“20-20” Quantitative Aptitude | Crack IBPS PO Prelims 2018 Day-192
Dear Readers, Find the aptitude test questions to crack latest bank exams. We regularly provide 20 aptitude test questions daily for students. Aspirants practice these questions on a regular basis to improve your score in aptitude section. Aspirants preparing for the exams can make use of this “20-20” Quantitative Aptitude Questions. Here we have started New Series of Practice Materials specially for Crack IBPS PO Prelims 2018. Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.
Are You preparing for Bank exams 2019? Start your preparation with Free Mock test Series.
X – (21*21*1725)/525 + 4913 = (58/100)*8800 + (57900/15)
X – 1449 + 4913 = 5104 + 3860
X = 5104 + 3860 + 1449 – 4913
X = 5500
Incorrect
Answer: d)
X – (21*21*1725)/525 + 4913 = (58/100)*8800 + (57900/15)
X – 1449 + 4913 = 5104 + 3860
X = 5104 + 3860 + 1449 – 4913
X = 5500
Question 8 of 20
8. Question
Directions (6 – 10): what value should come in place of question mark (?) in the following questions?
45 % of 3800 + (5/9) of 3402 – 216 × 78 ÷ 5616 = ?
Correct
Answer: b)
(45/100)*3800 + (5/9)*3402 – (216*78)/5616 = x
X = 1710 + 1890 – 3
X = 3597
Incorrect
Answer: b)
(45/100)*3800 + (5/9)*3402 – (216*78)/5616 = x
X = 1710 + 1890 – 3
X = 3597
Question 9 of 20
9. Question
Directions (6 – 10): what value should come in place of question mark (?) in the following questions?
√2916 ÷ 9 + ∛5639752 = 12^{3} + 27 % of 1500 – ?
Correct
Answer: a)
(54/9) + 178 = 1728 + (27/100)*1500 – x
6 + 178 = 1728 + 405 – x
x = 1728 + 405 – 6 – 178
x = 1949
Incorrect
Answer: a)
(54/9) + 178 = 1728 + (27/100)*1500 – x
6 + 178 = 1728 + 405 – x
x = 1728 + 405 – 6 – 178
x = 1949
Question 10 of 20
10. Question
Directions (6 – 10): what value should come in place of question mark (?) in the following questions?
∛1771561 – √12996* ? + (2/11) of 825 – 14 = 29
Correct
Answer: c)
121 – (114*x) + (2/11)*825 – 14 = 29
121 – (114*x) + 150 – 14 = 29
121 + 150 – 14 – 29 = (114*x)
228 = (114*x)
X = 228/114
X = 2
Incorrect
Answer: c)
121 – (114*x) + (2/11)*825 – 14 = 29
121 – (114*x) + 150 – 14 = 29
121 + 150 – 14 – 29 = (114*x)
228 = (114*x)
X = 228/114
X = 2
Question 11 of 20
11. Question
Sum of the circumference of circle and perimeter of rectangle is 148 cm. Find the area of circle, if the area of rectangle is 216 Sq cm and the length of rectangle is 18 cm?
Correct
Answer: d)
Sum of the circumference of circle and perimeter of rectangle = 148 cm
Area of rectangle = lb = 216 Sq cm
= > 18*b = 216
= > Breadth (b) = 216/18 = 12 cm
Perimeter of rectangle = 2*(l + b) = 2*(18 + 12) = 60 cm
The circumference of circle = 148 – 60 = 88 cm
= > 2πr = 88
= > 2*(22/7)*r = 88
= > r = 14 cm
Area of circle = πr^{2} = (22/7)*14*14 = 616 Sq cm
Incorrect
Answer: d)
Sum of the circumference of circle and perimeter of rectangle = 148 cm
Area of rectangle = lb = 216 Sq cm
= > 18*b = 216
= > Breadth (b) = 216/18 = 12 cm
Perimeter of rectangle = 2*(l + b) = 2*(18 + 12) = 60 cm
The circumference of circle = 148 – 60 = 88 cm
= > 2πr = 88
= > 2*(22/7)*r = 88
= > r = 14 cm
Area of circle = πr^{2} = (22/7)*14*14 = 616 Sq cm
Question 12 of 20
12. Question
Find the difference between compound interest on Rs. 25000 for 1 year at 8 % per annum compounded yearly and half yearly?
