“20-20” Quantitative Aptitude | Crack Dena bank 2018 Day-98
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“20-20” Aptitude Questions | Crack Dena Bank 2018 Day-98
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Question 1 of 20
1. Question
Directions (Q. 1 – 5) Read the information given below carefully and answer the questions that follow:
In a company there are 5200 employees in five departments – Operation, Production, Admin, IT and Marketing. Out of the total number of female employees in the company, 27% work in Operations, 22% work in Admin, and 16% work in Production and the remaining 840 female employees work in IT. There is no female in Marketing. Out of the total number of male employees in the company, 14% work in Operation, 30% work in Admin, 25% work in Production, and 11% work in IT and remaining in Marketing.
If the number of male employees in Production increases by 20%, the male employees in IT increases by 25%, 60 male employees join Marketing and the number of male employees in Operation and Admin remain the same, what is the percentage increase in the number of male employees in the company?
Correct
Directions (1-5):
Number of females employees in IT department= 840
Percentage of female employees in IT department
= 100- (27+22+16) = 100-65= 35%
So,
35%= 840
100%= 840/35*100= 2400
So,
Male employees in the company= 5200- 2400= 2800
Operations department:
Female = 27/100*2400= 648
Male = 14/100* 2800= 392
Admin Department:
Female= 22/100* 2400= 528
Male= 30/100* 2800= 840
Production Department
Female= 16/100* 2400= 384
Male= 25/100* 2800= 700
IT Department:
Female = 840
Male= 11/100* 2800= 308
Marketing
Female = 0
Male = 2800- (392+ 840+ 700+ 308) = 560
Department
Male
Female
Operation
392
648
Production
700
384
Admin
840
528
IT
308
840
Marketing
560
_
Answer c
Total increase in employees= 20% of 700 + 25% of 308 + 60= 277
Percentage Increase= 277/2800* 100= 9.89%
Incorrect
Directions (1-5):
Number of females employees in IT department= 840
Percentage of female employees in IT department
= 100- (27+22+16) = 100-65= 35%
So,
35%= 840
100%= 840/35*100= 2400
So,
Male employees in the company= 5200- 2400= 2800
Operations department:
Female = 27/100*2400= 648
Male = 14/100* 2800= 392
Admin Department:
Female= 22/100* 2400= 528
Male= 30/100* 2800= 840
Production Department
Female= 16/100* 2400= 384
Male= 25/100* 2800= 700
IT Department:
Female = 840
Male= 11/100* 2800= 308
Marketing
Female = 0
Male = 2800- (392+ 840+ 700+ 308) = 560
Department
Male
Female
Operation
392
648
Production
700
384
Admin
840
528
IT
308
840
Marketing
560
_
Answer c
Total increase in employees= 20% of 700 + 25% of 308 + 60= 277
Percentage Increase= 277/2800* 100= 9.89%
Question 2 of 20
2. Question
Directions (Q. 1 – 5) Read the information given below carefully and answer the questions that follow:
In a company there are 5200 employees in five departments – Operation, Production, Admin, IT and Marketing. Out of the total number of female employees in the company, 27% work in Operations, 22% work in Admin, and 16% work in Production and the remaining 840 female employees work in IT. There is no female in Marketing. Out of the total number of male employees in the company, 14% work in Operation, 30% work in Admin, 25% work in Production, and 11% work in IT and remaining in Marketing.
The total number of male employees working Admin and Production together what percent of the total number of employees working in these two departments?
Correct
Answer e
Total number of male employees in Admin and Production= 840+700= 1540
Total number of employees in these two departments
= > 840+528+700+384= 2452
Required percentage= (1540/2452)* 100= 62.8 %
Incorrect
Answer e
Total number of male employees in Admin and Production= 840+700= 1540
Total number of employees in these two departments
= > 840+528+700+384= 2452
Required percentage= (1540/2452)* 100= 62.8 %
Question 3 of 20
3. Question
Directions (Q. 1 – 5) Read the information given below carefully and answer the questions that follow:
In a company there are 5200 employees in five departments – Operation, Production, Admin, IT and Marketing. Out of the total number of female employees in the company, 27% work in Operations, 22% work in Admin, and 16% work in Production and the remaining 840 female employees work in IT. There is no female in Marketing. Out of the total number of male employees in the company, 14% work in Operation, 30% work in Admin, 25% work in Production, and 11% work in IT and remaining in Marketing.
