“20-20” Quantitative Aptitude | Crack Dena bank 2018 Day-92
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“20-20” Aptitude Questions | Crack Dena bank 2018 Day-92
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Question 1 of 20
1. Question
Directions (Q. 1 – 5): In the following question, a question is followed by information given in three statements. You have to study the question along with the statements and decide the information given in which of the statement(s) is necessary and sufficient to answer the question.
What is the two digit number?
Sum of the digits is 7.
The number is decreased by 9 by interchanging the digits.
in the ten’s place is bigger than the digit in the unit place by 1.
Correct
Answer e
Let the tens and units digit be x and y respectively
I. x + y = 7
II. (10x+y) – (10y +x) = 9
= > x-y =1
III. x-y= 1
Hence, I and II or I and III give the answer
Incorrect
Answer e
Let the tens and units digit be x and y respectively
I. x + y = 7
II. (10x+y) – (10y +x) = 9
= > x-y =1
III. x-y= 1
Hence, I and II or I and III give the answer
Question 2 of 20
2. Question
Directions (Q. 1 – 5): In the following question, a question is followed by information given in three statements. You have to study the question along with the statements and decide the information given in which of the statement(s) is necessary and sufficient to answer the question.
What is the present age of Tanya?
The ratio between the present ages of Tanya and her brother Amit is 3:4.
After 5 years the ratio between the ages of Tanya and Amit will be 4:5
Amit is 5 years older than Tanya.
Correct
Answer e
From I and II
3x+5/4x+5= 4/5
x = 5
Age of Tanya= 3*5= 15 years
From I and III
4x= 3x+5
x= 5
From II and III
X+5 / x+5+5= 4/5
x= 15
Incorrect
Answer e
From I and II
3x+5/4x+5= 4/5
x = 5
Age of Tanya= 3*5= 15 years
From I and III
4x= 3x+5
x= 5
From II and III
X+5 / x+5+5= 4/5
x= 15
Question 3 of 20
3. Question
Directions (Q. 1 – 5): In the following question, a question is followed by information given in three statements. You have to study the question along with the statements and decide the information given in which of the statement(s) is necessary and sufficient to answer the question.
What is the percentage of discount given?
23.5% profit was earned by selling an almirah for Rs. 12350
If no discount is allowed the earned profit would have been 30%
III. The cost price of the almirah was Rs. 10000
Correct
Answer a
From I
Cost Price = 12350/123.5* 100= Rs. 10000
From II
Marked Price = 130% of CP= 130/100*10000= Rs. 13000
From I and II
Discount= 13000- 12350= Rs. 650
Discount %= 650/13000*100= 5%
Thus I and II gives the answer
Incorrect
Answer a
From I
Cost Price = 12350/123.5* 100= Rs. 10000
From II
Marked Price = 130% of CP= 130/100*10000= Rs. 13000
From I and II
Discount= 13000- 12350= Rs. 650
Discount %= 650/13000*100= 5%
Thus I and II gives the answer
Question 4 of 20
4. Question
Directions (Q. 1 – 5): In the following question, a question is followed by information given in three statements. You have to study the question along with the statements and decide the information given in which of the statement(s) is necessary and sufficient to answer the question.
A path runs around a rectangular lawn. What is the width of the path?
The length and the breadth of the lawn are in the ratio of 3:1 respectively.
The width of the path is ten times the length of the lawn.
The cost of gravelling the path @ Rs. 50 per m^{2} is Rs. 8832
Correct
Answer d
From III
Area of the path= 8832/50 = 4416/25 m^{2}
From II
The width of path= 10* length of the lawn
From I
Length= 3x meters
Breadth= x meters
So all the three statements are required to find the answer
Incorrect
Answer d
From III
Area of the path= 8832/50 = 4416/25 m^{2}
From II
The width of path= 10* length of the lawn
From I
Length= 3x meters
Breadth= x meters
So all the three statements are required to find the answer
Question 5 of 20
5. Question
Directions (Q. 1 – 5): In the following question, a question is followed by information given in three statements. You have to study the question along with the statements and decide the information given in which of the statement(s) is necessary and sufficient to answer the question.
