Practice Quantitative Aptitude Questions For SBI PO Prelims& NIACL 2017 (Simplification)

Practice Quantitative Aptitude Questions For SBI PO Prelims& NIACL 2017

Practice Quantitative Aptitude Questions For SBI PO Prelims& NIACL 2017 (Simplification):

Dear Readers, Important Practice Aptitude Questions for Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the Bank Examination and other Competitive Examination can use this.


Directions (Q. 1-10): what will come in place of question mark (?) in the given questions .

1). [4 2/3 + 3 4/9 + 6 5/9] ÷ ? = 12
a)  2 2/9
b)  2 4/9
c)  1 2/9
d)  1 4/9
e)  1 8/9

2). √2? = (82× 52) ÷ (200 √2)
a)  6
b)  4
c)  5
d)  8
e)  7 

3). (0.6)2 × 5 = ? – 348 ÷ 24
a)  16.3
b)  13.9
c)  15.2
d)  17.2
e)  14.3

4). 8√8 × 83 ÷ 85/2= 2?
a)  24
b)  12
c)  18
d)  21
e)  None of these

5). ? of 420 + 486 ÷ 3 = (8)3
a)  5/7
b)  6/7
c)  5/6
d)  4/5
e)  3/4

6). √? ÷ √0.16 = 130
a)  2916
b)  1936
c)  3136
d)  2304
e)  2704

7). ?% of (584.2 – 244.2) = (9)2+ 21
a)  40
b)  45
c)  30
d)  60
e)  50

8). √625 ÷ 5 + ? = 18.9
a)  10.9
b)  13.9
c)  12.9
d)  11.9
e)  14.9

9). 210 – 1380 ÷ 11.5 = ? × 45
a)  3
b)  4
c)  2
d)  1.5
e)  2.5

10). (1.6)2 ÷ (0.8)2= [(2.4)2 ÷ (0.4)2] – ?
a)  24
b)  32
c)  40
d)  36
e)  28

Explanation:

1). C) [4 2/3 + 3 4/9 + 6 5/9] ÷ ? = 12
? = [14/3 + 31/9 + 59/9] ÷ 12
= (42 +31+59) / (9×12) = 132 / (9×12) = 11/9
= 1 2/9

2). C) √2? = (82 × 52) ÷ (200 √2)
= (64 x 25)/ ((200 √2)) = (8 /√2 ) × (√2/√2) = 4√2 = √25
? = 5

3). A)(0.6)2 x 5 = ? — 348 ÷ 24
or, 0.36 x 5 = ? – 14.5
or, ? = 14.5 + 1.8 = 16.3

4). E)8√8 × 83 ÷ 85/2 = 2?
81+1/2+3-5/2 = 2?
8(2+1+6-5)/2= 2?
84/2 = 2?à82 = 2?
? = 6

5). C)? of 420 + 486 ÷ 3 = (8)3
or, ? x 420 + 162 = 512
or, ? x 420 = 512-162
or, ? = 350/420
? = 5/6

6). E)√? ÷ √0.16 = 130
Or, √? = 130 × 0.4 = 52
? = 52 × 52 = 2704

7). C) ?% of (584.2 – 244.2) = 92 + 21
(?x340)/100 =81+21=102
? = (102×100)/340 = 30

8). B)√625 ÷ 5 + ? =18.9
or, 25 ÷ 5 + ? = 18.9
or, ? = 18.9 – 5 = 13.9

9). C) 210 – 1380 ÷ 11.5 = ? x 45
or, 210 – 120 = ? × 45
or, ? x 45 = 90
? = 45/90 = 2

10). B) (1.6)2 ÷ (0.8)2 = [(2.4)2÷ (0.4)2] – ?
Or, (1.6×1.6) / (0.8×0.8) = [(2.4 x2.4) / (0.4×0.4)] – ?
 or, 4 = 36-?

or, ? = 36 – 4 = 32


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