Correct
Answer: b)
Compounded yearly,
= > 25000*(8/100) = 2000
C.I = 2000
Compounded half yearly,
= > 25000*(4/100) = 1000
= > 26000*(4/100) = 1040
C.I = 1000 + 1040 = 2040
Difference = 2040 – 2000 = Rs. 40
Incorrect
Answer: b)
Compounded yearly,
= > 25000*(8/100) = 2000
C.I = 2000
Compounded half yearly,
= > 25000*(4/100) = 1000
= > 26000*(4/100) = 1040
C.I = 1000 + 1040 = 2040
Difference = 2040 – 2000 = Rs. 40
Question 13 of 20
13. Question
A invested one fifth of the investment for three-fourth of total period and B invested two third of the investment for one fourth of the total period and C invested the remaining amount for 3 months. Total profit at the end of the year is Rs. 63000. Find the share of B?
A boat can travel 24.5 km downstream in 42 minutes. If the speed of the current is 2/5 of the speed of the boat in still water, what distance can the boat travel in 27 minutes?
Correct
Answer: a)
Let the speed of the boat in still water be x km/hr,
A vessels contains 80 liters of pure milk. From this 30 liters of milk is replaced with water. The process is repeated one more time. Find the quantity of milk in the final solution?
Correct
Answer: a)
According to the formula,
Quantity of milk left = 80*(1 – (30/80))^{2}
= > 80*(5/8)*(5/8)
= > 31.25 liters
Incorrect
Answer: a)
According to the formula,
Quantity of milk left = 80*(1 – (30/80))^{2}
= > 80*(5/8)*(5/8)
= > 31.25 liters
Question 16 of 20
16. Question
Directions (16 – 20): Study the following information carefully and answer the given questions:
The sports club consisting of 5000 members, the ratio of males to females among them is 3: 2. They are all enrolled in five different games viz., Boxing, Badminton, Table tennis, Volley ball and Foot ball. 15 % of females are enrolled for boxing. 18 % of males are enrolled for Foot ball. One eighth of the females are enrolled for Badminton. The ratio of total number of females enrolled for badminton to that of Football is 1: 3. 22 % of males are enrolled for badminton. The total number of females enrolled for Table tennis is three fifth of total number of males enrolled for boxing. The one sixth of total number of males enrolled for boxing. The ratio of total number of males to that of females enrolled for Volley ball is 3: 2.
Find the difference between the total number of male badminton players to that of female volley ball players?
Correct
Directions (16 – 20):
Total number of players = 5000
Total number of male players = 5000*(3/5) = 3000
Total number of female players = 5000*(2/5) = 2000
Total number of female players enrolled for boxing = 2000*(15/100) = 300
Total number of male players enrolled for Foot ball = 3000*(18/100) = 540
Total number of female players enrolled for Badminton = 2000*(1/8) = 250
The ratio of total number of females enrolled for badminton to that of Football
= > 1 : 3 (x, 3x)
Total number of female players enrolled for Foot ball = 250*3 = 750
Total number of male players enrolled for Badminton = 3000*(22/100) = 660
The total number of males enrolled for boxing = 3000*(1/6) = 500
The total number of females enrolled for Table tennis
= > (3/5)*total number of males enrolled for boxing
= > (3/5)*500 = 300
The total number of females enrolled for volley ball
= > 2000 – (300 + 250 + 300 + 750) = 400
The ratio of total number of males to that of females enrolled for Volley ball
= > 3 : 2 (3x, 2x)
The total number of males enrolled for volley ball
= > (400/2)*3 = 600
The total number of males enrolled for Table tennis
= > 3000 – (500 + 660 + 600 + 540) = 700
Answer: d)
The total number of male badminton players = 660
The total number of female volley ball players = 400
Required difference = 660 – 400 = 260
Incorrect
Directions (16 – 20):
Total number of players = 5000
Total number of male players = 5000*(3/5) = 3000
Total number of female players = 5000*(2/5) = 2000
Total number of female players enrolled for boxing = 2000*(15/100) = 300
Total number of male players enrolled for Foot ball = 3000*(18/100) = 540
Total number of female players enrolled for Badminton = 2000*(1/8) = 250
The ratio of total number of females enrolled for badminton to that of Football
= > 1 : 3 (x, 3x)
Total number of female players enrolled for Foot ball = 250*3 = 750
Total number of male players enrolled for Badminton = 3000*(22/100) = 660