What is the average number of employees who work in Operation, Admin and Production department together?
Correct
Answer d
Average = (648+528+384+392+840+700)/3 = 3492/3=1164
Incorrect
Answer d
Average = (648+528+384+392+840+700)/3 = 3492/3=1164
Question 4 of 20
4. Question
Directions (Q. 1 – 5) Read the information given below carefully and answer the questions that follow:
In a company there are 5200 employees in five departments – Operation, Production, Admin, IT and Marketing. Out of the total number of female employees in the company, 27% work in Operations, 22% work in Admin, and 16% work in Production and the remaining 840 female employees work in IT. There is no female in Marketing. Out of the total number of male employees in the company, 14% work in Operation, 30% work in Admin, 25% work in Production, and 11% work in IT and remaining in Marketing.
If equal number of female and male employees working in Production leave the job, the ratio of the number of male employees working in Production to the number of females working in the same department reduces to 149: 70. What is the total number of employees working in Production department who left the job?
Correct
Answer a
Let the number of male employees who left the job be x
Then,
700-x/384-x= 149/70
149x- 70x= 149 * 384 – 700*70
79x= 57216- 49000
X= 8216/79= 104
So,
Total number of employees who left= 104*2= 208
Incorrect
Answer a
Let the number of male employees who left the job be x
Then,
700-x/384-x= 149/70
149x- 70x= 149 * 384 – 700*70
79x= 57216- 49000
X= 8216/79= 104
So,
Total number of employees who left= 104*2= 208
Question 5 of 20
5. Question
Directions (Q. 1 – 5) Read the information given below carefully and answer the questions that follow:
In a company there are 5200 employees in five departments – Operation, Production, Admin, IT and Marketing. Out of the total number of female employees in the company, 27% work in Operations, 22% work in Admin, and 16% work in Production and the remaining 840 female employees work in IT. There is no female in Marketing. Out of the total number of male employees in the company, 14% work in Operation, 30% work in Admin, 25% work in Production, and 11% work in IT and remaining in Marketing.
If 92 male employees of Operation are transferred to IT and 70 female employees of IT department are transferred to Operation, then what is the ratio of the number of male employees to the number of the female employees in IT after the transfer of employees?
Correct
Answer d
Number of male employees in IT after the transfer of 92 males = 308+92= 400
Number of females in IT= 840 -70= 770
Required ratio = 400:770= 40:77
Incorrect
Answer d
Number of male employees in IT after the transfer of 92 males = 308+92= 400
Number of females in IT= 840 -70= 770
Required ratio = 400:770= 40:77
Question 6 of 20
6. Question
Directions (Q. 6 – 10): The following questions are accompanied by three statements I, II and III. You have to determine which statement is/are sufficient to answer the questions. Give answer as:
What is the amount of profit earned?
10% discount was offered on the labelled price?
Had there been no discount, profit would have been 30%
Selling price was more than the cost price by 20%
Correct
Answer e
Let the marked price be x
From I
Selling Price= 90% of X= 9x/10
From II
If Selling price be x then gains= 30%
Cost Price= 100/130*x= 10x/13
From III
Gain= 20%
So, the answer cannot be find out.
Incorrect
Answer e
Let the marked price be x
From I
Selling Price= 90% of X= 9x/10
From II
If Selling price be x then gains= 30%
Cost Price= 100/130*x= 10x/13
From III
Gain= 20%
So, the answer cannot be find out.
Question 7 of 20
7. Question
Directions (Q. 6 – 10): The following questions are accompanied by three statements I, II and III. You have to determine which statement is/are sufficient to answer the questions. Give answer as:
A sum of money is placed at compound interest. In how many years will it amount to sixteen times of itself?
