# Crack IBPS Exam 2017 – Quantitative Aptitude Scoring Part (Day-7)

Crack IBPS Exam 2017 – Quantitative Aptitude Scoring Part (Day-7):

Dear Readers, Nowadays most of the aspirants are facing huge trouble to increase the overall marks. To score high you need to practice more and more standard questions daily. “Practice does not make perfect, Only Perfect Practice makes perfect”.

Here in Scoring Part we are providing 10 Questions in simplification, 10 Questions in Approximation, 5 Questions in number Series and 5 Questions in Quadratic Equations, total 30 questions in 20 Minutes. By practicing these questions regularly you can increase your calculation speed and it will help you to increase your score.

00:00:00

Direction (1-10): What value should come in place of question mark (?) in the following questions?
1). (139.93 × 24.102) - (27.89 × 7.53) = ?

2750
2920
3040
3150
3210

? ≈ (140 × 24) - (28 × 7.5)
= 3360 - 210 = 3150

2. (3248% of 55.055) ÷ 27.98 = ?

42
56
64
78
86
? ≈ (3248 × 55 / 100) ÷ 28
? = 3248 × 55 / 2800
? = 63.8 ≈ 64

3. √10600 × ³√19680 = ?

2780
2850
2940
3020
3150
(103)^2 = 10609
√10600 ≈103
(27)^3 = 19683
Since, ³√19680 ≈ 27
? ≈ 103 × 27 = 2781 ≈ 2780

4. 6844 ÷ √3360 + 255.65 ÷ 7.98 = ?

110
130
150
170
190
(58)^2 = 3364
Therefore, √3360 ≈ 58
? = 6844 / 58 + 256 / 8
? = 118 + 32 = 150

5. (248% of 17855) ÷ 23.98 = ?

1805
1815
1825
1835
1845
? ≈ (248 × 17855/100) ÷ 24
? = 44280.4 / 24 ≈ 1845

6. (48.048 ÷ 11.911) × √? = 112.012

676
784
900
1024
576
√? ≈ 112 / (48 ÷ 12)
√? = 112/4 = 28
? = 28^2 = 784

7. 4140.04 ÷ 36.06 + 55 × (8.998)^2 = ?

4570
4680
4750
4880
4960
? ≈ 4140/36 + 55 × (9)^2
? = 115 + 4455 = 4570

8. 32.48% of 1808 + 22.94% of 1508 = ?

710
820
930
1040
1150
? ≈ 32.5 × 1800 / 100 + 23 × 1500 / 100
= 585 + 345 = 930

9. 3√10650 = ?

28
26
24
22
18
(22)^3 = 10648
Therefore, 3√10650 ≈ 22

10. (10)^7.3 ÷ (100)^4.15 × (1000)^2 + 99999 = ? × 10^5

1
2
3
4
5
? × 10^5 = (10)^7.3 ÷ (10^2)^4.15 × (10^3)^2 + 99999
? × 10^5= (10)^7.3 ÷ (10)^8.3 × (10)^6 + 99999
? × 10^5= (10)^(7.3 – 8.3 + 6) + 99999
? × 10^5 = (10)5 + 99999 ≈ (10)^5 + (10)^5
? × 10^5 = 2 × 10^5
? = 2

Direction (11-20): What approximate value should come in place of question mark (?) in the following questions?
11.(2197)^-2 ÷ (28561)^-3 = 169 × (13)^?

2
3
4
5
1
(13^3)^-2 ÷ (13^4)^-3 = 169 × (13)^?
(13)^-6 ÷ (13)-12 = 169 × (13)^?
(13)^-6+12 = 169 × (13)^?
(13)^6 = 169 × (13)^?
169 × (13)^4 = 169 × (13)^?
? = 4

12. 7/12 of 5/21 of 1/23 of 48% of 28980 = ?

84
96
102
112
116
? = (7 × 5 × 48 × 28980) / (12 × 21 × 23 × 100)
? = 84

13. {14641 ÷ 11} × 3.5 = ?

4325.5
4472.5
4578.5
4658.5
4755.5
? = (14641 / 11) × 3.5
? = 1331 × 3.5
? = 4658.5

14. (28)^4.9 × (7)^0.1 × (2)^0.2 ÷ {(7)^-2.5 × (2)^-5} = (28)^?

3.1
7.1
4.1
6.1
2.1
28^? = (28)^4.9 × (7)^0.1 × (4)^0.1 ÷ (7^-2.5 × 4^-2.5)
28)? = (28))4.9 × (28))0.1 ÷ (28))-2.5
28)? = (28)^(4.5+0.1+2.5)
? = 7.1

15.(28.5% of 144) × 25 = ? × 6

171
172
173
174
175
6 × ? = (28.5 × 144 / 100) × 25
6 × ? = 41.04 × 25 = 1026
? = 1026 / 6 = 171

16. (8)^7.2 ÷ (512)^1.6 × (4096)^-1.2 ÷ (32768)^-1 = (8)^?

2.4
2.6
2.8
3
3.2

8^? = (8)^7.2 ÷ (8^3)^1.6 × (8^4)^-1.2 ÷ (8^5)^-1
8^? = (8)^7.2 ÷ 8^4.8 × 8^-4.8 ÷ 8^- 5
8^? = (8)^(7.2-4.8-4.8+5) = (8)^2.6
? = 2.6

17. 45.5% of 960 + 13.5% of 320 = ?% of 3000

8
12
16
20
24
3000 ×? / 100 = 45.5 × 9.6 + 13.5 × 3.2
3000 ×? / 100 = 436.8 + 43.2 = 480
? = 480 × 100 / 3000 = 16

18. {(13824)2/3 ÷ 16} × 7.5 = ?

