Dear Readers, Find the aptitude test questions to crack latest bank exams. We regularly provide 20 aptitude test questions daily for students. Aspirants practice these questions on a regular basis to improve your score in aptitude section. Aspirants preparing for the exams can make use of this “20-20” Quantitative Aptitude Questions. Here we have started New Series of Practice Materials specially for IBPS RRB Assistant Prelims 2018. Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.
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Question 1 of 20
1. Question
Directions (1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
X^{2} +16x + 48 =0
y^{2} + 30y +81 =0
Correct
Answer: e)
I. X^{2} + 16x + 48 =0
X^{2} +12x+4x+ 48 =0
(x+12) (x+4) =0
X= -12, -4
II. y^{2} + 30y +81 =0
y^{2} + 3y+27y +81 =0
(y+3) (y+27) =0
Y = -3, -27
Can’t be determined
Incorrect
Answer: e)
I. X^{2} + 16x + 48 =0
X^{2} +12x+4x+ 48 =0
(x+12) (x+4) =0
X= -12, -4
II. y^{2} + 30y +81 =0
y^{2} + 3y+27y +81 =0
(y+3) (y+27) =0
Y = -3, -27
Can’t be determined
Question 2 of 20
2. Question
Directions (1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
5x^{2} +42x + 49 =0
4y^{2} + 37y + 85 =0
Correct
Answer: e)
I. 5x^{2} +42x + 49 =0
5x^{2} +35x + 7x + 49 =0
5x(x+7) + 7(x+7) =0
(5x+7) (x+7) =0
X= -7/5, -7
II. 4y^{2} + 37y + 85 =0
4y^{2} + 20y+17y + 85 =0
4y(y+5) + 17 (y+5) =0
(4y+17)(y+5) =0
Y = -17/4, -5
Can’t be determined
Incorrect
Answer: e)
I. 5x^{2} +42x + 49 =0
5x^{2} +35x + 7x + 49 =0
5x(x+7) + 7(x+7) =0
(5x+7) (x+7) =0
X= -7/5, -7
II. 4y^{2} + 37y + 85 =0
4y^{2} + 20y+17y + 85 =0
4y(y+5) + 17 (y+5) =0
(4y+17)(y+5) =0
Y = -17/4, -5
Can’t be determined
Question 3 of 20
3. Question
Directions (1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
x^{2} – 17x + 72 = 0
y^{2} – 13y + 40 = 0
Correct
Answer: b)
I. x^{2} – 17x + 72 = 0
x^{2} – 8x – 9x + 72 = 0
x(x – 8) -9 (x – 8) = 0
(x – 9) (x – 8) = 0
X = 9, 8
II. y^{2} – 13y + 40 = 0
y^{2} – 5y – 8y + 40 = 0
y(y – 5) – 8(y – 5) = 0
(y – 8) (y – 5) = 0
Y = 8, 5
x ≥ y
Incorrect
Answer: b)
I. x^{2} – 17x + 72 = 0
x^{2} – 8x – 9x + 72 = 0
x(x – 8) -9 (x – 8) = 0
(x – 9) (x – 8) = 0
X = 9, 8
II. y^{2} – 13y + 40 = 0
y^{2} – 5y – 8y + 40 = 0
y(y – 5) – 8(y – 5) = 0
(y – 8) (y – 5) = 0
Y = 8, 5
x ≥ y
Question 4 of 20
4. Question
Directions (1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
5x^{2} – 17x + 14 = 0
8y^{2 }+ 3y – 5 = 0
Correct
Answer: a)
I. 5x^{2} – 17x + 14 = 0
5x^{2} – 10x – 7x + 14 = 0
5x(x – 2) -7 (x – 2) = 0
(5x – 7) (x – 2) = 0
X = 7/5, 2 = 1.4, 2
II. 8y^{2 }+ 3y – 5 = 0
8y^{2 }+ 8y – 5y – 5 = 0
8y(y + 1) – 5(y + 1) = 0
(8y – 5)(y + 1) = 0
Y = 5/8, -1 = 0.625, -1
X > y
Incorrect
Answer: a)
I. 5x^{2} – 17x + 14 = 0
5x^{2} – 10x – 7x + 14 = 0
5x(x – 2) -7 (x – 2) = 0
(5x – 7) (x – 2) = 0
X = 7/5, 2 = 1.4, 2
II. 8y^{2 }+ 3y – 5 = 0
8y^{2 }+ 8y – 5y – 5 = 0
8y(y + 1) – 5(y + 1) = 0
(8y – 5)(y + 1) = 0
Y = 5/8, -1 = 0.625, -1
X > y
Question 5 of 20
