“20-20” Quantitative Aptitude | Crack Dena bank 2018 Day-101
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“20-20” Aptitude Questions | Crack Dena Bank 2018 Day-101
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Question 1 of 20
1. Question
Directions (Q. 1 – 5) Read the following information carefully and answer the following and answer the following questions:
There are two companies, company A and B. Both companies produce four different types of products namely, Keyboard, Mouse, Camera and Monitor. The total number of products produced by company A is 700. Company B produces 30% more products than company A. Out of total production by company A, 20% is keyboard. One fourth of total production by company A is Monitor. 23% of the total production of company A is Mouse. Remaining products produced are cameras. The total number of monitor produced by both the companies is 480. 40% of the total production of company B is Mouse. 10% of the total production of company B is cameras. The remaining number of products produced by company B is keyboards. 20% of the mouse produced by both the companies is defective while 40% of keyboard produced by company A are defective. Rest all the products produced by the both companies are good.
If the cost price of each keyboard produced company A is Rs. 450 and it sold the defective keyboard produced at a loss of 10% then find at what price should company A sell the remaining keyboard to make up the loss incurred?
Correct
Solutions: (1-5)
Number of products produced by company B= 700*130/100= 910
Company A:
Number of keyboards produced by company A= 700*20/100= 140
Number of monitors produced by company A= 700/4= 175
Number of mouse produced by company A= 23*700/100= 161
Number of cameras produced by company A= 700- (140+175+161) = 224
Company B:
Monitors= 480-175= 305
Mouse= 40*910/100= 364
Camera= 10*910/100= 91
Keyboard= 910-(305+364+91) = 150
Defective mouse produced by both the companies= 20*525/100= 105
Defective keyboard produced by company A= 140*40/100= 56
Answer b
Total cost of keyboard produced by company A= 450*140= Rs. 63000
Cost price of 56 keyboard= 56*450= Rs 25200
Loss incurred by selling defective keyboard= (450*10/100)*56= Rs 45*56= Rs. 2520
Cost price of remaining keyboard= 63000-25200= Rs. 37800
Selling price of remaining keyboard should be= 37800 + 2520= Rs. 40320
Incorrect
Solutions: (1-5)
Number of products produced by company B= 700*130/100= 910
Company A:
Number of keyboards produced by company A= 700*20/100= 140
Number of monitors produced by company A= 700/4= 175
Number of mouse produced by company A= 23*700/100= 161
Number of cameras produced by company A= 700- (140+175+161) = 224
Company B:
Monitors= 480-175= 305
Mouse= 40*910/100= 364
Camera= 10*910/100= 91
Keyboard= 910-(305+364+91) = 150
Defective mouse produced by both the companies= 20*525/100= 105
Defective keyboard produced by company A= 140*40/100= 56
Answer b
Total cost of keyboard produced by company A= 450*140= Rs. 63000
Cost price of 56 keyboard= 56*450= Rs 25200
Loss incurred by selling defective keyboard= (450*10/100)*56= Rs 45*56= Rs. 2520
Cost price of remaining keyboard= 63000-25200= Rs. 37800
Selling price of remaining keyboard should be= 37800 + 2520= Rs. 40320
Question 2 of 20
2. Question
Directions (Q. 1 – 5) Read the following information carefully and answer the following and answer the following questions:
There are two companies, company A and B. Both companies produce four different types of products namely, Keyboard, Mouse, Camera and Monitor. The total number of products produced by company A is 700. Company B produces 30% more products than company A. Out of total production by company A, 20% is keyboard. One fourth of total production by company A is Monitor. 23% of the total production of company A is Mouse. Remaining products produced are cameras. The total number of monitor produced by both the companies is 480. 40% of the total production of company B is Mouse. 10% of the total production of company B is cameras. The remaining number of products produced by company B is keyboards. 20% of the mouse produced by both the companies is defective while 40% of keyboard produced by company A are defective. Rest all the products produced by the both companies are good.
Total number of keyboards produced by company A is approximately what percentage less than the total number of monitor produced by company B?