The sum doubles itself in 4 years
The sum amounts to eight times of itself in 12 years
The sum amount to four times of itself in 8 years
Correct
Answer d
From I
P (1+R/100)^{4} = 2P
= (1+R/100)^{4 }= 2
From II
P (1+R/100)^{12} = 8P
= (1+R/100)^{12 }= 8
From III
P (1+R/100)^{8} = 4P
= (1+R/100)^{8 }= 4
Let the given sum become 16 times in n years
P (1+R/100)^{n} = 16P
= (1+R/100)^{n }= 16
So, Any of the three statement is sufficient
Incorrect
Answer d
From I
P (1+R/100)^{4} = 2P
= (1+R/100)^{4 }= 2
From II
P (1+R/100)^{12} = 8P
= (1+R/100)^{12 }= 8
From III
P (1+R/100)^{8} = 4P
= (1+R/100)^{8 }= 4
Let the given sum become 16 times in n years
P (1+R/100)^{n} = 16P
= (1+R/100)^{n }= 16
So, Any of the three statement is sufficient
Question 8 of 20
8. Question
Directions (Q. 6 – 10): The following questions are accompanied by three statements I, II and III. You have to determine which statement is/are sufficient to answer the questions. Give answer as:
What is the speed of the boat in still water?
The speed downstream is 12 km/hr
The speed upstream is 4 km/hr
In a to and from journey between two points, the average speed of the boat was 6 km/hr
Correct
Answer d
From I and II
Speed of the boat in still water= ½*12= 6km/hr
From II and III
Using average speed,
2*4*y/4+y= 6
8y= 24+6y
y= 12
Required speed= ½(12+4) = 8 km/hr
Similarly I and III also give the answer.
Incorrect
Answer d
From I and II
Speed of the boat in still water= ½*12= 6km/hr
From II and III
Using average speed,
2*4*y/4+y= 6
8y= 24+6y
y= 12
Required speed= ½(12+4) = 8 km/hr
Similarly I and III also give the answer.
Question 9 of 20
9. Question
Directions (Q. 6 – 10): The following questions are accompanied by three statements I, II and III. You have to determine which statement is/are sufficient to answer the questions. Give answer as:
At what time will the train reach city X from city Y?
The length of the platform is 150 meters.
The train leaves city Y at 7:15 am towards city X which is situated at a distance of 558 km.
The 200 meters long train crosses a signal pole in 10 seconds.
Correct
Answer b
From III,
Speed = 200/10= 20m/s
In km/hr=20*18/5= 72km/hr
From II,
Time taken= 558/72= 31/4 hours = 7 hours 45 minutes
So, the train will reach city X at 3 pm
So, statement II and III is required.
Incorrect
Answer b
From III,
Speed = 200/10= 20m/s
In km/hr=20*18/5= 72km/hr
From II,
Time taken= 558/72= 31/4 hours = 7 hours 45 minutes
So, the train will reach city X at 3 pm
So, statement II and III is required.
Question 10 of 20
10. Question
Directions (Q. 6 – 10): The following questions are accompanied by three statements I, II and III. You have to determine which statement is/are sufficient to answer the questions. Give answer as:
If both the pipes are opened, how many hours will be taken to fill the tank?
The capacity of the tank is 400 liters
The pipe A fills the tank in 4 hours
The pipe B fills the tank in 6 hours
Correct
Answer b
From II and III,
Total units of work= 12
A’s one hour work= 3 units
B’s one hour work= 2 units
Working together they will take= 12/5 hours
Incorrect
Answer b
From II and III,
Total units of work= 12
A’s one hour work= 3 units
B’s one hour work= 2 units
Working together they will take= 12/5 hours
Question 11 of 20
11. Question
If the numerator of a fraction is increased by 130% and the denominator of the fraction is increased by 150%, the resultant fraction becomes 1/2. Then what is the original fraction?
