Practice Quantitative Aptitude – Application Sums (Day19):
Dear Readers, Important Practice Quantitative Aptitude – Application Sums for IBPS Exams 2017 was given here with Solutions. Aspirants those who are preparing for the Bank Examination and other Competitive Examination can use this material.
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Question 1 of 101. The ratio of number of girls to boys in a farewell party was 2:3, but when 3 girls and 4 boys left, the ratio became 1:2. How many people were originally present at the party?Explanation:
Correct Answer is: d
Let the number of girls be 2a, then number of boys would be 3a.
As per information given in question, (2a – 3)/(3a – 4) = 1/2
On solving we get, a = 2
Therefore, originally there were 4 girls and 6 boys in the party.
Explanation:
Correct Answer is: d
Let the number of girls be 2a, then number of boys would be 3a.
As per information given in question, (2a – 3)/(3a – 4) = 1/2
On solving we get, a = 2
Therefore, originally there were 4 girls and 6 boys in the party.

Question 2 of 102. Sudip, Pratik and Yash are three cooks working in a restaurant. Yash can prepapre 10 rotis in an hour. The number of rotis prepared by Sudip in 6 hours is the same as the number of rotis prepared by Pratik in 8 hours. All three of them working together can prepare 228 rotis in 6 hours. One day Sudip. Pratik and Yash worked for 5, 6 and 8 hours respectively. What is the total number of rotis prepared by them that day?Explanation:
Correct Answer is: d
Suppose Sudip and Pratik prepare S and P number of rotis in an hour respectively.
6S = 8P
=> P = 3S/4
Rotis prepared by all three of them in 1 hour = 228/6 = 38 of which 10 are prepared by Yash
Substituting the above relation,
S + 3S/4 + 10 = 38
=> 7S/4 = 28
Or S = 16
Hence P = 12
Total number of roties prepared in the given case = 16×5 + 12×6 + 10×8 = 232
Explanation:
Correct Answer is: d
Suppose Sudip and Pratik prepare S and P number of rotis in an hour respectively.
6S = 8P
=> P = 3S/4
Rotis prepared by all three of them in 1 hour = 228/6 = 38 of which 10 are prepared by Yash
Substituting the above relation,
S + 3S/4 + 10 = 38
=> 7S/4 = 28
Or S = 16
Hence P = 12
Total number of roties prepared in the given case = 16×5 + 12×6 + 10×8 = 232

Question 3 of 103. In an exam, Rakesh scored 52% marks and failed by 23 marks. In the same exam, Radhika secured 64% marks and scored 34 more than the passing marks. What is the score of Mohan in the same exam who secured 82% marks?Explanation:
Correct Answer is: e
Let the maximum marks be M
Passing marks = 0.52M + 23 = 0.64M – 34
=>0.12M=57
=> M = 475
Explanation:
Correct Answer is: e
Let the maximum marks be M
Passing marks = 0.52M + 23 = 0.64M – 34
=>0.12M=57
=> M = 475

Question 4 of 104. Wasim mixed two varieties of rice costing Rs 26/kg and Rs 35/kg in the ratio 7:11. He sold onethird of them at Rs 33/kg and the rest at Rs 34.5/kg. What is his gain %?Explanation:
Correct Answer is: b
Suppose he bought total 18 kg rice.
Total cost of rice = 26 x 7 + 35 x 11 = Rs 567
Now, he must have sold 6 kgs at 33/kg and the remaining 12kgs at Rs 34.5/kg
Total selling price = 33 x 6 + 34.5 x 12 = Rs 612
Profit % = (612567)/567 x 100 = 7.93%
Explanation:
Correct Answer is: b
Suppose he bought total 18 kg rice.
Total cost of rice = 26 x 7 + 35 x 11 = Rs 567
Now, he must have sold 6 kgs at 33/kg and the remaining 12kgs at Rs 34.5/kg
Total selling price = 33 x 6 + 34.5 x 12 = Rs 612
Profit % = (612567)/567 x 100 = 7.93%

