# “20-20” Quantitative Aptitude | Crack Dena bank 2018 Day-92

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“20-20” Aptitude Questions | Crack Dena bank 2018 Day-92

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Directions (Q. 1 – 5): In the following question, a question is followed by information given in three statements. You have to study the question along with the statements and decide the information given in which of the statement(s) is necessary and sufficient to answer the question.

1. What is the two digit number?
1. Sum of the digits is 7.
2. The number is decreased by 9 by interchanging the digits.
3. Digit in the ten’s place is bigger than the digit in the unit place by 1.
1. I and II only
2. II and III only
3. I and III only
4. All I, II, III
5. None of these
1. What is the present age of Tanya?
1. The ratio between the present ages of Tanya and her brother Amit is 3:4.
2. After 5 years the ratio between the ages of Tanya and Amit will be 4:5
3. Amit is 5 years older than Tanya.
1. I and II only
2. II and III only
3. I and III only
4. All I, II, III
5. Any two of the three
1. What is the percentage of discount given?
1. 23.5% profit was earned by selling an almirah for Rs. 12350
2. If no discount is allowed the earned profit would have been 30%
3. The cost price of the almirah was Rs. 10000
1. Only I and II
2. Only II and III
3. Only I and III
4. Any two of the three
5. None of these

4. A path runs around a rectangular lawn. What is the width of the path?

1. The length and the breadth of the lawn are in the ratio of 3:1 respectively.
2. The width of the path is ten times the length of the lawn.
3.  The cost of gravelling the path @ Rs. 50 per m2 is Rs. 8832
1. I and II only
2. II and III only
3. I and III only
4. All I, II, III
5. Any two of the three
1. A, B and C together start a business with a total investment of Rs. 15000. At the end of the year, the total profit is Rs. 3000. What is A’s share in the profit?
1. A’s Contribution is 3/2 times B’s.
2. B’s contribution is twice that of C
3.  A’s contribution is thrice that of C
1. I and II only
2. II and III only
3. I and III only
4. All I, II, III
5. Any two of the three

Directions (6-10): Read the following passage carefully and answer the given questions

There are four different furniture sold in three different months viz, April, May and June.

Table: No of tables sold in April is 100% more than the no of tables sold in June. No of tables sold in May is three-fourth of the no of tables sold in April. The difference between the no. of tables sold in April and May is equal to that of tables sold in May and June, which is 100.

Chair: The ratio of the no of chairs sold in April, May and June is 3: 5: 6. The difference between the no of chairs sold in April and May together and the no of chairs sold in May and June together is 120.

Sofa: No of sofa sold in May is equal to the no of chairs sold in April. No of sofa sold in April is 50% more than the no of sofa sold in May and the no of sofa sold in June is sum of the no of sofa sold in April and May together.

Bed: No of bed sold in April is 60 less than the no of sofa sold in the same month. No of bed sold in May is twice that of April and the no of sofa sold in June is 20 less than the no of chairs sold in May.

6) Find the ratio of the total no of furniture sold in April to the total no of furniture sold in June

1. 33:35
2. 31:41
3. 32:39
4. 28:27
5. None of these

7) If 20% of all the furniture sold is damaged, then find the no of furniture is not damaged

1. 1270
2. 1600
3. 1720
4. 1550
5. 2180

8) Total chairs sold for all the given months is what percent more/less than the total tables sold for all the given months?

1. 20
2. 16
3. 18
4. 24
5. 28

9) What is the difference between the total no of bed sold in June and May together and the total no of Sofa sold in April and May together?

1. 120
2. 80
3. 60
4. 150
5. 180

10) What is the average no of furniture items sold in April, May and June together?

1. 720
2. 700
3. 810
4. 770
5. None of these
1. A, B, C started a business with an investment of Rs. 72000, Rs. 54000 and Rs. 46000 respectively. After 5 months from the start of the business, A withdraws Rs. 10000 and at the same time B and C invested Rs. 20000 and Rs. 15000 more. The total profit at the end of the year is Rs. 174642. Find C’s share?
1. Rs. 45134
2. Rs. 58452
3. Rs. 51246
4. Rs. 43788
5. None of these
1. A man sold an article for Rs. 7600 and incurred a loss. Had he sold the article for Rs.8350, his gain would have been equal to half of the amount of loss that he incurred. At what price should he sell the article to have 20% profit?
1. Rs. 8560
2. Rs. 7680
3. Rs. 11240
4. Rs. 9720
5. None of these
1. Two pipes can fill a cistern in 15 and 21 hours respectively. The pipes are opened simultaneously and it is found that due to leakage in the bottom, 15 minutes extra are taken for the cistern to be filled up. If the cistern is full, in what time would the leak empty it?
1. 315 hours
2. 256 hours
3. 223 hours
4. 278 hours
5. None of these
1. The ratio of the present age of Kavitha to that Sunitha is 4:13. Chandra is 15 years older than Sunitha. Chandra’s age after 8 years will be 75 years. What is the present age of Kavitha’s mother, who is 30 years older than Kavitha?
1. 38 years
2. 42 years
3. 46 years
4. 50 years
5. None of these
1. A does half as much work as B in three- fourth of the time. If together they take 18 days to complete the work, how much time shall B take to do it?
1. 34 days
2. 30 days
3. 32 days
4. 28 days
5. None of these

Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer

1. if x > y
2. if x ≥ y
3. if x < y
4. if x ≤ y
5. if x = y or no relation can be established between x and y

16).

I. 2x2 -15x +27 =0

2y2 -13y +20 =0

17).

1. I. 3x2 +14x +15 =0
2. 3y2 +10y + 7 =0

18).

I. x2-10x +25 =0

II. Y2 -9y +20 =0

19).

1. I. 4x2 -13x +10 =0
2. 2y2 -15y +22 =0

20).

1. I. 30x2 +19x +2 =0
2. 3y2 +8y +4 =0

Let the tens and units digit be x and y respectively

I. x + y = 7

II. (10x+y) – (10y +x) = 9

= > x-y =1

III. x-y= 1

Hence, I and II or I and III give the answer

From I and II

3x+5/4x+5= 4/5

x = 5

Age of Tanya= 3*5= 15 years

From I and III

4x= 3x+5

x= 5

From II and III

X+5 / x+5+5= 4/5

x= 15

From I

Cost Price = 12350/123.5* 100= Rs. 10000

From II

Marked Price = 130% of CP= 130/100*10000= Rs. 13000

From I and II

Discount= 13000- 12350= Rs. 650

Discount %= 650/13000*100= 5%

Thus I and II gives the answer

From III

Area of the path= 8832/50 = 4416/25 m2

From II

The width of path= 10* length of the lawn

From I

Length= 3x meters

So all the three statements are required to find the answer

Let C’s contribution be Rs x

From I and II

C=x, B= 2x and A= 3/2*2x= 3x

From II and III

C= x, B= 2x and A= 3x

From I and III

C= x, A= 3x, B= 2/3* 3x= 2x

So, A: B: C= 3x: 2x: x= 3: 2: 1

A’s share= 3000*3/6= Rs. 1500

Direction (6-10)

Directions (6-10):

Table:

Let us take no of tables sold in June be x

No of tables sold in April = 200/100 *x = 2x

No of tables sold in May = 2x* ¾ = 3x/2

Difference = (April+May) – (May+June) = 100

= (3x/2+2x) –(3x/2+x) = 100

=>2x-x = 100

X= 100

April = 200

May = 150

Chair:

Difference = (3x+5x) – (5x+6x) = 120

=>8x-11x= 120

=>3x =120

=>x= 40

April = 120, May = 200, June = 240

Sofa:

No. of sofa sold in May = No of chairs sold in April = 120

No. of sofa sold in April = x

No. of chairs sold in April = 120 (100+50)% = 120 * 150/100

=>x = 120 * 3/2 => x=180

No. of Sofa sold in June = 120+180 = 300

Bed:

No of bed sold in April = 180- 60 = 120

No of bed sold in May = 2* 120 = 240

No of bed sold in June = 200-20 = 180

 Item name April May June Table 200 150 100 Chair 120 200 240 Sofa 180 120 300 Bed 120 240 180

Required ratio = (200+120+180+120): (100+240+300+180)

=620: 820 = 31:41

No of furniture not damaged

= 80/100 *(200+120+180+120+150+200+120+240+100+240+300+180)

= 80/100 * (620+710+820)

= 4/5 *2150 = 1720

Required percentage = (560-450)/450 *100

=110/450*100

= 24.44% = 24% (Approximately)

Required difference = (240+180) – (180+120) = 420 – 300 = 120

Required average = (620+710+820)/3 = 2150/3 = 717

Direction (11-15)

The share of A, B and C,

= > [72000*5 + 62000*7]: [54000*5 + 74000*7]: [46000*5 + 61000*7]

