“20-20” Quantitative Aptitude | Crack SBI PO Prelims 2018 Day-93
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Directions (Q. 1 – 5): What approximate value should come in place of question mark (?) in the following questions?
3289 ÷ 14 × 5.01 + 15 % of 500 + 27 % of 299 =?
Correct
Answer a
3290 ÷ 14 × 5 + 15 % of 500 + 27 % of 300 = x
(3290/14)*5 + (15/100)*500 + (27/100)*300 = x
X = 1175 + 75 + 81
X = 1331
Incorrect
Answer a
3290 ÷ 14 × 5 + 15 % of 500 + 27 % of 300 = x
(3290/14)*5 + (15/100)*500 + (27/100)*300 = x
X = 1175 + 75 + 81
X = 1331
Question 5 of 20
5. Question
Directions (Q. 1 – 5): What approximate value should come in place of question mark (?) in the following questions?
36 % of 489.8 + 52 % of 301.25 = 4 ×?
Correct
Answer e
36 % of 490 + 52 % of 300 = 4 ×?
(36/100)*490 + (52/100)*300 = 4x
4x = 180 + 156
4x = 336
X = (336/4) = 84
X = 84
Incorrect
Answer e
36 % of 490 + 52 % of 300 = 4 ×?
(36/100)*490 + (52/100)*300 = 4x
4x = 180 + 156
4x = 336
X = (336/4) = 84
X = 84
Question 6 of 20
6. Question
Directions (Q. 6 – 10): What value should come in place of question mark (?) in the following number series?
65, 133, 271, 549,? , 2225
Correct
Answer e
The pattern is, *2 +3, *2 +5, *2 +7, *2 + 9, *2 + 11….
The answer is, 1107
Incorrect
Answer e
The pattern is, *2 +3, *2 +5, *2 +7, *2 + 9, *2 + 11….
The answer is, 1107
Question 7 of 20
7. Question
Directions (Q. 6 – 10): What value should come in place of question mark (?) in the following number series?
7290, 2430, 810, 270,? , 30
Correct
Answer a
The pattern is, ÷ 3
The answer is, 90
Incorrect
Answer a
The pattern is, ÷ 3
The answer is, 90
Question 8 of 20
8. Question
Directions (Q. 6 – 10): What value should come in place of question mark (?) in the following number series?
117, 115, 124, 96,?
Correct
Answer c
The pattern is, -(1^{3} + 1), +(2^{3} + 1), -(3^{3} + 1), +(4^{3} + 1),..
The answer is, 161
Incorrect
Answer c
The pattern is, -(1^{3} + 1), +(2^{3} + 1), -(3^{3} + 1), +(4^{3} + 1),..
The answer is, 161
Question 9 of 20
9. Question
Directions (Q. 6 – 10): What value should come in place of question mark (?) in the following number series?
534, 266, 132, 65,? , 14.75
Correct
Answer b
The pattern is, ÷ 2 – 1
The answer is, 31.5
Incorrect
Answer b
The pattern is, ÷ 2 – 1
The answer is, 31.5
Question 10 of 20
10. Question
Directions (Q. 6 – 10): What value should come in place of question mark (?) in the following number series?
84, 43, 44, 67, 135,? , 1016.5
Correct
Answer d
The pattern is, *0.5 + 1, *1 +1, *1.5 +1, *2 +1, *2.5 +1, *3 +1….
The answer is, 338.5
Incorrect
Answer d
The pattern is, *0.5 + 1, *1 +1, *1.5 +1, *2 +1, *2.5 +1, *3 +1….
The answer is, 338.5
Question 11 of 20
11. Question
A, B and C entered into a partnership with investment in the ratio of 5:3:4 respectively. After one year B doubled his investment. At the end of two years, they earned a profit of Rs.54000. Find the share of B in the profit?
Correct
Answer c
The share of A, B and C
= > [5*2]: [3*1 + 6*1]: [4*2]
= > 10: 9: 8
27’s = 54000
1’s = 2000
The share of B = Rs. 18000.3
Incorrect
Answer c
The share of A, B and C
= > [5*2]: [3*1 + 6*1]: [4*2]
= > 10: 9: 8
27’s = 54000
1’s = 2000
The share of B = Rs. 18000.3
Question 12 of 20
12. Question
The ratio between the ages of two persons A and B is 2:5. If the difference between their ages is 18 years then find the age of another person C if the average age of all the persons five years hence will be 30 years?