Question 5 of 105. David invested Rs 1000 in a bank that offers simple interest at the rate of 12% per annum. John invested same amount in another bank which offers compound interest at rate of 10%. After how many years for the first time will John get more interest than David?Explanation:
Correct Answer is: c
If Principal amount is Rs P. time is t years and interest rate is r% per annum then, simple interest (S.I)= (P X t X r)/100
And compound interest (C.I) = P(1 + r/100)^{t} – P
According to the question, P = 1000
Simple interest is at 12% but compound interest is at 10%.
Hence SI after t years = (1000 X t X 12)/100=120t
And C.I after t years = 1000[(1.1)^{t}– 1]
According to the question, 1000[(1.1)^{t} 1] > 120t
=> 8.3[(1 .1)^{t} 1] >t
(1.1)^{4} = 1.4641 and (1.1)^{5} = 1.61 Putting these values, we see that when t = 5, the condition is satisfied.
Hence, after 5 years John will get more interest than David.
Explanation:
Correct Answer is: c
If Principal amount is Rs P. time is t years and interest rate is r% per annum then, simple interest (S.I)= (P X t X r)/100
And compound interest (C.I) = P(1 + r/100)^{t} – P
According to the question, P = 1000
Simple interest is at 12% but compound interest is at 10%.
Hence SI after t years = (1000 X t X 12)/100=120t
And C.I after t years = 1000[(1.1)^{t}– 1]
According to the question, 1000[(1.1)^{t} 1] > 120t
=> 8.3[(1 .1)^{t} 1] >t
(1.1)^{4} = 1.4641 and (1.1)^{5} = 1.61 Putting these values, we see that when t = 5, the condition is satisfied.
Hence, after 5 years John will get more interest than David.

Question 6 of 106. Alloy A contains copper and silver in the ratio 5:7 and Alloy B contains copper and silver in the ratio 7:9. If both the alloys are melted and mixed together in equal quantities, find the ratio of copper and silver in the new mixture.Explanation:
Correct Answer is: b
Part of copper in Alloy A = 5/12
Part of silver in Alloy A = 7/12
Part of copper in Alloy B = 7/16
Part of silver in Alloy B = 9/16
Ratio in third alloy = (5/12 + 7/16)/(7/12 + 9/16)
= 41:55
Explanation:
Correct Answer is: b
Part of copper in Alloy A = 5/12
Part of silver in Alloy A = 7/12
Part of copper in Alloy B = 7/16
Part of silver in Alloy B = 9/16
Ratio in third alloy = (5/12 + 7/16)/(7/12 + 9/16)
= 41:55

Question 7 of 107. Supraja is older than Paramitha by 16 years. 6 years ago, the ratio of their ages of Supraja and Paramitha is 18:10 respectively. What will be Disha's age 8 years hence, if Disha's present age is half of that Paramitha's present age?Explanation:
Correct Answer is: e
Let, Six years ago,
Age of Supraja = 18x years
Age of Paramitha = 10x years
According to the question, at present,
18x + 6 – 10x 6 = 16
8x = 16
x =2
Therefore, Paramitha’s age six years ago = 10x = 10*2 =20 years
Paramitha’s present age = 26 years
Disha’s present age = 1/2* 26 = 13 years
Thus, Disha’s age after 8 years = 13 +8 = 21 years
Explanation:
Correct Answer is: e
Let, Six years ago,
Age of Supraja = 18x years
Age of Paramitha = 10x years
According to the question, at present,
18x + 6 – 10x 6 = 16
8x = 16
x =2
Therefore, Paramitha’s age six years ago = 10x = 10*2 =20 years
Paramitha’s present age = 26 years
Disha’s present age = 1/2* 26 = 13 years
Thus, Disha’s age after 8 years = 13 +8 = 21 years

