# Race IBPS Clerk 2015- Practice Aptitude Questions (Inequality) with Solutions Set-38

Dear Readers, Important Practice Aptitude Questions for Upcoming IBPS Clerk V Exam was given here with solutions. Aspirants those who are preparing for the examination can use this.
Directions ( 1-5 ): In the given questions, two equations numbered โ  and โก are given. Solve both the equations and mark the appropriate answer.
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1).โ . 6x+5y=25ย ย ย ย ย ย ย ย ย ย โก.8x-7y=6
2).โ .12xยฒ+17x-40=0ย ย โก.12yยฒ-5y-25=0
3).โ .5xยฒ+4โ10x+8=0ย โก.yยฒ-22y+121=0
4).โ .xยฒ+x-30=0ย ย ย ย ย ย ย ย ย ย โก.yยฒ-12y+35=0
5).โ .xยฒ-20x+99=0ย ย ย ย ย ย โก.2xยฒ-23y+56=0

Directions (Q.6-10): In the given questions two equations numbered โ  and โก are given. You have to solve both the equations and mark the appropriate answer.
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6).โ . 3xยฒ+6x-9=0ย ย ย ย ย ย ย ย ย โก.2yยฒ-7y+3=0
7).โ .3x2+14x +15=0ย ย ย โก.4y2+16y+15=0
8).โ .2x2+17x +36=0ย ย ย ย โก.2y2+11y+14=0
9).โ .4x2-7x-2=0ย ย ย ย ย ย ย ย ย ย ย โก.6y2+11x+4=0
10).โ .5x2+16x +12=0ย ย ย โก.3yยฒ+32y+45=0
1). a) 2). e) 3). c) 4). d) 5).a ) 6).c ) 7). c) 8). b) 9).a ) 10). c)
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Solutions:
1).โ . 6x+5y=25 โฆ(โฐ)
โก. 8x-7y=6 โฆ(โฑ)
Solving (โฐ) and (โฑ), we get
ย ย ย ย ย ย ย ย ย  6x+5y=25 โฆ(โฐ)ร7
ย ย ย ย ย ย ย ย ย 8x-7y =6ย  โฆ(โฑ)ร5
ย ย ย ย ย ย ย ย ย 42x+35y=175
ย ย ย ย ย ย 40x-35y=30ย ย ย ย
82x=205
โด x=205/80=2.5
โด y= (25-15)/5=2
Hence x>y
2).โ . 12xยฒ+32x-15x-40
Or, (3x+8) (4x-5) =0
Or, x=-8/3, 5/4
โก. 12yยฒ+15y-20y-25=0
Or, (3y-5) (4y+5) =0
Or, y=5/3, -5/4
Relationship between x and y canโt be determined.
3).โ . 5xยฒ + 2 ร โ5xย  ร โ8 + 8=0
Or, (โ5x+โ8)ยฒ=0
Or, x=-โ8/โ5
โก. yยฒ-22y+121=0
Or, (y-11)ยฒ =0
Or, y=11
Hence x
4).โ . xยฒ+6x-5x-30=0
Or, (x-5) (x+6) =0
Or, x=5, -6
โก. yยฒ -7y-5y+35=0
Or, (y-5) (y-7) =0
Or, y=5, 7
Hence x<= y
5).โ . xยฒ-11x-9x+99=0
Or, (x-9) (x-11) =0
โด x=9, 11
โก. 2yยฒ -16y-7y+56=0
Or, (y-8) (2y-7) =0
โด y=8, 7/2
Hence x>y
6).โ . 3xยฒ+6x-9=0
Or, 3xยฒ+9x-3x-9=0
Or, 3x(x+3) -3(x+3) =0
Or, (3x-3) (x+3) =0
โด x=+1, -3
โก. 2yยฒ-7y+3=0
Or, 2yยฒ-6y-y+3=0
Or, 2y(y-3) -1(y-3) =0
Or, (2y-1) (y-3) =0
โดy=1/2, 3
7). โ . 3xยฒ+14x+15=0
Or, 3xยฒ+9x+5x+15=0
Or, 3x(x+3) +5(x+3) =0
Or, (3x+5) (x+3) =0
โด x=-5/3, -3
โก. 4yยฒ+16y+15=0
Or, 4yยฒ+10y+6y+15=0
Or, 2y (2y+5) +3y (2y+15) =0
Or, (2y+3) (2y+5) =0
โดy=-3/2, -5/2
Hence relation canโt be established
8). โ . 2xยฒ+17x+36=0
Or, 2xยฒ+9x+8x+36=0
Or, 2x(x+4) +9(x+4) =0
Or, (2x+9) (x+4) =0
โด x=-9/2=-4.5, -4
โก. 2yยฒ+11y+14=0
Or, 2yยฒ+7y+4y+14=0
Or, 2y(y+2) +7(y+2) =0
Or, (2y+7) (y+2) =0
โดy=-7/2, -2
Hence x
9). โ . 4xยฒ-7x-2=0
Or, 4xยฒ-8x+x-2=0
Or, 4x(x-2) +1(x-2) =0
Or, (4x+1) (x-2) =0
โด x=-1/4, 2
โก.6yยฒ+11y+4=0
Or, 6yยฒ+8y+3y+4=0
Or, 3y (2y+1) +4(2y+1) =0
Or, (3y+4) (2y+1) =0
โดy=-4/3, -1/2
Hence x>y
10).โ . 5xยฒ+16x+12=0
Or, 5xยฒ+10x+6x+12=0
Or, 5x(x+2) +6(x+2) =0
Or, (5x+6) (x+2) =0
โด x=-6/5, -2
โก. 3yยฒ+32y+45=0
Or, 3yยฒ+27y+5y+45=0
Or, 3y(y+9) +5(y+9) =0
โดy=-9, -5/3
Hence no relation can be established.