5. Question
Directions (1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
I. 2x^{2} – 8x – 24 = 0
II. 3y^{2} + 18y + 24 = 0
Correct
Answer: b)
I. 2x^{2} – 8x – 24 = 0
2x^{2} + 4x – 12x – 24 = 0
2x(x + 2) – 12(x + 2) = 0
(2x -12) (x + 2) = 0
X = 12/2, – 2 = 6, -2
II. 3y^{2} + 18y + 24 = 0
3y^{2} + 6y + 12y + 24 = 0
3y(y + 2) + 12(y + 2) = 0
(3y + 12) (y + 2) = 0
Y = -12/3, -2 = -4, -2
x ≥ y
Incorrect
Answer: b)
I. 2x^{2} – 8x – 24 = 0
2x^{2} + 4x – 12x – 24 = 0
2x(x + 2) – 12(x + 2) = 0
(2x -12) (x + 2) = 0
X = 12/2, – 2 = 6, -2
II. 3y^{2} + 18y + 24 = 0
3y^{2} + 6y + 12y + 24 = 0
3y(y + 2) + 12(y + 2) = 0
(3y + 12) (y + 2) = 0
Y = -12/3, -2 = -4, -2
x ≥ y
Question 6 of 20
6. Question
Directions (6 – 10): What approximate value should come in the place of question mark (?) in the following questions?
√(65025) ÷ 5.32 × 12.21 = ? – 16003 ÷ 15
Correct
Answer: a)
√(65025) ÷ 5 × 12 = x – 16005 ÷ 15
(255/5)*12 = x – (16005/15)
612 = x – 1067
X = 612 + 1067
X = 1679 = 1680
Incorrect
Answer: a)
√(65025) ÷ 5 × 12 = x – 16005 ÷ 15
(255/5)*12 = x – (16005/15)
612 = x – 1067
X = 612 + 1067
X = 1679 = 1680
Question 7 of 20
7. Question
Directions (6 – 10): What approximate value should come in the place of question mark (?) in the following questions?
3 3/13 of 4354.9 – (27.13)^{2} = ? + 560.68
Correct
Answer: b)
3*4355 – 729 = x + 561
13065 – 729 – 561 = x
X = 11775
Incorrect
Answer: b)
3*4355 – 729 = x + 561
13065 – 729 – 561 = x
X = 11775
Question 8 of 20
8. Question
Directions (6 – 10): What approximate value should come in the place of question mark (?) in the following questions?
8 2/7 % of 14697 + 5 2/3 % of 19499 =?
Correct
Answer: d)
8 % of 14700 + 6 % of 19500 = x
(8/100)*14700 + (6/100)*19500 = x
X = 1176 + 1170
X = 2346 = 2350
Incorrect
Answer: d)
8 % of 14700 + 6 % of 19500 = x
(8/100)*14700 + (6/100)*19500 = x
X = 1176 + 1170
X = 2346 = 2350
Question 9 of 20
9. Question
Directions (6 – 10): What approximate value should come in the place of question mark (?) in the following questions?
(32.89)^{2} + 18 % of 699 – (4/7) of 888 =? – (11.12)^{3}
Correct
Answer: c)
(33)^{2} + 18 % of 700 – (4/7) of 889 = x – 11^{3}
1089 + (18/100)*700 – (4/7)*889 = x – 1331
1089 + 126 – 508 + 1331 = x
X = 2038 = 2040
Incorrect
Answer: c)
(33)^{2} + 18 % of 700 – (4/7) of 889 = x – 11^{3}
1089 + (18/100)*700 – (4/7)*889 = x – 1331
1089 + 126 – 508 + 1331 = x
X = 2038 = 2040
Question 10 of 20
10. Question
Directions (6 – 10): What approximate value should come in the place of question mark (?) in the following questions?
(4/9) of 1222 = ? – 127.4 × 51.21 ÷ 381
Correct
Answer: c)
(4/9)*1224 = x – (127 × 51)/381
544 + 17 = x
X = 561 = 560
Incorrect
Answer: c)
(4/9)*1224 = x – (127 × 51)/381
544 + 17 = x
X = 561 = 560
Question 11 of 20
11. Question
The radius of the semicircle is equal to the half the side of the square. The area of the square is 1764 Sq. Cm. Find the perimeter of the semicircle.