Correct
Answer c
Keyboard produced by company A= 140
Monitor produced by company B= 305
Difference in production= 305-140= 165
Required percentage= (165/305)*100 = 54%
Incorrect
Answer c
Keyboard produced by company A= 140
Monitor produced by company B= 305
Difference in production= 305-140= 165
Required percentage= (165/305)*100 = 54%
Question 3 of 20
3. Question
Directions (Q. 1 – 5) Read the following information carefully and answer the following and answer the following questions:
There are two companies, company A and B. Both companies produce four different types of products namely, Keyboard, Mouse, Camera and Monitor. The total number of products produced by company A is 700. Company B produces 30% more products than company A. Out of total production by company A, 20% is keyboard. One fourth of total production by company A is Monitor. 23% of the total production of company A is Mouse. Remaining products produced are cameras. The total number of monitor produced by both the companies is 480. 40% of the total production of company B is Mouse. 10% of the total production of company B is cameras. The remaining number of products produced by company B is keyboards. 20% of the mouse produced by both the companies is defective while 40% of keyboard produced by company A are defective. Rest all the products produced by the both companies are good.
If the cost of a mouse produced by company A is Rs. 240 while that of company B is Rs. 300 then find the difference between the revenue generated by both the companies if they sold their products at 20% profit?
Correct
Answer e
Revenue generated by company A by selling mouse
= 240*161*120/100
=Rs. 46368
Revenue generated by company B by selling mouse
= 300*364*120/100
= Rs. 131040
Required difference= 131040 – 46368= Rs. 84672
Incorrect
Answer e
Revenue generated by company A by selling mouse
= 240*161*120/100
=Rs. 46368
Revenue generated by company B by selling mouse
= 300*364*120/100
= Rs. 131040
Required difference= 131040 – 46368= Rs. 84672
Question 4 of 20
4. Question
Directions (Q. 1 – 5) Read the following information carefully and answer the following and answer the following questions:
There are two companies, company A and B. Both companies produce four different types of products namely, Keyboard, Mouse, Camera and Monitor. The total number of products produced by company A is 700. Company B produces 30% more products than company A. Out of total production by company A, 20% is keyboard. One fourth of total production by company A is Monitor. 23% of the total production of company A is Mouse. Remaining products produced are cameras. The total number of monitor produced by both the companies is 480. 40% of the total production of company B is Mouse. 10% of the total production of company B is cameras. The remaining number of products produced by company B is keyboards. 20% of the mouse produced by both the companies is defective while 40% of keyboard produced by company A are defective. Rest all the products produced by the both companies are good.
Out of the defective mouse produced by both the companies, 20% is of company A, then find the number of defective mouse produced by company B?
Correct
Answer b
Total defective mouse produced= 105
Defective mouse produced by company B= 105*(80/100) = 84
Incorrect
Answer b
Total defective mouse produced= 105
Defective mouse produced by company B= 105*(80/100) = 84
Question 5 of 20
5. Question
Directions (Q. 1 – 5) Read the following information carefully and answer the following and answer the following questions:
There are two companies, company A and B. Both companies produce four different types of products namely, Keyboard, Mouse, Camera and Monitor. The total number of products produced by company A is 700. Company B produces 30% more products than company A. Out of total production by company A, 20% is keyboard. One fourth of total production by company A is Monitor. 23% of the total production of company A is Mouse. Remaining products produced are cameras. The total number of monitor produced by both the companies is 480. 40% of the total production of company B is Mouse. 10% of the total production of company B is cameras. The remaining number of products produced by company B is keyboards. 20% of the mouse produced by both the companies is defective while 40% of keyboard produced by company A are defective. Rest all the products produced by the both companies are good.
If the company B marked up the price of keyboard by 20% and allowed 10% discount to its regular customer, then find the cost price of each keyboard, if company B earned a profit Rs. 2400 by selling the keyboards?
Correct
Answer a
Let the cost of keyboard produced by company B be x
Markup price= x*120/100 = 6x/5
Selling price= 6x/5 * 90/100 = 27x/25
Profit= 27x/25 – x = 2x/25
So,
2x/25= 2400
x= 2400*25/2= Rs. 30000
Total keyboard produced by company B = 150
Cost price of each keyboard = 30000/150= Rs. 200
Incorrect
Answer a
Let the cost of keyboard produced by company B be x
Markup price= x*120/100 = 6x/5
Selling price= 6x/5 * 90/100 = 27x/25
Profit= 27x/25 – x = 2x/25
So,
2x/25= 2400
x= 2400*25/2= Rs. 30000
Total keyboard produced by company B = 150
Cost price of each keyboard = 30000/150= Rs. 200
Question 6 of 20
6. Question
Directions (Q. 6 – 10): The following questions are accompanied by three statements I, II and III. You have to determine which statement is/are sufficient to answer the questions. Give answer as:-
What is the speed of the train ‘A’?
