# SBI PO Prelims Quantitative Aptitude Questions 2019 (Day-43)

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Directions (Q. 1 – 5): What value should come in place of (?) in the following questions?

1) (11/110) of 54330 + 6.5 ÷ 13 × 280 – 31 × 5 = ?

a) 5418

b) 5952

c) 4276

d) 4534

e) None of these

2) 1680 ÷ ? + 173 × 2 = 642 – 256 + 25 % of 400

a) 18

b) 23

c) 15

d) 12

e) None of these

3) (242 – 112) × 8 ÷ 26 + ? % of 250 = 196

a) 28

b) 22.4

c) 19.6

d) 33

e) None of these

4) ? % of (√144) × 25 + 390 = 453

a) 28

b) 32

c) 21

d) 17

e) None of these

5) (8/11) of [956 – 373] + 286 = ? – 1125

a) 1835

b) 2156

c) 2278

d) 1543

e) None of these

Directions (6 – 10): Study the following information carefully and answer the questions given below.

Following two pie chart show the information about total number of employees and total number of male employees in 5 different companies respectively.  6) If the ratio of females who are under graduate and post graduate in company B and C is 7: 8 and 13: 8 respectively, total number of females who are post graduate in those company is approximately what percentage of number of males in those company?

a) 37%

b) 23%

c) 25%

d) 29%

e) 27%

7) Find the ratio between the average number of female in company A, D and E together to the number of employees in E.

a) 1: 2

b) 2: 3

c) 3: 7

d) 2: 9

e) 1: 9

8) Find the impact on total number of employees in company C and D, if the number of males in company C and D increased by 50%.

a) 28% increase

b) 32% increase

c) 35% increase

d) 56% increase

e) 15% increase

9) Find the ratio between the sum of the 15% of male employees in company A and 18% of female employees in company B and the sum of total employees in C and the number of male employees in D.

a) 26: 5

b) 2: 15

c) 3: 13

d) 3: 26

e) 15: 7

10) What is the difference between the central angle made by the employees of A, C and E and the number of females in company C, D and E, if the total number of females are put in a pie chart?

a) 46.8°

b) 36.5°

c) 56.2°

d) 24.9°

e) 85.6°

(11/110)*54330 + (6.5/13)* 280 – 31*5 = x

5433 + 140 – 155 = x

X = 5418

(1680/x) + 173*2 = 642 – 256 + (25/100)*400

(1680/x) = 642 – 256 + 100 – 346

(1680/x) = 140

X = 12

[(24 + 11) (24 – 11)] × 8 ÷ 26 + (x/100)*250 = 196

(35*13*8)/26 + (5x/2) = 196

140 + (5x/2) = 196

(5x/2) = 196 – 140

5x/2 = 56

X = (56*2)/5 = 22.4

(X/100)*12*25 + 390 = 453

3x = 453 – 390

3x = 63

X = 63/3 = 21

(8/11)*583 + 286 = x – 1125

424 + 286 + 1125 = x

X = 1835

Directions (6 – 10):

In B,

Total number of employees = 23/100 * 1800 = 414

Number of males = 22/100 * 1200 = 264

Number of females = 414 – 264 = 150

Number of females who are post graduate = 150/15 * 8 = 80

In C,

Total number of employees = 19/100 * 1800 = 342

Number of males = 18/100 * 1200 = 216

Number of females = 342 – 216 = 126

Number of females who are post graduate = 126/21 * 8 = 48

Required % = [(80 + 48)/(264 + 216)] * 100 = 128/480 * 100 = 26.667% = 27%

In A,

Total number of employees = 14/100 * 1800 = 252

Number of males = 20/100 * 1200 = 240

Number of females = 252 – 240 = 12

In D,

Total number of employees = 17/100 * 1800 = 306

Number of males = 17/100 * 1200 = 204

Number of females = 306 – 204 = 102

In E,

Total number of employees = 27/100 * 1800 = 486

Number of males = 23/100 * 1200 = 276

Number of females = 486 – 276 = 210

Required ratio = [(12 + 102 + 210)/3]: 486

= 2: 9

In D,

Total number of employees = 17/100 * 1800 = 306

Number of males = 17/100 * 1200 = 204

50% of males = 102

In C,

Total number of employees = 19/100 * 1800 = 342

Number of males = 18/100 * 1200 = 216

50% of males = 108

Total increase = 210

% of increase = (210/(342 + 306)) * 100 = 32.40%  = 32%

In A,

Number of males = 20/100 * 1200 = 240

15% of males =240 * 15/100 = 36

In B,

Total number of employees = 23/100 * 1800 = 414

Number of males = 22/100 * 1200 = 264

Number of females = 414 – 264 = 150

18% of females = 150 * 18/100 = 27

In D,

Number of males = 17/100 * 1200 = 204

In C,

Total number of employees = 19/100 * 1800 = 342

Required ratio = (36 + 27): (342 + 204) = 3: 26

In A,

Total number of employees = 14/100 * 1800 = 252

In C,

Total number of employees = 19/100 * 1800 = 342

Number of males = 18/100 * 1200 = 216

Number of females = 342 – 216 = 126

In D,

Total number of employees = 17/100 * 1800 = 306

Number of males = 17/100 * 1200 = 204

Number of females = 306 – 204 = 102

In E,

Total number of employees = 27/100 * 1800 = 486

Number of males = 23/100 * 1200 = 276

Number of females = 486 – 276 = 210

Total female employees = 1800 – 1200 = 600 = 360°

Total female employees in C, D and E = 126 + 102 + 210 = 438

Angle made by female employees in C, D and E = (360 * 438)/600

= 262.8°

Angle made by employees in A, C and E = [(14 + 19 + 27)/100] * 360

= 216°

Required difference = 262.8° – 216°

= 46.8°

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