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Directions (6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
8x^{2} + 5x – 42 = 0
7y^{2} + 43y + 60 = 0
Correct
Answer: e)
I. 8x^{2} + 5x – 42 = 0
8x^{2} – 16x + 21x – 42 = 0
8x (x – 2) + 21 (x – 2) = 0
(8x + 21) (x – 2) = 0
X = -21/8, 2 = -2.625, 2
II. 7y^{2} + 43y + 60 = 0
7y^{2} + 28y + 15y + 60 = 0
7y(y + 4) + 15(y + 4) = 0
(7y + 15) (y + 4) = 0
Y = -15/7, -4 = – 2.14, -4
Can’t be determined
Incorrect
Answer: e)
I. 8x^{2} + 5x – 42 = 0
8x^{2} – 16x + 21x – 42 = 0
8x (x – 2) + 21 (x – 2) = 0
(8x + 21) (x – 2) = 0
X = -21/8, 2 = -2.625, 2
II. 7y^{2} + 43y + 60 = 0
7y^{2} + 28y + 15y + 60 = 0
7y(y + 4) + 15(y + 4) = 0
(7y + 15) (y + 4) = 0
Y = -15/7, -4 = – 2.14, -4
Can’t be determined
Question 7 of 20
7. Question
Directions (6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
7x^{2} – 34x – 5 = 0
2y^{2} + 3y – 14 = 0
Correct
Answer: e)
I. 7x^{2} – 34x – 5 = 0
7x^{2} – 35x + x – 5 = 0
7x(x – 5) + 1 (x – 5) = 0
(7x + 1) (x – 5) = 0
X = -1/7, 5 = – 0.14, 5
II. 2y^{2} + 3y – 14 = 0
2y^{2} – 4y + 7y – 14 = 0
2y(y – 2) + 7(y – 2) = 0
(2y + 7) (y -2) = 0
Y = -7/2, 2 = -3.5, 2
Can’t be determined
Incorrect
Answer: e)
I. 7x^{2} – 34x – 5 = 0
7x^{2} – 35x + x – 5 = 0
7x(x – 5) + 1 (x – 5) = 0
(7x + 1) (x – 5) = 0
X = -1/7, 5 = – 0.14, 5
II. 2y^{2} + 3y – 14 = 0
2y^{2} – 4y + 7y – 14 = 0
2y(y – 2) + 7(y – 2) = 0
(2y + 7) (y -2) = 0
Y = -7/2, 2 = -3.5, 2
Can’t be determined
Question 8 of 20
8. Question
Directions (6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
2x^{2} – 2x – 24 = 0
4y^{2} + 17y + 18 = 0
Correct
Answer: e)
I. 2x^{2} – 2x – 24 = 0
2x^{2} – 8x + 6x – 24 = 0
2x (x – 4) + 6 (x – 4) = 0
(2x + 6) (x – 4) = 0
X = -3, 4
II. 4y^{2} + 17y + 18 = 0
4y^{2} + 8y + 9y + 18 = 0
4y(y + 2) + 9 (y + 2) =0
(4y + 9) (y + 2) =0
Y = -9/4, -2 = -2.25, -2
Can’t be determined
Incorrect
Answer: e)
I. 2x^{2} – 2x – 24 = 0
2x^{2} – 8x + 6x – 24 = 0
2x (x – 4) + 6 (x – 4) = 0
(2x + 6) (x – 4) = 0
X = -3, 4
II. 4y^{2} + 17y + 18 = 0
4y^{2} + 8y + 9y + 18 = 0
4y(y + 2) + 9 (y + 2) =0
(4y + 9) (y + 2) =0
Y = -9/4, -2 = -2.25, -2
Can’t be determined
Question 9 of 20
9. Question
Directions (6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
12x^{2} – 17x + 7 = 0
10y^{2} + 37y – 12 = 0
Correct
Answer: e)
I. 12x^{2} – 17x + 7 = 0
12x^{2} + 4x – 21x + 7 = 0
4x(3x – 1) -7(3x -1) = 0
(4x – 7) (3x – 1) = 0
X = 7/4, 1/3 = 1.75, 0.33
II. 10y^{2} – 7y – 12 = 0
10y^{2} – 15y + 8y – 12 = 0
5y(2y – 3) + 4 (2y – 3) = 0
(5y + 4) (2y – 3) = 0
Y = – 4/5, 3/2 = -0.8, 1.5
Can’t be determined
Incorrect
Answer: e)
I. 12x^{2} – 17x + 7 = 0
12x^{2} + 4x – 21x + 7 = 0
4x(3x – 1) -7(3x -1) = 0
(4x – 7) (3x – 1) = 0
X = 7/4, 1/3 = 1.75, 0.33
II. 10y^{2} – 7y – 12 = 0
10y^{2} – 15y + 8y – 12 = 0