220
250
270
300
320
? = {(24^3)^2/3 ÷ 16) × 7.5
? = {(24)^2 ÷ 16} × 7.5
? = 36 × 7.5 = 270

19. {6^3.6 ÷ (36)^- 4.2 }^1/4 = √?

41616
43264
44944
46656
47524
√? = {6^3.6 ÷ (6^2)^-4.2}^1/4
√? = {6^3.6 ÷ 6^-8.4)^1/4 = (6^(3.6 + 8.4)}^1/4
√? = {6^12}^1/4 = 6^3 = 216
or ? = (216)^2 = 46656

20. ³√12167 × √24025 = ?

3255
3297
3565
3611
3875
? = ³√12167 × √24025
? = 23 × 155 = 3565

Direction (21 – 25): What value should come in place of the question mark (?) in the following number series?
21). 24, 28 , 19 , 35 , 10 , ?

45
44
46
42
47
The series is,
24 + 2^2 = 24 + 4 = 28;
28 – 3^2 = 28 - 9 = 19;
19 + 4^2 = 19 + 16 = 35;
35 – 5^2 = 35 - 25 = 10;
10 + 6^2 = 10 + 36 = 46

22. 14 , 6 , 4 , 4, 8 , ?

32
8
4
16
14
The series is,
14 x 1 - 8 = 6;
6 x 2 - 8 = 4;
4 x 3 - 8 = 4;
4 x 4 - 8 = 8;
8 x 5 - 8 = 32

23. 14, 25, 47, 91, ?, 355

100
197
179
335
155
The series is,
14 x 2 - 3 = 25;
25 x 2 - 3 = 47;
47 x 2 - 3 = 91;
91 x 2 - 3 = 179;

24. 11, 24, 44, 70, 101, ?

136
102
80
102
163
The difference of difference of the series is, +7, +6, +5, +4, ….

25. 18, 8, 6, 8, 24, ?

6
48
24
176
167
The series is,
18 x 0.5 - 1 = 8;
8 x 1- 2 = 6;
6 x 2 - 4 = 8;
8 x 4 - 8 = 24;
24 x 8 - 16 = 176

Direction (26-30): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and given answer:
a) if x>y
b) if x≥y
c) if x< y
d) if x≤y
e) if x = y or no relation can be established between x and y.

26. I. 9x^2 - 41x+46=0
II. 12y^2 + 43y+ 38 = 0

a)
b)
c)
d)
e)
I 9x^2 - 41x + 46 = 0
or, 9x^2 - 18x - 23x + 46 = 0
or, 9x(x - 2) - 23(x - 2) = 0
or, (9x - 23) (x - 2) =0
x = 23/9, 2
II. 12y^2 + 43y + 38 =0
or, 12y^2 + 24y + 19y + 38 = 0
or, 12y(y + 2) + 19(y + 2) = 0
or, (12y + 19) (y+ 2) = 0
y = - 19/12, - 2
Therefore x> y

27.I. 6x^2 + 13x - 169 =0
II. y^2 + 8y - 65 = 0

a)
b)
c)
d)
e)
I.6x^2 + I3x - 169 = 0
or, 6x^2 - 26x + 39x - 169 =0
or, 2x(3x - 13) + 13(3x - 13) = 0
or, (2x + 13) (3x - 13) = 0
x = -13/2, 13/3
II. y^2 + 8y - 65 = 0
or, y^2 + 13y - 5y - 65 = 0
or, y(y + 13) - 5(y + 13) = 0
or, (y - 5) (y + 13) = 0.
y = 5, -13
Therefore relation can't be established between x and y

28. I. 3x + 5y = 4
II. 6x - 7y= 25

a)
b)
c)
d)
e)
I. 3x + 5y = 4
II. 6x – 7y = 25
Solving equation (I) and (II), we get
(I) × 2 ---- 6x + 10y = 8
(II) ----- 6x – 7y = 25
By subtracting (I) × 2 – (II),
17y = -17
y = -1 and x =3,
Therefore x> y

29. I. x^2 - 5x + 4 = 0
II. y^2 + 11y – 12 = 0

a)
b)
c)
d)
e)
I. x^2 - 5x + 4 = 0
or, x^2 – 4x – x + 4 = 0
or, x(x - 4) – 1(x -4) = 0
or, (x -1) (x - 4) = 0
x = 1, 4
Il.y^2 + 11y - 12= 0
or, y^2 + 12y – y -12 = 0
or, y(y + 12) – 1(y + 12) = 0 or, (y - 1) (y + 12) = 0
y = 1, -12
Therefore, x ≥ y

30.I. 8x^2 + 50x + 57 = 0
II. 6y^2 – y – 57 = 0

a)
b)
c)
d)
e)
I. 8x^2 + 50x + 57 = 0
or, 8x^2 + 12x + 38x +57=0
or, 4x(2x + 3) + 19(2x + 3) = 0
or, (4x + 19) (2x + 3) = 0
x = -19/4, -3/2
II.6y^2 – y - 57=0
or, 6y^2 + 18y - 19y - 57 = 0
or, 6y(y + 3) - 19(y + 3) = 0
or, (6y - 19) (y + 3) = 0
y= 19/6, -3
Therefore relation can't be established.

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