“20-20” Quantitative Aptitude | Crack SBI Clerk / IDBI Executive 2018 Day-80

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“20-20” Aptitude Questions | Crack SBI Clerk / IDBI Executive 2018 Day-80

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Directions (Q. 1 – 5): What value should come in place of question mark (?) in the following questions?

  1. 65 % of 485 + 76 % of 350 = 3 × ?
  1. 25
  2. 50
  3. 75
  4. 25
  5. 50

 

  1. (1/4) of (210/684) of (28/63) of 4104 = x
  1. 132
  2. 143
  3. 157
  4. 119
  5. None of these

 

  1. (4/3) of ? – (2/3) of (12/19) of 3515 = 52 % of 850
  1. 4
  2. 7
  3. 6
  4. 5
  5. None of these

 

  1. 782 – 2184 ÷ 78 = ? × 42
  1. 25
  2. 5
  3. 75
  4. 25
  5. None of these

 

  1. [(62)2 ÷ 31 × 8] ÷ 16 = 8 × ?
  1. 5
  2. 25
  3. 5
  4. 75
  5. None of these

 

  1. The present age of Ravi’s father is four times Ravi’s present age. Five years back, Ravi’s father was seven times as old as Ravi was at that time. What is the present age of Ravi’s father?
  1. 40 years
  2. 35 years
  3. 32 years
  4. 28 years
  5. None of these

 

  1. A, B and C started a business with investment in the ratio 4: 5: 6 respectively. After 1 year, A withdrew 50% of his capital and B increased his capital by 30% of his investment. At the end of 2 years, they earned a profit of Rs.118000. Find the share of B in the profit?
  1. 32000
  2. 36000
  3. 46000
  4. 42000
  5. None of these

 

  1. Three pipes X, Y, Z can fill a tank in 5 hours. After working together for 2 hours, Z is closed and X, Y can fill the remaining part in 4 hours. Find the number of hours taken by Z alone to fill the tank.
  1. 18 hours
  2. 20 hours
  3. 15 hours
  4. 10 hours
  5. None of these

 

  1. Difference between CI and SI on a certain amount at 15% per annum for three years is Rs.109856.25. Find the sum.
  1. 1330000
  2. 1420000
  3. 1450000
  4. 1550000
  5. None of these

 

  1. A shopkeeper purchased a mobile for Rs. 1200 and spent Rs. 240 for its repair. At what price he should sell the mobile so that his percentage repairing cost incurred for mobile is equal to the profit percentage earned on the mobile?
  1. 1913
  2. 1627
  3. 1728
  4. 1856
  5. None of these

 

Directions (Q. 11 – 15): What value should come in place of question mark (?) in the following number series?

  1. 8, 15, 47, 122, ?
  1. 176
  2. 258
  3. 214
  4. 296
  5. 187

 

  1. 5, 6, 23, 208, ?
  1. 3327
  2. 2178
  3. 1765
  4. 3263
  5. 1571

 

  1. 17, 19, 41, 127, ? , 2571
  1. 492
  2. 684
  3. 513
  4. 729
  5. 815

 

  1. 65, 83, 108, 147, ? , 295
  1. 243
  2. 207
  3. 195
  4. 259
  5. 236

 

  1. 117, 126, 137, 150, ? , 182
  1. 157
  2. 171
  3. 169
  4. 165
  5. 173

 

Directions (Q. 16 – 20) Study the following information carefully and answer the given questions:

Following pie chart shows percentage distribution of total no of cars sold in five different cities and the table shows the ratio of two different model cars sold in those cities.

 

  1. Find the total no of M2 cars sold in all the five cities together?
  1. 51788
  2. 53445
  3. 49113
  4. 57566
  5. None of these

 

  1. Total no of M1 cars sold in City P, R, T together is approximately what percentage more/less than the total no of M2 cars sold in City Q, S and T together?
  1. 21 % less
  2. 32 % more
  3. 21 % more
  4. 32 % less
  5. None of these

 

  1. Which city has sold highest no of M1 cars?
  1. City S
  2. City Q
  3. City R
  4. City P
  5. City T

 

  1. Find the difference between the total no of M2 cars sold in City P, Q together to that of total no of M1 cars sold in City S and T together?
  1. 11678
  2. 12834
  3. 13116
  4. 14552
  5. None of these

 

  1. Find the ratio between the total no of cars sold in City P, R, T together to that of total no of cars sold in City Q, R, S together?
  1. 526 : 421
  2. 613 : 517
  3. 638 : 627
  4. 597 : 491
  5. None of these

 

Answers

Directions (Q. 1 – 5):

  1. Answer c

Explanation:

(65/100)*485 + (76/100)*350 = 3x

315.25 + 266 = 3x

581.25= 3x

X = 581.25/3

X = 193.75

 