A, B and C together start a business with a total investment of Rs. 15000. At the end of the year, the total profit is Rs. 3000. What is A’s share in the profit?
A’s Contribution is 3/2 times B’s.
B’s contribution is twice that of C
A’s contribution is thrice that of C
Correct
Answer e
Let C’s contribution be Rs x
From I and II
C=x, B= 2x and A= 3/2*2x= 3x
From II and III
C= x, B= 2x and A= 3x
From I and III
C= x, A= 3x, B= 2/3* 3x= 2x
So, A: B: C= 3x: 2x: x= 3: 2: 1
A’s share= 3000*3/6= Rs. 1500
Incorrect
Answer e
Let C’s contribution be Rs x
From I and II
C=x, B= 2x and A= 3/2*2x= 3x
From II and III
C= x, B= 2x and A= 3x
From I and III
C= x, A= 3x, B= 2/3* 3x= 2x
So, A: B: C= 3x: 2x: x= 3: 2: 1
A’s share= 3000*3/6= Rs. 1500
Question 6 of 20
6. Question
Directions (6-10): Read the following passage carefully and answer the given questions
There are four different furniture sold in three different months viz, April, May and June.
Table: No of tables sold in April is 100% more than the no of tables sold in June. No of tables sold in May is three-fourth of the no of tables sold in April. The difference between the no. of tables sold in April and May is equal to that of tables sold in May and June, which is 100.
Chair: The ratio of the no of chairs sold in April, May and June is 3: 5: 6. The difference between the no of chairs sold in April and May together and the no of chairs sold in May and June together is 120.
Sofa: No of sofa sold in May is equal to the no of chairs sold in April. No of sofa sold in April is 50% more than the no of sofa sold in May and the no of sofa sold in June is sum of the no of sofa sold in April and May together.
Bed: No of bed sold in April is 60 less than the no of sofa sold in the same month. No of bed sold in May is twice that of April and the no of sofa sold in June is 20 less than the no of chairs sold in May.
Find the ratio of the total no of furniture sold in April to the total no of furniture sold in June
Correct
Directions (6-10):
Table:
Let us take no of tables sold in June be x
No of tables sold in April = 200/100 *x = 2x
No of tables sold in May = 2x* ¾ = 3x/2
Difference = (April+May) – (May+June) = 100
= (3x/2+2x) –(3x/2+x) = 100
=>2x-x = 100
X= 100
April = 200
May = 150
Chair:
Difference = (3x+5x) – (5x+6x) = 120
=>8x-11x= 120
=>3x =120
=>x= 40
April = 120, May = 200, June = 240
Sofa:
No. of sofa sold in May = No of chairs sold in April = 120
No. of sofa sold in April = x
No. of chairs sold in April = 120 (100+50)% = 120 * 150/100
=>x = 120 * 3/2 => x=180
No. of Sofa sold in June = 120+180 = 300
Bed:
No of bed sold in April = 180- 60 = 120
No of bed sold in May = 2* 120 = 240
No of bed sold in June = 200-20 = 180
Item name
April
May
June
Table
200
150
100
Chair
120
200
240
Sofa
180
120
300
Bed
120
240
180
Answer: b
Required ratio = (200+120+180+120): (100+240+300+180)
=620: 820 = 31:41
Incorrect
Directions (6-10):
Table:
Let us take no of tables sold in June be x
No of tables sold in April = 200/100 *x = 2x
No of tables sold in May = 2x* ¾ = 3x/2
Difference = (April+May) – (May+June) = 100
= (3x/2+2x) –(3x/2+x) = 100
=>2x-x = 100
X= 100
April = 200
May = 150
Chair:
Difference = (3x+5x) – (5x+6x) = 120
=>8x-11x= 120
=>3x =120
=>x= 40
April = 120, May = 200, June = 240
Sofa:
No. of sofa sold in May = No of chairs sold in April = 120
No. of sofa sold in April = x
No. of chairs sold in April = 120 (100+50)% = 120 * 150/100
=>x = 120 * 3/2 => x=180
No. of Sofa sold in June = 120+180 = 300
Bed:
No of bed sold in April = 180- 60 = 120
No of bed sold in May = 2* 120 = 240
No of bed sold in June = 200-20 = 180
Item name
April
May
June
Table
200
150
100
Chair
120
200
240
Sofa
180
120
300
Bed
120
240
180
Answer: b
Required ratio = (200+120+180+120): (100+240+300+180)
=620: 820 = 31:41
Question 7 of 20
7. Question
Directions (6-10): Read the following passage carefully and answer the given questions
There are four different furniture sold in three different months viz, April, May and June.
