Dear Readers, Find the aptitude test questions to crack latest bank exams. We regularly provide 20 aptitude test questions daily for students. Aspirants practice these questions on a regular basis to improve your score in aptitude section. Aspirants preparing for the exams can make use of this “20-20” Quantitative Aptitude Questions. Here we have started New Series of Practice Materials specially for IBPS RRB Assistant Prelims 2018. Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.
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Review
Question 1 of 20
1. Question
Directions (1 – 5): What value should come in the place of question mark (?) in the following questions?
(4 × 4)3 ÷ (512 ÷ 8)4 × (32 × 8)4 = (4)? + 4
Correct
Answer: d)
46 ÷ (512/8)4 × (32 × 8)4 = (4)x + 4
46 ÷ 644 × 2564 = (4)x + 4
46 ÷ 412 × 416 = 4x + 4
46 – 12 + 16 = 4x + 4
410 = 4x + 4
x + 4 = 10
x = 6
Incorrect
Answer: d)
46 ÷ (512/8)4 × (32 × 8)4 = (4)x + 4
46 ÷ 644 × 2564 = (4)x + 4
46 ÷ 412 × 416 = 4x + 4
46 – 12 + 16 = 4x + 4
410 = 4x + 4
x + 4 = 10
x = 6
Question 2 of 20
2. Question
Directions (1 – 5): What value should come in the place of question mark (?) in the following questions?
76 % of 1285 – 35 % of 1256 =?
Correct
Answer: a)
(76/100)*1285 – (35/100)*1256 = X
X = 976.6 – 439.6
X = 537
Incorrect
Answer: a)
(76/100)*1285 – (35/100)*1256 = X
X = 976.6 – 439.6
X = 537
Question 3 of 20
3. Question
Directions (1 – 5): What value should come in the place of question mark (?) in the following questions?
(2/7) of 5033 + 78 % of 650 = (?)2 + 181
Correct
Answer: c)
(2/7)*5033 + (78/100)*650 = x2 + 181
1438 + 507 – 181 = x2
X2 = 1764
X = 42
Incorrect
Answer: c)
(2/7)*5033 + (78/100)*650 = x2 + 181
1438 + 507 – 181 = x2
X2 = 1764
X = 42
Question 4 of 20
4. Question
Directions (1 – 5): What value should come in the place of question mark (?) in the following questions?
32 % of 480 + (5/7) of 1890 – 28 % of 820 =?
Correct
Answer: d)
(32/100)*480 + (5/7)*1890 – (28/100)*820 = x
X = 153.6 + 1350 – 229.6
X = 1274
Incorrect
Answer: d)
(32/100)*480 + (5/7)*1890 – (28/100)*820 = x
X = 153.6 + 1350 – 229.6
X = 1274
Question 5 of 20
5. Question
Directions (1 – 5): What value should come in the place of question mark (?) in the following questions?
? *100/(140 × 8 – 680) = 330 + 452
Correct
Answer: b)
(x*100)/(1120 – 680) = 330 + 2025
x/100)*(440) = 2355
x = 2355*(440/100)
x = 10362
Incorrect
Answer: b)
(x*100)/(1120 – 680) = 330 + 2025
x/100)*(440) = 2355
x = 2355*(440/100)
x = 10362
Question 6 of 20
6. Question
Directions (6 – 10): What value should come in the place of question mark (?) in the following number series?
14, 8, 16, 59, 300, ?
Correct
Answer: e)
The pattern is, *0.5 + 13, *1 + 23, *2 + 33, *4 +43, *8 + 53,..
The answer is, 2525
Incorrect
Answer: e)
The pattern is, *0.5 + 13, *1 + 23, *2 + 33, *4 +43, *8 + 53,..
The answer is, 2525
Question 7 of 20
7. Question
Directions (6 – 10): What value should come in the place of question mark (?) in the following number series?
8, 17, 70, 423, 3388, ?
Correct
Answer: a)
The pattern is, *2 + 1, *4 + 2, *6 +3, *8 + 4, *10 + 5,..
The answer is, 33885
Incorrect
Answer: a)
The pattern is, *2 + 1, *4 + 2, *6 +3, *8 + 4, *10 + 5,..
The answer is, 33885
Question 8 of 20
8. Question
Directions (6 – 10): What value should come in the place of question mark (?) in the following number series?
14224, 7113, 2374, 598.5, ?
