + 2/5 of 125 = ?

    11054
    11354
    11056
    12346
    10156
    2). Answer: c)
    ? = √17161 × 18 + 92 × 94 + 2/5 of 125
    = 131 × 18 + 8648 + 50
    = 2358 + 8648 + 50 = 11056

    3. ?% of 650 + 40% of 525 = 275

    12
    15
    10
    13
    8
    3). Answer: c)
    ?% of 650 + 40% of 525 = 275
    ?/100 × 650 + 210 = 275
    6.5 × ? = 275 - 210 = 65
    ? = 650/65 = 10


    4. 3√12167 ×√11881 + 70% of 6210=?

    6823
    7853
    6854
    9231
    8454
    4). Answer: c)
    ? = 3√12167 ×√11881 + 70%of 6210
    = 23 x 109 + 70/100 × 6210
    = 2507 + 4347 = 6854


    5). ∛35937 ×∛1331 ÷ √121 + 60% of 1295 = ?

    895
    890
    610
    810
    980
    5). Answer: d)
    ? = 3√35937 × 3√1331 ÷√121 + 60% of 1295
    = 33 × 11 ÷ 11 + 3/5 × 1295
    = 33 + 777 = 810


    6. 15% of 240 + √11449 - 25% of 160 = ?

    109
    112
    116
    103
    None of these
    6). Answer: d)
    ? = 15/100 × 240 + 107 – 25/100 × 160
    = 36 + 107 - 40 = 103


    7. (64)^4.5 × (4096)^3.4 ÷ (16)^1.5 × (4)^3 = ?

    4^(43.8 )
    4^(42.9 )
    4^(40.8 )
    4^(33.9)
    None of these
    7). Answer: d)
    ? = (64)^4.5 × (4096)^3.4 ÷ (16)^1.5 × (4)³
    = (4³)^4.5 × (4^6)^3.4 ÷ (42)^1.5 × 4^3
    = (4)^13.5 × (4)^20.4 ÷ (4)^3 × 4^3
    = (4)^(13.5) × (4)^(20.4 – 3) × 4^3
    = (4)^(13.5 + 17.4 + 3)
    = (4)^(33.9)


    8. (207)^2 + 20% of 200 × √1225 - 25% of 160 = ?

    46409
    49409
    44209
    35409
    None of these
    8). Answer: c)
    ? = (207)² + 20% of 200 × √1225 - 25.1% of 160
    = 42849 + 1/5 × 200 × 35 – 1/4 × 160
    = 42849 + 40 × 35 - 40 = 44209

    9. √9216 ×∛1728 - 40%of 1200 = ?

    685
    772
    840
    672
    None of these
    9). Answer: d)
    ? = √9216 × ³√1728 - 40% of 1200
    = 96 × 12 – 2/5 × 1200
    = 1152 - 480 = 672

    10. 2/5 of 1/4 of 5/3 of ∛46656 = ?

    12
    9
    6
    15
    None of these
    10). Answer: c)
    ? = 2/5 × 1/4 × 5/3 ×3√46656 =1/6 × 36 = 6

    Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
    11. (871% of 752) ÷ 251 = ?

    26
    38
    45
    66
    75
    11). Answer: a)
    ? = (871% of 752) + 251
    = (870 / 100) × 750 × (1 / 250) = 26.1 ≈ 26

    12. 0.5% of 349 × 8.2% of 574 = ?

    80.5
    84.5
    89.5
    95.5
    None of these
    12). Answer: a)
    ?= (0.5% of 349) × (8.2% of 574)
    = (0.5% of 350) × 8% of 575
    = [( 0.5 / 100) × 350] × [( 8 / 100) × 575]
    = (1.75 × 46) = 80.5

    13. 29.99% of 155.012 + 12.98% of 164.99 = ?

    54
    58
    64
    66
    68
    13). Answer: e)
    ? = 29.99% of 155.012 + 12.98% of 164.99
    = (30% of 155) + (13% of 165)
    = [ (30 / 100) × 155 ] + [ (13 / 100) × 165 ]
    = 46.5 + 21.45 = 67.95 ≈ 68

    14. 57% of 394 – 2.5% of 996 = ?

    215
    175
    200
    180
    205
    14). Answer: c)
    ? = (57% of 394) – (2.5% of 996) = ?
    ? ≈ [(57 × 400) / 100] – [(25 × 1000) / 1000]
    (actual answer less than this)
    = 228 – 25 = 203 = 200

    15. (1.65% of 5471) – (0.61% of 8336) = ?

    20.15
    26.25
    31.45
    38.85
    40.35
    15). Answer: e)
    ? = (1.65% of 5471) – (0.61% of 8336) = ?
    ≈ (1.5% of 5470) – (0.5% of 8340)
    = [(1.5 / 100) × 5470] – [(0.5 / 100) × 8340]
    = 82.05 – 41.7 ≈ 40.35

    16. 74.75% of 240 + 151% of 180 = ?

    390
    415
    425
    450
    465

    16). Answer: d)
    (74.75% of 240) + (151% of 180) = ?
    = (75% of 240) + (150% of 180)
    = [(75 / 100) × 240] – [(150 / 100) ×180]
    = (180 + 270) = 450

    17. 49% of 2647 + 27% of 7589 = ?

