# Practice Quantitative Aptitude Questions For SBI PO Prelims& Upcoming Exams 2017 (Quadratic Equation) Answers Updated

Practice Quantitative Aptitude Questions For SBI PO Prelims& Upcoming Exams 2017 (Quadratic Equation):
Dear Readers, Important Practice Aptitude Questions for Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the Bank Examination and other Competitive Examination can use this.

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Directions (Q. 1-5): In each question two equations numbered I and II are given. You have to solve both the equations and mark the answer
a)  If x> y
b)  If x โฅ y
c)  If x< y
d)  If x โค y
e)  If x = y or no relation can be established between x and y.
1). I. 4x2โ 15x + 14 = 0
II. 6y2 โ 10y + 4 = 0
2). I. 3x2+ 10x + 3 = 0
II. 2y2 + 15y + 27 = 0
3). I. 7x2+ 12x + 5 = 0
II. 3y2+ 7y + 2 = 0
4). I. 16x2โ 14x + 3 = 0
II. 6y2โ 19y + 15 = 0
5). I. x2+ 11x + 18 = 0

II. y2 – โ81 = 0

Directions (Q. 6-10): In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option. Give answer
a)  If x> y
b)  If x โฅ y
c)  If x< y
d)  If x โค y
e)  If x = y or relationship between x and y canโt be established
6). I.32491/2x – โ625 = 4079
II.57761/2– โ324 = 4162
7). I.3x โ 2y = 37
II.5x โ 3y = 59
8). I.9x2+ 4x โ 28 = 0
II.2y2 โ 17y + 36 = 0
9). I.โ169 x + 561 = 678
II.โ324 y + 678 = 822
10). I.7x2 + 19x โ 36 = 0
II.2y2 โ 21y โ 98 = 0

Solution with Explanation:

1).I. 4x2โ 15x + 14 = 0
x = (-8/7), (-7/4)
x = 2, 1.75
II. 6y2 โ 10y + 4 = 0
y = (-6/6), (-4/6)
y = 1, 2/3
Hence, x> y

2).I. 3x2+ 10x + 3 = 0
x = (9/3), (1/3)
x = -3, -1/3
II. 2y2 + 15y + 27 = 0
y = (9/2), (6/2)
y = -4.5, -3
Hence, x โฅ y

3).I. 7x2+ 12x + 5 = 0
x = (7/7), (5/7)
x = -1, -5/7
II. 3y2+ 7y + 2 = 0
y = (6/3), (1/3)
y = -2, -1/3
Thus relationship canโt be established.

4).I. 16x2โ 14x + 3 = 0
x = (-8/16), (-6/16)
x = 1/2, 3/8
II. 6y2โ 19y + 15 = 0
y = (-10/9), (-9/6)
y = 5/3, 3/2
Hence x< y.

5).I. x2+ 11x + 18 = 0
x = (9/1), (2/1)
x = -9, -2
II. y2 – โ81 = 0
y2 = โ81
y2 = 9
y = ยฑ3
Hence, no relation can be established.

6). I. 32491/2 x – โ625 = 4079
or, 57x = 4079 + 25 = 4104
x = 4104/57 = 72
II. 57761/2 – โ324 = 4162
Or, 76y = 4162 +18 = 4180
y = 4180/76= 55
Hence x> y

7). 3x โ 2y = 37    โฆ(i)
5x โ 3y = 59          โฆ(ii)
Equation (i) ร 3 โ (ii) ร 2
(9x -6y = 111) + (10x โ 6y = 118)
x = 7
Putting the value of x in eqn (i) we get
21 โ 2y = 37
-2y = 36
y = (-16/2) = -8
Hence x> y

8).I. 9x2 + 4x โ 28 = 0
x = (18/9), (-14/9)
x = -2, 14/9
II. 2y2 โ 17y + 36 = 0
Y = (-9/2), (-8/2)
Y = 4.5, 4
Hence x< y

9).I. โ169 x + 561 = 678
13x = 678 โ 561 = 117
x = 117/13 = 9
II. โ324 y + 678 = 822
18y = 822 โ 678 = 144
x = 144/8
Hence x> y

10).I. 7x2 + 19x โ 36 = 0
x = (28/7), (-9/7)
x = -4, 9/7
II. 2y2 โ 21y โ 98 = 0
y = (-28/2), (7/2)
y = 14, -3.5
Hence relationship canโt be established.

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