Correct
Answer: c)
The pattern is, ÷ 2 +1, ÷ 3 +3, ÷ 4 +5, ÷ 5 +7,..
The answer is, 126.7
Incorrect
Answer: c)
The pattern is, ÷ 2 +1, ÷ 3 +3, ÷ 4 +5, ÷ 5 +7,..
The answer is, 126.7
Question 9 of 20
9. Question
Directions (6 – 10): What value should come in the place of question mark (?) in the following number series?
53, 26, 27, 39, 80, 197.5, ?
Correct
Answer: d)
The pattern is, *0.5 – 0.5, *1 + 1, *1.5 -1.5, *2 + 2, *2.5 – 2.5, *3 + 3,..
The answer is, 595.5
Incorrect
Answer: d)
The pattern is, *0.5 – 0.5, *1 + 1, *1.5 -1.5, *2 + 2, *2.5 – 2.5, *3 + 3,..
The answer is, 595.5
Question 10 of 20
10. Question
Directions (6 – 10): What value should come in the place of question mark (?) in the following number series?
552, 666, 788, 926, ?, 1330
Correct
Answer: b)
The difference of difference is, ×2
The answer is, 1096
Incorrect
Answer: b)
The difference of difference is, ×2
The answer is, 1096
Question 11 of 20
11. Question
The ratio of age of P, 4 years ago and the age of Q, 3 years after is 3: 5. Sum of the present ages of P and Q is 49 years. Find the age of P, 3 years after?
Correct
Answer: a)
The ratio of ages of P, 4 years ago and the ages of Q, 3 years after = 3: 5 (3x, 5x)
Present ages of P and Q = 3x + 4, 5x – 3
According to the question,
3x + 4 + 5x – 3 = 49
8x + 1 = 49
8x = 48
X = 6
Present age of P = 3x + 4 = 22
The age of P, 3 years after = 25 years
Incorrect
Answer: a)
The ratio of ages of P, 4 years ago and the ages of Q, 3 years after = 3: 5 (3x, 5x)
Present ages of P and Q = 3x + 4, 5x – 3
According to the question,
3x + 4 + 5x – 3 = 49
8x + 1 = 49
8x = 48
X = 6
Present age of P = 3x + 4 = 22
The age of P, 3 years after = 25 years
Question 12 of 20
12. Question
A box contains 5 white balls, 6 violet balls and 3 yellow balls. If 2 balls are drawn randomly, then the probability of getting both the balls is either white or violet balls?
Correct
Answer: d)
Total probability n(S) = 14C2
Required probability n(E) = 5C2 or 6C2
P(E) = n(E)/n(S) = 5C2 or 6C2 / 14C2
= > 25/91
Incorrect
Answer: d)
Total probability n(S) = 14C2
Required probability n(E) = 5C2 or 6C2
P(E) = n(E)/n(S) = 5C2 or 6C2 / 14C2
= > 25/91
Question 13 of 20
13. Question
The length of train A is 150 m and that of train B is 200 m. These two trains are running in the opposite direction with the velocities of 50 km/hr and 40 km/hr respectively. Find the time taken to cross each other?
Correct
Answer: a)
T = D/S
T = (150 + 200)/[(50 + 40)*(5/18)]
T = (350*18)/(90*5)
T = 14 sec
Incorrect
Answer: a)
T = D/S
T = (150 + 200)/[(50 + 40)*(5/18)]
T = (350*18)/(90*5)
T = 14 sec
Question 14 of 20
14. Question
Agila, Manoj and Prithika enter into a partnership. Agila invests 2 times as much as Manoj’s investment and Manoj invests 4/7th of Prithika’s investment. If the total profit earned at the end of the year is Rs. 123500, then find the share of Manoj?
Correct
Answer: c)
The investment of Agila and Manoj = 2: 1
Agila’s investment = (4/7)* Prithika’s investment
The investment of Manoj and Prithika = 4: 7
The investment of Agila, Manoj and Prithika = 8: 4: 7
Here, the period is not given. So,
The ratio of investment = The ratio of profit
Total profit = Rs. 123500
19’s = 123500
1’s = 6500
The share of Manoj = 4’s = Rs. 26000
Incorrect
Answer: c)
The investment of Agila and Manoj = 2: 1
Agila’s investment = (4/7)* Prithika’s investment
The investment of Manoj and Prithika = 4: 7
The investment of Agila, Manoj and Prithika = 8: 4: 7
Here, the period is not given. So,
The ratio of investment = The ratio of profit
Total profit = Rs. 123500
19’s = 123500
1’s = 6500
The share of Manoj = 4’s = Rs. 26000
Question 15 of 20
15. Question
The CI on a certain sum of money for 3 years at 5 % per annum is Rs. 7881.25. Then find the principle?
