“20-20” Quantitative Aptitude | Crack SBI PO Prelims 2018 Day-96

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“20-20” Aptitude Questions | Crack SBI PO Prelims 2018 Day-96

Click here to view Quantitative Aptitude Questions in Hindi

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Directions (Q. 1 – 5): What value should come in place of question mark (?) in the following number series?

  1. 17, ? , 102, 408, 2040
  1. 27
  2. 52
  3. 34
  4. 68
  5. 46
  1. 480, 240, 160,? , 96, 80
  1. 124
  2. 138
  3. 142
  4. 120
  5. 136
  1. 5, 12, 38,? , 772, 4634
  1. 72
  2. 154
  3. 216
  4. 358
  5. 276
  1. 720, 4320, 864, 3456, ? , 2304
  1. 1152
  2. 1078
  3. 1256
  4. 1464
  5. 1638
  1. 92, 90, 99, 71, ? , 10
  1. 114
  2. 128
  3. 92
  4. 84
  5. 136

Directions (Q. 6 – 10): What approximate value should come in place of question mark (?) in the following questions?

  1. 90.05 + 281 ÷ 4 – 151.21 = ∛x
  1. 512
  2. 343
  3. 1000
  4. 729
  5. 216
  1. (17.98)2 ÷ (3.05)2 × 90.11 ÷ 5.01 =? – 551 ÷ 3.98
  1. 830
  2. 720
  3. 790
  4. 880
  5. 940
  1. 80.12 % of 149.98 + 59.98 % of 50 =?
  1. 200
  2. 225
  3. 175
  4. 125
  5. 150
  1. √628 × 18.01 ÷ 15.11 =? – (16.89)2
  1. 320
  2. 390
  3. 430
  4. 480
  5. 270
  1. (1/8) × 121 + (1/5) × 76 – ? = 25
  1. 12
  2. 5
  3. 18
  4. 9
  5. 24
  1. P, Q and R started a business by investing an amount of Rs. 75000, Rs. 90000 and Rs. 80000 respectively. After 3 months, P invested 20 % of initial investment more, Q withdraw Rs. 10000. And after 3 months, R invested Rs. 15000. Find the share of R, if the total profit at the end of the year is Rs. 64370?
  1. Rs. 26760
  2. Rs. 21980
  3. Rs. 32540
  4. Rs. 36620
  5. Rs. 23740
  1. In three numbers, the first is twice the second and thrice the third. If the average of three numbers is 99, then the first number is?
  1. 162
  2. 134
  3. 146
  4. 178
  5. 126
  1. The percentage profit earned when the article is sold for Rs. 546 is double the percentage profit earned when the same article is sold for Rs. 483. If the marked price of the article is 40 % above the cost price, then find the marked price of the article?
  1. Rs. 514
  2. Rs. 552
  3. Rs. 578
  4. Rs. 588
  5. Rs. 512
  1. 5 years ago, the ratio of ages of A to that of B was 2 : 3. C is 12 years older than A and 12 years younger than B. What is C’s present age?
  1. 56 years
  2. 52 years
  3. 65 years
  4. 63 years
  5. None of these
  1. A sum of Rs. 1750 was partly lent at 7 % and 11 % per annum simple interest. The total interest received by them after 4 years was Rs. 706. Find the ratio between the amounts lent at 7 % to that of 11 %?
  1. 8 : 27
  2. 11 : 19
  3. 13 : 25
  4. 17 : 29
  5. None of these

Directions (Q. 16 – 20) Study the following table carefully and answer the given questions:

Following shows the percentage of marks scored by 5 students in 6 different subjects.

  Maths

(200)

 Physics

(150)

 Chemistry

(150)

 Biology

(125)

 Sanskrit

(75)

 English

(100)
A 95 % 84 % 66 % 78 % 92 % 62 %
B 88 % 77 % 78 % 83 % 86 % 78 %
C 76 % 68 % 89 % 91 % 80 % 95 %
D 93 % 56 % 87 % 89 % 75 % 77 %
E 81 % 82 % 78 % 69 % 82 % 90 %

 

  1. Find the total marks scored by Student B in all the given subjects together?
  1. 578.25
  2. 612.50
  3. 654.75
  4. 556.25
  5. 696.75
  1. Find the ratio between the total marks scored by A and C in Maths and Physics together to that of total marks scored by D and E in Chemistry and English together?
  1. 1140 : 829
  2. 1089 : 737
  3. 954 : 751
  4. 861 : 683
  5. None of these
  1. Find the average marks scored by all the given students in Biology?
  1. 112.5
  2. 125.5
  3. 124.5
  4. 102.5
  5. 105.5
  1. Total marks scored by all the given students in Chemistry is approximately what percentage more/less than the total marks scored by all the given students in Physics?
  1. 10%
  2. 8%
  3. 12%
  4. 16%
  5. 18%
  1. Find the difference between the total marks scored by all the students in Sanskrit to that of total marks scored by all the students in English?
  1. 95.75
  2. 92.5
  3. 90.75
  4. 91.5
  5. 96.25

Answers:

1). Answer c

The pattern is, *2, *3, *4, *5…

The answer is, 34

2). Answer d

The pattern is, *1/2, *2/3, *3/4, *4/5, *5/6

The answer is, 120

3). Answer b

The pattern is, *2 + 2, *3 +2, *4 +2, *5 +2, *6 +2…

The answer is, 154

4). Answer a

The pattern is, *6, ÷ 5, *4, ÷ 3, *2…

The answer is, 1152

5). Answer e

The pattern is, -(13 +1), +(23 +1), -(33+1), +(43 +1), -(53 +1),..

