Dear Readers, Find the aptitude test questions to crack latest bank exams. We regularly provide 20 aptitude test questions daily for students. Aspirants practice these questions on a regular basis to improve your score in aptitude section. Aspirants preparing for the exams can make use of this “20-20” Quantitative Aptitude Questions. Here we have started New Series of Practice Materials specially for IBPS RRB PO Prelims 2018. Aspirants those who are preparing for the exams can use this **“20-20” Quantitative Aptitude Questions.**

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**“20-20” Aptitude Questions | Crack IBPS RRB PO Prelims 2018 Day-164**

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**Click here to view Quantitative Aptitude Questions in Hindi**

**Directions (Q. 1 – 5) In the following questions, two equations I and II are given. You have to solve both the equations and g****ive Answer as,**

a) If x > y

b) If x ≥ y

c) If x < y

d) If x ≤ y

e) If x = y or the relation cannot be established

**1) I.** X^{3} =1331

II. 2y^{2} -21y +55 =0

**2) I.** 5x = 7y+21

II. 11x +4y+109 =0

**3) I.** 2x^{2} -11x +12 =0

II. 2y^{2} -17y +36 =0

**4) ****I.** 6x^{2} – 32x + 42 = 0

II. y^{2 }+ 7y + 12 = 0

**5) ****I.** x^{2} + 6x + 8 = 0

II. 4y^{2} – 13y + 9 = 0

**Directions (Q. 6 – 10): What approximate value should come in the place of question mark (?) in the following questions?**

**6) ****(3/7) of (34/13) of 3054 – ? + 56 % of 7549 = 63.21**

a) 8150

b) 6830

c) 5670

d) 7690

e) 9560

**7) ****48 % of 4249 + ? % of 5597 = 52 % of 4648 + 1301.67**

a) 30

b) 45

c) 60

d) 80

e) 55

** ****8) 35 % of ? – 2650 ÷ 17 – 2021 ÷ 7 = 52.21**

a) 2150

b) 1870

c) 1420

d) 1630

e) 2340

**9) ****[(45 × 23) ÷ 46 – 749.9 ÷ 149] = 3 × ?**

a) 12

b) 6

c) 20

d) 17

e) 25

** ****10) ****27 % of 4495 – 32 % of 247 = ? – ****√286 % of 1187**

a) 2150

b) 2370

c) 1580

d) 1760

e) 1340

** ****11) A certain sum is divided among A, B and C in such a way that A gets 35 more than the 2/5 of the sum and B gets Rs. 75 less than the 1/5 of the sum and C gets Rs. 350. Find the sum?**

a) Rs. 900

b) Rs. 775

c) Rs. 825

d) Rs. 1050

e) None of these

** ****12) The angles of quadrilateral are in the ratio of 3:2:5:8. The second smallest angle of quadrilateral is equal to second smallest angle of triangle. One of the angles of triangle is equal to twice its smallest angle. Find the largest angle of triangle?**

a) 80^{◦}

b) 60^{◦}

c) 100^{◦}

d) 40^{◦}

e) None of these

** ****13) The average weight of 8 persons is increased by 2 when one of the person whose weight is 62 kg is replaced by 2 women. Find the average weight of 2 women?**

a) 30 kg

b) 38 kg

c) 39 kg

d) 42 kg

e) None of these

** ****14) A circular road runs around a circular ground. If the radius of the ground is 5.5 m and the difference between the circumference of the outer circle and that of the inner circle is 110m, then the area of the road is?**

a) 1354.25 m

b) 1678.75 m

c) 1567.50 m

d) 2119.25 m

e) None of these

**15) Ravi spends 30% of his monthly income on food and 20% on education of his children. Of the remaining salary, he spends 25% on entertainment and 15% on conveyance. He is now left with Rs. 12,336. What is the monthly salary of Ravi?**

a) Rs. 27600

b) Rs. 28750

c) Rs. 33200

d) Rs. 41120

e) None of these

** ****Directions (Q. 16 – 20): Study the following information carefully and answer the given questions.**

Following pie chart -1 shows the percentage distribution of savings of 5 different friends in January 2018 and pie chart – 2 shows the percentage distribution of savings of 5 friends in February 2018.