Correct
Answer: b)
C.I = P*[(1 + (r/100))3 – 1]
7881.25 = P*[(1 + 5/100)3 – 1]
7881.25 = P*[(105/100)3 – 1]
7881.25 = P*[(21/20)3 – 1]
7881.25 = P*[(9261/8000) – 1]
7881.25 = P*(1261/8000)
7881.25*(8000/1261) = P
P = Rs. 50000
Incorrect
Answer: b)
C.I = P*[(1 + (r/100))3 – 1]
7881.25 = P*[(1 + 5/100)3 – 1]
7881.25 = P*[(105/100)3 – 1]
7881.25 = P*[(21/20)3 – 1]
7881.25 = P*[(9261/8000) – 1]
7881.25 = P*(1261/8000)
7881.25*(8000/1261) = P
P = Rs. 50000
Question 16 of 20
16. Question
Directions (16 – 20): Study the following information carefully and answer the given questions:
Following table shows the total no students appeared for 10th Public examination and pass %, from different schools in different years.
Find the ratio between the total number of passing students from all the given schools together in the year 2013 to that of 2015?
Correct
Answer: c)
The total number of passing students from all the given schools together in the year 2013
= > 2200*(72/100) + 2600*(68/100) + 2600*(70/100)
= > 1584 + 1768 + 1820 = 5172
The total number of passing students from all the given schools together in the year 2015
= > 2400*(80/100) + 3200*(78/100) + 2800*(78/100)
= > 1920 + 2496 + 2184 = 6600
Required ratio = 5172: 6600 = 431: 550
Incorrect
Answer: c)
The total number of passing students from all the given schools together in the year 2013
= > 2200*(72/100) + 2600*(68/100) + 2600*(70/100)
= > 1584 + 1768 + 1820 = 5172
The total number of passing students from all the given schools together in the year 2015
= > 2400*(80/100) + 3200*(78/100) + 2800*(78/100)
= > 1920 + 2496 + 2184 = 6600
Required ratio = 5172: 6600 = 431: 550
Question 17 of 20
17. Question
Directions (16 – 20): Study the following information carefully and answer the given questions:
Following table shows the total no students appeared for 10th Public examination and pass %, from different schools in different years.
Total number of appeared students in the year 2012 from School P and R together is approximately what percentage of total number of appeared students in the year 2016 from School Q and R together?
Correct
Answer: a)
Total number of appeared students in the year 2012 from School P and R together
= > 1800 + 2000 = 3800
Total number of appeared students in the year 2016 from School Q and R together
= > 3500 + 2600 = 6100
Required % = (3800/6100)*100 = 62 % = 62 %
Incorrect
Answer: a)
Total number of appeared students in the year 2012 from School P and R together
= > 1800 + 2000 = 3800
Total number of appeared students in the year 2016 from School Q and R together
= > 3500 + 2600 = 6100
Required % = (3800/6100)*100 = 62 % = 62 %
Question 18 of 20
18. Question
Directions (16 – 20): Study the following information carefully and answer the given questions:
Following table shows the total no students appeared for 10th Public examination and pass %, from different schools in different years.
Find the average number of passed students from School Q in the year 2012, 2014, 2015 and 2016 together?
Correct
Answer: d)
The total number of passed students from School Q in the year 2012, 2014, 2015 and 2016 together
Directions (16 – 20): Study the following information carefully and answer the given questions:
Following table shows the total no students appeared for 10th Public examination and pass %, from different schools in different years.
Find the difference between the total number of appeared students in the year 2013 and 2014 together to that of total number of appeared students in the year 2015 and 2016 together from all the given schools together?
Correct
Answer: b)
The total number of appeared students in the year 2013 and 2014 together from all the given schools together
= > 2200 + 2600 + 2600 + 3500 + 2900 + 3100
= > 16900
The total number of appeared students in the year 2015 and 2016 together from all the given schools together
= > 2400 + 3200 + 2800 + 3300 + 3500 + 2600
= > 17800
Required difference = 17800 – 16900 = 900
Incorrect
Answer: b)
The total number of appeared students in the year 2013 and 2014 together from all the given schools together
= > 2200 + 2600 + 2600 + 3500 + 2900 + 3100
= > 16900
The total number of appeared students in the year 2015 and 2016 together from all the given schools together
= > 2400 + 3200 + 2800 + 3300 + 3500 + 2600
= > 17800
Required difference = 17800 – 16900 = 900
Question 20 of 20
20. Question
Directions (16 – 20): Study the following information carefully and answer the given questions:
Following table shows the total no students appeared for 10th Public examination and pass %, from different schools in different years.