Correct
Answer: c)
Area of square = a^{2} = 1764
Side (a) = 42 cm
Radius of the semicircle = (1/2) * 42 = 21 cm
Perimeter of semicircle = πr + d
= > (22/7)*21 + 42 = 108 cm
Incorrect
Answer: c)
Area of square = a^{2} = 1764
Side (a) = 42 cm
Radius of the semicircle = (1/2) * 42 = 21 cm
Perimeter of semicircle = πr + d
= > (22/7)*21 + 42 = 108 cm
Question 12 of 20
12. Question
Pipe P and Q fill the tank in 15 min and 24 min respectively. If both the pipes are opened, after how much time Q should be closed so as to fill the tank in 10 min?
Correct
Answer: c)
Let Q should be closed after ‘x’ min,
According to the question,
(10/15) + (x/24) = 1
(x/24) = 1 – (2/3)
(x/24) = 1/3
X = 8 min
Incorrect
Answer: c)
Let Q should be closed after ‘x’ min,
According to the question,
(10/15) + (x/24) = 1
(x/24) = 1 – (2/3)
(x/24) = 1/3
X = 8 min
Question 13 of 20
13. Question
Find the difference between the compound interest on Rs. 50000 for 2 years at 6 % per annum compounded yearly and half yearly?
The marked price of A is Rs. 3200 more than the cost price. When the discount of Rs. 400 is allowed, the profit of 20 % is earned. At what price should A be sold to earn the profit of 25 %?
Correct
Answer: b)
Let the C.P be x,
M.P = 3200 + C.P = 3200 + x
S. P = (3200 + x) – 400 = 2800 + x
S.P = (120/100)*x = (6/5)*x
2800 + x = (6/5)*x
2800 = (1/5)*x
C.P(x) = 14000
To earn a profit of 25 %,
S. P = (125/100)*14000 = Rs. 17500
Incorrect
Answer: b)
Let the C.P be x,
M.P = 3200 + C.P = 3200 + x
S. P = (3200 + x) – 400 = 2800 + x
S.P = (120/100)*x = (6/5)*x
2800 + x = (6/5)*x
2800 = (1/5)*x
C.P(x) = 14000
To earn a profit of 25 %,
S. P = (125/100)*14000 = Rs. 17500
Question 15 of 20
15. Question
A jar contains 78 litres of mixture of milk and water in the ratio of 11: 2. 39 litres of mixture is taken out and 3 litres of water is added to the jar. Find the percentage of water in the mixture?
Correct
Answer: c)
Quantity of water in the mixture = 39 * (2/13) = 6 litres
Quantity of milk in the mixture = 39 * (11/13) = 33 litres
Remaining mixture = 78 – 39 = 39 litres
Now, 3 litres of water is added,
= > 6 + 3 = 9 litres
Percentage of water = (9/42)*100 = 150/7 = 21 3/7 %
Incorrect
Answer: c)
Quantity of water in the mixture = 39 * (2/13) = 6 litres
Quantity of milk in the mixture = 39 * (11/13) = 33 litres
Remaining mixture = 78 – 39 = 39 litres
Now, 3 litres of water is added,
= > 6 + 3 = 9 litres
Percentage of water = (9/42)*100 = 150/7 = 21 3/7 %
Question 16 of 20
16. Question
Directions (16 – 20): Study the following graph carefully and answer the given questions:
Following pie chart shows the percentage distribution of total number of mobile users in different networks in a certain state.
Total number of users = 10 Crore
The table shows the total number of male and females mobile users in different networks.
Total number of female Airtel network users is what percentage of total number of male Idea network users?
Correct
Answer: d)
Total number of female Airtel network users
= > 10*(22/100)*(6/11) = 1.2 Crore
Total number of male Idea network users
= > 10*(16/100)*(3/8) = 0.6 Crore
Required % = (1.2/0.6)*100 = 200 %
Incorrect
Answer: d)
Total number of female Airtel network users
= > 10*(22/100)*(6/11) = 1.2 Crore
Total number of male Idea network users
= > 10*(16/100)*(3/8) = 0.6 Crore
Required % = (1.2/0.6)*100 = 200 %
Question 17 of 20
17. Question
Directions (16 – 20): Study the following graph carefully and answer the given questions:
Following pie chart shows the percentage distribution of total number of mobile users in different networks in a certain state.
Total number of users = 10 Crore
The table shows the total number of male and females mobile users in different networks.
Find the ratio between total number of Reliance network users to that of total number of female Vodafone network users?
