# “20-20” Quantitative Aptitude | Crack SBI Clerk Prelims 2018 Day-109

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“20-20” Aptitude Questions | Crack SBI Clerk Prelims 2018 Day-109

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Directions (Q. 1 – 5): What value should come in place of question mark (?) in the following questions?

1. 3 5/28 % of 12768 + (4/9) of 34785 + 272 = 4 ×?
1. 3218.45
2. 4148.71
3. 3568.23
4. 4858.17
5. None of these
1. 12 7/12 + 8 5/6 – 5 ½ – 7 ¼ =? + 3 ¾
1. 5 6/7
2. 8 3/5
3. 4 11/12
4. 6 7/9
5. None of these
1. (5/17) of (408/75) of (124/248) of 32736 = 30 % of ?
1. 87296
2. 75428
3. 62374
4. 52742
5. None of these
1. (1256 ÷ 4) × (138 ÷ 3) = 810 ÷ 3 +?
1. 27895
2. 35621
3. 22782
4. 14174
5. None of these
1. 3796416 – √50176 + 75 % of 1500 =?
1. 2178
2. 1456
3. 1057
4. 2453
5. None of these

Directions (Q. 6 – 10): What value should come in place of question mark (?) in the following number series?

1. 218, 221, 230, 257, ?
1. 345
2. 338
3. 312
4. 324
5. 373
1. 54, 109, 336, 1369, ?
1. 4578
2. 6894
3. 5272
4. 3566
5. 4912
1. 327, 331, 367, 415, 565, 745, ?
1. 956
2. 1045
3. 878
4. 1137
5. 1342
1. 12, 60, 254, 492, ?
1. 510
2. 572
3. 686
4. 614
5. 648
1. 97, 253, 481, 793, 1201, ?
1. 1453
2. 1542
3. 1717
4. 1684
5. 1978

1. The perimeter of a rectangle is 64 m and the difference between the length and the breadth of the rectangle is 14 m then find the area of the rectangle?
1. 315 Sq m
2. 278 Sq m
3. 256 Sq m
4. 207 Sq m
5. None of these
1. The average cost of three mobiles A, B and C of a certain company is Rs. 48000. The average cost decrease by 10 % when mobile D of the same company is included, find the cost price of mobile D?
1. Rs. 26700
2. Rs. 28800
3. Rs. 24300
4. Rs. 30600
5. None of these
1. A can do a piece of work in 25 days, B can do it in 20 days. They started the work together but A left 5 days before the completion of the work. The work has finished in?
1. 13 1/3 days
2. 15 3/7 days
3. 11 4/9 days
4. 9 3/8 days
5. None of these
1. Three years hence, the ratio of Karthi and Janvi will be 7:5. The age of Karthi two years hence is equal to two times of age of Janvi, 5 years ago. What is the present age of Karthi?
1. 24 years
2. 26 years
3. 32 years
4. 38 years
5. None of these
1. 250 m long train crosses a pole in 12 sec and the same train crosses a bridge in 15 sec. Find the length of the bridge?
1. 72.5 m
2. 65 m
3. 62.5 m
4. 150 m
5. None of these

Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:

Following table shows the total number of students studying in various departments in various colleges in the year 2016.

 Colleges A B C Streams Girls Boys Girls Boys Girls Boys CSE 125 140 110 115 85 95 ECE 130 115 90 75 100 110 EEE 75 60 85 95 70 100 MECH 90 85 95 125 115 105 IT 65 75 85 70 90 65

1. Total number of girls studying in the department of CSE, EEE and IT in the college A and C is approximately what percentage more/less than the total number of boys studying in the department of ECE, MECH in the college B and C?
1. 23 % more
2. 31 % less
3. 45 % more
4. 27 % less
5. 38 % more
1. Find the difference between the total number of boys studying in the college B to that of total number of girls studying in the college A of all the given departments?
1. 8
2. 12
3. 18
4. 5
5. None of these
1. Find the ratio of total number of students studying in the department of CSE and MECH to that of total number of students studying in the department of ECE and IT of all the given colleges?
1. 157 : 121
2. 257 : 214
3. 245 : 176
4. 132 : 107
5. None of these
1. Find the average number of students studying in the college B?
1. 178
2. 184
3. 189
4. 196
5. None of these
1. Total number of students studying in the department of EEE of all the given colleges together is approximately what percentage less than the total number of students studying in the department of ECE of all the given colleges together?
1. 22 %
2. 34 %
3. 16 %
4. 48 %
5. 54 %

(89/2800)*12768 + (4/9)*34785 + 729 = 4x

405.84 + 15460 + 729 = 4x

16594.84 = 4x

X = 16594.84/4 = 4148.71

12 7/12 + 8 5/6 – 5 ½ – 7 ¼ – 3 ¾ = x

X = (12 + 8 – 5 – 7 – 3) (7/12 + 5/6 – ½ – ¼ – ¾)

X = 5 [(7 + 10 – 6 – 3 – 9)/12]

X = 5 (-1/12) = (60 – 1)/12 = 59/12

X = 4 11/12

(5/17)*(408/75)*(124/248)*32736 = (30/100)*x

X = 654720*(4/30)

X = 87296

(1256/4)*(138/3) = (810/3) + x

314*46 = 270 + x

14444 – 270 = x

X = 14174

156 – 224 + (75/100)*1500 = x

X = 156 – 224 + 1125

X = 1057

Direction (6-10)

The difference is, 3, 32, 33, 34,..