Find the total number of failed students from School P in all the given years together?
Correct
Answer: c)
The total number of failed students from School P in all the given years together
Directions (1 – 5): What value should come in the place of question mark (?) in the following questions?
1) (4 × 4)3 ÷ (512 ÷ 8)4 × (32 × 8)4 = (4)? + 4
a) 8
b) 5
c) 7
d) 6
e) None of these
2) 76 % of 1285 – 35 % of 1256 =?
a) 537
b) 629
c) 451
d) 787
e) None of these
3) (2/7) of 5033 + 78 % of 650 = (?)2 + 181
a) 48
b) 46
c) 42
d) 39
e) None of these
4) 32 % of 480 + (5/7) of 1890 – 28 % of 820 =?
a) 1336
b) 1178
c) 1452
d) 1274
e) None of these
5) ? *100/(140 × 8 – 680) = 330 + 452
a) 9857
b) 10362
c) 11238
d) 8564
e) None of these
Directions (6 – 10): What value should come in the place of question mark (?) in the following number series?
6) 14, 8, 16, 59, 300, ?
a) 1486
b) 1652
c) 1893
d) 2177
e) 2525
7) 8, 17, 70, 423, 3388, ?
a) 33885
b) 25640
c) 21373
d) 29787
e) 35662
8) 14224, 7113, 2374, 598.5, ?
a) 178.3
b) 185.4
c) 126.7
d) 132.5
e) 154.6
9) 53, 26, 27, 39, 80, 197.5, ?
a) 378
b) 424
c) 517.5
d) 595.5
e) 492.5
10) 552, 666, 788, 926, ?, 1330
a) 1124
b) 1096
c) 1078
d) 1212
e) 1250
11) The ratio of age of P, 4 years ago and the age of Q, 3 years after is 3: 5. Sum of the present ages of P and Q is 49 years. Find the age of P, 3 years after?
a) 25 years
b) 28 years
c) 32 years
d) 30 years
e) None of these
12) A box contains 5 white balls, 6 violet balls and 3 yellow balls. If 2 balls are drawn randomly, then the probability of getting both the balls is either white or violet balls?
a) 11/56
b) 23/72
c) 35/83
d) 25/91
e) None of these
13) The length of train A is 150 m and that of train B is 200 m. These two trains are running in the opposite direction with the velocities of 50 km/hr and 40 km/hr respectively. Find the time taken to cross each other?
a) 14 sec
b) 21 sec
c) 18 sec
d) 25 sec
e) None of these
14) Agila, Manoj and Prithika enter into a partnership. Agila invests 2 times as much as Manoj’s investment and Manoj invests 4/7th of Prithika’s investment. If the total profit earned at the end of the year is Rs. 123500, then find the share of Manoj?
a) Rs. 28000
b) Rs. 22000
c) Rs. 26000
d) Rs. 30000
e) None of these
15) The CI on a certain sum of money for 3 years at 5 % per annum is Rs. 7881.25. Then find the principle?
a) Rs. 45000
b) Rs. 50000
c) Rs. 42000
d) Rs. 36000
e) None of these
Directions (16 – 20): Study the following information carefully and answer the given questions:
Following table shows the total no students appeared for 10th Public examination and pass %, from different schools in different years.
16) Find the ratio between the total number of passing students from all the given schools together in the year 2013 to that of 2015?
a) 124: 175
b) 256: 313
c) 431: 550
d) 378: 415
e) None of these
17) Total number of appeared students in the year 2012 from School P and R together is approximately what percentage of total number of appeared students in the year 2016 from School Q and R together?
a) 62 %
b) 80 %
c) 50 %
d) 90 %
e) 100 %
18) Find the average number of passed students from School Q in the year 2012, 2014, 2015 and 2016 together?
a) 2527
b) 2413
c) 2355
d) 2219
e) None of these
19) Find the difference between the total number of appeared students in the year 2013 and 2014 together to that of total number of appeared students in the year 2015 and 2016 together from all the given schools together?