Train A crosses 120meter long train B running in opposite direction in 15 seconds.
Speed of train B is 72 km/hr.
Length of train A is thrice that of train B.
Correct
Answer e
By using all the statement together
Speed of train B in m/s= 72*5/18= 20m/s
15= (120+ 360)/(20+ x)
= 300+ 15x= 480
= x= 480-300/15
= x= 12 m/s
Speed of train A in km/hr = 12*18/5= 43.2 km/hr
Incorrect
Answer e
By using all the statement together
Speed of train B in m/s= 72*5/18= 20m/s
15= (120+ 360)/(20+ x)
= 300+ 15x= 480
= x= 480-300/15
= x= 12 m/s
Speed of train A in km/hr = 12*18/5= 43.2 km/hr
Question 7 of 20
7. Question
Directions (Q. 6 – 10): The following questions are accompanied by three statements I, II and III. You have to determine which statement is/are sufficient to answer the questions. Give answer as:-
A person travels by car from place M to N and from N to M. How long will it take to travel from M to N by train if the speed of the train is 30% more than the speed of the car?
It takes 13 hours in travelling from M to N by car.
The distance between the two places is 650km.
If he travels by bus he takes 6 hours more.
Correct
Answer a
From statement I:
Speed of the train = 130/100 * speed of the car
Train/Car = 13/10
Time ratio of train to car = 10: 13
Required time = 13/13*10 = 10 hours
Incorrect
Answer a
From statement I:
Speed of the train = 130/100 * speed of the car
Train/Car = 13/10
Time ratio of train to car = 10: 13
Required time = 13/13*10 = 10 hours
Question 8 of 20
8. Question
Directions (Q. 6 – 10): The following questions are accompanied by three statements I, II and III. You have to determine which statement is/are sufficient to answer the questions. Give answer as:-
What is the ratio of boys and girls in the school?
There are 900 students in the school.
The number of boys in the school is 20% more than that of girls.
The number of girls in the school is 100 less than that of boys.
Correct
Answer c
From II:
No of girls be x and boys 120/100*x
Boys: girls = 120: 100 = 6:5
From I and III:
Total = 900
Boys + Girls = 900
Boys + Boys – 100= 900
2 Boys = 1000
=>Boys = 500
Girls = 400
Ratio = 500: 400 = 5:4
The answer can be determined by using statement I and III together or II alone is sufficient to answer the given question
Incorrect
Answer c
From II:
No of girls be x and boys 120/100*x
Boys: girls = 120: 100 = 6:5
From I and III:
Total = 900
Boys + Girls = 900
Boys + Boys – 100= 900
2 Boys = 1000
=>Boys = 500
Girls = 400
Ratio = 500: 400 = 5:4
The answer can be determined by using statement I and III together or II alone is sufficient to answer the given question
Question 9 of 20
9. Question
Directions (Q. 6 – 10): The following questions are accompanied by three statements I, II and III. You have to determine which statement is/are sufficient to answer the questions. Give answer as:-
How long will it take for A, B and C to complete the work together?
A and B complete a work in 10 days
B and C together complete the same piece of work in 15 days.
A and C together complete the same piece of work in 20 days.
Correct
Answer e
From statement I, II, III
Total units of work= 120
A+ B one day work= 12 units
B+C one day work= 8 units
A + C one day work= 6 units
2(A+B+C) = 26 units
A+B+C= 13 units
Time required by A, B and C= 120/13 days
Incorrect
Answer e
From statement I, II, III
Total units of work= 120
A+ B one day work= 12 units
B+C one day work= 8 units
A + C one day work= 6 units
2(A+B+C) = 26 units
A+B+C= 13 units
Time required by A, B and C= 120/13 days
Question 10 of 20
10. Question
Directions (Q. 6 – 10): The following questions are accompanied by three statements I, II and III. You have to determine which statement is/are sufficient to answer the questions. Give answer as:-
A shopkeeper purchased an article for Rs 300 and incurred Rs 40 for transportation. Find the profit earned by the shopkeeper.
The shopkeeper marked up price of the article by 30%.
15% discount was allowed by the shopkeeper.
He marked the price of the article at Rs 442.