5y(2y – 3) + 4 (2y – 3) = 0
(5y + 4) (2y – 3) = 0
Y = – 4/5, 3/2 = -0.8, 1.5
Can’t be determined
Question 10 of 20
10. Question
Directions (6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
x^{2} = 1369
y = ∛4913
Correct
Answer: e)
I. x^{2} = 1369
X = 37, -37
II. y = ∛4913
Y = 17
Can’t be determined
Incorrect
Answer: e)
I. x^{2} = 1369
X = 37, -37
II. y = ∛4913
Y = 17
Can’t be determined
Question 11 of 20
11. Question
Mahesh can do a work in 24 days. He works alone for 6 days and Naren alone finishes the remaining work in 12 days. Both of them together can complete the work in?
Correct
Answer: d)
Mahesh one day work = 1/24
6 days work = 6/24 = 1/4
Remaining work = 1 – (1/4) = 3/4
Naren alone finishes the remaining work in 12 days.
= > (3/4) * Naren’s whole work = 12
= > Naren’s whole work = 16 days
Mahesh and Naren’s one day work,
= > (1/24) + (1/16)
= > 5/48
Both Mahesh and Naren together complete the work in,
= > 48/5 days = 9 3/5 days
Incorrect
Answer: d)
Mahesh one day work = 1/24
6 days work = 6/24 = 1/4
Remaining work = 1 – (1/4) = 3/4
Naren alone finishes the remaining work in 12 days.
= > (3/4) * Naren’s whole work = 12
= > Naren’s whole work = 16 days
Mahesh and Naren’s one day work,
= > (1/24) + (1/16)
= > 5/48
Both Mahesh and Naren together complete the work in,
= > 48/5 days = 9 3/5 days
Question 12 of 20
12. Question
A, B and C started a business by investing Rs. 40500, Rs. 45000 and Rs. 60000 respectively. After 6 months C withdrew Rs. 15000 while A invested Rs. 4500 more. If the total profit at the end of the year is Rs. 149600, then the share of C will exceed that of A by?
The difference between the shares of A to that of C
= > 13’s = 13*800 = Rs. 10400
Question 13 of 20
13. Question
The simple interest accrued on an amount of Rs. 17,000 at the end of 4 years is Rs. 6800. What would be the compound interest accrued on the same amount at the same rate in the same period?
Correct
Answer: a)
S.I = PNR/100
6800 = (17000*4*R)/100
R = (6800*100)/(17000*4) = 10%
C.I = P*(1 + (R/100))^{n} – 1)
= > 17000*(1 + (10/100))^{4} – 1)
= > 17000*(110/100)^{4} – 1)
= > 17000*[(14641/10000) – 1]
= > 17000*(4641/10000)
= > Rs. 7889.70
Incorrect
Answer: a)
S.I = PNR/100
6800 = (17000*4*R)/100
R = (6800*100)/(17000*4) = 10%
C.I = P*(1 + (R/100))^{n} – 1)
= > 17000*(1 + (10/100))^{4} – 1)
= > 17000*(110/100)^{4} – 1)
= > 17000*[(14641/10000) – 1]
= > 17000*(4641/10000)
= > Rs. 7889.70
Question 14 of 20
14. Question
Smallest angle of a triangle is equal to two-third of the smallest angle of a quadrilateral. The ratio between the angles of the quadrilateral is 3: 4: 5: 6. Largest angle of the triangle is twice its smallest angle. What is the sum of second largest angle of the triangle and largest angle of the quadrilateral?
