# Practice Reasoning Questions (with explanation) for Upcoming Bank PO and Clerk Exams 2015 Set-17

Practice Reasoning Questions (with explanation) for Upcoming Bank PO and Clerk Exams 2015 Set-17:
The List of Practice Reasoning Questions for Upcoming Bank PO/Clerk Exams was given below with explanation. Candidates those who are preparing for the examinations can use these questions.

Directions (Q.1-6): In each question below are given three statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts and then decide which of the given conclusions logically follows from the given statements, disregarding commonly known facts. Given answer
1)   If only conclusion I follows
2)   If only conclusion II follows
3)   If either conclusion I or II follows
4)   If neither conclusion I nor II follows
5)   If both conclusions I and II follow.
Questions (01 and 02):
Statements:Some papers are covers.
All pages are covers.
All pages are books.

1).Conclusions:  I.All books being papers is a possibility
II.At least some covers are books.

2).Conclusions: I.At least some papers are not pages
II.At least some papers are pages

Questions (03 and 04):
Statements:All numbers are digits
No digit is a letter
All letters are consonants

3).Conclusions: I.Some consonants are not digits
II.Some consonants are letters.

4).Conclusions: I.At least some letters is digits
II.All numbers are definitely not letters

Questions (05 and 06):
Statements:Some boxes are bottles.
No bottle is a bowl
All bowls are glasses.

5).Conclusions: I.At least some boxes are not bowls
II.No bowl is a bottle

6).Conclusions: I.At least some bottles are glasses
II.Some glasses are not bowls.

Directions (Q.7-11): Study the following information carefully and answer the questions given below:
There are seven family members P, Q, R, S, T, U and V sitting in a row facing north. There are three couples in the family. P is on the immediate right of his mother-in-law. R has two children. U sits second to the left of his father T, who is third to the right of S, who is second to the right of Q. The one who is wife of R does not sit on the extreme ends of the row. S is daughter of Q, who is wife of R. The one who is wife of T sits an extreme end of the row. T is brother-in-law of S. U is the nephew of P.

7).Which of the following pairs sits on the extreme ends of the row?
a)   S, T
b)   V, T
c)   R, Q
d)   P, V
e)   None of these

8).Who among the following is third to the left of R?
a)   T
b)   V
c)   P
d)   Q
e)   None of these

9).How is P related to S?
a)   Husband
b)   Brother
c)   Father
d)   Wife
e)   None of these

10).How is S related to T?
a)   Sister
b)   Brother
c)   Wife
d)   Sister-in-law
e)   None of these

11).Who among the following is third to the right of Q?
a)   V’s daughter
b)   R’s grandson
c)   Son of S
d)   Q’s granddaughter
e)   None of these

1). e)   2). c)   3). e)   4). b)   5). e)   6). d)   7). b)   8). c)   9). a)   10). d)  11).b)
Check below the detailed explanation for the above Reasoning Questions:

1). There is no negative statement. Thus the possibility in I exists. Hence Conclusion I follows.
Again, some covers are pages + All pages are books (A) = I + A = I = Some covers are books. Hence conclusion II follows.

2). Some papers are covers (I)à conversionà Some covers are papers (I). Now, All pages are covers (A) + Some covers are papers (I) = A + I = No Conclusion.
But conclusion I and II make a complementary pair (I-O). Thus, either conclusion I or II follows.

3). No digit is a letter (E) + All letters are consonants (A) = E + A = O* = Some consonants are not digits. Hence conclusion I follows.
Again, All letters are consonants (A)à conversionà Some consonants are letters (I). Hence conclusion II follows.

4). No digit is a letter (E)à conversionà No letter is a digit (E). Hence conclusion I does not follow.
All number are digits (A) + No digit is a letter (E) = A + E = E = No number is a letter. Thus, all number are not letters. Hence conclusion II follows.

5). Some boxes are bottles + No bottle is a bowl = I + E = O = Some boxes are not bowls. Hence I follows. No bottle is a bowl (E)àconversionàNo bowl is a bottle (E). Hence II follows.