Dear Aspirants, Quantitative Aptitude plays a crucial role in Banking and all other competitive exams. To enrich your preparation, here we have provided New Pattern Aptitude Questions for IBPS Clerk Mains. Candidates those who are going to appear in IBPS Clerk Mains can practice these questions daily and make your preparation effective.
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[WpProQuiz 4579]
Directions (1 – 5): Study the following information carefully and answer the given questions:
The number of students who appears the exam of two different institutes (XYZ and ABCD) over the years,
2014: The number of students who appear in the exam from XYZ institute is 300 and the 60% of the students pass the examination. 30% of the students passed in the exam from ABCD institute.
2015: The number of students who appear in the exam from XYZ institute is 400 and 45% of the students pass the exam. 45% of the students pass the exam from ABCD institute.
2016: The number of students who appear in the exam from ABCD institute is 280 and 60% of the students pass the exam. 50% of the students pass the exam from XYZ institute.
2017: The number of students who appear the exam from XYZ institute and ABCD institute is 380 and 400 respectively.
1) What is the average number of passed students over the years from XYZ institute" layout="responsive" width="560" height="314">
Answers:
Directions(1-5):
1) Answer: a)
From Statement I,
Number of students passed from XYZ in 2017=40/100*380=152
Number of students passed from XYZ in 2016=150
Number of students passed from XYZ in 2014=300*60/100=180
Number of students passed from XYZ in 2015=400*45/100=180
Average= (152+150+180+180)/4 = 662/4
So, Statement I alone is sufficient to the answer the question.
From Statement II,
If the ratio of the number of students passed from XYZ institute in 2017 and 2016 is 4:5.
So, Statement II alone is not sufficient to the answer the question.
2) Answer: a)
From quantity I,
Number of students appeared from ABCD in 2014=400*80/100=320
Number of students passed from ABCD in 2014=320*30/100=96
Number of students passed from ABCD 2016=280*60/100=168
Average= (96+168)/2=132
From quantity II,
Number of students failed from XYZ 2015=400*55/100=220
Number of students failed from ABCD 2016=280*40/100=112
Difference=220-112=108
Quantity I > Quantity II
3) Answer: a)
Number of students appeared from XYZ institute in 2018=400*80/100=320
Number of students passed from XYZ in 2018=320*70/100=224
Number of students passed from ABCD in 2016=280*60/100=168
Required percentage = [(224 – 168)/168]*100 = 33.33%
4) Answer: a)
ABCD in 2014=400*120/100=480
ABCD in 2015=360
Number of students failed from ABCD in 2014=480*70/100=336
Number of students failed from ABCD in 2015=360*55/100=198
Number of students failed from ABCD in 2016=280*40/100=112
Number of students failed from ABCD in 2017=400*30/100=120
Required total= (336+198+112+120) = 766
5) Answer: a)
Number of students passed the exam from XYZ institute in 2016=180*100/50=360
Number of students passed the exam from ABCD institute in 2017=400
Required percentage = 360*(100/400) = 90%
Directions (6-10):
6) Answer: e)
I – series pattern:
II – series pattern:
16 * 2 = 32
32 * 3 = 96
96* 4 = 384
III – series pattern:
18.5 * 1 – 1 = 17.5
17.5 * 2 – 2 = 33
33 * 3 – 3 = 96
96*4 – 4 = 380
All the three given series exactly replaces the same number in the question mark.
7) Answer: c)
I – series pattern:
18 * 1.5 – 2 = 25
25 * 2 + 2 = 52
52 * 2.5 – 2 = 128
128 * 3 + 2 = 386
II – series pattern:
III – series pattern:
In all the given series, only I and II exactly replaces the same number in the question mark.
8) Answer: b)
I – series pattern:
11178/3 = 3726
3726/3 = 1242
1242/3 = 414
414/3 = 138
138/3 = 46
II – series pattern:
15.5 * 2 + 2 = 33
33 * 2 + 2 = 68
68 * 2 + 2 = 138
138 * 2 + 2 = 278
III – series pattern:
39 + (1*2) = 41
41 + (2*3) = 47
47 + (3*4) = 59
59 + (4*5) = 79
79 + (5*6) = 109
109 + (6*7) = 151
(Or)
In all the given series, no one exactly replaces the same number in the question mark.
9) Answer: a)
I – series pattern:
1319 + (5*2) = 1329
1329 + (5*3) = 1344
1344 + (5*5) = 1369
1369 + (5*7) = 1404
1404 + (5*11) = 1459
II – series pattern:
1194 + 121 = 1315
1315 – 144 = 1171
1171 + 169 = 1340
1340 – 196 = 1144
1144 + 225 = 1369
III – series pattern:
In all the given series, only I and II exactly replaces the same number in the question mark.
10) Answer: d)
I – series pattern:
13 = 1
23 = 8
33 = 27
43 = 64
53 = 125
63 = 216
II – series pattern:
(30 + 1)* 1 = 31
(31+1)*2 = 64
(64+1)*3 = 195
(195+1)*4 = 784
III – series pattern:
32 * 2 = 64
64 * 4 = 256
256 * 6 = 1536
1536 * 8 = 12288
All the three given series exactly replaces the same number in the question mark.
This post was last modified on December 28, 2018 5:23 pm