    4133.5
    3222.5
    2111.5
    1000.5
    None of these
    17). Answer: b)
    ? = (49% of 2647) + (27% of 7589)
    ≈ (50% of 2650) + (25% of 7590)
    = [(50 / 100) × 2650] – [(25 / 100) × 7590]
    = (1325 + 1897.5) ≈ 3222.5

    18. 23.5% of 4924.2 + ? % of 4324.4 = 1849.091

    16
    18.5
    36.5
    46.5
    52.5
    18). Answer: a)
    23.5% of 4924.2 + ? % of 4324.4 = 1849.091
    (? / 100) × 4325 ≈ 1850 – 4925 × (23.5 / 100)
    ? ≈ (693 × 100) / 4325
    ? = 16


    19. (296% of 112) ÷ 73.92 = ?

    9.86
    8.42
    6.15
    5.24
    4.48
    19). Answer: e)
    (296% of 112) ÷ 73.92 = ?
    = (296% of 112) ÷ 74
    = (296 / 100) × 112 × (1 / 74) ≈ 4.48


    20.(37% of 1222 – 13% of 1211) ÷ 61 = ?

    18
    24
    28
    34
    None of these
    20). Answer: e)
    ? = (37% of 1222 – 13% of 1211) ÷ 61 = ?
    = [(37 / 100) × 1200] – [(13 / 100) × 1200] × (1 / 60)
    = [1200 / (100 × 60) ] × (37 – 13) = 4.8 ≈ 5

    Direction (21 – 25): In the following number series only one number is wrong. Find out the wrong number.
    21. 2, 6, 18, 54, 162, ?, 1458

    274
    486
    1236
    1032
    None of these
    21). Answer: b)
    The series is ×3, ×3, ×3, ×3,…..


    22. 0, 3, 8, 15, 24, 35, 48, ?

    60
    62
    63
    64
    None of these
    22). Answer: c)
    The series is 1² – 1, 2² – 1, 3² – 1, 4² – 1, 5² – 1, …..


    23. 0, 7, 26, 63, 124, ?, 342

    128
    300
    240
    215
    None of these
    23). Answer: d)
    The series is 1³ – 1, 2³ – 1, 3³ – 1, 4³ – 1, 5³ – 1,…..

    24. 9, 11, 16, 26, ?, 69

    29
    34
    45
    57
    None of these
    24).Answer: e)
    The difference of difference of the series is, 3, 5, 7, 9,..

    25. 3, 4, 10, 33, 136, ?

    685
    447
    366
    586
    None of these
    25). Answer: a)
    The series is,
    3 x 1 + 1 = 4
    4 x 2 + 2 = 10
    10 x 3 + 3 = 33
    33 x 4 + 4 = 136
    136 x 5 + 5 = 685

    Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
    a) if x> y
    b) if x ≥ y
    c) if x< y< br> d) if x ≤ y
    e) if x = y or no relation can be established between x and y.

    26). I. x² – 11x + 30 = 0
    II. 2y² – 9y + 10 =0

    a)
    b)
    c)
    d)
    e)
    26). Answer: a)
    I.x² – 6x – 5x + 30 = 0
    x (x-6) -5 (x- 6) = 0
    (x-6) (x-5) = 0
    => x = 6, 5.
    II. 2y² – 9y + 10 =0
    2y² – 4y – 5y + 10 =0
    2y (y-2) -5 (y-2) =0
    => y = 2, 5/2.
    Therefore, x> y

    27). I. 15x² + 8x + 1 =0
    II. 3y² + 14y + 8 = 0

    a)
    b)
    c)
    d)
    e)
    27). Answer: a)
    I.15x² + 8x + 1 =0
    15x² + 5x + 3x + 1 =0
    5x (3x+1) + 1(3x+1)) = 0
    (5x+1) (3x+1) = 0
    => x = -1/5, -1/3.
    II. 3y² + 14y + 8 = 0
    3y² + 12y +2y + 8 = 0
    3y (y+4) +2(y+4) =0
    => y = -4, -2/3.
    Therefore, x> y

    28). I. 4x² – 17x+ 18 = 0
    II. 2y² – 21y + 40 = 0

    a)
    b)
    c)
    d)
    e)
    28). Answer: c)
    I.4x² – 17x+ 18 = 0
    4x² -8x -9x + 18 =0
    4x (x-2)-9(x-2)) = 0
    (x-2)(4x-9) = 0
    => x = 2, 9/4
    II. 2y² – 21y + 40 = 0
    2y² – 16y-5y + 40 = 0
    2y(y-8)-5(y-8) =0
    => y = 8, 5/2.
    Therefore, x< y

    29). I. 6x² – 25x + 14 =0
    II. 9y² -9y + 2 =0

    a)
    b)
    c)
    d)
    e)
    29). Answer: b)
    I. 6x² – 25x + 14 =0
    6x² – 4x -21x + 14 =0
    2x (3x-2)-7(3x-2)) = 0
    (2x-7)(3x-2) = 0
    => x = 7/2, 2/3
    II. 9y² -9y + 2 =0
    9y² -6y -3y + 2 =0
    3y(3y-2)-1(3y-2) =0
    => y = 2/3, 1/3.
    Therefore, x ≥ y

    30). I.8x² + 25x + 3 =0
    II. 2y² + 17y + 30 = 0

    a)
    b)
    c)
    d)
    e)
    30). Answer: e)
    I. 8x² + 25x + 3 =0
    8x² + 24x + x + 3 =0
    8x (x+3)+1(x+3)) = 0
    (8x+1)(x+3) = 0
    => x = -1/8, -3
    II. 2y² + 17y + 30 = 0
    2y² + 12y +5y + 30 = 0
    2y (y+6) +5(y+6) =0
    (2y+5) (y+6) =0
    => y = -5/2, -6.
    Therefore, the relationship cannot be established.

     


     
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