Correct
Answer a
The original fraction be (X/Y)
[X*(230/100)]/[Y*(250/100)] = (1/2)
23X/25Y = ½
(X/Y) = (1/2)*(25/23) = 25/46
Incorrect
Answer a
The original fraction be (X/Y)
[X*(230/100)]/[Y*(250/100)] = (1/2)
23X/25Y = ½
(X/Y) = (1/2)*(25/23) = 25/46
Question 12 of 20
12. Question
Ajay gave 35% of his salary to his wife. From the remaining amount 40% he kept in his bank account. The sum of the amount he kept in bank and he gave to his wife was Rs 87840. What was his monthly salary?
Correct
Answer d
Let the monthly salary of Ajay be x
Amount given to her wife= x*35/100= 7x/20
Remaining amount= x-7x/20= 13x/20
Amount kept in bank
= (13x/20)*40/100= 13x/50
So,
13x/50 + 7x/20= 87840
26x+35x/100= 87840
61x= 87840*100
x= 8784000/61
x= Rs. 144000
Incorrect
Answer d
Let the monthly salary of Ajay be x
Amount given to her wife= x*35/100= 7x/20
Remaining amount= x-7x/20= 13x/20
Amount kept in bank
= (13x/20)*40/100= 13x/50
So,
13x/50 + 7x/20= 87840
26x+35x/100= 87840
61x= 87840*100
x= 8784000/61
x= Rs. 144000
Question 13 of 20
13. Question
A can finish a work in 24 days. B can finish the same work in 9 days and C in 12 days. B and C start the work but they are forced to leave after 3 days. How many days A will take to finish the remaining work?
Correct
Answer b
A’s one day work = (1/24)
B’s one day work = (1/9)
C’s one day work = (1/12)
(B + C)’s one day work = (1/9) + (1/12) = 21/(9*12) = 7/36
(B + C)’s 3 day work = (7/36)*3 = 7/12
Remaining work = 5/12
A can finish the remaining work in,
= > (5/12)*24 = 10 days
Incorrect
Answer b
A’s one day work = (1/24)
B’s one day work = (1/9)
C’s one day work = (1/12)
(B + C)’s one day work = (1/9) + (1/12) = 21/(9*12) = 7/36
(B + C)’s 3 day work = (7/36)*3 = 7/12
Remaining work = 5/12
A can finish the remaining work in,
= > (5/12)*24 = 10 days
Question 14 of 20
14. Question
A train crosses a platform of length 150 m in 12 sec and the same train crosses a pole in 8 sec. Find the length of the train?
Correct
Answer c
According to the question,
(T.L + 150)/12 = T.L/8
2T.L + 300 = 3T.L
300 = T.L
The length of the train = 300 m
Incorrect
Answer c
According to the question,
(T.L + 150)/12 = T.L/8
2T.L + 300 = 3T.L
300 = T.L
The length of the train = 300 m
Question 15 of 20
15. Question
Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is?