Correct
Answer: b)
The ratio between the angles of the quadrilateral = 3: 4: 5: 6
3x + 4x + 5x + 6x = 360
=> 18x = 360
=> x = 20
Smallest angle of triangle = (2/3)*60 = 40
Largest angle of the triangle = 2*40 = 80
Second largest angle of the triangle = 180 – 40 – 80 = 60
Required sum = 60 + 120 = 180°
Incorrect
Answer: b)
The ratio between the angles of the quadrilateral = 3: 4: 5: 6
3x + 4x + 5x + 6x = 360
=> 18x = 360
=> x = 20
Smallest angle of triangle = (2/3)*60 = 40
Largest angle of the triangle = 2*40 = 80
Second largest angle of the triangle = 180 – 40 – 80 = 60
Required sum = 60 + 120 = 180°
Question 15 of 20
15. Question
If the numerator of a fraction is increased by 350% and the denominator of the fraction is increased by 150%, the resultant fraction becomes 27/50. Then find the original fraction?
Correct
Answer: d)
The original fraction is,
= > (x*(450/100))/(y*(250/100)) = 27/50
= > x/y = 27*5/9*50 = 3/10
Incorrect
Answer: d)
The original fraction is,
= > (x*(450/100))/(y*(250/100)) = 27/50
= > x/y = 27*5/9*50 = 3/10
Question 16 of 20
16. Question
Directions (16 – 20): Study the following information carefully and answer the given questions.
Following table shows the total number of students and the percentage of girl students among them and the ratio of total number of students and teachers in 5 different schools.
Total number of boy students in school Q is what percentage of total number of boys in school S?
Correct
Answer: b)
Total number of boy students in school Q
= > 1500*(54/100) = 810
Total number of boys in school S
= > 1800*(60/100) = 1080
Required % = (810/1080)*100 = 75 %
Incorrect
Answer: b)
Total number of boy students in school Q
= > 1500*(54/100) = 810
Total number of boys in school S
= > 1800*(60/100) = 1080
Required % = (810/1080)*100 = 75 %
Question 17 of 20
17. Question
Directions (16 – 20): Study the following information carefully and answer the given questions.
Following table shows the total number of students and the percentage of girl students among them and the ratio of total number of students and teachers in 5 different schools.
Find the ratio between the total number of girl students in School P to that of School R?
Correct
Answer: d)
The total number of girl students in School P
= > 2000*(52/100) = 1040
The total number of girl students in School R
= > 1200*(55/100) = 660
Required ratio = 1040 : 660 = 52 : 33
Incorrect
Answer: d)
The total number of girl students in School P
= > 2000*(52/100) = 1040
The total number of girl students in School R
= > 1200*(55/100) = 660
Required ratio = 1040 : 660 = 52 : 33
Question 18 of 20
18. Question
Directions (16 – 20): Study the following information carefully and answer the given questions.
Following table shows the total number of students and the percentage of girl students among them and the ratio of total number of students and teachers in 5 different schools.
Find the difference between the total number of teachers in school Q to that of school T?
Correct
Answer: c)
The total number of teachers in school Q
= > (1500/25) = 60
The total number of teachers in school T
= > (2400/48) = 50
Required difference = 60 – 50 = 10
Incorrect
Answer: c)
The total number of teachers in school Q
= > (1500/25) = 60
The total number of teachers in school T
= > (2400/48) = 50
Required difference = 60 – 50 = 10
Question 19 of 20
19. Question
Directions (16 – 20): Study the following information carefully and answer the given questions.
Following table shows the total number of students and the percentage of girl students among them and the ratio of total number of students and teachers in 5 different schools.
Find the total number of teachers in school P, R and S together?