Correct
Answer a
Let the ratio of ages A and B be 2x and 5x respectively
So,
5x-2x= 18
3x=18
x= 6 years
A’s age= 6*2= 12 years
B’s age= 6*5= 30 years
Total ages of A, B and C at present= 30*3= 90 – 15 = 75 years
Age of C= 75 – (30+12) = 33 years
Incorrect
Answer a
Let the ratio of ages A and B be 2x and 5x respectively
So,
5x-2x= 18
3x=18
x= 6 years
A’s age= 6*2= 12 years
B’s age= 6*5= 30 years
Total ages of A, B and C at present= 30*3= 90 – 15 = 75 years
Age of C= 75 – (30+12) = 33 years
Question 13 of 20
13. Question
A person covers 480 km in 6 hours. He covers some distance by bus at the average speed of 50 km/hr and the remaining distance by train at the average speed 90 km/hr. Find the distance covered by the train?
Correct
Answer c
Average speed of the person= 480/6= 80 km/hr
By applying the rule of allegation we get,
= > 1: 3
Ratio between distances covered as 1: 3
So, Distance covered by train= 480*3/4 = 360 km
Incorrect
Answer c
Average speed of the person= 480/6= 80 km/hr
By applying the rule of allegation we get,
= > 1: 3
Ratio between distances covered as 1: 3
So, Distance covered by train= 480*3/4 = 360 km
Question 14 of 20
14. Question
A and B together can complete a work in 12 days while A is 50% more efficient than B then find in how many days the work will be complete if they work on alternative days starting with A?
Correct
Answer a
Efficiency of A and B = 150: 100 = 3: 2
The ratio of time taken by A and B = 2: 3(2x, 3x)
(1/2x) + (1/3x) = 1/12
5x/(2x*3x) = 1/12
X = 10
The time taken by A and B = 2x, 3x = 20 and 30 days
Total units = 60 (LCM of 20, 30)
A’s one day work= 60/20= 3 units
B’s one day work= 60/30= 2 units
Work done in 2 days= 3 + 2 = 5 units
Work done in 24 days = 5*12 = 60 units
Work will be completed in 24 days.
Incorrect
Answer a
Efficiency of A and B = 150: 100 = 3: 2
The ratio of time taken by A and B = 2: 3(2x, 3x)
(1/2x) + (1/3x) = 1/12
5x/(2x*3x) = 1/12
X = 10
The time taken by A and B = 2x, 3x = 20 and 30 days
Total units = 60 (LCM of 20, 30)
A’s one day work= 60/20= 3 units
B’s one day work= 60/30= 2 units
Work done in 2 days= 3 + 2 = 5 units
Work done in 24 days = 5*12 = 60 units
Work will be completed in 24 days.
Question 15 of 20
15. Question
A trade man marks his goods at 30 % above its cost price and allows a discount of 40 %. How much profit/Loss percent does he make?
Correct
Answer c
Let the cost price be Rs. 100
Marked price = 100*(130/100) = 130
Selling Price = 130*(60/100) = 78
Loss % = (Loss/CP)*100 = (22/100)*100 = 22 %
Incorrect
Answer c
Let the cost price be Rs. 100
Marked price = 100*(130/100) = 130
Selling Price = 130*(60/100) = 78
Loss % = (Loss/CP)*100 = (22/100)*100 = 22 %
Question 16 of 20
16. Question
Directions (Q. 16-20) Study the following information carefully and answer the given questions:
Following pie chart shows the percentage distribution of students in various branches in engineering college and the table shows the ratio of students interested in different sports and the ratio of interested and not interested students also given in that table.
Branches
Interested in sports: Not interested in sports
Football: Hockey: Others
CSE
2 : 1
3 : 2 : 3
ECE
5 : 4
2 : 2 : 1
EEE
5 : 1
4 : 1 : 2
IT
7 : 2
2 : 1 : 1
MECH
2 : 1
3 : 1 : 2
AERO
7 : 2
2 : 3 : 1
Total number of CSE, EEE and IT branches students, who are all interested in Football is approximately what percentage of a total number of ECE, MECH and AERO branches students, who are all interested in Hockey?