Correct
Answer: b)
Total number of Reliance network users
= > 10*(23/100) = 2.3 Crore
Total number of female Vodafone network users
= > 10*(21/100)*(3/7) = 0.9 Crore
Required ratio = 2.3: 0.9 = 23: 9
Incorrect
Answer: b)
Total number of Reliance network users
= > 10*(23/100) = 2.3 Crore
Total number of female Vodafone network users
= > 10*(21/100)*(3/7) = 0.9 Crore
Required ratio = 2.3: 0.9 = 23: 9
Question 18 of 20
18. Question
Directions (16 – 20): Study the following graph carefully and answer the given questions:
Following pie chart shows the percentage distribution of total number of mobile users in different networks in a certain state.
Total number of users = 10 Crore
The table shows the total number of male and females mobile users in different networks.
Find the difference between the total number of male BSNL network users to that of total number of female Airtel network users?
Correct
Answer: a)
The total number of male BSNL network users
= > 10*(18/100)*(5/9) = 1 Crore
The total number of female Airtel network users
= > 10*(22/100)*(6/11) = 1.2 Crore
Required difference = 1.2 – 1 = 0.2 Crore
Incorrect
Answer: a)
The total number of male BSNL network users
= > 10*(18/100)*(5/9) = 1 Crore
The total number of female Airtel network users
= > 10*(22/100)*(6/11) = 1.2 Crore
Required difference = 1.2 – 1 = 0.2 Crore
Question 19 of 20
19. Question
Directions (16 – 20): Study the following graph carefully and answer the given questions:
Following pie chart shows the percentage distribution of total number of mobile users in different networks in a certain state.
Total number of users = 10 Crore
The table shows the total number of male and females mobile users in different networks.
Find the average number of female mobile phone users of Reliance, Vodafone and Idea together?
Correct
Answer: c)
The total number of female mobile phone users of Reliance, Vodafone and Idea together
Directions (16 – 20): Study the following graph carefully and answer the given questions:
Following pie chart shows the percentage distribution of total number of mobile users in different networks in a certain state.
Total number of users = 10 Crore
The table shows the total number of male and females mobile users in different networks.
Total number of mobile phone users of Airtel network is approximately what percentage more than the total number of mobile phone users of Vodafone network?
Directions (1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
1) I. X^{2} +16x + 48 =0
II. y^{2} + 30y +81 =0
2) I. 5x^{2} +42x + 49 =0
II. 4y^{2} + 37y + 85 =0
3) I. x^{2} – 17x + 72 = 0
II. y^{2} – 13y + 40 = 0
4) I. 5x^{2} – 17x + 14 = 0
II. 8y^{2 }+ 3y – 5 = 0
5) I. 2x^{2} – 8x – 24 = 0
II. 3y^{2} + 18y + 24 = 0
Directions (6 – 10): What approximate value should come in the place of question mark (?) in the following questions?
6) √(65025) ÷ 5.32 × 12.21 = ? – 16003 ÷ 15
a) 1680
b) 1785
c) 1840
d) 1570
e) 1950
7) 3 3/13 of 4354.9 – (27.13)^{2} = ? + 560.68
a) 11360
b) 11775
c) 14570
d) 15890
e) 14565
8) 8 2/7 % of 14697 + 5 2/3 % of 19499 =?
a) 2570
b) 2045
c) 2130
d) 2350
e) 2890
9) (32.89)^{2} + 18 % of 699 – (4/7) of 888 =? – (11.12)^{3}
a) 2565
b) 2375
c) 2040
d) 2150
e) 2825
10) (4/9) of 1222 = ? – 127.4 × 51.21 ÷ 381
a) 480
b) 625
c) 560
d) 720
e) 750
11) The radius of the semicircle is equal to the half the side of the square. The area of the square is 1764 Sq. Cm. Find the perimeter of the semicircle.
a) 86 cm
b) 92 cm
c) 108 cm
d) 116 cm
e) None of these
12) Pipe P and Q fill the tank in 15 min and 24 min respectively. If both the pipes are opened, after how much time Q should be closed so as to fill the tank in 10 min?
a) 5 min
b) 6 min
c) 8 min
d) 7 min
e) None of these
13) Find the difference between the compound interest on Rs. 50000 for 2 years at 6 % per annum compounded yearly and half yearly?
a) 74.255
b) 95.4405
c) 82.5625
d) 90.625
e) None of these
14) The marked price of A is Rs. 3200 more than the cost price. When the discount of Rs. 400 is allowed, the profit of 20 % is earned. At what price should A be sold to earn the profit of 25 %?
a) 16250
b) 17500
c) 21750
d) 23800
e) None of these
15) A jar contains 78 litres of mixture of milk and water in the ratio of 11: 2. 39 litres of mixture is taken out and 3 litres of water is added to the jar. Find the percentage of water in the mixture?
a) 20 %
b) 24 %
c) 21 3/7 %
d) 27 1/3 %
e) None of these
Directions (16 – 20): Study the following graph carefully and answer the given questions:
Following pie chart shows the percentage distribution of total number of mobile users in different networks in a certain state.