Correct
Answer: a)
The total number of teachers in school P, R and S together
= > (2000/50) + (1200/24) + (1800/36)
= > 40 + 50 + 50 = 140
Incorrect
Answer: a)
The total number of teachers in school P, R and S together
= > (2000/50) + (1200/24) + (1800/36)
= > 40 + 50 + 50 = 140
Question 20 of 20
20. Question
Directions (16 – 20): Study the following information carefully and answer the given questions.
Following table shows the total number of students and the percentage of girl students among them and the ratio of total number of students and teachers in 5 different schools.
Total number of students in school P is approximately what percentage more/less than the total number of students in school R?
5) 58.3 % of 749 + (1760 ÷ 15) × (27.21)^{2} =? – (4/9) of 2751
a) 75600
b) 71400
c) 73500
d) 77800
e) 87200
Directions (6 – 10): In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established
6) I. 8x^{2} + 5x – 42 = 0
II. 7y^{2} + 43y + 60 = 0
7) I. 7x^{2} – 34x – 5 = 0
II. 2y^{2} + 3y – 14 = 0
8) I. 2x^{2} – 2x – 24 = 0
II. 4y^{2} + 17y + 18 = 0
9) I. 12x^{2} – 17x + 7 = 0
II. 10y^{2} + 37y – 12 = 0
10) I. x^{2} = 1369
II. y = ∛4913
11) Mahesh can do a work in 24 days. He works alone for 6 days and Naren alone finishes the remaining work in 12 days. Both of them together can complete the work in?
a) 7 2/7 days
b) 15 ¼ days
c) 12 2/3 days
d) 9 3/5 days
e) None of these
12) A, B and C started a business by investing Rs. 40500, Rs. 45000 and Rs. 60000 respectively. After 6 months C withdrew Rs. 15000 while A invested Rs. 4500 more. If the total profit at the end of the year is Rs. 149600, then the share of C will exceed that of A by?
a) Rs. 19000
b) Rs. 11500
c) Rs. 13000
d) Rs. 10400
e) None of these
13) The simple interest accrued on an amount of Rs. 17,000 at the end of 4 years is Rs. 6800. What would be the compound interest accrued on the same amount at the same rate in the same period?
a) Rs. 7889.70
b) Rs. 8324.20
c) Rs. 6990.50
d) Rs. 7129.30
e) Rs. 7558.60
14) Smallest angle of a triangle is equal to two-third of the smallest angle of a quadrilateral. The ratio between the angles of the quadrilateral is 3: 4: 5: 6. Largest angle of the triangle is twice its smallest angle. What is the sum of second largest angle of the triangle and largest angle of the quadrilateral?
a) 160°
b) 180°
c) 190°
d) 170°
e) 150°
15) If the numerator of a fraction is increased by 350% and the denominator of the fraction is increased by 150%, the resultant fraction becomes 27/50. Then find the original fraction?
a) 13/15
b) 11/17
c) 11/13
d) 3/10
e) None of these
Directions (16 – 20): Study the following information carefully and answer the given questions.
Following table shows the total number of students and the percentage of girl students among them and the ratio of total number of students and teachers in 5 different schools.
Schools
Total number of students
% of girl students
Total students : Teachers
P
2000
52 %
50 : 1
Q
1500
46 %
25 : 1
R
1200
55 %
24 : 1
S
1800
40 %
36 : 1
T
2400
48 %
48 : 1
16) Total number of boy students in school Q is what percentage of total number of boys in school S?
a) 60 %
b) 75 %
c) 90 %
d) 80 %
e) None of these
17) Find the ratio between the total number of girl students in School P to that of School R?
a) 15: 8
b) 21: 13
c) 34: 15
d) 52: 33
e) None of these
18) Find the difference between the total number of teachers in school Q to that of school T?
a) 15
b) 25
c) 10
d) 20
e) None of these
19) Find the total number of teachers in school P, R and S together?
a) 140
b) 120
c) 105
d) 130
e) None of these
20) Total number of students in school P is approximately what percentage more/less than the total number of students in school R?