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Directions (Q. 1 – 5): What approximate value should come in the place of question mark (?) in the following questions?
27 % of 804 + (1749 ÷ 14.2) × (7.99)^{2} =? – (3/7) of 2729
Correct
Answer: b)
(27/100)*800 + (1750/14)*64 = x – (3/7)* 2730
216 + 8000 = x – 1170
216 + 8000 + 1170 = x
X = 9386 = 9390
Incorrect
Answer: b)
(27/100)*800 + (1750/14)*64 = x – (3/7)* 2730
216 + 8000 = x – 1170
216 + 8000 + 1170 = x
X = 9386 = 9390
Question 6 of 20
6. Question
Directions (Q. 6 – 10) In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
If x > y
If x ≥ y
If x < y
If x ≤ y
If x = y or the relation cannot be established
6x^{2} + 37x + 35 = 0
4y^{2} + 5y + 1 = 0
Correct
Answer: c)
I. 6x^{2} + 37x + 35 = 0
6x^{2} + 30x + 7x + 35 = 0
6x(x + 5) + 7(x + 5) = 0
(6x + 7) (x + 5) = 0
X = -7/6, -5 = -1.166, -5
II. 4y^{2} + 5y + 1 = 0
4y^{2} + 4y + y + 1 = 0
4y(y + 1) + 1(y + 1) = 0
(4y + 1) (y + 1) = 0
Y = -1/4, -1 = -0.25, -1
X < y
Incorrect
Answer: c)
I. 6x^{2} + 37x + 35 = 0
6x^{2} + 30x + 7x + 35 = 0
6x(x + 5) + 7(x + 5) = 0
(6x + 7) (x + 5) = 0
X = -7/6, -5 = -1.166, -5
II. 4y^{2} + 5y + 1 = 0
4y^{2} + 4y + y + 1 = 0
4y(y + 1) + 1(y + 1) = 0
(4y + 1) (y + 1) = 0
Y = -1/4, -1 = -0.25, -1
X < y
Question 7 of 20
7. Question
Directions (Q. 6 – 10) In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
If x > y
If x ≥ y
If x < y
If x ≤ y
If x = y or the relation cannot be established
x^{2} + 14^{2} = 27^{2} – 49
y^{1/2} – 272 + 410 = 12^{2}
Correct
Answer: c)
I. x^{2} + 14^{2} = 27^{2} – 49
X^{2} = 729 – 49 – 196
X^{2} = 484
X = 22, -22
II. y^{1/2} – 272 + 410 = 12^{2}
Y^{1/2} = 144 + 272 – 410
Y^{1/2} = 6
Y = 36
X < y
Incorrect
Answer: c)
I. x^{2} + 14^{2} = 27^{2} – 49
X^{2} = 729 – 49 – 196
X^{2} = 484
X = 22, -22
II. y^{1/2} – 272 + 410 = 12^{2}
Y^{1/2} = 144 + 272 – 410
Y^{1/2} = 6
Y = 36
X < y
Question 8 of 20
8. Question
Directions (Q. 6 – 10) In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
If x > y
If x ≥ y
If x < y
If x ≤ y
If x = y or the relation cannot be established
√(x + 4) = √676 – √361
y^{3} – 32568 = 26751
Correct
Answer: a)
I. √(x + 4) = √676 – √361
√(x + 4) = 26 – 19
(x + 4) = 7^{2}
X = 49 – 4 = 45
II. y^{3} – 32568 = 26751
Y^{3} = 26751 + 32568
Y^{3} = 59319
Y = ∛59319 = 39
X > y
Incorrect
Answer: a)
I. √(x + 4) = √676 – √361
√(x + 4) = 26 – 19
(x + 4) = 7^{2}
X = 49 – 4 = 45
II. y^{3} – 32568 = 26751
Y^{3} = 26751 + 32568
Y^{3} = 59319
Y = ∛59319 = 39
X > y
Question 9 of 20
9. Question
Directions (Q. 6 – 10) In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
If x > y
If x ≥ y
If x < y
If x ≤ y
If x = y or the relation cannot be established
3x^{2} +26x + 56 = 0
5y^{2} + 29y + 42 = 0
Correct
Answer: c)
I. 3x^{2} +26x + 56 = 0
3x^{2} + 12x +14x + 56 = 0
3x(x + 4) + 14(x + 4) = 0
(3x + 14) (x + 4) = 0
X = -14/3, -4 = -4.66, -4
II. 5y^{2} + 29y + 42 = 0
5y^{2} + 15y + 14y + 42 = 0
5y(y + 3) +14(y + 3) = 0
(5y + 14) (y + 3) = 0
Y = -14/5, -3= -2.8, -3
X < y
Incorrect
