“20-20” Quantitative Aptitude | Crack SBI PO Prelims 2018 Day-93

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“20-20” Aptitude Questions | Crack SBI PO Prelims 2018 Day-93

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Directions (Q. 1 – 5): What approximate value should come in place of question mark (?) in the following questions?

  1. (5/7) of 341 + (2/3) of (7/15) of 1889 =? % of 700
  1. 150
  2. 90
  3. 120
  4. 210
  5. 250
  1. [48.78 ÷ 7 × 5] ÷ 70 = 18.01 ×?
  1. 3/47
  2. 2/35
  3. 4/57
  4. 1/36
  5. 5/74
  1. √? + 27.65 = (375.39 + 72.01) ÷ 49.78 + (18.78 × 2.75)
  1. 1225
  2. 1444
  3. 1681
  4. 961
  5. 2025
  1. 3289 ÷ 14 × 5.01 + 15 % of 500 + 27 % of 299 =?
  1. 1330
  2. 1860
  3. 2150
  4. 2740
  5. 1570

5. 36 % of 489.8 + 52 % of 301.25 = 4 ×?

  1. 75
  2. 66
  3. 92
  4. 127
  5. 84

 

Directions (Q. 6 – 10): What value should come in place of question mark (?) in the following number series?

  1. 65, 133, 271, 549,? , 2225
  1. 941
  2. 1277
  3. 1593
  4. 1541
  5. 1107
  1. 7290, 2430, 810, 270,? , 30
  1. 90
  2. 120
  3. 150
  4. 75
  5. 60
  1. 117, 115, 124, 96,?
  1. 145
  2. 178
  3. 161
  4. 152
  5. 187
  1. 534, 266, 132, 65,? , 14.7
  1. 48.5
  2. 31.5
  3. 37.5
  4. 42.5
  5. 45.5
  1. 84, 43, 44, 67, 135,? , 1016.5
  1. 5
  2. 578
  3. 662
  4. 5
  5. 775

11. A, B and C entered into a partnership with investment in the ratio of 5:3:4 respectively. After one year B doubled his investment. At the end of two years, they earned a profit of Rs.54000. Find the share of B in the profit?

  1. 21000
  2. 27000
  3. 18000
  4. 14000
  5. None of these
  1. The ratio between the ages of two persons A and B is 2:5. If the difference between their ages is 18 years then find the age of another person C if the average age of all the persons five years hence will be 30 years?
  1. 33 years
  2. 35 years
  3. 28 years
  4. 24 years
  5. None of these
  1. A person covers 480 km in 6 hours. He covers some distance by bus at the average speed of 50 km/hr and the remaining distance by train at the average speed 90 km/hr. Find the distance covered by the train?
  1. 280 km
  2. 240 km
  3. 360 km
  4. 320 km
  5. None of these
  1. A and B together can complete a work in 12 days while A is 50% more efficient than B then find in how many days the work will be complete if they work on alternative days starting with A?
  1. 24 days
  2. 20 days
  3. 18 days
  4. 16 days
  5. None of these
  1. A trade man marks his goods at 30 % above its cost price and allows a discount of 40 %. How much profit/Loss percent does he make?
  1. 28 %
  2. 16 %
  3. 22 %
  4. 34 %
  5. None of these

 

Directions (Q. 16-20) Study the following information carefully and answer the given questions:

Following pie chart shows the percentage distribution of students in various branches in engineering college and the table shows the ratio of students interested in different sports and the ratio of interested and not interested students also given in that table.

 

Branches Interested in sports: Not interested in sports Football: Hockey: Others
CSE 2 : 1 3 : 2 : 3
ECE 5 : 4 2 : 2 : 1
EEE 5 : 1 4 : 1 : 2
IT 7 : 2 2 : 1 : 1
MECH 2 : 1 3 : 1 : 2
AERO 7 : 2 2 : 3 : 1

 

  1. Total number of CSE, EEE and IT branches students, who are all interested in Football is approximately what percentage of a total number of ECE, MECH and AERO branches students, who are all interested in Hockey?
  1. 189 %
  2. 173 %
  3. 271 %
  4. 245 %
  5. 257 %
  1. Find the ratio between the total number of CSE and ECE branches students who are all interested in sports to that of a total number of MECH and AERO branches students who are all not interested in any sports?
  1. 169: 57
  2. 171: 62
  3. 153: 47
  4. 145: 43
  5. None of these
  1. Find the difference between the total number of students who are all interested in Hockey to that of other sports, for all the given branches?
  1. 28
  2. 16
  3. 32
  4. 24
  5. None of these
  1. Find the central angle of CSE and IT branches together?
  1. 156°
  2. 132°
  3. 120°
  4. 144°
  5. None of these
  1. Total number of students who are all interested in football is approximately what percentage more/less than the total number of students who are all not interested in any sports, of all the given branches together?
  1. 43 % more
  2. 57 % less
  3. 64 % less
  4. 36 % more
  5. 22 % more

 

Answers:

Directions (Q. 1 – 5):

  1. Answer c

(5/7) of 343 + (2/3) of (7/15) of 1890 = x % of 700

(5/7) * 343 + (2/3) * (7/15) * 1890 = (x/100)*700

245 + 588 = 7x

833 = 7x

X = 833/7

X = 119 = 120 (Approximately)

  1. Answer d
[49 ÷ 7 × 5] ÷ 70 = 18 ×?

(7*5)/70 = 18x

35/70 = 18x

X = (1/2)*(1/18) = 1/36

  1. Answer b

√x + 28 = (375 + 72) ÷ 50 + (19 × 3)

√x + 28 = 447/50 + 57

√x = 9 + 57 – 28

√x = 38

X = 382 = 1444

  1. Answer a

3290 ÷ 14 × 5 + 15 % of 500 + 27 % of 300 = x

(3290/14)*5 + (15/100)*500 + (27/100)*300 = x

X = 1175 + 75 + 81

X = 1331

  1. Answer e

36 % of 490 + 52 % of 300 = 4 ×?