Correct
Directions (16-20):
Branch
Total students
Interested in sports
Not interested in sports
Football
Hockey
Others
CSE
252
168
84
63
42
63
ECE
306
170
136
68
68
34
EEE
378
315
63
180
45
90
IT
468
364
104
182
91
91
MECH
234
156
78
78
26
52
AERO
162
126
36
42
63
21
Answer c
Total number of CSE, EEE and IT branches students, who are all interested in Football
= > 63 + 180 + 182 = 425
Total number of ECE, MECH and AERO branches students, who are all interested in Hockey
= > 68 + 26 + 63 = 157
Required % = (425/157)*100 = 270.70 % = 271 %
Incorrect
Directions (16-20):
Branch
Total students
Interested in sports
Not interested in sports
Football
Hockey
Others
CSE
252
168
84
63
42
63
ECE
306
170
136
68
68
34
EEE
378
315
63
180
45
90
IT
468
364
104
182
91
91
MECH
234
156
78
78
26
52
AERO
162
126
36
42
63
21
Answer c
Total number of CSE, EEE and IT branches students, who are all interested in Football
= > 63 + 180 + 182 = 425
Total number of ECE, MECH and AERO branches students, who are all interested in Hockey
= > 68 + 26 + 63 = 157
Required % = (425/157)*100 = 270.70 % = 271 %
Question 17 of 20
17. Question
Directions (Q. 16-20) Study the following information carefully and answer the given questions:
Following pie chart shows the percentage distribution of students in various branches in engineering college and the table shows the ratio of students interested in different sports and the ratio of interested and not interested students also given in that table.
Branches
Interested in sports: Not interested in sports
Football: Hockey: Others
CSE
2 : 1
3 : 2 : 3
ECE
5 : 4
2 : 2 : 1
EEE
5 : 1
4 : 1 : 2
IT
7 : 2
2 : 1 : 1
MECH
2 : 1
3 : 1 : 2
AERO
7 : 2
2 : 3 : 1
Find the ratio between the total number of CSE and ECE branches students who are all interested in sports to that of a total number of MECH and AERO branches students who are all not interested in any sports?
Correct
Answer a
The total number of CSE and ECE branches students who are all interested in sports
= > 168 + 170 = 338
Total number of MECH and AERO branches students who are all not interested in any sports
= > 78 + 36 = 114
Required ratio = 338: 114 = 169: 57
Incorrect
Answer a
The total number of CSE and ECE branches students who are all interested in sports
= > 168 + 170 = 338
Total number of MECH and AERO branches students who are all not interested in any sports
= > 78 + 36 = 114
Required ratio = 338: 114 = 169: 57
Question 18 of 20
18. Question
Directions (Q. 16-20) Study the following information carefully and answer the given questions:
Following pie chart shows the percentage distribution of students in various branches in engineering college and the table shows the ratio of students interested in different sports and the ratio of interested and not interested students also given in that table.
Branches
Interested in sports: Not interested in sports
Football: Hockey: Others
CSE
2 : 1
3 : 2 : 3
ECE
5 : 4
2 : 2 : 1
EEE
5 : 1
4 : 1 : 2
IT
7 : 2
2 : 1 : 1
MECH
2 : 1
3 : 1 : 2
AERO
7 : 2
2 : 3 : 1
Find the difference between the total number of students who are all interested in Hockey to that of other sports, for all the given branches?
Correct
Answer b
The total number of students who are all interested in Hockey for all the given branches
= > 42 + 68 + 45 + 91 + 26 + 63 = 335
The total number of students who are all interested in other sports for all the given branches
= > 63 + 34 + 90 + 91 + 52 + 21 = 351
Required difference = 351 – 335 = 16
Incorrect
Answer b
The total number of students who are all interested in Hockey for all the given branches
= > 42 + 68 + 45 + 91 + 26 + 63 = 335
The total number of students who are all interested in other sports for all the given branches
= > 63 + 34 + 90 + 91 + 52 + 21 = 351
Required difference = 351 – 335 = 16
Question 19 of 20
19. Question
Directions (Q. 16-20) Study the following information carefully and answer the given questions:
Following pie chart shows the percentage distribution of students in various branches in engineering college and the table shows the ratio of students interested in different sports and the ratio of interested and not interested students also given in that table.
Branches
Interested in sports: Not interested in sports
Football: Hockey: Others
CSE
2 : 1
3 : 2 : 3
ECE
5 : 4
2 : 2 : 1
EEE
5 : 1
4 : 1 : 2
IT
7 : 2
2 : 1 : 1
MECH
2 : 1
3 : 1 : 2
AERO
7 : 2
2 : 3 : 1
Find the central angle of CSE and IT branches together?
