“20-20” Quantitative Aptitude | Crack SBI PO Prelims 2018 Day-96
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Directions (Q. 6 – 10): What approximate value should come in place of question mark (?) in the following questions?
80.12 % of 149.98 + 59.98 % of 50 =?
Correct
Answer e
80 % of 150 + 60 % of 50 = x
(80/100)*150 + (60/100)*50 = x
X = 120 + 30
X = 150
Incorrect
Answer e
80 % of 150 + 60 % of 50 = x
(80/100)*150 + (60/100)*50 = x
X = 120 + 30
X = 150
Question 9 of 20
9. Question
Directions (Q. 6 – 10): What approximate value should come in place of question mark (?) in the following questions?
√628 × 18.01 ÷ 15.11 =? – (16.89)^{2}
Correct
Answer a
√625 × 18 ÷ 15 =? – (17)^{2}
25*(18/15) = x – 289
30 + 289 = x
X = 319 = 320
Incorrect
Answer a
√625 × 18 ÷ 15 =? – (17)^{2}
25*(18/15) = x – 289
30 + 289 = x
X = 319 = 320
Question 10 of 20
10. Question
Directions (Q. 6 – 10): What approximate value should come in place of question mark (?) in the following questions?
(1/8) × 121 + (1/5) × 76 – ? = 25
Correct
Answer b
(1/8)*120 + (1/5)*75 – x = 25
15 + 15 – 25 = x
X = 5
Incorrect
Answer b
(1/8)*120 + (1/5)*75 – x = 25
15 + 15 – 25 = x
X = 5
Question 11 of 20
11. Question
P, Q and R started a business by investing an amount of Rs. 75000, Rs. 90000 and Rs. 80000 respectively. After 3 months, P invested 20 % of initial investment more, Q withdraw Rs. 10000. And after 3 months, R invested Rs. 15000. Find the share of R, if the total profit at the end of the year is Rs. 64370?
In three numbers, the first is twice the second and thrice the third. If the average of three numbers is 99, then the first number is?
Correct
Answer a
Let the first, second and third number be a, b and c.
First number = 2* second number
First number = 3* third number
Average of three numbers = 99
Total of three numbers = 99*3 = 297
According to the question,
a = 2b = 3c
a = 2b = > (a/b) = (2/1)
2b = 3c = > (b/c) = (3/2)
a : b : c = 6 : 3 : 2
11’s = 297
1’s = 27
First number = 6’s = 162
Incorrect
Answer a
Let the first, second and third number be a, b and c.
First number = 2* second number
First number = 3* third number
Average of three numbers = 99
Total of three numbers = 99*3 = 297
According to the question,
a = 2b = 3c
a = 2b = > (a/b) = (2/1)
2b = 3c = > (b/c) = (3/2)
a : b : c = 6 : 3 : 2
11’s = 297
1’s = 27
First number = 6’s = 162
Question 13 of 20
13. Question
The percentage profit earned when the article is sold for Rs. 546 is double the percentage profit earned when the same article is sold for Rs. 483. If the marked price of the article is 40 % above the cost price, then find the marked price of the article?
Correct
Answer d
According to the question,
SP1 – CP = 2*(SP2 – CP)
546 – CP = 2*(483 – CP)
546 – CP = 966 – 2CP
CP = 420
MP = (420/100)*140 = Rs. 588
Incorrect
Answer d
According to the question,
SP1 – CP = 2*(SP2 – CP)
546 – CP = 2*(483 – CP)
546 – CP = 966 – 2CP
CP = 420
MP = (420/100)*140 = Rs. 588
Question 14 of 20
14. Question
5 years ago, the ratio of ages of A to that of B was 2 : 3. C is 12 years older than A and 12 years younger than B. What is C’s present age?