Correct
Answer e
From statement I and II
Marked up price of the article= 340*130/100= Rs 442
Selling price = 442*85/100= Rs 375.70
Profit= 375.70- 340= Rs 35.70
From II and III
The profit can be easily determined in the same way.
Incorrect
Answer e
From statement I and II
Marked up price of the article= 340*130/100= Rs 442
Selling price = 442*85/100= Rs 375.70
Profit= 375.70- 340= Rs 35.70
From II and III
The profit can be easily determined in the same way.
Question 11 of 20
11. Question
A man rows to a place 60 km distance and come back in 8 hours. He finds that he can row 10 km with the stream in the same time as 6 km against the stream. The rate of the stream is?
Correct
Answer c
Speed of downstream = 10/x
Speed of upstream = 6/x
60/(10/x) + 60/(6/x) = 8
X = 1/2
So, Speed of downstream = 20 km/hr, Speed of upstream = 12 km/hr
Rate of the stream = ½(Speed of downstream – Speed of upstream)
= > ½*(20 – 12)
= 1/2 * 8 = 4 km/hr
Incorrect
Answer c
Speed of downstream = 10/x
Speed of upstream = 6/x
60/(10/x) + 60/(6/x) = 8
X = 1/2
So, Speed of downstream = 20 km/hr, Speed of upstream = 12 km/hr
Rate of the stream = ½(Speed of downstream – Speed of upstream)
= > ½*(20 – 12)
= 1/2 * 8 = 4 km/hr
Question 12 of 20
12. Question
From a pack of 52 cards, one card is drawn at random. What is the probability that the card drawn is a five or a Spade?
Correct
Answer a
Here n(S) = 52
There are 13 Spade cards (including one five) and also 3 more fives are there.
Let E = event of getting a five or a Spade
Then n(E) = 13+4 -1 = 13+3
n(E) = 16
Therefore P(E) = n(E) / n(S)
=16 / 52
P(E) = 4/13
Incorrect
Answer a
Here n(S) = 52
There are 13 Spade cards (including one five) and also 3 more fives are there.
Let E = event of getting a five or a Spade
Then n(E) = 13+4 -1 = 13+3
n(E) = 16
Therefore P(E) = n(E) / n(S)
=16 / 52
P(E) = 4/13
Question 13 of 20
13. Question
P, Q and R started a business by investing in the ratio of 5: 4: 9. After 4 months, P invested 10% of his initial investment more and R withdraws Rs. 2000. Find the share of Q, if the total profit at the end of the year is Rs. 63200?
Raji got 32 % of marks in the examination and failed by 14 marks. Another student Preetha got 45 % of marks and got 12 more than the passing marks. Find the passing percentage in the examination?
Correct
Answer b
Let the total marks be x,
Here passing mark is equal. So,
32 % of total marks + 14 = 45 % of total marks – 12
14 + 12 = (45 % – 32 %) of total marks
26 = 13 % of total marks
(13/100)*x = 26
X = 26*(100/13) = 200
Pass mark = (32/100)*200 + 14 = 64 + 14 = 78
Pass % = (78/200)*100 = 39 %
Incorrect
Answer b
Let the total marks be x,
Here passing mark is equal. So,
32 % of total marks + 14 = 45 % of total marks – 12
14 + 12 = (45 % – 32 %) of total marks
26 = 13 % of total marks
(13/100)*x = 26
X = 26*(100/13) = 200
Pass mark = (32/100)*200 + 14 = 64 + 14 = 78
Pass % = (78/200)*100 = 39 %
Question 15 of 20
15. Question
6 years hence, the ratio of age of P and Q is 5: 7. The difference between their ages is 10 years. The average present age of P, Q and R is 26 years. Find the ratio of the age of P, after 11 years to that of the age of R, 5 years ago?