Correct
Answer a
Compound Interest:
4000*(10/100) = 400
4400*(10/100) = 440
C.I = 840
S.I = (1/2)*C.I = 840/2 = 420
According to the question,
= > S.I = PNR/100
= > 420 = P*3*8/100
= > P = (420*100)/24
= > P = Rs. 1750
Incorrect
Answer a
Compound Interest:
4000*(10/100) = 400
4400*(10/100) = 440
C.I = 840
S.I = (1/2)*C.I = 840/2 = 420
According to the question,
= > S.I = PNR/100
= > 420 = P*3*8/100
= > P = (420*100)/24
= > P = Rs. 1750
Question 16 of 20
16. Question
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
10x^{2} -17x +7 =0
15y^{2} -19y +6 =0
Correct
Answer a
I. 10x^{2} -17x +7 =0
10x^{2} -10x-7x +7 =0
10x(x-1) -7(x-1) =0
(10x-7) (x-1) =0
X= 7/10, 1
II. 15y^{2} -19y +6 =0
15y^{2} -10y-9y +6 =0
5y(3y-2)-3 (3y-2) =0
(5y-3) (3y-2) =0
Y= 3/5, 2/3
x>y
Incorrect
Answer a
I. 10x^{2} -17x +7 =0
10x^{2} -10x-7x +7 =0
10x(x-1) -7(x-1) =0
(10x-7) (x-1) =0
X= 7/10, 1
II. 15y^{2} -19y +6 =0
15y^{2} -10y-9y +6 =0
5y(3y-2)-3 (3y-2) =0
(5y-3) (3y-2) =0
Y= 3/5, 2/3
x>y
Question 17 of 20
17. Question
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
12x^{2} +19x +5 =0
5y^{2} + 16y +3 =0
Correct
Answer e
I. 12x^{2} +19x +5 =0
12x^{2} +4x +15x +5 =0
4x(3x+1)+5 (3x+1) =0
(4x+5)(3x+1) =0
X=-5/4, -1/3
II. 5y^{2} + 16y +3 =0
5y^{2} + y+15y +3 =0
Y(5y+1)+3 (5y+1) =0
(y+3) (5y+1) =0
Y=-3, -1/5
Can’t be determined
Incorrect
Answer e
I. 12x^{2} +19x +5 =0
12x^{2} +4x +15x +5 =0
4x(3x+1)+5 (3x+1) =0
(4x+5)(3x+1) =0
X=-5/4, -1/3
II. 5y^{2} + 16y +3 =0
5y^{2} + y+15y +3 =0
Y(5y+1)+3 (5y+1) =0
(y+3) (5y+1) =0
Y=-3, -1/5
Can’t be determined
Question 18 of 20
18. Question
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
6x^{2} + 31x + 35 =0
2y^{2 }+ 3y + 1=0
Correct
Answer c
I. 6x^{2} + 31x + 35 =0
6x^{2} + 21x+10x + 35 =0
3x(2x+7)+5 (2x+7)=0
(3x+5)(2x+7) =0
X= -5/3, -7/2
II. 2y^{2 }+ 3y + 1=0
2y^{2 }+ 2y +y+ 1=0
2y(y+1) +1(y+1) =0
(2y+1) (y+1) =0
Y= -1/2, -1
X<y
Incorrect
Answer c
I. 6x^{2} + 31x + 35 =0
6x^{2} + 21x+10x + 35 =0
3x(2x+7)+5 (2x+7)=0
(3x+5)(2x+7) =0
X= -5/3, -7/2
II. 2y^{2 }+ 3y + 1=0
2y^{2 }+ 2y +y+ 1=0
2y(y+1) +1(y+1) =0
(2y+1) (y+1) =0
Y= -1/2, -1
X<y
Question 19 of 20
19. Question
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
X^{2} – 264 = 361
y^{3} – 878 = 453
Correct
Answer e
I. X^{2} – 264 = 361
X^{2} = 361+264
X^{2} = 625
X= 25, -25
II. y^{3} – 878 = 453
Y^{3} = 453 + 878
Y^{3} = 1331
Y =11
Can’t be determined
Incorrect
Answer e
I. X^{2} – 264 = 361
X^{2} = 361+264
X^{2} = 625
X= 25, -25
II. y^{3} – 878 = 453
Y^{3} = 453 + 878
Y^{3} = 1331
Y =11
Can’t be determined
Question 20 of 20
20. Question
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
Click “Start Quiz” to attend these Questions and view Solutions
Directions (Q. 1 – 5) Read the information given below carefully and answer the questions that follow:
In a company there are 5200 employees in five departments – Operation, Production, Admin, IT and Marketing. Out of the total number of female employees in the company, 27% work in Operations, 22% work in Admin, and 16% work in Production and the remaining 840 female employees work in IT. There is no female in Marketing. Out of the total number of male employees in the company, 14% work in Operation, 30% work in Admin, 25% work in Production, and 11% work in IT and remaining in Marketing.