(36/100)*490 + (52/100)*300 = 4x

4x = 180 + 156

4x = 336

X = (336/4) = 84

X = 84

 

Directions (Q. 6 – 10):

  1. Answer e

The pattern is, *2 +3, *2 +5, *2 +7, *2 + 9, *2 + 11….

The answer is, 1107

  1. Answer a

The pattern is, ÷ 3

The answer is, 90

  1. Answer c

The pattern is, -(13 + 1), +(23 + 1), -(33 + 1), +(43 + 1),..

The answer is, 161

  1. Answer b

The pattern is, ÷ 2 – 1

The answer is, 31.5

  1. Answer d

The pattern is, *0.5 + 1, *1 +1, *1.5 +1, *2 +1, *2.5 +1, *3 +1….

The answer is, 338.5

  1. Answer c

The share of A, B and C

= > [5*2]: [3*1 + 6*1]: [4*2]

= > 10: 9: 8

27’s = 54000

1’s = 2000

The share of B = Rs. 18000.3

  1. Answer a

Let the ratio of ages A and B be 2x and 5x respectively

So,

5x-2x= 18

3x=18

x= 6 years

A’s age= 6*2= 12 years

B’s age= 6*5= 30 years

Total ages of A, B and C at present= 30*3= 90 – 15 = 75 years

Age of C= 75 – (30+12) = 33 years

  1. Answer c

Average speed of the person= 480/6= 80 km/hr

By applying the rule of allegation we get,

 

= > 1: 3

Ratio between distances covered as 1: 3

So, Distance covered by train= 480*3/4 = 360 km

  1. Answer a

Efficiency of A and B = 150: 100 = 3: 2

The ratio of time taken by A and B = 2: 3(2x, 3x)

(1/2x) + (1/3x) = 1/12

5x/(2x*3x) = 1/12

X = 10

The time taken by A and B = 2x, 3x = 20 and 30 days

Total units = 60 (LCM of 20, 30)

A’s one day work= 60/20= 3 units

B’s one day work= 60/30= 2 units

Work done in 2 days= 3 + 2 = 5 units

Work done in 24 days = 5*12 = 60 units

Work will be completed in 24 days.

  1. Answer c

Let the cost price be Rs. 100

Marked price = 100*(130/100) = 130

Selling Price = 130*(60/100) = 78

Loss % = (Loss/CP)*100 = (22/100)*100 = 22 %

 

Directions (Q. 16-20)

Branch Total students Interested in sports Not interested in sports Football Hockey Others
CSE 252 168 84 63 42 63
ECE 306 170 136 68 68 34
EEE 378 315 63 180 45 90
IT 468 364 104 182 91 91
MECH 234 156 78 78 26 52
AERO 162 126 36 42 63 21

 

  1. Answer c

Total number of CSE, EEE and IT branches students, who are all interested in Football

= > 63 + 180 + 182 = 425

Total number of ECE, MECH and AERO branches students, who are all interested in Hockey

= > 68 + 26 + 63 = 157

Required % = (425/157)*100 = 270.70 % = 271 %

  1. Answer a

The total number of CSE and ECE branches students who are all interested in sports

= > 168 + 170 = 338

Total number of MECH and AERO branches students who are all not interested in any sports

= > 78 + 36 = 114

Required ratio = 338: 114 = 169: 57

  1. Answer b

The total number of students who are all interested in Hockey for all the given branches

= > 42 + 68 + 45 + 91 + 26 + 63 = 335

The total number of students who are all interested in other sports for all the given branches

= > 63 + 34 + 90 + 91 + 52 + 21 = 351

Required difference = 351 – 335 = 16

  1. Answer d

The central angle of CSE and IT branches together

= > [(14 + 26)/100]*360

= > (40/100)*360 = 1440

  1. Answer e

Total number of students who are all interested in football of all the given branches together

= > 63 + 68 + 180 + 182 + 78 + 42

= > 613

Total number of students who are all not interested in any sports of all the given branches together

= > 84 + 136 + 63 + 104 + 78 + 36

= > 501

Required % = [(613 – 501)/501]*100 = (112/501)*100 = 22.35 % = 22 % more

 

 

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Current Affairs Quiz 9.00 AM
Quantitative Aptitude “20-20” 11.00 AM
Vocabulary (Based on The Hindu) 12.00 PM
Static GK Quiz 1.00 PM
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Reasoning Puzzles & Seating 4.00 PM
Daily Current Affairs Updates 5.00 PM
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Reasoning Ability “20-20” 7.00 PM
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