Correct
Answer a
6 years hence, the ratio of age of P and Q = 5: 7(5x, 7x)
The difference between their age = 10 years
7x – 5x = 10
2x = 10
X = 5
The present age of P and Q = 5x – 6, 7x – 6 = 19, 29
The average present age of P, Q and R = 26 years
Total present age of P, Q and R = 26*3 = 78
P + Q + R = 78
19 + 29 + R = 78
R = 78 – 48 = 30
Required ratio = 30: 25 = 6: 5
Incorrect
Answer a
6 years hence, the ratio of age of P and Q = 5: 7(5x, 7x)
The difference between their age = 10 years
7x – 5x = 10
2x = 10
X = 5
The present age of P and Q = 5x – 6, 7x – 6 = 19, 29
The average present age of P, Q and R = 26 years
Total present age of P, Q and R = 26*3 = 78
P + Q + R = 78
19 + 29 + R = 78
R = 78 – 48 = 30
Required ratio = 30: 25 = 6: 5
Question 16 of 20
16. Question
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer as,
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
5x2 – 22x -15 = 0
4y2 – 24y – 13 = 0
Correct
Answer e
I. 5x2 – 22x -15 = 0
5x2 – 25x + 3x -15 = 0
5x(x – 5) + 3(x – 5) = 0
(5x + 3) (x – 5) = 0
X = -3/5, 5 = -0.6, 5
II. 4y2 – 24y – 13 = 0
4y2 + 2y – 26y – 13 = 0
2y (2y + 1) – 13(2y + 1) = 0
(2y – 13) (2y + 1) = 0
Y = 13/2, -1/2 = 6.5, -0.5
Can’t be determined
Incorrect
Answer e
I. 5x2 – 22x -15 = 0
5x2 – 25x + 3x -15 = 0
5x(x – 5) + 3(x – 5) = 0
(5x + 3) (x – 5) = 0
X = -3/5, 5 = -0.6, 5
II. 4y2 – 24y – 13 = 0
4y2 + 2y – 26y – 13 = 0
2y (2y + 1) – 13(2y + 1) = 0
(2y – 13) (2y + 1) = 0
Y = 13/2, -1/2 = 6.5, -0.5
Can’t be determined
Question 17 of 20
17. Question
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer as,
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
5x + 3y = -35
7x + 2y = -38
Correct
Answer a
5x + 3y = -35 –> (1)
7x + 2y = -38 –> (2)
By solving the equation (1) and (2),
x = – 4, y = -5
x > y
Incorrect
Answer a
5x + 3y = -35 –> (1)
7x + 2y = -38 –> (2)
By solving the equation (1) and (2),
x = – 4, y = -5
x > y
Question 18 of 20
18. Question
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer as,
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
2x2 + 19x + 45 = 0
y2 – 17y + 72 = 0
Correct
Answer c
I. 2x2 + 19x + 45 = 0
2x2 + 10x+ 9x + 45 = 0
2x(x + 5) + 9 (x + 5) = 0
(2x + 9) (x + 5) = 0
X = -9/2, -5 = -4.5, -5
II. y2 – 17y + 72 = 0
y2 – 8y – 9y + 72 = 0
y(y – 8) – 9(y – 9) = 0
(y – 8) (y – 9) = 0
Y = 8, 9
X < y
Incorrect
Answer c
I. 2x2 + 19x + 45 = 0
2x2 + 10x+ 9x + 45 = 0
2x(x + 5) + 9 (x + 5) = 0
(2x + 9) (x + 5) = 0
X = -9/2, -5 = -4.5, -5
II. y2 – 17y + 72 = 0
y2 – 8y – 9y + 72 = 0
y(y – 8) – 9(y – 9) = 0
(y – 8) (y – 9) = 0
Y = 8, 9
X < y
Question 19 of 20
19. Question
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer as,
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
x = √(20443- 4567)
y = ∛592704
Correct
Answer a
I. x = √(20443- 4567)
X = √15876 = 126
II. y = ∛592704
Y = 84
X > y
Incorrect
Answer a
I. x = √(20443- 4567)
X = √15876 = 126
II. y = ∛592704
Y = 84
X > y
Question 20 of 20
20. Question
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer as,
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
Click “Start Quiz” to attend these Questions and view Solutions
Directions (Q. 1 – 5) Read the following information carefully and answer the following and answer the following questions:
There are two companies, company A and B. Both companies produce four different types of products namely, Keyboard, Mouse, Camera and Monitor. The total number of products produced by company A is 700. Company B produces 30% more products than company A. Out of total production by company A, 20% is keyboard. One fourth of total production by company A is Monitor. 23% of the total production of company A is Mouse. Remaining products produced are cameras. The total number of monitor produced by both the companies is 480. 40% of the total production of company B is Mouse. 10% of the total production of company B is cameras. The remaining number of products produced by company B is keyboards. 20% of the mouse produced by both the companies is defective while 40% of keyboard produced by company A are defective. Rest all the products produced by the both companies are good.