= > 794000: 788000: 657000

= > 794: 788: 657

Total profit = Rs. 174642

2239’s = 174642

1’s = 78

The share of C = 657’s = Rs. 51246

Loss = C.P – 7600

Profit = 8350 – CP

Profit = (1/2)*Loss

8350 – C.P = (1/2) [C.P – 7600]

16700 – 2C.P = C.P – 7600

3C.P = 16700 + 7600

3C.P = 24300

C.P = Rs. 8100

Selling price = 8100*(120/100) = Rs. 9720

If both filling pipes are working together, a portion of the cistern filled in an hour

= 1/15 + 1/21 = (15+21)/(15*21) = 4/35

Hence time taken to fill the cistern = 35/4 hours = 8 3/4 hours = 8 hours 45 minutes.

But due to leak, it takes 15 min more.

Hence total time taken = 8 hours 45 minutes + 15 min = 9 hours.

Let the leak take n hours to empty the cistern.

So, 1/15 + 1/21 – 1/n = 1/9.

=> 4/35 – 1/n = 1/9

=› 1/n = 4/35 – 1/9 = 1/315

Hence the cistern will be emptied in 315 hours.

The ratio of the present age of Kavitha to that Sunitha = 4:13(4x, 13x)

Chandra = Sunitha + 15

Chandra’s age after 8 years = 75

Chandra’s present age = 75 – 8 = 67

Sunitha’s present age = 67 – 15 = 52

13’s = 52

1’s = 4

The present age of Kavitha = 16

Kavitha’s mother = Kavitha + 30 = 16 + 30 = 46 years

Suppose B does the work in x days

Then A does half work in 3x/4 days

So, A does 1 work in 3x/2 days

Now,

A+B do the work in x*3x/2/ x+3x/2=18

Or, 3×2/2/ 5x/2= 18

X= 18*5/3= 30 days

Direction (16-20)

16). I. 2x2 -15x +27 =0

2x2 -6x -9x + 27 =0

2x(x-3)-9(x-3) =0

(2x-9) (x-3) =0

X=9/2, 3 = 4.5, 3

II. 2y2 -13y +20 =0

2y2 -8y-5y +20 =0

2y(x-4)-5(x-4) =0

(2y-5) (x-4) =0

Y = 5/2, 4 =2.5, 4

Can’t be determined

I. 3x2 +14x +15 =0

3x2 +9x+5x +15 =0

3x(x+3)+5(x+3) =0

(3x+5) (x+3) =0

X= -5/3 , -3

II. 3y2 +10y + 7 =0

3y2 +7y+3y + 7 =0

Y(3y+7)+1(3y+7) =0

(y+1)(3y+7) =0

Y=-1, -7/3

Can’t be determined

I. x2-10x +25 =0

x2-5x-5x +25 =0

x(x-5) -5 (x-5) =0

(x-5) (x-5) =0

X= 5, 5

II. Y2 -9y +20 =0

Y2 -4y-5y +20 =0

Y(y-4)-5(y-4) =0

(y-5)(y-4) =0

Y=5, 4

x ≥ y

I. 4x2 -13x +10 =0

4x2 -8x -5x +10 =0

4X(x-2)-5(x-2)=0

(4x-5)(x-2) =0

X=5/4, 2

II. 2y2 -15y +22 =0

2y2 -11y-4y +22 =0

Y(2y-11)-2 (2y-11) =0

(y-2) (2y-11) =0

y = 2 , 11/2

x ≤ y

I. 30x2 +19x +2 =0

30x2 +15x+4x +2 =0

15(2x+1)+2(2x+1) =0

(15x+2) (2x+1) =0

X= -2/15, -1/2

II. 3y2 +8y +4 =0

3y2 +6y+2y +4 =0

3y(y+2)+2(y+2) =0

(3y+2) (y+2) =0

Y= -2/3, -2

x>y

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 Topic Daily Publishing Time Daily News Papers & Editorials 8.00 AM Current Affairs Quiz 9.00 AM Logical Reasoning 10.00 AM Quantitative Aptitude “20-20” 11.00 AM Vocabulary (Based on The Hindu) 12.00 PM Static GK Quiz 1.00 PM English Language “20-20” 2.00 PM Banking Awareness Quiz 3.00 PM Reasoning Puzzles & Seating 4.00 PM Daily Current Affairs Updates 5.00 PM Data Interpretation / Application Sums (Topic Wise) 6.00 PM Reasoning Ability “20-20” 7.00 PM English Language (New Pattern Questions) 8.00 PM General / Financial Awareness Quiz 9.00 PM