Practice Aptitude Questions For RBI Grade B& Upcoming Exams 2017

Practice Aptitude Questions For RBI Grade - B& Upcoming Exams 2017:

Practice Aptitude Questions For RBI Grade – B& Upcoming Exams 2017 (Quadratic Equation):

Dear Readers, Important Practice Aptitude Questions for RBI Grade B 2017 Exam was given here with Solutions. Aspirants those who are preparing for RBI Grade – B and all other Competitive examination can use this.


Directions (Q. 1-10): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
a)  If x> y
b)  If x ≥ y
c)  If x< y
d)  If x ≤ y
e)  If x = y or if there is no relation between ‘x’ and ‘y’.
1). I.15x2 – 46x + 35 = 0
II.4y2– 15y + 14 = 0
2). I.x2 + 42 = 13x
II.y=4√1296
3).I.3x2 – 23x + 40 = 0
II.2y2– 23y + 66 = 0
4). I.x2 + 5x – 6 = 0
II.2y2 – 11y + 15 = 0
5). I.x2 + x – 2 = 0
II. y2 + 7y + 12 = 0
6). I.3x2+ 15x + 18 = 0
II.2y2 + 15y + 27 = 0
7). I.4x2+ 3x – 1 = 0
II.6y2 – 5y + 1 = 0
8). I.x2 + 11x + 30 = 0
II.y2 + 9y + 20 = 0
9). I.x =3√357911
II.y = √5041
10). I.5x + 7y = -43
II.9x – 17y = 41
Explanation With Answer Key:
1). I.15x2 – 25x – 21x + 35 = 0
or 5x(3x – 5) – 7(3x – 5) = 0
or (5x – 7) (3x – 5) = 0
x = 7/5, 5/3
II.4y2 – 8y – 7y + 14 = 0
or 4y(y – 2) – 7(y – 2) = 0
or (4y – 7) (y – 2) = 0
y = 2, 7/4
Answer is: c)
2).  I. x2+ 42 = 13x
or x2 – 13x + 42 = 0
or x2 – 7x – 6x + 42 = 0
or x(x – 7) – 6(x – 7) = 0
or (x – 6) (x – 7) = 0
x = 6, 7
II.y=4√1296
y = 6
x ≥ y
Answer is: b)
3).  I. 3x2– 23x + 40 = 0
or 3x2 – 15x – 8x + 40 = 0
or 3x(x – 5) – 8(x – 5) = 0
or (3x – 8) (x – 5) = 0
x = 5, 8/3
II.2y2 – 23y + 66 = 0
or 2y2 – 12y – 11y + 66 = 0
or 2y (y – 6) -11 (y – 6) = 0
or (y – 6)(2y – 11) = 0
y = 6, 11/ 2
x< y
Answer is: c)
4).  I. x2– x + 6x -6 = 0
or x(x – 1) + 6(x – 1) = 0
or (x – 1) (x + 6) = 0
x = 1, -6
II.2y2 – 6y – 5y + 15 = 0
or 2y(y – 3) – 5(y – 3) = 0
or (y – 3) (2y – 5) = 0
y = 3, 5/2
Answer is: c)
5).  I.x2+ x – 2 = 0
or x2 + 2x – x – 2 = 0
or x(x + 2) – 1(x + 2) = 0
or (x – 1) (x + 2) = 0
x = 1, – 2
II.y2 + 7y + 12 = 0
or y2 + 3y + 4y + 12 = 0
or y(y + 3) + 4(y + 3) = 0
or (y + 3) (y + 4) = 0
y = -3, -4
x> y
Answer is: a)
6). I.3x2 + 9x + 6x + 18 = 0
or 3x(x + 3) + 6(x + 3) = 0
or (x + 3)(3x + 6) = 0
x = -3, -2
II.2y2 + 6y + 9y+ 27 = 0
or 2y(y + 3) + 9(y + 3) = 0
or (2y + 9)(y + 3) = 0
y = -3, -9/2
x ≥ y
Answer is: b)
7). I.4x2 + 4x – x -1 = 0
or 4x(x+ 1)- 1(x + 1) = 0
or (4x – 1) (x + 1) = 0
 x = -1, 1/4
II.6y2 – 3y – 2y + 1 = 0
or 3y(2y – 1) – 1(2y – 1) = 0
or (3y – 1) (2y – 1) = 0
y = 1/2,1/3
x< y
Answer is: c)
8).  I. x2+ 11x + 30 = 0
or x(x + 5) + 6(x + 5) = 0
or (x + 5) (x + 6) = 0
x = -5, -6
II. y2 + 4y + 5y + 20 = 0
or y(y + 4) + 5(y + 4) = 0
or (y + 4) (y + 5) = 0
y = -4,-5
x ≤ y
Answer is: d)
9). I.x =3√357911 = x = 71
II.y = √5041= y = 71
x = y
Answer is: e)
10).Equation (l) ×9 & Equation (II) × 5
45x + 63y = -387
45x – 85y = 205
–        +         –
148y = -592
y = -4 and x = -3
 x> y
Answer is: a)
Do you feel that you are weak in English Section?
Here we are creating a pathway to win the English Section in upcoming IBPS PO 2017