If the cost price of each keyboard produced company A is Rs. 450 and it sold the defective keyboard produced at a loss of 10% then find at what price should company A sell the remaining keyboard to make up the loss incurred?
a) Rs. 20150
b) Rs. 40320
c) Rs. 55123
d) Rs. 30120
e) Rs. 60560
Total number of keyboards produced by company A is approximately what percentage less than the total number of monitor produced by company B?
a) 42 %
b) 65 %
c) 54 %
d) 73 %
e) 38 %
If the cost of a mouse produced by company A is Rs. 240 while that of company B is Rs. 300 then find the difference between the revenue generated by both the companies if they sold their products at 20% profit?
a) 20400
b) 40150
c) 55123
d) 30560
e) 84672
Out of the defective mouse produced by both the companies, 20% is of company A, then find the number of defective mouse produced by company B?
76
84
62
68
70
If the company B marked up the price of keyboard by 20% and allowed 10% discount to its regular customer, then find the cost price of each keyboard, if company B earned a profit Rs. 2400 by selling the keyboards?
a) 200
b) 400
c) 550
d) 300
e) 600
Directions (Q. 6 – 10): The following questions are accompanied by three statements I, II and III. You have to determine which statement is/are sufficient to answer the questions. Give answer as:-
What is the speed of the train ‘A’?
Train A crosses 120meter long train B running in opposite direction in 15 seconds.
Speed of train B is 72 km/hr.
Length of train A is thrice that of train B.
a) If statement I and III are necessary
b) If III and either I or II are necessary
c) If I and either II or III are necessary
d) If any two of I, II and III are necessary
e) If all statements together are necessary
A person travels by car from place M to N and from N to M. How long will it take to travel from M to N by train if the speed of the train is 30% more than the speed of the car?
It takes 13 hours in travelling from M to N by car.
The distance between the two places is 650km.
If he travels by bus he takes 6 hours more.
a) If I alone is sufficient
b) If III and either I or II are sufficient
c) If I and either II or III are sufficient
d) If any two of I, II and III are sufficient
e) If all statements together are necessary
What is the ratio of boys and girls in the school?
There are 900 students in the school.
The number of boys in the school is 20% more than that of girls.
The number of girls in the school is 100 less than that of boys.
a) If either I or II is sufficient
b) If III and either I or II are sufficient
c) If I and III together or II alone is sufficient
d) If any two of I, II and III are sufficient.
e) If all statements together are necessary
How long will it take for A, B and C to complete the work together?
A and B complete a work in 10 days
B and C together complete the same piece of work in 15 days.
A and C together complete the same piece of work in 20 days.
a) If either I or II is sufficient
b) If III and either I or II are sufficient
c) If I and either II or III are sufficient
d) If any two of I, II and III are sufficient.
e) If all statements together are necessary
A shopkeeper purchased an article for Rs 300 and incurred Rs 40 for transportation. Find the profit earned by the shopkeeper.
The shopkeeper marked up price of the article by 30%.
15% discount was allowed by the shopkeeper.
He marked the price of the article at Rs 442.
a) If either I or II is sufficient
b) If III and either I or II are sufficient
c) If I and either II or III are sufficient
d) If any two of I, II and III are sufficient.
e) None of these
A man rows to a place 60 km distance and come back in 8 hours. He finds that he can row 10 km with the stream in the same time as 6 km against the stream. The rate of the stream is?
6 km/hr
8 km/hr
4 km/hr
5 km/hr
None of these
From a pack of 52 cards, one card is drawn at random. What is the probability that the card drawn is a five or a Spade?
4/13
¾
6/13
21/52
None of these
P, Q and R started a business by investing in the ratio of 5: 4: 9. After 4 months, P invested 10% of his initial investment more and R withdraws Rs. 2000. Find the share of Q, if the total profit at the end of the year is Rs. 63200?
Rs. 23460
Rs. 25320
Rs. 19710
Rs. 17280
None of these
Raji got 32 % of marks in the examination and failed by 14 marks. Another student Preetha got 45 % of marks and got 12 more than the passing marks. Find the passing percentage in the examination?
41 %
39 %
34 %
36 %
None of these
6 years hence, the ratio of age of P and Q is 5: 7. The difference between their ages is 10 years. The average present age of P, Q and R is 26 years. Find the ratio of the age of P, after 11 years to that of the age of R, 5 years ago?