Correct
Answer d
The central angle of CSE and IT branches together
= > [(14 + 26)/100]*360
= > (40/100)*360 = 144^{0}
Incorrect
Answer d
The central angle of CSE and IT branches together
= > [(14 + 26)/100]*360
= > (40/100)*360 = 144^{0}
Question 20 of 20
20. Question
Directions (Q. 16-20) Study the following information carefully and answer the given questions:
Following pie chart shows the percentage distribution of students in various branches in engineering college and the table shows the ratio of students interested in different sports and the ratio of interested and not interested students also given in that table.
Branches
Interested in sports: Not interested in sports
Football: Hockey: Others
CSE
2 : 1
3 : 2 : 3
ECE
5 : 4
2 : 2 : 1
EEE
5 : 1
4 : 1 : 2
IT
7 : 2
2 : 1 : 1
MECH
2 : 1
3 : 1 : 2
AERO
7 : 2
2 : 3 : 1
Total number of students who are all interested in football is approximately what percentage more/less than the total number of students who are all not interested in any sports, of all the given branches together?
Correct
Answer e
Total number of students who are all interested in football of all the given branches together
= > 63 + 68 + 180 + 182 + 78 + 42
= > 613
Total number of students who are all not interested in any sports of all the given branches together
Directions (Q. 6 – 10): What value should come in place of question mark (?) in the following number series?
65, 133, 271, 549,? , 2225
941
1277
1593
1541
1107
7290, 2430, 810, 270,? , 30
90
120
150
75
60
117, 115, 124, 96,?
145
178
161
152
187
534, 266, 132, 65,? , 14.7
48.5
31.5
37.5
42.5
45.5
84, 43, 44, 67, 135,? , 1016.5
5
578
662
5
775
11. A, B and C entered into a partnership with investment in the ratio of 5:3:4 respectively. After one year B doubled his investment. At the end of two years, they earned a profit of Rs.54000. Find the share of B in the profit?
21000
27000
18000
14000
None of these
The ratio between the ages of two persons A and B is 2:5. If the difference between their ages is 18 years then find the age of another person C if the average age of all the persons five years hence will be 30 years?
33 years
35 years
28 years
24 years
None of these
A person covers 480 km in 6 hours. He covers some distance by bus at the average speed of 50 km/hr and the remaining distance by train at the average speed 90 km/hr. Find the distance covered by the train?
280 km
240 km
360 km
320 km
None of these
A and B together can complete a work in 12 days while A is 50% more efficient than B then find in how many days the work will be complete if they work on alternative days starting with A?
24 days
20 days
18 days
16 days
None of these
A trade man marks his goods at 30 % above its cost price and allows a discount of 40 %. How much profit/Loss percent does he make?
28 %
16 %
22 %
34 %
None of these
Directions (Q. 16-20) Study the following information carefully and answer the given questions:
Following pie chart shows the percentage distribution of students in various branches in engineering college and the table shows the ratio of students interested in different sports and the ratio of interested and not interested students also given in that table.
Branches
Interested in sports: Not interested in sports
Football: Hockey: Others
CSE
2 : 1
3 : 2 : 3
ECE
5 : 4
2 : 2 : 1
EEE
5 : 1
4 : 1 : 2
IT
7 : 2
2 : 1 : 1
MECH
2 : 1
3 : 1 : 2
AERO
7 : 2
2 : 3 : 1
Total number of CSE, EEE and IT branches students, who are all interested in Football is approximately what percentage of a total number of ECE, MECH and AERO branches students, who are all interested in Hockey?
189 %
173 %
271 %
245 %
257 %
Find the ratio between the total number of CSE and ECE branches students who are all interested in sports to that of a total number of MECH and AERO branches students who are all not interested in any sports?
169: 57
171: 62
153: 47
145: 43
None of these
Find the difference between the total number of students who are all interested in Hockey to that of other sports, for all the given branches?
28
16
32
24
None of these
Find the central angle of CSE and IT branches together?
156°
132°
120°
144°
None of these
Total number of students who are all interested in football is approximately what percentage more/less than the total number of students who are all not interested in any sports, of all the given branches together?
43 % more
57 % less
64 % less
36 % more
22 % more
Answers:
Directions (Q. 1 – 5):
Answer c
(5/7) of 343 + (2/3) of (7/15) of 1890 = x % of 700
(5/7) * 343 + (2/3) * (7/15) * 1890 = (x/100)*700
245 + 588 = 7x
833 = 7x
X = 833/7
X = 119 = 120 (Approximately)
Answer d
[49 ÷ 7 × 5] ÷ 70 = 18 ×?