Table: No of tables sold in April is 100% more than the no of tables sold in June. No of tables sold in May is three-fourth of the no of tables sold in April. The difference between the no. of tables sold in April and May is equal to that of tables sold in May and June, which is 100.
Chair: The ratio of the no of chairs sold in April, May and June is 3: 5: 6. The difference between the no of chairs sold in April and May together and the no of chairs sold in May and June together is 120.
Sofa: No of sofa sold in May is equal to the no of chairs sold in April. No of sofa sold in April is 50% more than the no of sofa sold in May and the no of sofa sold in June is sum of the no of sofa sold in April and May together.
Bed: No of bed sold in April is 60 less than the no of sofa sold in the same month. No of bed sold in May is twice that of April and the no of sofa sold in June is 20 less than the no of chairs sold in May.
If 20% of all the furniture sold is damaged, then find the no of furniture is not damaged
Directions (6-10): Read the following passage carefully and answer the given questions
There are four different furniture sold in three different months viz, April, May and June.
Table: No of tables sold in April is 100% more than the no of tables sold in June. No of tables sold in May is three-fourth of the no of tables sold in April. The difference between the no. of tables sold in April and May is equal to that of tables sold in May and June, which is 100.
Chair: The ratio of the no of chairs sold in April, May and June is 3: 5: 6. The difference between the no of chairs sold in April and May together and the no of chairs sold in May and June together is 120.
Sofa: No of sofa sold in May is equal to the no of chairs sold in April. No of sofa sold in April is 50% more than the no of sofa sold in May and the no of sofa sold in June is sum of the no of sofa sold in April and May together.
Bed: No of bed sold in April is 60 less than the no of sofa sold in the same month. No of bed sold in May is twice that of April and the no of sofa sold in June is 20 less than the no of chairs sold in May.
Total chairs sold for all the given months is what percent more/less than the total tables sold for all the given months?
Correct
Answer: d
Required percentage = (560-450)/450 *100
=110/450*100
= 24.44% = 24% (Approximately)
Incorrect
Answer: d
Required percentage = (560-450)/450 *100
=110/450*100
= 24.44% = 24% (Approximately)
Question 9 of 20
9. Question
Directions (6-10): Read the following passage carefully and answer the given questions
There are four different furniture sold in three different months viz, April, May and June.
Table: No of tables sold in April is 100% more than the no of tables sold in June. No of tables sold in May is three-fourth of the no of tables sold in April. The difference between the no. of tables sold in April and May is equal to that of tables sold in May and June, which is 100.
Chair: The ratio of the no of chairs sold in April, May and June is 3: 5: 6. The difference between the no of chairs sold in April and May together and the no of chairs sold in May and June together is 120.
Sofa: No of sofa sold in May is equal to the no of chairs sold in April. No of sofa sold in April is 50% more than the no of sofa sold in May and the no of sofa sold in June is sum of the no of sofa sold in April and May together.
Bed: No of bed sold in April is 60 less than the no of sofa sold in the same month. No of bed sold in May is twice that of April and the no of sofa sold in June is 20 less than the no of chairs sold in May.
What is the difference between the total no of bed sold in June and May together and the total no of Sofa sold in April and May together?
Directions (6-10): Read the following passage carefully and answer the given questions
There are four different furniture sold in three different months viz, April, May and June.