6 : 5
3 : 4
5 : 3
8 : 7
None of these
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer as,
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
I. 5x2 – 22x -15 = 0
II. 4y2 – 24y – 13 = 0
I. 5x + 3y = -35
II. 7x + 2y = -38
I. 2x2 + 19x + 45 = 0
II. y2 – 17y + 72 = 0
I. x = √(20443- 4567)
II. y = ∛592704
I. x2 – 9x – 252 = 0
II. y2 – 6y – 187 = 0
Answers:
Solutions: (1-5)
Number of products produced by company B= 700*130/100= 910
Company A:
Number of keyboards produced by company A= 700*20/100= 140
Number of monitors produced by company A= 700/4= 175
Number of mouse produced by company A= 23*700/100= 161
Number of cameras produced by company A= 700- (140+175+161) = 224
Company B:
Monitors= 480-175= 305
Mouse= 40*910/100= 364
Camera= 10*910/100= 91
Keyboard= 910-(305+364+91) = 150
Defective mouse produced by both the companies= 20*525/100= 105
Defective keyboard produced by company A= 140*40/100= 56
1). Answer b
Total cost of keyboard produced by company A= 450*140= Rs. 63000
Cost price of 56 keyboard= 56*450= Rs 25200
Loss incurred by selling defective keyboard= (450*10/100)*56= Rs 45*56= Rs. 2520
Cost price of remaining keyboard= 63000-25200= Rs. 37800
Selling price of remaining keyboard should be= 37800 + 2520= Rs. 40320
2). Answer c
Keyboard produced by company A= 140
Monitor produced by company B= 305
Difference in production= 305-140= 165
Required percentage= (165/305)*100 = 54%
3). Answer e
Revenue generated by company A by selling mouse
= 240*161*120/100
=Rs. 46368
Revenue generated by company B by selling mouse
= 300*364*120/100
= Rs. 131040
Required difference= 131040 – 46368= Rs. 84672
4). Answer b
Total defective mouse produced= 105
Defective mouse produced by company B= 105*(80/100) = 84
5). Answer a
Let the cost of keyboard produced by company B be x
Markup price= x*120/100 = 6x/5
Selling price= 6x/5 * 90/100 = 27x/25
Profit= 27x/25 – x = 2x/25
So,
2x/25= 2400
x= 2400*25/2= Rs. 30000
Total keyboard produced by company B = 150
Cost price of each keyboard = 30000/150= Rs. 200
6. Answer e
By using all the statement together
Speed of train B in m/s= 72*5/18= 20m/s
15= (120+ 360)/(20+ x)
= 300+ 15x= 480
= x= 480-300/15
= x= 12 m/s
Speed of train A in km/hr = 12*18/5= 43.2 km/hr
7). Answer a
From statement I:
Speed of the train = 130/100 * speed of the car
Train/Car = 13/10
Time ratio of train to car = 10: 13
Required time = 13/13*10 = 10 hours
8). Answer c
From II:
No of girls be x and boys 120/100*x
Boys: girls = 120: 100 = 6:5
From I and III:
Total = 900
Boys + Girls = 900
Boys + Boys – 100= 900
2 Boys = 1000
=>Boys = 500
Girls = 400
Ratio = 500: 400 = 5:4
The answer can be determined by using statement I and III together or II alone is sufficient to answer the given question
9). Answer e
From statement I, II, III
Total units of work= 120
A+ B one day work= 12 units
B+C one day work= 8 units
A + C one day work= 6 units
2(A+B+C) = 26 units
A+B+C= 13 units
Time required by A, B and C= 120/13 days
10). Answer e
From statement I and II
Marked up price of the article= 340*130/100= Rs 442
Selling price = 442*85/100= Rs 375.70
Profit= 375.70- 340= Rs 35.70
From II and III
The profit can be easily determined in the same way.
11). Answer c
Speed of downstream = 10/x
Speed of upstream = 6/x
60/(10/x) + 60/(6/x) = 8
X = 1/2
So, Speed of downstream = 20 km/hr, Speed of upstream = 12 km/hr
Rate of the stream = ½(Speed of downstream – Speed of upstream)
= > ½*(20 – 12)
= 1/2 * 8 = 4 km/hr
12). Answer a
Here n(S) = 52
There are 13 Spade cards (including one five) and also 3 more fives are there.