**16) The savings of Manoj and Pari together in January 2018 is what percentage more/less than the savings of Pari and Subha together in February 2018?**

a) 15 % more

b) 25 % less

c) 15 % less

d) 25 % more

e) 20 % more

** ****17) Find the difference between the average savings of Sree and Moni together in January 2018 to that of the average savings of Moni and Manoj together in February 2018?**

a) 725

b) Rs. 900

c) Rs. 850

d) Rs. 675

e) None of these

** ****18) Find the ratio between the savings of Manoj and Subha together in January 2018 to that of the savings of Pari and Moni together in February 2018?**

a) 315 : 223

b) 447 : 335

c) 15 : 7

d) 259 : 312

e) None of these

** ****19) Total savings of Moni in January 2018 is what percentage of total savings of Pari in February 2018?**

a) 150 %

b) 125 %

c) 140 %

d) 105 %

e) None of these

** ****20) Find the total savings of Manoj and Subha in January and February together?**

a) Rs. 26800

b) Rs. 24550

c) 28150

d) Rs. 32500

e) None of these

** Answers:**

**Direction (1-5)**

**1) Answer: a)**

I. X^{3} =1331

X = ∛1331 =11

II. 2y^{2} -21y + 55 =0

2y^{2} -10y -11y +55 =0

2y(y – 5)-11 (y – 5) =0

(2y – 11) (y – 5) =0

Y= 11/2, 5

X > y

**2) Answer: a)**

5x – 7y = 21 —> (1)

11x +4y = -109 –> (2)

By solving the equation (1), (2), we get,

X= -7, y = -8

X > y

**3) Answer: d)**

I. 2x^{2} -11x +12 = 0

2x^{2} – 8x – 3x +12 = 0

2x (x – 4) -3 (x – 4) = 0

(2x – 3) (x – 4) =0

X = 3/2, 4

II. 2y^{2} -17y +36 = 0

2y^{2} – 9y – 8y + 36 = 0

y (2y – 9) – 4 (2y – 9) = 0

(y – 4) (2y – 9) =0

Y = 4, 9/2

X ≤ y

**4) Answer: a)**

I. 6x^{2} – 32x + 42 = 0

6x^{2} – 18x – 14x + 42 = 0

6x(x – 3)-14 (x – 3) =0

(6x – 14)(x – 3) = 0

x = 3, 7/3

II. y^{2 }+ 7y + 12 = 0

(y + 4) (y + 3) = 0

y = -4, -3

x > y

**5) Answer: c)**

I. x^{2} + 6x + 8 = 0

(x + 4)(x + 2) = 0

x = -4, -2

II. 4y^{2} – 13y + 9 = 0

4y^{2} – 4y – 9y + 9 = 0

4y(y – 1) – 9 (y – 1) =0

(4y – 9) (y – 1) = 0

y = 1, 9/4

x < y

**Direction (6-10)**

**6) Answer: d)**

(3/7)*(35/13)*3055 – x + (56/100)*7550 = 63

3525 – x + 4228 = 63

X = 3525 + 4228 – 63

X = 7690

**7) Answer: a)**

(48/100)*4250 + (x/100)*5600 = (52/100)*4650 + 1302

2040 + 56x = 2418 + 1302

56x = 2418 + 1302 – 2040

56x = 1680

X = 30

**8) Answer: c)**

(35/100)*x – (2652/17) – (2023/7) = 52

(7x/20) – 156 – 289 = 52

(7x/20) = 52 + 156 + 289

(7x/20) = 497

X = 497*(20/7) = 1420

**9) Answer: b)**

(46*23)/46 – (750/150) = 3x

23 – 5 = 3x

18 = 3x

X = 18/3 = 6

**10) Answer: e)**

(27/100)*4500 – (32/100)*250 = x – (17/100)*1200

1215 – 80 = x – 204

1215 – 80 + 204 = x

X = 1339 = 1340

**11) Answer: b)**

Let total sum be x,

A= (2/5)*x +35

B = (1/5)*x – 75

C = 350

A + B + C = x

(2/5)*x + 35 + (1/5)*x – 75 + 350 = x

(3/5)*x + 310 = x

310 = x – (3/5)*x

(2/5)*x = 310

X= 310*(5/2) = Rs. 775

**12) Answer: b)**

The angles of quadrilateral are in the ratio of 3:2:5:8.