  1. Answer e

Explanation:

(1/4)*(210/684)*(28/63)*4104 = x

X = 140

 

  1. Answer d

Explanation:

(4/3) of x – (2/3) of (12/19) of 3515 = 52 % of 850

(4x/3) – 1480= (52/100)*850
(4x/3) – 1480= 442

(4x/3) = 442 + 1480

(4x/3) = 1922

X = 1922*(3/4)

X = 1441.5

 

  1. Answer b

Explanation:

6084 – (2184/78) = 16x

6084 – 28 = 16x

6056/16 = x

X = 378.5

 

  1. Answer d

Explanation:

[(62*62*8)/31] ÷ 16 = 8x

992/16 = 8x

62/8 = x

X = 7.75

 

  1. Answer a

Explanation:

Let the present age of Ravi be x

Present age of Ravi’s father= 4x

Now 5 yr ago

Ravi’s father’s age= 7 * Ravi’s age

= > 4x-5=7(x-5)

= > x= 10

Ravi’s Father’s age = 4*10= 40 years

  1. Answer c

Explanation:

Ratio of shares:

A : B : C = (4 + 4/2) : (5 + 5 x 130/100) : (6 + 6)

= > 6 : 23/2 : 12

= > 12 : 23 : 24

Share of B in the profit = 23/59 x 118000 = Rs. 46000

 

  1. Answer b

Explanation:

Work done by all the three pipes in 2 hours = 2/5

Remaining work = 3/5

x, y can fill 3/5 part in 4 hours

x, y can fill 1 part in 4 *5/3 hours = 20/3 hours.

Z’s one day work = 1/5 – 3/20 = 1/20

Number of hours taken by Z alone to fill the tank = 20 hours.

 

  1. Answer d

Explanation:

Difference between CI and SI for three years

CI – SI = P (r/100)2 x (300 + r)/100

=> 109856.25 = P (15/100)2 x (315/100)

=> P = 109856.25 x (400/9) x (100/315)

=> P = Rs.1550000

 

  1. Answer c

Explanation:

Repairing cost percentage= 240*100/1200 = 20%

So he has to earn a profit of 20%

Total cost of the mobile= 1200+240= 1440

To earn 20% profit he should at = 1440*120/100= Rs. 1728

 

Directions (Q. 11 – 15):

  1. Answer b

Explanation:

The pattern is, +(32 – 2), +(62 – 4), +(92 – 6), +(122 – 8),..

The answer is, 258

 

  1. Answer a

Explanation:

The pattern is, *12 + 1, *22 – 1, *32 + 1, *42 – 1,..

The answer is, 3327

 

  1. Answer c

Explanation:

The pattern is, *1 + 2, *2 +3, *3 +4, *4 +5, *5 +6,..

The answer is, 513

 

  1. Answer b

Explanation:

The difference of difference is, 7, 14, 21, 28,..

The answer is, 207

 

  1. Answer d

Explanation:

The pattern is, [(2*5) – 1], [(2*6) – 1], [(2*7) – 1], [(2*8) – 1],..

The answer is, 165

 

Directions (Q. 16 – 20)

  1. Answer d

Explanation:

City Total Cars sold M1 cars sold M2 cars sold
P 29040 17424 11616
Q 23760 11880 11880
R 19800 8800 11000
S 31680 20160 11520
T 27720 16170 11550

 

Total no of M2 cars sold in all the five cities together,

= > 11616 + 11880 + 11000 + 11520 + 11550

= > 57566

 

  1. Answer c

Explanation:

Total no of M1 cars sold in City P, R, T together

= > 17424 + 8800 + 16170

= > 42394

The total no of M2 cars sold in City Q, S and T together

= > 11880 + 11520 + 11550

= > 34950

Required % = [(42394 – 34950)/34950]*100

= > (7444/34950)*100 = 21.29 % = 21 % more

 

  1. Answer a

Explanation:

In city P, M1 cars = 17424

In city Q, M1 cars = 11880

In city R, M1 cars = 8800

In city S, M1 cars = 20160

In city T, M1 cars = 16170

So, City S sold highest no of M1 cars.

 

  1. Answer b

Explanation:

The total no of M2 cars sold in City P, Q together

= > 11616 + 11880 = 23496

The total no of M1 cars sold in City S, T together

= > 20160 + 16170 = 36330

Required difference = 36330 – 23496 = 12834

 

  1. Answer c

Explanation:

The total no of cars sold in City P, R, T together

= > 29040 + 19800 + 27720 = 76560

The total no of cars sold in City Q, R, S together

= > 23760 + 19800 + 31680 = 75240

Required ratio = 76560 : 75240 = 638 : 627

 

 

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