Correct
Answer c
5 years ago, the ratio of ages of A to that of B = 2 : 3(2x, 3x)
C = 12 + A
C = B – 12
According to the question,
12 + A = B -12
B – A = 24
3’s – 2’s = 24
1’s = 24
5 years ago, A = 48, B = 72
Present age of A = 53, B = 77
C’s present age = 77 – 12 = 65 years
Incorrect
Answer c
5 years ago, the ratio of ages of A to that of B = 2 : 3(2x, 3x)
C = 12 + A
C = B – 12
According to the question,
12 + A = B -12
B – A = 24
3’s – 2’s = 24
1’s = 24
5 years ago, A = 48, B = 72
Present age of A = 53, B = 77
C’s present age = 77 – 12 = 65 years
Question 15 of 20
15. Question
A sum of Rs. 1750 was partly lent at 7 % and 11 % per annum simple interest. The total interest received by them after 4 years was Rs. 706. Find the ratio between the amounts lent at 7 % to that of 11 %?
Correct
Answer a
Let the amount of two parts be x and 1750 – x
(X*7*4/100) + [(1750-x)*11*4/100] = 706
(4/100) [7x + 19250 – 11x] = 706
19250 – 4x = 17650
19250 – 16750 = 4x
X = 1600/4 = 400
Required ratio = 400: 1350 = 8: 27
Incorrect
Answer a
Let the amount of two parts be x and 1750 – x
(X*7*4/100) + [(1750-x)*11*4/100] = 706
(4/100) [7x + 19250 – 11x] = 706
19250 – 4x = 17650
19250 – 16750 = 4x
X = 1600/4 = 400
Required ratio = 400: 1350 = 8: 27
Question 16 of 20
16. Question
Directions (Q. 16 – 20) Study the following table carefully and answer the given questions:
Following shows the percentage of marks scored by 5 students in 6 different subjects.
Maths
(200)
Physics
(150)
Chemistry
(150)
Biology
(125)
Sanskrit
(75)
English
(100)
A
95 %
84 %
66 %
78 %
92 %
62 %
B
88 %
77 %
78 %
83 %
86 %
78 %
C
76 %
68 %
89 %
91 %
80 %
95 %
D
93 %
56 %
87 %
89 %
75 %
77 %
E
81 %
82 %
78 %
69 %
82 %
90 %
Find the total marks scored by Student B in all the given subjects together?
Correct
Answer c
The total marks scored by Student B in all the given subjects
Directions (Q. 16 – 20) Study the following table carefully and answer the given questions:
Following shows the percentage of marks scored by 5 students in 6 different subjects.
Maths
(200)
Physics
(150)
Chemistry
(150)
Biology
(125)
Sanskrit
(75)
English
(100)
A
95 %
84 %
66 %
78 %
92 %
62 %
B
88 %
77 %
78 %
83 %
86 %
78 %
C
76 %
68 %
89 %
91 %
80 %
95 %
D
93 %
56 %
87 %
89 %
75 %
77 %
E
81 %
82 %
78 %
69 %
82 %
90 %
Find the ratio between the total marks scored by A and C in Maths and Physics together to that of total marks scored by D and E in Chemistry and English together?
Correct
Answer a
The total marks scored by A and C in Maths and Physics together
Directions (Q. 16 – 20) Study the following table carefully and answer the given questions:
Following shows the percentage of marks scored by 5 students in 6 different subjects.
Maths
(200)
Physics
(150)
Chemistry
(150)
Biology
(125)
Sanskrit
(75)
English
(100)
A
95 %
84 %
66 %
78 %
92 %
62 %
B
88 %
77 %
78 %
83 %
86 %
78 %
C
76 %
68 %
89 %
91 %
80 %
95 %
D
93 %
56 %
87 %
89 %
75 %
77 %
E
81 %
82 %
78 %
69 %
82 %
90 %
Find the average marks scored by all the given students in Biology?
Correct
Answer d
Total marks scored by all the given students in Biology
= > (78 + 83 + 91 + 89 + 69)*125/100
= > 410*(125/100)
= > 512.5
Average marks scored by all the given students in Biology
= > 512.5/5 = 102.5
Incorrect
Answer d
Total marks scored by all the given students in Biology
= > (78 + 83 + 91 + 89 + 69)*125/100
= > 410*(125/100)
= > 512.5
Average marks scored by all the given students in Biology
= > 512.5/5 = 102.5
Question 19 of 20
19. Question
Directions (Q. 16 – 20) Study the following table carefully and answer the given questions:
Following shows the percentage of marks scored by 5 students in 6 different subjects.