Table: No of tables sold in April is 100% more than the no of tables sold in June. No of tables sold in May is three-fourth of the no of tables sold in April. The difference between the no. of tables sold in April and May is equal to that of tables sold in May and June, which is 100.
Chair: The ratio of the no of chairs sold in April, May and June is 3: 5: 6. The difference between the no of chairs sold in April and May together and the no of chairs sold in May and June together is 120.
Sofa: No of sofa sold in May is equal to the no of chairs sold in April. No of sofa sold in April is 50% more than the no of sofa sold in May and the no of sofa sold in June is sum of the no of sofa sold in April and May together.
Bed: No of bed sold in April is 60 less than the no of sofa sold in the same month. No of bed sold in May is twice that of April and the no of sofa sold in June is 20 less than the no of chairs sold in May.
What is the average no of furniture items sold in April, May and June together?
Correct
Answer: e
Required average = (620+710+820)/3 = 2150/3 = 717
Incorrect
Answer: e
Required average = (620+710+820)/3 = 2150/3 = 717
Question 11 of 20
11. Question
A, B, C started a business with an investment of Rs. 72000, Rs. 54000 and Rs. 46000 respectively. After 5 months from the start of the business, A withdraws Rs. 10000 and at the same time B and C invested Rs. 20000 and Rs. 15000 more. The total profit at the end of the year is Rs. 174642. Find C’s share?
A man sold an article for Rs. 7600 and incurred a loss. Had he sold the article for Rs.8350, his gain would have been equal to half of the amount of loss that he incurred. At what price should he sell the article to have 20% profit?
Correct
Answer d
Loss = C.P – 7600
Profit = 8350 – CP
Profit = (1/2)*Loss
8350 – C.P = (1/2) [C.P – 7600]
16700 – 2C.P = C.P – 7600
3C.P = 16700 + 7600
3C.P = 24300
C.P = Rs. 8100
Selling price = 8100*(120/100) = Rs. 9720
Incorrect
Answer d
Loss = C.P – 7600
Profit = 8350 – CP
Profit = (1/2)*Loss
8350 – C.P = (1/2) [C.P – 7600]
16700 – 2C.P = C.P – 7600
3C.P = 16700 + 7600
3C.P = 24300
C.P = Rs. 8100
Selling price = 8100*(120/100) = Rs. 9720
Question 13 of 20
13. Question
Two pipes can fill a cistern in 15 and 21 hours respectively. The pipes are opened simultaneously and it is found that due to leakage in the bottom, 15 minutes extra are taken for the cistern to be filled up. If the cistern is full, in what time would the leak empty it?
Correct
Answer a
If both filling pipes are working together, a portion of the cistern filled in an hour
= 1/15 + 1/21 = (15+21)/(15*21) = 4/35
Hence time taken to fill the cistern = 35/4 hours = 8 3/4 hours = 8 hours 45 minutes.
But due to leak, it takes 15 min more.
Hence total time taken = 8 hours 45 minutes + 15 min = 9 hours.
Let the leak take n hours to empty the cistern.
So, 1/15 + 1/21 – 1/n = 1/9.
=> 4/35 – 1/n = 1/9
=› 1/n = 4/35 – 1/9 = 1/315
Hence the cistern will be emptied in 315 hours.
Incorrect
Answer a
If both filling pipes are working together, a portion of the cistern filled in an hour
= 1/15 + 1/21 = (15+21)/(15*21) = 4/35
Hence time taken to fill the cistern = 35/4 hours = 8 3/4 hours = 8 hours 45 minutes.
But due to leak, it takes 15 min more.
Hence total time taken = 8 hours 45 minutes + 15 min = 9 hours.
Let the leak take n hours to empty the cistern.
So, 1/15 + 1/21 – 1/n = 1/9.
=> 4/35 – 1/n = 1/9
=› 1/n = 4/35 – 1/9 = 1/315
Hence the cistern will be emptied in 315 hours.