The answer is, 136

Directions (Q. 6 – 10):

6). Answer d

90 + (280/4) – 151 = ∛x

90 + 70 – 151 = ∛x

9 = ∛x

X = 93 = 729

7). Answer c

182 ÷ 32 × 90 ÷ 5 =? – (552/4)

[(18*18)/(3*3)]*(90/5) = x – (552/4)

648 + 138 = x

X = 786 = 790

8). Answer e

80 % of 150 + 60 % of 50 = x

(80/100)*150 + (60/100)*50 = x

X = 120 + 30

X = 150

9). Answer a

√625 × 18 ÷ 15 =? – (17)2

25*(18/15) = x – 289

30 + 289 = x

X = 319 = 320

10). Answer b

(1/8)*120 + (1/5)*75 – x = 25

15 + 15 – 25 = x

X = 5

 

11). Answer b

The share of P, Q and R

= > [75000*3 + 75000*(120/100)*9]: [90000*3 + 80000*9]: [80000*6 + 95000*6]

= > 1035000: 990000: 1050000

= > 69: 66: 70

Total profit = Rs. 64370

205’s = 64370

1’s = 314

The share of R = 70’s = 70*314 = Rs. 21980

12). Answer a

Let the first, second and third number be a, b and c.

First number = 2* second number

First number = 3* third number

Average of three numbers = 99

Total of three numbers = 99*3 = 297

According to the question,

a = 2b = 3c

a = 2b = > (a/b) = (2/1)

2b = 3c = > (b/c) = (3/2)

a : b : c = 6 : 3 : 2

11’s = 297

1’s = 27

First number = 6’s = 162

13). Answer d

According to the question,

SP1 – CP = 2*(SP2 – CP)

546 – CP = 2*(483 – CP)

546 – CP = 966 – 2CP

CP = 420

MP = (420/100)*140 = Rs. 588

14). Answer c

5 years ago, the ratio of ages of A to that of B = 2 : 3(2x, 3x)

C = 12 + A

C = B – 12

According to the question,

12 + A = B -12

B – A = 24

3’s – 2’s = 24

1’s = 24

5 years ago, A = 48, B = 72

Present age of A = 53, B = 77

C’s present age = 77 – 12 = 65 years

15). Answer a

Let the amount of two parts be x and 1750 – x

(X*7*4/100) + [(1750-x)*11*4/100] = 706

(4/100) [7x + 19250 – 11x] = 706

19250 – 4x = 17650

19250 – 16750 = 4x

X = 1600/4 = 400

Required ratio = 400: 1350 = 8: 27

Directions (Q. 16 – 20)

16). Answer c

The total marks scored by Student B in all the given subjects

= > (88/100)*200 + (77/100)*150 + (78/100)*150 + (83/100)*125 + (86/100)*75 + (78/100)*100

= > 176 + 115.5 + 117 + 103.75 + 64.5 + 78

= > 654.75

17). Answer a

The total marks scored by A and C in Maths and Physics together

= > (95/100)*200 + (84/100)*150 + (76/100)*200 + (68/100)*150

= > 190 + 126 + 152 + 102

= > 570

The total marks scored by D and E in Chemistry and English together

= > (87/100)*150 + (77/100)*100 + (78/100)*150 + (90/100)*100

= > 130.5 + 77 + 117 + 90

= > 414.5

Required ratio = 570: 414.5 = 5700: 4145 = 1140: 829

18). Answer d

Total marks scored by all the given students in Biology

= > (78 + 83 + 91 + 89 + 69)*125/100

= > 410*(125/100)

= > 512.5

Average marks scored by all the given students in Biology

= > 512.5/5 = 102.5

19). Answer b

Total marks scored by all the given students in Chemistry

= > (66 + 78 + 89 + 87 + 78)*(150/100)

= > 398*(150/100) = 597

Total marks scored by all the given students in Physics

= > (84 + 77 + 68 + 56 + 82)*(150/100)

= > 367*(150/100) = 550.5

Required % = [(597 – 550.5)/550.5]*100 = (46.5/550.5)*100

= > 8.446 % = 8 % more

20). Answer c

The total marks scored by all the students in Sanskrit

= > (92 + 86 + 80 + 75 + 82)*(75/100)

= > 415*(75/100) = 311.25

The total marks scored by all the students in English

= > (62 + 78 + 95 + 77 + 90)*(100/100)

= > 402

Required difference = 402-311.25 = 90.75

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Reasoning Ability “20-20” 7.00 PM
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