Dear Aspirants, Quantitative Aptitude plays a crucial role in Banking and all other competitive exams. To enrich your preparation, here we have provided New Pattern Aptitude Questions for IBPS Clerk Mains. Candidates those who are going to appear in IBPS Clerk Mains can practice these questions daily and make your preparation effective.
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[WpProQuiz 4663]
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Directions (1 – 5): Study the following information carefully and answer the given questions:
The given bar graph shows the number (in thousands) of products manufactured and line graph shows percentage of unsold products by a company over the years 2013 – 2017.
1) What is the average number of product sold in over the years 2013 to 2017" layout="responsive" width="560" height="314">
Answers :
Direction (1-5) :
1) Answer: a)
In 2013 = (80/100)*30000 = 24000
In 2014 = (65/100)*35000 = 22750
In 2015 = (82/100)*42000 = 34440
In 2016 = (78/100)*28000 = 21840
In 2017 = (85/100)*48000 = 40800
Average = (24000 + 22750 + 34440 + 21840 + 40800)/5 = 28766
2) Answer: c)
From Statement I,
Defective product in 2017 = (80/100) * (18/100) * 42000 = 6048
Non defective product in 2017 = 48000 – 6048 = 41952
Required ratio = 6048 : 41952 = 63 : 437
From Statement II,
Non defective product in 2017 = 30000/2 = 15000
Defective product in 2017 = 48000 – 15000 = 33000
Required ratio =15000 : 33000 = 5 : 11
Either I or II is sufficient to answer the question.
3) Answer: c)
From quantity I,
Product which is going to manufactured in 2018 = (120/100)*28000 = 33600
Unsold product in 2018 = (3/7)*33600 = 14400
From quantity II,
The non defective product of the company in the year 2014
= > (80/100)*the number of product sold in 2013
= > (80/100)*30000*(80/100) = 19200
Defective product in 2014 = 35000 – 19200 = 15800
Number unsold product in 2018 = 15800
4) Answer: b)
Difference of sold and unsold product in 2014 = (30/100) * 35000 = 10500
Difference of sold and unsold product in 2015 = (64/100) * 42000 = 26880
Sum = 10500 + 26880 = 37380
Unsold product in 2017 = (15/100) * 48000 = 7200
Unsold product in 2016 = (22/100) * 28000 = 6160
Unsold product in 2013 = (20/100) * 30000 = 6000
Total = 7200 + 6160 + 6000 = 19360
Required percentage = [(37380 – 19360)/19360] * 100 = 93%
5) Answer: c)
Average of products manufactured = (35000 + 28000 + 48000)/3 = 37000
Direction (6-10) :
6) Answer: b)
From quantity I,
(P*20*18/100) – (P*12*18/100) = 540
P*18*8 = 54000
P = 54000 / (18*8) = Rs. 375
From quantity II,
Difference of SI and CI = 165 – 150 = 15
Diff = Sum*(r/100)2
15 = Sum*(5/100)2
(15*100*100)/25 = Sum
Sum = 6000
From Quantity III,
Profit ratio of A and B = (4000*6 + 3200*6) : (2000*12) = 9 : 5
B’s share = (5/14) * 2800 = Rs. 1000
Quantity I < Quantity II > Quantity III
7) Answer: b)
From quantity I,
Ratio = 7x : 5x : 3x
10*7x + 50*5x + 3x*100 = 6200
620x = 6200
X=10
Rs.50 notes = 10*5*50 = Rs. 2500
From quantity II,
Profit = Loss
SP1 – CP = CP – SP2
2540 + 2326 = 2CP
CP = (2540 + 2326)/2 = Rs. 2433
From quantity III,
4*(22/7)*r*r = 61600
r =70 cm
Radius of the circle = (½)*70 = 35 cm
Area of the circle = (22/7)*35*35 = 3850 cm2
Quantity I > Quantity II < Quantity III
8) Answer: c)
From quantity I
4x*(120/100 + 5x*110/100 =103000
4.8x + 5.5x = 103000
10.3x=103000
X = 10000
Male population = 4*10000*120/100 = 48000
From quantity II,
Selling price of Sofa = 8100*(115/100) = Rs. 9315
Marked price*(90/100) = 9315
Marked price of Sofa = 9315*(100/90) = Rs. 10350
From quantity III,
(P*5*(R+5)/100) – (P*5*R/100) =12000
5PR + 25P – 5PR = 120000
25P = 1200000
P = 48000
SI = 48000*10*10/100 = 48000
Quantity I > Quantity II < Quantity III
9) Answer: c)
From quantity I,
Present age of Ram=7x
Present age of Suresh=8x
Present age of Suresh’s sister=y
Difference = (8x+15) – (7x+15) = 4
X=4 years
Suresh age=8*4=32
After 10 years the age will be=32+10 = 42 years
Suresh’s sister age after 10 years = (2/3)*42 = 28 years
Suresh’s sister age after 7 years = 28 – 3 = 25 years
From quantity II,
X2 – 51y + 650 = 0
(x – 26) (x – 25) = 0
X = 26, 25
From quantity III,
T = D/S
According to the question,
15 = (175 + 100) / [(90 – x)*(5/18)]
15* [(90 – x)*(5/18)] = 275
[(90 – x)*(5/18)] = 275/15
(90 – x) = (275/15)*(18/5)
90 – x = 66
X = 24 km/hr
The speed of the second train = 24 km/hr
Quantity I ≤ Quantity II > Quantity III
10) Answer: e)
From quantity I,
d/(20 – 12) – d/(20 + 12) = 9
d/8 – d/32 = 9
3d/32 = 9
d = 32*3 = 96 km
From quantity II,
200 = (x – 60)*5/18*20
36= (x – 60)
X= 96 kmph
From quantity III,
Let the distance travelled on foot be x km.
Then distance travelled on bicycle= (91 – x) km
Now, (x/6) + ((91 – x)/12) = 9
(2x + 91 – x)/12 = 9
(X + 91)/12 = 9
X + 91 = 108
X = 17 km
Quantity I = Quantity II > Quantity III
Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Current Affairs Quiz (Hindi) | 9.30 AM |
| IBPS SO/NIACL AO Prelims – Reasoning | 10.00 AM |
| IBPS SO/NIACL AO Prelims – Reasoning (Hindi) | 10.30 AM |
| IBPS SO/NIACL AO Prelims – Quantitative Aptitude | 11.00 AM |
| IBPS SO/NIACL AO Prelims – Quantitative Aptitude (Hindi) | 11.30 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| IBPS SO/NIACL AO Prelims – English Language | 1.00 PM |
| SSC Practice Questions (Reasoning/Quantitative aptitude) | 2.00 PM |
| IBPS Clerk – GK Questions | 3.00 PM |
| SSC Practice Questions (English/General Knowledge) | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| SBI PO/IBPS Clerk Mains – Reasoning | 6.00 PM |
| SBI PO/IBPS Clerk Mains – Quantitative Aptitude | 7.00 PM |
| SBI PO/IBPS Clerk Mains – English Language | 8.00 PM |
This post was last modified on January 23, 2019 4:59 pm