Question 14 of 20
14. Question
The ratio of the present age of Kavitha to that Sunitha is 4:13. Chandra is 15 years older than Sunitha. Chandra’s age after 8 years will be 75 years. What is the present age of Kavitha’s mother, who is 30 years older than Kavitha?
Correct
Answer c
The ratio of the present age of Kavitha to that Sunitha = 4:13(4x, 13x)
Click “Start Quiz” to attend these Questions and view Solutions
Directions (Q. 1 – 5): In the following question, a question is followed by information given in three statements. You have to study the question along with the statements and decide the information given in which of the statement(s) is necessary and sufficient to answer the question.
What is the two digit number?
Sum of the digits is 7.
The number is decreased by 9 by interchanging the digits.
Digit in the ten’s place is bigger than the digit in the unit place by 1.
I and II only
II and III only
I and III only
All I, II, III
None of these
What is the present age of Tanya?
The ratio between the present ages of Tanya and her brother Amit is 3:4.
After 5 years the ratio between the ages of Tanya and Amit will be 4:5
Amit is 5 years older than Tanya.
I and II only
II and III only
I and III only
All I, II, III
Any two of the three
What is the percentage of discount given?
23.5% profit was earned by selling an almirah for Rs. 12350
If no discount is allowed the earned profit would have been 30%
The cost price of the almirah was Rs. 10000
Only I and II
Only II and III
Only I and III
Any two of the three
None of these
4. A path runs around a rectangular lawn. What is the width of the path?
The length and the breadth of the lawn are in the ratio of 3:1 respectively.
The width of the path is ten times the length of the lawn.
The cost of gravelling the path @ Rs. 50 per m^{2} is Rs. 8832
I and II only
II and III only
I and III only
All I, II, III
Any two of the three
A, B and C together start a business with a total investment of Rs. 15000. At the end of the year, the total profit is Rs. 3000. What is A’s share in the profit?
A’s Contribution is 3/2 times B’s.
B’s contribution is twice that of C
A’s contribution is thrice that of C
I and II only
II and III only
I and III only
All I, II, III
Any two of the three
Directions (6-10): Read the following passage carefully and answer the given questions
There are four different furniture sold in three different months viz, April, May and June.
Table: No of tables sold in April is 100% more than the no of tables sold in June. No of tables sold in May is three-fourth of the no of tables sold in April. The difference between the no. of tables sold in April and May is equal to that of tables sold in May and June, which is 100.
Chair: The ratio of the no of chairs sold in April, May and June is 3: 5: 6. The difference between the no of chairs sold in April and May together and the no of chairs sold in May and June together is 120.
Sofa: No of sofa sold in May is equal to the no of chairs sold in April. No of sofa sold in April is 50% more than the no of sofa sold in May and the no of sofa sold in June is sum of the no of sofa sold in April and May together.
Bed: No of bed sold in April is 60 less than the no of sofa sold in the same month. No of bed sold in May is twice that of April and the no of sofa sold in June is 20 less than the no of chairs sold in May.
6) Find the ratio of the total no of furniture sold in April to the total no of furniture sold in June
33:35
31:41
32:39
28:27
None of these
7) If 20% of all the furniture sold is damaged, then find the no of furniture is not damaged
1270
1600
1720
1550
2180
8) Total chairs sold for all the given months is what percent more/less than the total tables sold for all the given months?
20
16
18
24
28
9) What is the difference between the total no of bed sold in June and May together and the total no of Sofa sold in April and May together?
120
80
60
150
180
10) What is the average no of furniture items sold in April, May and June together?
720
700
810
770
None of these
A, B, C started a business with an investment of Rs. 72000, Rs. 54000 and Rs. 46000 respectively. After 5 months from the start of the business, A withdraws Rs. 10000 and at the same time B and C invested Rs. 20000 and Rs. 15000 more. The total profit at the end of the year is Rs. 174642. Find C’s share?