Question 8 of 108. Two candles having height in the ratio of 3:2 lighted at the same time. The first candle is consumed in 15 hours and second candle is consumed in 12 hours. Assuming that each candle burns at the constant rate after how much time, ratio of height of first candle to second candle becomes 4:5?Explanation:
Correct Answer is: e
Let the height of the candles be 3h and 2h cm respectively.
Rate of consumption of 1st candle = 3h/15 = h/5 cm/hr
Rate of consumption of 2nd candle = 2h/12 = h/6 cm/hr
Let’s assume after t hours their heights will be in the ratio of 4:5.
Hence, (3h(ht/5))/(2h(ht/6))= 4/5
=> (3(t/5))/(2(t/6)) = 4/5
=>5(3(t/5)) = 4(2(t/6))
=> 15 – t = 8 – 2t/3
=> 7 = t/3
=> t = 21
Since both the candles will be consumed by 15 hours and 12 hours hence this answer of 21 hours is not realistic.
Explanation:
Correct Answer is: e
Let the height of the candles be 3h and 2h cm respectively.
Rate of consumption of 1st candle = 3h/15 = h/5 cm/hr
Rate of consumption of 2nd candle = 2h/12 = h/6 cm/hr
Let’s assume after t hours their heights will be in the ratio of 4:5.
Hence, (3h(ht/5))/(2h(ht/6))= 4/5
=> (3(t/5))/(2(t/6)) = 4/5
=>5(3(t/5)) = 4(2(t/6))
=> 15 – t = 8 – 2t/3
=> 7 = t/3
=> t = 21
Since both the candles will be consumed by 15 hours and 12 hours hence this answer of 21 hours is not realistic.

Question 9 of 109. After spending 70%, 85% and 60% the ratio of savings of A, B and C is 7 : 9 : 6. What is the ratio of salary of A, B and C?Explanation:
Correct Answer is: c
Let the salary of A, B and C be Rs 100a, Rs 100b and Rs 100c respectively.
According to the question; 30a : 15b : 40c = 7 : 9 : 6
=> a : b : c = 7/30:9/15:6/40
=>a:b:c=28:72: 18
=>a:b:c=14: 36:9
Explanation:
Correct Answer is: c
Let the salary of A, B and C be Rs 100a, Rs 100b and Rs 100c respectively.
According to the question; 30a : 15b : 40c = 7 : 9 : 6
=> a : b : c = 7/30:9/15:6/40
=>a:b:c=28:72: 18
=>a:b:c=14: 36:9

Question 10 of 1010. A, B, C and D enters into a partnership to start a business, It is known that A invests 1/3^{rd }of the total capital, B invests 1/5^{th} of the total capital, C invests 1/4^{th} of the total capital and D invests remaining amount. If D gets Rs 19500 as the total profit then what is the highest profit that anybody will get?Explanation:
Correct Answer is: a
Let the total amount invested by A, B, C and D is = Rs 60n
Amount invested by A = Rs 20n
Amount invested by B = Rs 12n
Amount invested by C = Rs 15n
Amount invested by D = Rs 13n
Therefore the ratio in which profit will be divided between A B, C and D respectively
= 20n : 12n : 15n : 13n
= 20 : 12 : 15 : 13
It is clear that highest profit will be obtained by A
Hence amount of profit obtained by A = Rs (19500/13 X 20) = Rs 30000
Explanation:
Correct Answer is: a
Let the total amount invested by A, B, C and D is = Rs 60n
Amount invested by A = Rs 20n
Amount invested by B = Rs 12n
Amount invested by C = Rs 15n
Amount invested by D = Rs 13n
Therefore the ratio in which profit will be divided between A B, C and D respectively
= 20n : 12n : 15n : 13n
= 20 : 12 : 15 : 13
It is clear that highest profit will be obtained by A
Hence amount of profit obtained by A = Rs (19500/13 X 20) = Rs 30000