Answer: c)
I. 3x^{2} +26x + 56 = 0
3x^{2} + 12x +14x + 56 = 0
3x(x + 4) + 14(x + 4) = 0
(3x + 14) (x + 4) = 0
X = -14/3, -4 = -4.66, -4
II. 5y^{2} + 29y + 42 = 0
5y^{2} + 15y + 14y + 42 = 0
5y(y + 3) +14(y + 3) = 0
(5y + 14) (y + 3) = 0
Y = -14/5, -3= -2.8, -3
X < y
Question 10 of 20
10. Question
Directions (Q. 6 – 10) In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
If x > y
If x ≥ y
If x < y
If x ≤ y
If x = y or the relation cannot be established
I. 2x^{2} + 9x – 45 = 0;
II. 4y^{2} + 19y + 22 = 0
Correct
Answer: e)
I. 2x^{2} + 9x – 45 = 0
2x^{2} – 6x + 15x – 45 = 0
2x(x -3) +15 (x – 3) = 0
(2x + 15) (x – 3) = 0
x = 3, -7.5
II. 4y^{2} + 19y + 22 = 0
4y^{2} + 8y + 11y + 22 = 0
4y (y + 2) + 11(y + 2) = 0
y = -2, -11/4
Can’t be determined
Incorrect
Answer: e)
I. 2x^{2} + 9x – 45 = 0
2x^{2} – 6x + 15x – 45 = 0
2x(x -3) +15 (x – 3) = 0
(2x + 15) (x – 3) = 0
x = 3, -7.5
II. 4y^{2} + 19y + 22 = 0
4y^{2} + 8y + 11y + 22 = 0
4y (y + 2) + 11(y + 2) = 0
y = -2, -11/4
Can’t be determined
Question 11 of 20
11. Question
A, B and C entered into a partnership by investing in the ratio of 5: 6: 9. At the end of the year, the total profit is in the ratio of 10: 8: 9. Find the ratio of period of time they invested in the business?
Correct
Answer: b)
The ratio of investment = 5: 6: 9
The ratio of profit = 10: 8: 9
Ratio of investment * Ratio of Period = Ratio of Profit
Ratio of Period = Ratio of Profit/ Ratio of investment
According to the question,
= > (10/5): (8/6): (9/9)
= > 2: (4/3): 1
= > 6: 4: 3
Incorrect
Answer: b)
The ratio of investment = 5: 6: 9
The ratio of profit = 10: 8: 9
Ratio of investment * Ratio of Period = Ratio of Profit
Ratio of Period = Ratio of Profit/ Ratio of investment
According to the question,
= > (10/5): (8/6): (9/9)
= > 2: (4/3): 1
= > 6: 4: 3
Question 12 of 20
12. Question
The average weight of 75 students in a class is 50 kg. The weights of two students were wrongly entered as 64 kg and 56 kg instead of 46 kg and 59 kg respectively. Find the corrected average weight of the class?
Find the volume of a cylinder, whose radius is one-fourth of the radius of a circle having an area of 2464 cm^{2}. Height of the cylinder is double of its radius?
Correct
Answer: a)
πr^{2} = 2464
=> (22/7)* r^{2} = 2464
=> r^{2} = 2464 x (7/22)
=> r^{2} = 784
=> r = 28 cm
Radius of the cylinder = 28*(1/4) = 7 cm
Height of the cylinder = 7*2 = 14 cm
Volume of the cylinder = πr^{2}h = (22/7)*7*7*14 = 2156 cm^{3}
Incorrect
Answer: a)
πr^{2} = 2464
=> (22/7)* r^{2} = 2464
=> r^{2} = 2464 x (7/22)
=> r^{2} = 784
=> r = 28 cm
Radius of the cylinder = 28*(1/4) = 7 cm
Height of the cylinder = 7*2 = 14 cm
Volume of the cylinder = πr^{2}h = (22/7)*7*7*14 = 2156 cm^{3}
Question 14 of 20
14. Question
Two pipes can fill an empty tank in 3 hours 15 min. The pipes are opened simultaneously and it is found that due to leakage in the bottom of the tank, it takes 45 min more to fill the tank. If the tank is full, in what time would the leakage empty the full tank?