Total angles = 360^{◦}

18’s = 360

1’s = 20

The angles are,

= > 60◦, 40◦, 100◦, 160◦

Second smallest angle of quadrilateral = 60◦ = Second smallest angle of triangle

One of the angles of triangle = 2* 40◦ = 80◦

Total angles of triangle= 180◦

Remaining angle = 180 – (60+80) = 40◦

Largest angle of triangle = 80◦

**13) Answer: c)**

Increased weight = 8*2 = 16 kg

So 2 women’s weight = 62kg +16 kg = 78 kg

Average weight of 2 women = 78/2 = 39 kg

**14) Answer: c)**

Radius of the ground(r) = 5.5 m

The difference between the circumference of the outer circle and that of the inner circle is 110m

= > 2πR – 2πr = 110

= > 2*(22/7)*(R – r) = 110

= > R – r = 17.5

= > R- 5.5 = 17.5

= > R = 23 m

The area of the road is,

=> πR^{2} – πr^{2}

=> (22/7) (23^{2} – 5.5^{2})

= > (22/7) (23 + 5.5) (23 – 5.5)

= > (22/7)*28.5*17.5

= > 1567.5 m

**15) Answer: d)**

Let Ravi’s monthly salary be x,

According to the question,

X*(50/100)*(60/100) = 12336

X = Rs. 41120

**Direction (16-20)**

**16) Answer: c)**

The savings of Manoj and Pari together in January 2018

= > (33/100)*35000 = 11550

The savings of Pari and Subha together in February 2018

= > (34/100)*40000 = 13600

Required % = [(13600 – 11550)/13600]*100 = 15 % less

**17) Answer: a)**

The average savings of Sree and Moni together in January 2018

= > (45/100)*35000*(1/2) = 7875

The average savings of Moni and Manoj together in February 2018

= > (43/100)*40000*(1/2) = 8600

Required difference = 8600 – 7875 = Rs. 725

**18) Answer: d)**

The savings of Manoj and Subha together in January 2018

= > (37/100)*35000 = 12950

The savings of Pari and Moni together in February 2018

= > (39/100)*40000 = 15600

Required ratio = 12950 : 15600 = 259 : 312

**19) Answer: b)**

Total savings of Moni in January 2018

= > (20/100)*35000 = 7000

Total savings of Pari in February 2018

= > (14/100)*40000 = 5600

Required % = (7000/5600)*100 = 125 %

**20) Answer: c)**

The total savings of Manoj and Subha in January

= > (37/100)*35000 = Rs. 12950

The total savings of Manoj and Subha in February

= > (38/100)*40000 = Rs. 15200

Required sum = 12950 + 15200 = Rs. 28150

**Daily Practice Test Schedule | Good Luck**

Topic |
Daily Publishing Time |

Daily News Papers & Editorials |
8.00 AM |

Current Affairs Quiz |
9.00 AM |

Quantitative Aptitude “20-20” |
11.00 AM |

Vocabulary (Based on The Hindu) |
12.00 PM |

General Awareness “20-20” |
1.00 PM |

English Language “20-20” |
2.00 PM |

Reasoning Puzzles & Seating |
4.00 PM |

Daily Current Affairs Updates |
5.00 PM |

Data Interpretation / Application Sums (Topic Wise) |
6.00 PM |

Reasoning Ability “20-20” |
7.00 PM |

English Language (New Pattern Questions) |
8.00 PM |