If the number of male employees in Production increases by 20% , the male employees in IT increases by 25%, 60 male employees join Marketing and the number of male employees in Operation and Admin remain the same, what is the percentage increase in the number of male employees in the company?
a) 11.12 %
b) 127.22 %
c) 9.89 %
d) 6.77 %
e) 12.87 %
The total number of male employees working Admin and Production together what percent of the total number of employees working in these two departments?
a) 70.50 %
b) 24.45 %
c) 50.25 %
d) 45.65 %
e) 62.80 %
What is the average number of employees who work in Operation, Admin and Production department together?
a) 1112
b) 1222
c) 1989
d) 1164
e) 1275
If equal number of female and male employees working in Production leave the job, the ratio of the number of male employees working in Production to the number of females working in the same department reduces to 149: 70. What is the total number of employees working in Production department who left the job?
a) 208
b) 122
c) 198
d) 102
e) 127
If 92 male employees of Operation are transferred to IT and 70 female employees of IT department are transferred to Operation, then what is the ratio of the number of male employees to the number of the female employees in IT after the transfer of employees?
a) 11:12
b) 12:17
c) 19:89
d) 40:77
e) 12:75
Directions (Q. 6 – 10): The following questions are accompanied by three statements I, II and III. You have to determine which statement is/are sufficient to answer the questions. Give answer as:
What is the amount of profit earned?
10% discount was offered on the labelled price?
Had there been no discount, profit would have been 30%
Selling price was more than the cost price by 20%
a) Only I and II
b) Only II and III
c) Only I and III
d) Any two of the three
e) All three together is not sufficient.
A sum of money is placed at compound interest. In how many years will it amount to sixteen times of itself?
The sum doubles itself in 4 years
The sum amounts to eight times of itself in 12 years
The sum amount to four times of itself in 8 years
a) Only I and II
b) Only II and III
c) Only I and III
d) Any one of the three
e) All three together is not sufficient
What is the speed of the boat in still water?
The speed downstream is 12 km/hr
The speed upstream is 4 km/hr
In a to and from journey between two points, the average speed of the boat was 6 km/hr
a) Only I and II
b) Only II and III
c) Only I and III
d) Any two of the three
e) All three together is not sufficient.
At what time will the train reach city X from city Y?
The length of the platform is 150 meters.
The train leaves city Y at 7:15 am towards city X which is situated at a distance of 558 km.
The 200 meters long train crosses a signal pole in 10 seconds.
a) Only I and II
b) Only II and III
c) Only I and III
d) Any two of the three
e) All three together is not sufficient
If both the pipes are opened, how many hours will be taken to fill the tank?
The capacity of the tank is 400 liters
The pipe A fills the tank in 4 hours
The pipe B fills the tank in 6 hours
a) Only I and II
b) Only II and III
c) Only I and III
d) Any two of the three
e) All three together is not sufficient
If the numerator of a fraction is increased by 130% and the denominator of the fraction is increased by 150%, the resultant fraction becomes 1/2. Then what is the original fraction?
25/46
13/19
15/26
27/32
None of these
Ajay gave 35% of his salary to his wife. From the remaining amount 40% he kept in his bank account. The sum of the amount he kept in bank and he gave to his wife was Rs 87840. What was his monthly salary?
98000
85000
116000
144000
None of these
A can finish a work in 24 days. B can finish the same work in 9 days and C in 12 days. B and C start the work but they are forced to leave after 3 days. How many days A will take to finish the remaining work?
14 days
10 days
18 days
12 days
None of these
A train crosses a platform of length 150 m in 12 sec and the same train crosses a pole in 8 sec. Find the length of the train?
175 m
225 m
300 m
275 m
None of these
Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is?
1750
2500
3150
3750
None of these
Directions (Q. 16 – 20): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer
if x > y
if x ≥ y
if x < y
if x ≤ y
if x = y or no relation can be established between x and y
16).
I. 10x^{2} -17x +7 =0
II. 15y^{2} -19y +6 =0
17).
I. 12x^{2} +19x +5 =0
II. 5y^{2} + 16y +3 =0
^{ 18). }
I. 6x^{2} + 31x + 35 =0
II. 2y^{2 }+ 3y + 1=0
19).