Correct
Answer: c)
Two pipes can fill an empty tank in = 3 hours 15 min = 3 15/60 = 3 1/4
But due to the leakage, it takes 45 min more,
So, Total time taken to fill the tank = 4 hours
Required number of hours = 4/13 – (1/4) = (16 – 13)/52 = 3/52
The leakage empty the full tank in 52/3 = 17 hours 20 min
Incorrect
Answer: c)
Two pipes can fill an empty tank in = 3 hours 15 min = 3 15/60 = 3 1/4
But due to the leakage, it takes 45 min more,
So, Total time taken to fill the tank = 4 hours
Required number of hours = 4/13 – (1/4) = (16 – 13)/52 = 3/52
The leakage empty the full tank in 52/3 = 17 hours 20 min
Question 15 of 20
15. Question
P, Q and R started a business by investing Rs. 28000, Rs. 32000 and Rs. 36000 respectively. After 4 months, P invested Rs. 7000 more and R withdraw Rs. 6000. Find the share of P, if the total profit at the end of the year is Rs. 98600?
Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:
Following table shows the total number items produced by 5 different companies (In thousands) and the percentage of items sold and the cost per items.
Find the total cost earned by the company B and D together?
Correct
Answer: d)
The total cost earned by the company B and D together
= > 64*(72/100)*125 + 90*(76/100)*200
= > (5760 + 13680) thousands
= > 1.944 Crore
Incorrect
Answer: d)
The total cost earned by the company B and D together
= > 64*(72/100)*125 + 90*(76/100)*200
= > (5760 + 13680) thousands
= > 1.944 Crore
Question 18 of 20
18. Question
Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:
Following table shows the total number items produced by 5 different companies (In thousands) and the percentage of items sold and the cost per items.
Find the ratio between the total number of items sold by the company B to that of company D?
Correct
Answer: b)
The total number of items sold by the company B
= > 64*(72/100)
The total number of items sold by the company D
= > 90*(76/100)
Required ratio = [64*(72/100)]: [90*(76/100)]
= > 64: 95
Incorrect
Answer: b)
The total number of items sold by the company B
= > 64*(72/100)
The total number of items sold by the company D
= > 90*(76/100)
Required ratio = [64*(72/100)]: [90*(76/100)]
= > 64: 95
Question 19 of 20
19. Question
Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:
Following table shows the total number items produced by 5 different companies (In thousands) and the percentage of items sold and the cost per items.
Find the difference between the total cost earned by the company A to that of company E?
Correct
Answer: a)
The total cost earned by the company A
= > 78*(60/100)*250 = 11700 thousand
= > 1.17 Crore
The total cost earned by the company E
= > 65*(84/100)*150 = 8190 thousand
= > 0.819 Crore
Required difference = 1.17 – 0.819 = 0.351 Crore
Incorrect
Answer: a)
The total cost earned by the company A
= > 78*(60/100)*250 = 11700 thousand
= > 1.17 Crore
The total cost earned by the company E
= > 65*(84/100)*150 = 8190 thousand
= > 0.819 Crore
Required difference = 1.17 – 0.819 = 0.351 Crore
Question 20 of 20
20. Question
Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:
Following table shows the total number items produced by 5 different companies (In thousands) and the percentage of items sold and the cost per items.
Total number of items produced by the company A and D together is approximately what percentage more/less than the total number of items produced by the company B and C together?
Correct
Answer: c)
Total number of items produced by the company A and D together
= > 78 + 90 = 168000
Total number of items produced by the company B and C together
= > 64 + 82 = 146000
Required % = [(168000 – 146000)/146000]*100 = 15 % more
Incorrect
Answer: c)
Total number of items produced by the company A and D together
= > 78 + 90 = 168000
Total number of items produced by the company B and C together
= > 64 + 82 = 146000
Required % = [(168000 – 146000)/146000]*100 = 15 % more
Click “Start Quiz” to attend these Questions and view Solutions
Directions (Q. 1 – 5): What approximate value should come in the place of question mark (?) in the following questions?