The total number of males enrolled for boxing = 3000*(1/6) = 500
The total number of females enrolled for Table tennis
= > (3/5)*total number of males enrolled for boxing
= > (3/5)*500 = 300
The total number of females enrolled for volley ball
= > 2000 – (300 + 250 + 300 + 750) = 400
The ratio of total number of males to that of females enrolled for Volley ball
= > 3 : 2 (3x, 2x)
The total number of males enrolled for volley ball
= > (400/2)*3 = 600
The total number of males enrolled for Table tennis
= > 3000 – (500 + 660 + 600 + 540) = 700
Answer: d)
The total number of male badminton players = 660
The total number of female volley ball players = 400
Required difference = 660 – 400 = 260
Question 17 of 20
17. Question
Directions (16 – 20): Study the following information carefully and answer the given questions:
The sports club consisting of 5000 members, the ratio of males to females among them is 3: 2. They are all enrolled in five different games viz., Boxing, Badminton, Table tennis, Volley ball and Foot ball. 15 % of females are enrolled for boxing. 18 % of males are enrolled for Foot ball. One eighth of the females are enrolled for Badminton. The ratio of total number of females enrolled for badminton to that of Football is 1: 3. 22 % of males are enrolled for badminton. The total number of females enrolled for Table tennis is three fifth of total number of males enrolled for boxing. The one sixth of total number of males enrolled for boxing. The ratio of total number of males to that of females enrolled for Volley ball is 3: 2.
Find the ratio between the total number of male boxing and Foot ball players together to that of total number of female badminton and volley ball players together?
Correct
Answer: b)
The total number of male boxing and Foot ball players together
= > 500 + 540 = 1040
The total number of female badminton and volley ball players together
= > 250 + 400 = 650
Required ratio = 1040: 650 = 8: 5
Incorrect
Answer: b)
The total number of male boxing and Foot ball players together
= > 500 + 540 = 1040
The total number of female badminton and volley ball players together
= > 250 + 400 = 650
Required ratio = 1040: 650 = 8: 5
Question 18 of 20
18. Question
Directions (16 – 20): Study the following information carefully and answer the given questions:
The sports club consisting of 5000 members, the ratio of males to females among them is 3: 2. They are all enrolled in five different games viz., Boxing, Badminton, Table tennis, Volley ball and Foot ball. 15 % of females are enrolled for boxing. 18 % of males are enrolled for Foot ball. One eighth of the females are enrolled for Badminton. The ratio of total number of females enrolled for badminton to that of Football is 1: 3. 22 % of males are enrolled for badminton. The total number of females enrolled for Table tennis is three fifth of total number of males enrolled for boxing. The one sixth of total number of males enrolled for boxing. The ratio of total number of males to that of females enrolled for Volley ball is 3: 2.
Find the average number of male boxing, table tennis and volley ball players together?
Correct
Answer: a)
The average number of male boxing, table tennis and volley ball players together
= > [500 + 700 + 600]/3
= > 1800/3 = 600
Incorrect
Answer: a)
The average number of male boxing, table tennis and volley ball players together
= > [500 + 700 + 600]/3
= > 1800/3 = 600
Question 19 of 20
19. Question
Directions (16 – 20): Study the following information carefully and answer the given questions:
The sports club consisting of 5000 members, the ratio of males to females among them is 3: 2. They are all enrolled in five different games viz., Boxing, Badminton, Table tennis, Volley ball and Foot ball. 15 % of females are enrolled for boxing. 18 % of males are enrolled for Foot ball. One eighth of the females are enrolled for Badminton. The ratio of total number of females enrolled for badminton to that of Football is 1: 3. 22 % of males are enrolled for badminton. The total number of females enrolled for Table tennis is three fifth of total number of males enrolled for boxing. The one sixth of total number of males enrolled for boxing. The ratio of total number of males to that of females enrolled for Volley ball is 3: 2.
