Practice Quantitative Aptitude Questions For SBI PO Prelims& Upcoming Exams 2017 (Simplification) Answers Updated

IPPB Scale I& IBPS SO 2017 - Practice Quantitative Aptitude Questions (Number Series& Quadratic Equation)  Answers Updated
Practice Quantitative Aptitude Questions For SBI PO Prelims& Upcoming Exams 2017 (Simplification):
Dear Readers, Important Practice Aptitude Questions for Upcoming Exams was given here with Solutions. Aspirants those who are preparing for the Bank Examination and other Competitive Examination can use this.


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Directions (Q. 1-10): What should come in place of question mark in the following questions?

1). √(15 + 24 x 0.5) / √(10.2 ÷ ?) = 3
a)  2.4
b)  5.7
c)  1.7
d)  3.4
e)  6.8

2). √[(2) + (1/144)] ÷ √[(1) + (49/576)] × (27/34) = ? ÷ 25
a)  3
b)  27
c)  6
d)  9
e)  15

3). 65 x 9 ÷ ? – 101 = √256
a)  4.5
b)  4
c)  18
d)  3
e)  5

4). 1 2/3  of 1440 + 40% of 3550 – ? = 612
a)  99
b)  129
c)  81
d)  121
e)  119

5). ? ÷ [25% of 289 – 32 3/4 ] = 0.2
a)  6.5
b)  7.9
c)  6.7
d)  3.8
e)  8.5

6). 84 + 142= ? x 105 ÷ 8.25
a)  23
b)  21
c)  22
d)  24
e)  26

7). (12.5 x 14) ÷ 20 + 41.25 = ?3 ÷ 2.5
a)  6
b)  5
c)  3
d)  4
e)  7

8). 0.36 x 0.36 + 0.28 x 0.36 + 0.142= ?
a)  0.144
b)  0.25
c)  0.016
d)  0.025
e)  0.16

9). [(15.5 × 30) ÷15 – 1250 ÷ 50] = ? × 2
a)  3
b)  2
c)  5
d)  1
e)  None of these

10). 1/4 of 3832 + 150% of x = 2500
a)  1028
b)  1020
c)  1026
d)  1120
e)  None of these

Explanation with Answers

1). D)√(15+24×0.5) / √(10.2 ÷ ?) = 3
or, √27/3 = √(10.2 ÷ ?)
or,√3 = √(10.2 ÷ ?)
Squaring both sides, we get
3 = 10.2 ÷ ?
? = 10.2 / 3= 3.4

2). B)? ÷ 25
= √[(2) + (1/144)] ÷ √[(1) + (49/576)] × (27/34)
= √(289/144) × √(576/625) = (17/12) × (24/25) × (27/34) = 27/25
? = (27/25) × 25 = 27

3). E)  65 x 9 ÷ ? = 101 + √256 = 101 + 16 = 117
or, ? = (65×9) /117 = 5

4). A)5/3 of 1440 + 40% of 3550 – ? = 612
or, 5/3 x 1440 + 2/5 x 3550 – 612 = ?
or, 5 x 480 + 2 x 710 – 3721 = ?
or, ? = 2400 + 1420 – 3721 = 99

5). B)? ÷ (25% of 289 – 32 3/4 ) = 0.2 
or, ? ÷ [(1/4) × 289 – (131/4)] = 0.2
or, ? ÷ (289-131)/4 = 0.2
 or, ? x (4/158)= 0.2
? = (0.2 x158)/4 = 0.2 x 39.5 = 7.9

6). C)84 + 142 = ? x 105 ÷ 8.25
or, 84 + 196 = (? x 105) / 8.25
? = (280×8.25)/105 = [(280×8) + 280x(1/4)] / 105
= (2240+70) /105 = 2310/105 = 22

7). B)(12.5 x 14) ÷ 20 + 41.25 = (?)3÷ 2.5
or, 8.75+41.25 = ?3 / 2.5
or, 50 × 2.5 = ?3
? = 3√(5×5×5) = 5

8). B)  0.36 × 0.36 + 0.28 x 0.36 + 0.142
(a + b)2= a2+ 2ab + b2
So, (0.36 + 0.14)2 =- (0.5)2 = 0.25

9). A)


10). A)

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