I. X^{2} – 264 = 361
II. y^{3} – 878 = 453
20).
I. 4x^{2}– 30x +56 =0
II. y^{2 }– 7y+12 =0
Answers:
Directions (1-5):
Number of females employees in IT department= 840
Percentage of female employees in IT department
= 100- (27+22+16) = 100-65= 35%
So,
35%= 840
100%= 840/35*100= 2400
So,
Male employees in the company= 5200- 2400= 2800
Operations department:
Female = 27/100*2400= 648
Male = 14/100* 2800= 392
Admin Department:
Female= 22/100* 2400= 528
Male= 30/100* 2800= 840
Production Department
Female= 16/100* 2400= 384
Male= 25/100* 2800= 700
IT Department:
Female = 840
Male= 11/100* 2800= 308
Marketing
Female = 0
Male = 2800- (392+ 840+ 700+ 308) = 560
Department
Male
Female
Operation
392
648
Production
700
384
Admin
840
528
IT
308
840
Marketing
560
_
Answer c
Total increase in employees= 20% of 700 + 25% of 308 + 60= 277
Percentage Increase= 277/2800* 100= 9.89%
Answer e
Total number of male employees in Admin and Production= 840+700= 1540
Total number of employees in these two departments
= > 840+528+700+384= 2452
Required percentage= (1540/2452)* 100= 62.8 %
Answer d
Average = (648+528+384+392+840+700)/3 = 3492/3=1164
Answer a
Let the number of male employees who left the job be x
Then,
700-x/384-x= 149/70
149x- 70x= 149 * 384 – 700*70
79x= 57216- 49000
X= 8216/79= 104
So,
Total number of employees who left= 104*2= 208
Answer d
Number of male employees in IT after the transfer of 92 males = 308+92= 400
Number of females in IT= 840 -70= 770
Required ratio = 400:770= 40:77
Directions (Q. 6 – 10):
Answer e
Let the marked price be x
From I
Selling Price= 90% of X= 9x/10
From II
If Selling price be x then gains= 30%
Cost Price= 100/130*x= 10x/13
From III
Gain= 20%
So, the answer cannot be find out.
Answer d
From I
P (1+R/100)^{4} = 2P
= (1+R/100)^{4 }= 2
From II
P (1+R/100)^{12} = 8P
= (1+R/100)^{12 }= 8
From III
P (1+R/100)^{8} = 4P
= (1+R/100)^{8 }= 4
Let the given sum become 16 times in n years
P (1+R/100)^{n} = 16P
= (1+R/100)^{n }= 16
So, Any of the three statement is sufficient
Answer d
From I and II
Speed of the boat in still water= ½*12= 6km/hr
From II and III
Using average speed,
2*4*y/4+y= 6
8y= 24+6y
y= 12
Required speed= ½(12+4) = 8 km/hr
Similarly I and III also give the answer.
Answer b
From III,
Speed = 200/10= 20m/s
In km/hr=20*18/5= 72km/hr
From II,
Time taken= 558/72= 31/4 hours = 7 hours 45 minutes
So, the train will reach city X at 3 pm
So, statement II and III is required.
Answer b
From II and III,
Total units of work= 12
A’s one hour work= 3 units
B’s one hour work= 2 units
Working together they will take= 12/5 hours
Answer a
The original fraction be (X/Y)
[X*(230/100)]/[Y*(250/100)] = (1/2)
23X/25Y = ½
(X/Y) = (1/2)*(25/23) = 25/46
Answer d
Let the monthly salary of Ajay be x
Amount given to her wife= x*35/100= 7x/20
Remaining amount= x-7x/20= 13x/20
Amount kept in bank
= (13x/20)*40/100= 13x/50
So,
13x/50 + 7x/20= 87840
26x+35x/100= 87840
61x= 87840*100
x= 8784000/61
x= Rs. 144000
Answer b
A’s one day work = (1/24)
B’s one day work = (1/9)
C’s one day work = (1/12)
(B + C)’s one day work = (1/9) + (1/12) = 21/(9*12) = 7/36