Total number of male foot ball player is what percentage of total number of female boxing player?
Correct
Answer: c)
Total number of male foot ball player = 540
Total number of female boxing player = 300
Required % = (540/300)*100 = 180 %
Incorrect
Answer: c)
Total number of male foot ball player = 540
Total number of female boxing player = 300
Required % = (540/300)*100 = 180 %
Question 20 of 20
20. Question
Directions (16 – 20): Study the following information carefully and answer the given questions:
The sports club consisting of 5000 members, the ratio of males to females among them is 3: 2. They are all enrolled in five different games viz., Boxing, Badminton, Table tennis, Volley ball and Foot ball. 15 % of females are enrolled for boxing. 18 % of males are enrolled for Foot ball. One eighth of the females are enrolled for Badminton. The ratio of total number of females enrolled for badminton to that of Football is 1: 3. 22 % of males are enrolled for badminton. The total number of females enrolled for Table tennis is three fifth of total number of males enrolled for boxing. The one sixth of total number of males enrolled for boxing. The ratio of total number of males to that of females enrolled for Volley ball is 3: 2.
Total number of male badminton and volleyball players together is what percentage more than the total number of female football players?
Correct
Answer: b)
Total number of male badminton and volleyball players together
= > 660 + 600 = 1260
Total number of female football players = 750
Required % = [(1260 – 750)/750]*100 = 68 %
Incorrect
Answer: b)
Total number of male badminton and volleyball players together
= > 660 + 600 = 1260
Total number of female football players = 750
Required % = [(1260 – 750)/750]*100 = 68 %
Click “Start Quiz” to attend these Questions and view Solutions
11) Sum of the circumference of circle and perimeter of rectangle is 148 cm. Find the area of circle, if the area of rectangle is 216 Sq cm and the length of rectangle is 18 cm?
a) 576 Sq cm
b) 684 Sq cm
c) 720 Sq cm
d) 616 Sq cm
e) None of these
12) Find the difference between compound interest on Rs. 25000 for 1 year at 8 % per annum compounded yearly and half yearly?
a) Rs. 25
b) Rs. 40
c) Rs. 35
d) Rs. 50
e) None of these
13) A invested one fifth of the investment for three-fourth of total period and B invested two third of the investment for one fourth of the total period and C invested the remaining amount for 3 months. Total profit at the end of the year is Rs. 63000. Find the share of B?
a) Rs. 22000
b) Rs. 25000
c) Rs. 28000
d) Rs. 30000
e) None of these
14) A boat can travel 24.5 km downstream in 42 minutes. If the speed of the current is 2/5 of the speed of the boat in still water, what distance can the boat travel in 27 minutes?
a) 11.25 km
b) 15 km
c) 17.6 km
d) 19 km
e) None of these
15) A vessels contains 80 liters of pure milk. From this 30 liters of milk is replaced with water. The process is repeated one more time. Find the quantity of milk in the final solution?
a) 31.25 liters
b) 34 liters
c) 29 liters
d) 27 liters
e) None of these
Directions (16 – 20): Study the following information carefully and answer the given questions:
The sports club consisting of 5000 members, the ratio of males to females among them is 3: 2. They are all enrolled in five different games viz., Boxing, Badminton, Table tennis, Volley ball and Foot ball. 15 % of females are enrolled for boxing. 18 % of males are enrolled for Foot ball. One eighth of the females are enrolled for Badminton. The ratio of total number of females enrolled for badminton to that of Football is 1: 3. 22 % of males are enrolled for badminton. The total number of females enrolled for Table tennis is three fifth of total number of males enrolled for boxing. The one sixth of total number of males enrolled for boxing. The ratio of total number of males to that of females enrolled for Volley ball is 3: 2.