1) 32.75 % of 1398 + 29.899 % of 3897 = 40 % of?
a) 3250
b) 3800
c) 4400
d) 4050
e) 5500
2) 15 × 280.19 ÷ 7.12 +? – 2899 = 325
a) 2625
b) 2150
c) 2475
d) 3100
e) 3350
3) 125 × 333 ÷ 37 % of 1799 = ? – 728.91
a) 630
b) 670
c) 790
d) 720
e) 840
4) (5278 + 1546) ÷ 21 + (42/51) of (254/41) of 1025 =? – (12.23)^{2}
a) 5380
b) 5540
c) 6150
d) 6590
e) 5690
5) 27 % of 804 + (1749 ÷ 14.2) × (7.99)^{2} =? – (3/7) of 2729
a) 8570
b) 9390
c) 8920
d) 8340
e) 9560
Directions (Q. 6 – 10) In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,
If x > y
If x ≥ y
If x < y
If x ≤ y
If x = y or the relation cannot be established
6) I. 6x^{2} + 37x + 35 = 0
II. 4y^{2} + 5y + 1 = 0
7) I. x^{2} + 14^{2} = 27^{2} – 49
II. y^{1/2} – 272 + 410 = 12^{2}
8) I. √(x + 4) = √676 – √361
II. y^{3} – 32568 = 26751
9) I. 3x^{2} +26x + 56 = 0
II. 5y^{2} + 29y + 42 = 0
10) I. 2x^{2} + 9x – 45 = 0;
II. 4y^{2} + 19y + 22 = 0
11) A, B and C entered into a partnership by investing in the ratio of 5: 6: 9. At the end of the year, the total profit is in the ratio of 10: 8: 9. Find the ratio of period of time they invested in the business?
a) 8: 5: 4
b) 6: 4: 3
c) 11: 6: 4
d) 9: 7: 5
e) None of these
12) The average weight of 75 students in a class is 50 kg. The weights of two students were wrongly entered as 64 kg and 56 kg instead of 46 kg and 59 kg respectively. Find the corrected average weight of the class?
a) 49.20 kg
b) 49.60 kg
c) 48.40 kg
d) 49.80 kg
e) None of these
13) Find the volume of a cylinder, whose radius is one-fourth of the radius of a circle having an area of 2464 cm^{2}. Height of the cylinder is double of its radius?
a) 2156 cm^{3}
b) 2564 cm^{3}
c) 2272 cm^{3}
d) 2678 cm^{3}
e) None of these
14) Two pipes can fill an empty tank in 3 hours 15 min. The pipes are opened simultaneously and it is found that due to leakage in the bottom of the tank, it takes 45 min more to fill the tank. If the tank is full, in what time would the leakage empty the full tank?
a) 16 hours 25 min
b) 15 hours 45 min
c) 17 hours 20 min
d) 18 hours 30 min
e) None of these
15) P, Q and R started a business by investing Rs. 28000, Rs. 32000 and Rs. 36000 respectively. After 4 months, P invested Rs. 7000 more and R withdraw Rs. 6000. Find the share of P, if the total profit at the end of the year is Rs. 98600?
a) Rs. 33320
b) Rs. 34550
c) Rs. 32780
d) Rs. 38600
e) None of these
Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:
Following table shows the total number items produced by 5 different companies (In thousands) and the percentage of items sold and the cost per items.
Company
Total number of items produced
(In thousands)
% of items sold
Cost per items
(In Rs.)
A
78
60 %
250
B
64
72 %
125
C
82
58 %
180
D
90
76 %
200
E
65
84 %
150
16) Total number of items sold by the company A is approximately what percentage of total number of items sold by the company C?
a) 100 %
b) 90 %
c) 80 %
d) 115 %
e) 65 %
17) Find the total cost earned by the company B and D together?
a) 1.728 Crore
b) 1.856 Crore
c) 1.642 Crore
d) 1.944 Crore
e) None of these
18) Find the ratio between the total number of items sold by the company B to that of company D?
a) 25: 36
b) 64: 95
c) 52: 77
d) 48: 69
e) None of these
19) Find the difference between the total cost earned by the company A to that of company E?
a) 0.351 Crore
b) 3.51 Crore
c) 0.0351 Crore
d) 35.1 lakhs
e) None of these
20) Total number of items produced by the company A and D together is approximately what percentage more/less than the total number of items produced by the company B and C together?