Rs. 45134
Rs. 58452
Rs. 51246
Rs. 43788
None of these
A man sold an article for Rs. 7600 and incurred a loss. Had he sold the article for Rs.8350, his gain would have been equal to half of the amount of loss that he incurred. At what price should he sell the article to have 20% profit?
Rs. 8560
Rs. 7680
Rs. 11240
Rs. 9720
None of these
Two pipes can fill a cistern in 15 and 21 hours respectively. The pipes are opened simultaneously and it is found that due to leakage in the bottom, 15 minutes extra are taken for the cistern to be filled up. If the cistern is full, in what time would the leak empty it?
315 hours
256 hours
223 hours
278 hours
None of these
The ratio of the present age of Kavitha to that Sunitha is 4:13. Chandra is 15 years older than Sunitha. Chandra’s age after 8 years will be 75 years. What is the present age of Kavitha’s mother, who is 30 years older than Kavitha?
38 years
42 years
46 years
50 years
None of these
A does half as much work as B in three- fourth of the time. If together they take 18 days to complete the work, how much time shall B take to do it?
34 days
30 days
32 days
28 days
None of these
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
16).
I. 2x^{2} -15x +27 =0
2y^{2} -13y +20 =0
17).
I. 3x^{2} +14x +15 =0
3y^{2} +10y + 7 =0
18).
I. x^{2}-10x +25 =0
II. Y^{2} -9y +20 =0
19).
I. 4x^{2} -13x +10 =0
2y^{2} -15y +22 =0
20).
I. 30x^{2} +19x +2 =0
3y^{2} +8y +4 =0
Answers:
1). Answer e
Let the tens and units digit be x and y respectively
I. x + y = 7
II. (10x+y) – (10y +x) = 9
= > x-y =1
III. x-y= 1
Hence, I and II or I and III give the answer
2). Answer e
From I and II
3x+5/4x+5= 4/5
x = 5
Age of Tanya= 3*5= 15 years
From I and III
4x= 3x+5
x= 5
From II and III
X+5 / x+5+5= 4/5
x= 15
3). Answer a
From I
Cost Price = 12350/123.5* 100= Rs. 10000
From II
Marked Price = 130% of CP= 130/100*10000= Rs. 13000
From I and II
Discount= 13000- 12350= Rs. 650
Discount %= 650/13000*100= 5%
Thus I and II gives the answer
4). Answer d
From III
Area of the path= 8832/50 = 4416/25 m^{2}
From II
The width of path= 10* length of the lawn
From I
Length= 3x meters
Breadth= x meters
So all the three statements are required to find the answer
5). Answer e
Let C’s contribution be Rs x
From I and II
C=x, B= 2x and A= 3/2*2x= 3x
From II and III
C= x, B= 2x and A= 3x
From I and III
C= x, A= 3x, B= 2/3* 3x= 2x
So, A: B: C= 3x: 2x: x= 3: 2: 1
A’s share= 3000*3/6= Rs. 1500
Direction (6-10)
Directions (6-10):
Table:
Let us take no of tables sold in June be x
No of tables sold in April = 200/100 *x = 2x
No of tables sold in May = 2x* ¾ = 3x/2
Difference = (April+May) – (May+June) = 100
= (3x/2+2x) –(3x/2+x) = 100
=>2x-x = 100
X= 100
April = 200
May = 150
Chair:
Difference = (3x+5x) – (5x+6x) = 120
=>8x-11x= 120
=>3x =120
=>x= 40
April = 120, May = 200, June = 240
Sofa:
No. of sofa sold in May = No of chairs sold in April = 120
No. of sofa sold in April = x
No. of chairs sold in April = 120 (100+50)% = 120 * 150/100
=>x = 120 * 3/2 => x=180
No. of Sofa sold in June = 120+180 = 300
Bed:
No of bed sold in April = 180- 60 = 120
No of bed sold in May = 2* 120 = 240
No of bed sold in June = 200-20 = 180
Item name
April
May
June
Table
200
150
100
Chair
120
200
240
Sofa
180
120
300
Bed
120
240
180
6). Answer: b
Required ratio = (200+120+180+120): (100+240+300+180)