16) Find the difference between the total number of male badminton players to that of female volley ball players?
a) 280
b) 340
c) 170
d) 260
e) None of these
17) Find the ratio between the total number of male boxing and Foot ball players together to that of total number of female badminton and volley ball players together?
a) 5 : 3
b) 8 : 5
c) 11 : 7
d) 9 : 7
e) None of these
18) Find the average number of male boxing, table tennis and volley ball players together?
a) 600
b) 550
c) 625
d) 575
e) None of these
19) Total number of male foot ball player is what percentage of total number of female boxing player?
a) 150 %
b) 130 %
c) 180 %
d) 165 %
e) None of these
20) Total number of male badminton and volleyball players together is what percentage more than the total number of female football players?
a) 75 %
b) 68 %
c) 56 %
d) 80 %
e) None of these
Answers:
1) Answer: d)
I. 12x^{2} – 40x + 32 = 0
12x^{2} – 24x – 16x + 32 = 0
12x(x – 2) – 16(x – 2) = 0
(12x – 16) (x – 2) = 0
X = 16/12, 2 = 1.33, 2
II.8y^{2} – 40y + 48 = 0
8y^{2} – 16y – 24y + 48 = 0
8y(y – 2) – 24(y – 2) = 0
(8y – 24) (y – 2) = 0
Y = 3, 2
x ≤ y
2) Answer: a)
9x – 7y = 15–> (1)
3x – y = – 3—> (2)
By solving the equation (1) and (2), we get,
X = -3, y = -6
X > y
3) Answer: e)
I. 12x^{2} + 40x + 32 = 0
12x^{2} + 24x + 16x + 32 = 0
12x(x + 2) + 16(x + 2) = 0
(12x + 16) (x + 2) = 0
X = -16/12, -2 = -1.33, -2
II. 8y^{2} + 40y + 42 = 0
8y^{2} + 12y + 28y + 42 = 0
4y (2y + 3) + 14(2y + 3) = 0
(4y + 14) (2y + 3) = 0
Y = -14/4, -3/2 = -3.5, -1.5
Can’t be determined
4) Answer: e)
I. 4x^{2} – 7x – 57 = 0
4x^{2} +12x – 19x – 57 = 0
4x(x + 3) – 19(x + 3) = 0
(4x – 19)(x + 3) = 0
X = 19/4, -3 = 4.75, – 3
II. 5y^{2} – 6y – 63 = 0
5y^{2} + 15y – 21y – 63 = 0
5y(y + 3) – 21(y + 3) = 0
(5y – 21) (y + 3) = 0
Y = 21/5, -3 = 4.2, -3
Can’t be determined
5) Answer: e)
I. 12x^{2} + 17x – 57 = 0
12x^{2} – 36x + 19x – 57 = 0
12x(x – 3) + 19(x – 3) = 0
(12x + 19) (x – 3) = 0
X = -19/12, 3 = -1.58, 3
II. 4y^{2} -7y – 36 = 0
4y^{2} -16y + 9y – 36 = 0
4y(y – 4) + 9(y – 4) = 0
(4y + 9) (y – 4) = 0
Y = – 9/4, 4 = 2.25, 4
Can’t be determined
Direction (6-10)
6) Answer: a)
(37/400)*18000 + (62/500)*23000 + (46/300)*19530 = x
X = 1665 + 2852 + 2994.6
X = 7511.6
7) Answer: d)
X – (21*21*1725)/525 + 4913 = (58/100)*8800 + (57900/15)
X – 1449 + 4913 = 5104 + 3860
X = 5104 + 3860 + 1449 – 4913
X = 5500
8) Answer: b)
(45/100)*3800 + (5/9)*3402 – (216*78)/5616 = x
X = 1710 + 1890 – 3
X = 3597
9) Answer: a)
(54/9) + 178 = 1728 + (27/100)*1500 – x
6 + 178 = 1728 + 405 – x
x = 1728 + 405 – 6 – 178
x = 1949
10) Answer: c)
121 – (114*x) + (2/11)*825 – 14 = 29
121 – (114*x) + 150 – 14 = 29
121 + 150 – 14 – 29 = (114*x)
228 = (114*x)
X = 228/114
X = 2
11) Answer: d)
Sum of the circumference of circle and perimeter of rectangle = 148 cm
Area of rectangle = lb = 216 Sq cm
= > 18*b = 216
= > Breadth (b) = 216/18 = 12 cm
Perimeter of rectangle = 2*(l + b) = 2*(18 + 12) = 60 cm
The circumference of circle = 148 – 60 = 88 cm
= > 2πr = 88
= > 2*(22/7)*r = 88
= > r = 14 cm
Area of circle = πr^{2} = (22/7)*14*14 = 616 Sq cm