Directions (Q.15): These questions are based on the following letter / number/ symbol arrangement. Study it carefully and answer the questions that follow
B # A R 5 8 E % M F 4 J 1 U @ H 2 © 9 T I 6 * W 3 P # K 7 $ Y S
1.Which of the following is the twelfth to the left of the twentieth from the left end of the above arrangement?
Answer: A
2.If all the numbers in the above arrangement are dropped, which of the following will be the eleventh from the right end?
11th from right end is ©
Answer is: e)
3. Which of the following is the fifteenth to the left of the seventh from the right end of the above arrangement?
Answer is: b)
4.How many such numbers are there in the above arrangement each of which is immediately preceded by a consonant and also immediately followed by a symbol?
Answer is: c)
5. Four of the following are alike in a certain way based on their positions in the above arrangement and so form a group. Which is the one that does not belong to that group?
1 + 2 = @ ; 1 – 2 = 4
© + 2 = T ; ©  2 = H
W + 2 = P ; W – 2 = 6
9 – 2 = 2 ; 9 + 2 = I
# + 2 = 7 ; #  2 = 3
So 9 2 I is not belong to that group.
Answer is: d)
Directions (Q.610): In a certain instruction system the different computation processes are written as follows:
(i) a $ b «c means c is subtracted from the product of a and b.
(ii) a @ b # c means a is multiplied by the sum of b and c.
(iii) a * b& c means c is subtracted from b and the resultant is added to a.
(iv) a © b % c means b is divided by c and the resultant is added to square of a.
In each of the following questions, a set of instruction sequence is given. You are required to find out the outcome which should come in place of the question mark (?) in each of the given sets of sequence.
6.m * 78& 56 = 50
m @ 7 # 13 = ?
(78  56) + m = 50 [Use instruction (iv)]
m = 50  22 = 28
Now, we have
28 @ 7 # 13
28 × (7 + 13) [Use instruction (i)]
= 560
? = 560
Answer is: a)
7. 17 $ 4 « 8 = t
7 © t % 15 = ?
(17 × 4)  8 [Use instruction (iii)]
= 60
Hence t = 60
Now, we have
7 © 60 % 15
(60 ÷ 15) + 72 [Use instruction (ii)]
= 53
? = 53
Answer is: b)
8. 5 © 49 % 7 = a
a * 87& 29 = ?
(49 ÷ 7) + 52 [Use instruction (ii)]
= 32
Hence a = 32
Now, we have
32 * 87& 29
(87  29) + 32 [Use instruction (iv)]
= 58 + 32 = 90
?= 90
Answer is: e)
9. 13 @ 4 # 3 = p
p $ 5 « 55 = ?
13 × (4 + 3) [Use instruction (i)]
= 91
Hence p = 91
Now, we have
91 $ 5 « 55
(91 × 5)  55 [Use instruction (iii)]
= 400
?= 400
Answer is: d)
10.b $ 15 « 18 = 42
b © 36 % 9 = ?
(b × 15)  18 = 42 [Use instruction (iii)]
(b × 15) = 42 + 18
b = 4
Now, we have
4 © 36 % 9
(36 ÷9) +16 [Use instruction (ii)]
= 20
? = 20
Answer is: c
English Learning Session :– (Day1)


English Learning Session :– (Day2)


English Learning Session :– (Day3)