a) 750
b) 900
c) 800
d) 650
e) None of these
20) Find the total number of failed students from School P in all the given years together?
a) 2178
b) 2564
c) 3081
d) 2893
e) None of these
Answers:
Direction (1-5)
1) Answer: d)
46 ÷ (512/8)4 × (32 × 8)4 = (4)x + 4
46 ÷ 644 × 2564 = (4)x + 4
46 ÷ 412 × 416 = 4x + 4
46 – 12 + 16 = 4x + 4
410 = 4x + 4
x + 4 = 10
x = 6
2) Answer: a)
(76/100)*1285 – (35/100)*1256 = X
X = 976.6 – 439.6
X = 537
3) Answer: c)
(2/7)*5033 + (78/100)*650 = x2 + 181
1438 + 507 – 181 = x2
X2 = 1764
X = 42
4) Answer: d)
(32/100)*480 + (5/7)*1890 – (28/100)*820 = x
X = 153.6 + 1350 – 229.6
X = 1274
5) Answer: b)
(x*100)/(1120 – 680) = 330 + 2025
x/100)*(440) = 2355
x = 2355*(440/100)
x = 10362
Direction (6-10)
6) Answer: e)
The pattern is, *0.5 + 13, *1 + 23, *2 + 33, *4 +43, *8 + 53,..
The answer is, 2525
7) Answer: a)
The pattern is, *2 + 1, *4 + 2, *6 +3, *8 + 4, *10 + 5,..
The answer is, 33885
8) Answer: c)
The pattern is, ÷ 2 +1, ÷ 3 +3, ÷ 4 +5, ÷ 5 +7,..
The answer is, 126.7
9) Answer: d)
The pattern is, *0.5 – 0.5, *1 + 1, *1.5 -1.5, *2 + 2, *2.5 – 2.5, *3 + 3,..
The answer is, 595.5
10) Answer: b)
The difference of difference is, ×2
The answer is, 1096
11) Answer: a)
The ratio of ages of P, 4 years ago and the ages of Q, 3 years after = 3: 5 (3x, 5x)
Present ages of P and Q = 3x + 4, 5x – 3
According to the question,
3x + 4 + 5x – 3 = 49
8x + 1 = 49
8x = 48
X = 6
Present age of P = 3x + 4 = 22
The age of P, 3 years after = 25 years
12) Answer: d)
Total probability n(S) = 14C2
Required probability n(E) = 5C2 or 6C2
P(E) = n(E)/n(S) = 5C2 or 6C2 / 14C2
= > 25/91
13) Answer: a)
T = D/S
T = (150 + 200)/[(50 + 40)*(5/18)]
T = (350*18)/(90*5)
T = 14 sec
14) Answer: c)
The investment of Agila and Manoj = 2: 1
Agila’s investment = (4/7)* Prithika’s investment
The investment of Manoj and Prithika = 4: 7
The investment of Agila, Manoj and Prithika = 8: 4: 7
Here, the period is not given. So,
The ratio of investment = The ratio of profit
Total profit = Rs. 123500
19’s = 123500
1’s = 6500
The share of Manoj = 4’s = Rs. 26000
15) Answer: b)
C.I = P*[(1 + (r/100))3 – 1]
7881.25 = P*[(1 + 5/100)3 – 1]
7881.25 = P*[(105/100)3 – 1]
7881.25 = P*[(21/20)3 – 1]
7881.25 = P*[(9261/8000) – 1]
7881.25 = P*(1261/8000)
7881.25*(8000/1261) = P
P = Rs. 50000
Direction (16-20)
16) Answer: c)
The total number of passing students from all the given schools together in the year 2013
= > 2200*(72/100) + 2600*(68/100) + 2600*(70/100)
= > 1584 + 1768 + 1820 = 5172
The total number of passing students from all the given schools together in the year 2015
= > 2400*(80/100) + 3200*(78/100) + 2800*(78/100)
= > 1920 + 2496 + 2184 = 6600
Required ratio = 5172: 6600 = 431: 550
17) Answer: a)
Total number of appeared students in the year 2012 from School P and R together
= > 1800 + 2000 = 3800
Total number of appeared students in the year 2016 from School Q and R together
= > 3500 + 2600 = 6100
Required % = (3800/6100)*100 = 62 % = 62 %
18) Answer: d)
The total number of passed students from School Q in the year 2012, 2014, 2015 and 2016 together