The pattern is, *2+12, *3+32, *4+52, *5+72,..

The pattern is, +(23 – 22), +(33+ 32), +(43 – 42), +(53 + 52), +(63 – 62), +(73 + 72)..

The pattern is, ×6 -12, ×4 +14, ×2-16, ×1 +18

The pattern is, 72 × 2 – 1, 82 × 4 – 3, 92 × 6 – 5, 102 × 8 – 7, 112 × 10 – 9, 122 × 12 – 11,..

The perimeter of a rectangle = 64 m

2(l + b) = 64

l + b = 32–> (1)

l – b = 14–> (2)

By solving the equations (1) and (2),

2l = 46

l = 23 m

b = 9 m

The area of rectangle = lb = 23*9 = 207 m2

The average cost of three mobiles A, B and C = 48000

Total cost of three mobiles A, B and C = 48000*3 = 144000

Average cost of mobiles A, B, C and D = 48000*(90/100) = 43200

Total cost of Four mobiles A, B, C and D = 43200*4 = 172800

The cost price of mobile D = 172800 – 144000 = Rs. 28800

(x – 5)/25 + x/20 = 1

(4x – 20 + 5x)/100 = 1

9x – 20 = 100

9x = 120

X = 120/9 = 13 3/9 = 13 1/3 days

Three years hence, the ratio of Karthi and Janvi = 7:5(7x, 5x)

Present age of Karthi and Janvi = 7x – 3, 5x – 3

According to the question,

7x – 1 = 2*(5x – 8)

7x – 1 = 10x – 16

3x = 15

X = 5

The present age of Karthi = 7x – 3 = 35 – 3 = 32 years

According to the question,

Speed equal, so,

250/12 = (250+B.L)/15 (Here B.L is Bridge Length)

1250 = 1000 +4 B.L

4B.L = 1250 – 1000

B.L = 250/4 = 125/2= 62.5 m

Direction (16-20)

Total number of girls studying in the department of CSE, EEE and IT in the college A and C

=> 125 + 75 + 65 + 85 + 70 + 90

= > 510

Total number of boys studying in the department of ECE, MECH in the college B and C

= > 75 + 125 + 110 + 105

= > 415

Required % = [(510 – 415)/415]*100 = 22.89 % = 23 % more

The total number of boys studying in the college B of all the given departments

= > 115 + 75 + 95 + 125 + 70

= > 480

The total number of girls studying in the college A of all the given departments

= > 125 + 130 + 75 + 90 + 65

= > 485

Required difference = 485 – 480 = 5

The total number of students studying in the department of CSE and MECH

= > 125 + 140 + 110 + 115 + 85 + 95 + 90 + 85 + 95 + 125 + 115 + 105

= > 1285

The total number of students studying in the department of ECE and IT

= > 130 + 115 + 90 + 75 + 100 + 110 + 65 + 75 + 85 + 70 + 90 + 65

= > 1070

Required ratio = 1285: 1070 = 257: 214

The total number of students studying in the college B

= > 110 + 115 + 90 + 75 + 85 + 95 + 95 + 125 + 85 + 70

= > 945

Required average = 945/5 = 189

Total number of students studying in the department of EEE of all the given colleges together

= > 75 + 60 + 85 + 95 + 70 + 100

= > 485

Total number of students studying in the department of ECE of all the given colleges together

= > 130 + 115 + 90 + 75 + 100 + 110

= > 620

Required % = [(620 – 485)/620]*100 =21.77 % = 22 % less

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 Topic Daily Publishing Time Daily News Papers & Editorials 8.00 AM Current Affairs Quiz 9.00 AM Quantitative Aptitude “20-20” 11.00 AM Vocabulary (Based on The Hindu) 12.00 PM General Awareness “20-20” 1.00 PM English Language “20-20” 2.00 PM Reasoning Puzzles & Seating 4.00 PM Daily Current Affairs Updates 5.00 PM Data Interpretation / Application Sums (Topic Wise) 6.00 PM Reasoning Ability “20-20” 7.00 PM English Language (New Pattern Questions) 8.00 PM