Maths
(200)
Physics
(150)
Chemistry
(150)
Biology
(125)
Sanskrit
(75)
English
(100)
A
95 %
84 %
66 %
78 %
92 %
62 %
B
88 %
77 %
78 %
83 %
86 %
78 %
C
76 %
68 %
89 %
91 %
80 %
95 %
D
93 %
56 %
87 %
89 %
75 %
77 %
E
81 %
82 %
78 %
69 %
82 %
90 %
Total marks scored by all the given students in Chemistry is approximately what percentage more/less than the total marks scored by all the given students in Physics?
Correct
Answer b
Total marks scored by all the given students in Chemistry
= > (66 + 78 + 89 + 87 + 78)*(150/100)
= > 398*(150/100) = 597
Total marks scored by all the given students in Physics
P, Q and R started a business by investing an amount of Rs. 75000, Rs. 90000 and Rs. 80000 respectively. After 3 months, P invested 20 % of initial investment more, Q withdraw Rs. 10000. And after 3 months, R invested Rs. 15000. Find the share of R, if the total profit at the end of the year is Rs. 64370?
Rs. 26760
Rs. 21980
Rs. 32540
Rs. 36620
Rs. 23740
In three numbers, the first is twice the second and thrice the third. If the average of three numbers is 99, then the first number is?
162
134
146
178
126
The percentage profit earned when the article is sold for Rs. 546 is double the percentage profit earned when the same article is sold for Rs. 483. If the marked price of the article is 40 % above the cost price, then find the marked price of the article?
Rs. 514
Rs. 552
Rs. 578
Rs. 588
Rs. 512
5 years ago, the ratio of ages of A to that of B was 2 : 3. C is 12 years older than A and 12 years younger than B. What is C’s present age?
56 years
52 years
65 years
63 years
None of these
A sum of Rs. 1750 was partly lent at 7 % and 11 % per annum simple interest. The total interest received by them after 4 years was Rs. 706. Find the ratio between the amounts lent at 7 % to that of 11 %?
8 : 27
11 : 19
13 : 25
17 : 29
None of these
Directions (Q. 16 – 20) Study the following table carefully and answer the given questions:
Following shows the percentage of marks scored by 5 students in 6 different subjects.
Maths
(200)
Physics
(150)
Chemistry
(150)
Biology
(125)
Sanskrit
(75)
English
(100)
A
95 %
84 %
66 %
78 %
92 %
62 %
B
88 %
77 %
78 %
83 %
86 %
78 %
C
76 %
68 %
89 %
91 %
80 %
95 %
D
93 %
56 %
87 %
89 %
75 %
77 %
E
81 %
82 %
78 %
69 %
82 %
90 %
Find the total marks scored by Student B in all the given subjects together?
578.25
612.50
654.75
556.25
696.75
Find the ratio between the total marks scored by A and C in Maths and Physics together to that of total marks scored by D and E in Chemistry and English together?
1140 : 829
1089 : 737
954 : 751
861 : 683
None of these
Find the average marks scored by all the given students in Biology?
112.5
125.5
124.5
102.5
105.5
Total marks scored by all the given students in Chemistry is approximately what percentage more/less than the total marks scored by all the given students in Physics?
10%
8%
12%
16%
18%
Find the difference between the total marks scored by all the students in Sanskrit to that of total marks scored by all the students in English?
95.75
92.5
90.75
91.5
96.25
Answers:
1). Answer c
The pattern is, *2, *3, *4, *5…
The answer is, 34
2). Answer d
The pattern is, *1/2, *2/3, *3/4, *4/5, *5/6
The answer is, 120
3). Answer b
The pattern is, *2 + 2, *3 +2, *4 +2, *5 +2, *6 +2…
The answer is, 154
4). Answer a
The pattern is, *6, ÷ 5, *4, ÷ 3, *2…
The answer is, 1152
5). Answer e
The pattern is, -(1^{3} +1), +(2^{3} +1), -(3^{3}+1), +(4^{3} +1), -(5^{3} +1),..