(7*5)/70 = 18x
35/70 = 18x
X = (1/2)*(1/18) = 1/36
Answer b
√x + 28 = (375 + 72) ÷ 50 + (19 × 3)
√x + 28 = 447/50 + 57
√x = 9 + 57 – 28
√x = 38
X = 38^{2} = 1444
Answer a
3290 ÷ 14 × 5 + 15 % of 500 + 27 % of 300 = x
(3290/14)*5 + (15/100)*500 + (27/100)*300 = x
X = 1175 + 75 + 81
X = 1331
Answer e
36 % of 490 + 52 % of 300 = 4 ×?
(36/100)*490 + (52/100)*300 = 4x
4x = 180 + 156
4x = 336
X = (336/4) = 84
X = 84
Directions (Q. 6 – 10):
Answer e
The pattern is, *2 +3, *2 +5, *2 +7, *2 + 9, *2 + 11….
The answer is, 1107
Answer a
The pattern is, ÷ 3
The answer is, 90
Answer c
The pattern is, -(1^{3} + 1), +(2^{3} + 1), -(3^{3} + 1), +(4^{3} + 1),..
The answer is, 161
Answer b
The pattern is, ÷ 2 – 1
The answer is, 31.5
Answer d
The pattern is, *0.5 + 1, *1 +1, *1.5 +1, *2 +1, *2.5 +1, *3 +1….
The answer is, 338.5
Answer c
The share of A, B and C
= > [5*2]: [3*1 + 6*1]: [4*2]
= > 10: 9: 8
27’s = 54000
1’s = 2000
The share of B = Rs. 18000.3
Answer a
Let the ratio of ages A and B be 2x and 5x respectively
So,
5x-2x= 18
3x=18
x= 6 years
A’s age= 6*2= 12 years
B’s age= 6*5= 30 years
Total ages of A, B and C at present= 30*3= 90 – 15 = 75 years
Age of C= 75 – (30+12) = 33 years
Answer c
Average speed of the person= 480/6= 80 km/hr
By applying the rule of allegation we get,
= > 1: 3
Ratio between distances covered as 1: 3
So, Distance covered by train= 480*3/4 = 360 km
Answer a
Efficiency of A and B = 150: 100 = 3: 2
The ratio of time taken by A and B = 2: 3(2x, 3x)
(1/2x) + (1/3x) = 1/12
5x/(2x*3x) = 1/12
X = 10
The time taken by A and B = 2x, 3x = 20 and 30 days
Total units = 60 (LCM of 20, 30)
A’s one day work= 60/20= 3 units
B’s one day work= 60/30= 2 units
Work done in 2 days= 3 + 2 = 5 units
Work done in 24 days = 5*12 = 60 units
Work will be completed in 24 days.
Answer c
Let the cost price be Rs. 100
Marked price = 100*(130/100) = 130
Selling Price = 130*(60/100) = 78
Loss % = (Loss/CP)*100 = (22/100)*100 = 22 %
Directions (Q. 16-20)
Branch
Total students
Interested in sports
Not interested in sports
Football
Hockey
Others
CSE
252
168
84
63
42
63
ECE
306
170
136
68
68
34
EEE
378
315
63
180
45
90
IT
468
364
104
182
91
91
MECH
234
156
78
78
26
52
AERO
162
126
36
42
63
21
Answer c
Total number of CSE, EEE and IT branches students, who are all interested in Football
= > 63 + 180 + 182 = 425
Total number of ECE, MECH and AERO branches students, who are all interested in Hockey
= > 68 + 26 + 63 = 157
Required % = (425/157)*100 = 270.70 % = 271 %
Answer a
The total number of CSE and ECE branches students who are all interested in sports
= > 168 + 170 = 338
Total number of MECH and AERO branches students who are all not interested in any sports
= > 78 + 36 = 114
Required ratio = 338: 114 = 169: 57
Answer b
The total number of students who are all interested in Hockey for all the given branches
= > 42 + 68 + 45 + 91 + 26 + 63 = 335
The total number of students who are all interested in other sports for all the given branches
= > 63 + 34 + 90 + 91 + 52 + 21 = 351
Required difference = 351 – 335 = 16
Answer d
The central angle of CSE and IT branches together
= > [(14 + 26)/100]*360
= > (40/100)*360 = 144^{0}
Answer e
Total number of students who are all interested in football of all the given branches together
= > 63 + 68 + 180 + 182 + 78 + 42
= > 613
Total number of students who are all not interested in any sports of all the given branches together