Total number of users = 10 Crore
The table shows the total number of male and females mobile users in different networks.
Networks
Male : Female
BSNL
5 : 4
Airtel
5 : 6
Reliance
12 : 11
Vodafone
4 : 3
Idea
3 : 5
16) Total number of female Airtel network users is what percentage of total number of male Idea network users?
a) 150 %
b) 175 %
c) 225 %
d) 200 %
e) None of these
17) Find the ratio between total number of Reliance network users to that of total number of female Vodafone network users?
a) 18: 5
b) 23: 9
c) 29: 7
d) 33: 12
e) None of these
18) Find the difference between the total number of male BSNL network users to that of total number of female Airtel network users?
a) 0.2 Crore
b) 0.3 Crore
c) 0.5 Crore
d) 0.4 Crore
e) None of these
19) Find the average number of female mobile phone users of Reliance, Vodafone and Idea together?
a) 1.3 Crore
b) 1.5 Crore
c) 1 Crore
d) 1.8 Crore
e) None of these
20) Total number of mobile phone users of Airtel network is approximately what percentage more than the total number of mobile phone users of Vodafone network?
a) 5 %
b) 10 %
c) 15 %
d) 20 %
e) 25 %
Answers:
Direction (1-5)
1) Answer: e)
I. X^{2} + 16x + 48 =0
X^{2} +12x+4x+ 48 =0
(x+12) (x+4) =0
X= -12, -4
II. y^{2} + 30y +81 =0
y^{2} + 3y+27y +81 =0
(y+3) (y+27) =0
Y = -3, -27
Can’t be determined
2) Answer: e)
I. 5x^{2} +42x + 49 =0
5x^{2} +35x + 7x + 49 =0
5x(x+7) + 7(x+7) =0
(5x+7) (x+7) =0
X= -7/5, -7
II. 4y^{2} + 37y + 85 =0
4y^{2} + 20y+17y + 85 =0
4y(y+5) + 17 (y+5) =0
(4y+17)(y+5) =0
Y = -17/4, -5
Can’t be determined
3) Answer: b)
I. x^{2} – 17x + 72 = 0
x^{2} – 8x – 9x + 72 = 0
x(x – 8) -9 (x – 8) = 0
(x – 9) (x – 8) = 0
X = 9, 8
II. y^{2} – 13y + 40 = 0
y^{2} – 5y – 8y + 40 = 0
y(y – 5) – 8(y – 5) = 0
(y – 8) (y – 5) = 0
Y = 8, 5
x ≥ y
4) Answer: a)
I. 5x^{2} – 17x + 14 = 0
5x^{2} – 10x – 7x + 14 = 0
5x(x – 2) -7 (x – 2) = 0
(5x – 7) (x – 2) = 0
X = 7/5, 2 = 1.4, 2
II. 8y^{2 }+ 3y – 5 = 0
8y^{2 }+ 8y – 5y – 5 = 0
8y(y + 1) – 5(y + 1) = 0
(8y – 5)(y + 1) = 0
Y = 5/8, -1 = 0.625, -1
X > y
5) Answer: b)
I. 2x^{2} – 8x – 24 = 0
2x^{2} + 4x – 12x – 24 = 0
2x(x + 2) – 12(x + 2) = 0
(2x -12) (x + 2) = 0
X = 12/2, – 2 = 6, -2
II. 3y^{2} + 18y + 24 = 0
3y^{2} + 6y + 12y + 24 = 0
3y(y + 2) + 12(y + 2) = 0
(3y + 12) (y + 2) = 0
Y = -12/3, -2 = -4, -2
x ≥ y
Direction (6-10)
6) Answer: a)
√(65025) ÷ 5 × 12 = x – 16005 ÷ 15
(255/5)*12 = x – (16005/15)
612 = x – 1067
X = 612 + 1067
X = 1679 = 1680
7) Answer: b)
3*4355 – 729 = x + 561
13065 – 729 – 561 = x
X = 11775
8) Answer: d)
8 % of 14700 + 6 % of 19500 = x
(8/100)*14700 + (6/100)*19500 = x
X = 1176 + 1170
X = 2346 = 2350
9) Answer: c)
(33)^{2} + 18 % of 700 – (4/7) of 889 = x – 11^{3}