Hard Level Reasoning Questions Asked in IBPS PO Mains 2017 (Day-16)

By admin - Dec 27 2017

Reasoning Questions asked in IBPS PO Mains 2017 was quite harder compared to other exams, aspirants those who are preparing for Upcoming Mains Examination have to Practice More on Reasoning Ability Questions to tackle the exam in a better way. We all knew that IBPS have increased the questions standard in the recent time examination; we can’t say that Questions were harder; it seems to be hard because you are not practicing those level questions. If you Practising Hard Level Questions then you can speed up yourself and you can improve your scores.
Dear Readers, Reasoning Questions Section in IBPS PO Mains 2017 examination remains quite mystery for the aspirants. And there is more chance to expect same model questions in the Upcoming Mains Exams. To guide you all about the Reasoning Questions here we have giving the Hard Reasoning Questions Asked in IBPS PO Mains 2017.

Hard Level Reasoning Questions Asked in IBPS PO Mains

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Direction (1-5) Study the given information and answer the following questions

 School X has to play two cricket matches with School Y in different stadiums I and II respectively. Number of players in the team must be only 5. School X has to choose from Nine players. The information about Nine players is given below representing their role in the team and the money to be paid for playing one match.

Player A – Batsman – Rs. 1000

Player B – Batsman – Rs. 2000

Player  C – Batsman – Rs. 1500

Player D- Batsman or Wicket keeper – Rs. 2000

Player E – Specialist Wicket Keeper – Rs.1500

Player F – Bowler (Spin) – Rs. 1000

Player G – Bowler (Fast) – Rs. 2000

Player H- Bowler (Spin) – Rs.1500

Player I – Bowler (Fast) – Rs.1500

Note: Player D can be considered as either as Batsman or Wicket Keeper but not both

Conditions:

  1. A and B cannot be selected together
  2. Wicket Keeper is must in the team
  3. F and H cannot be selected together
  4. Among D, F, G, H maximum two persons can be selected
  5. If I is selected, B should be selected
  6. Among C, D, E maximum two persons can be selected
  7. There must be at least two batsman and two bowlers in the team

Q1. If it is known that stadium I was favorable to spin, School X decided to select ‘H’ and ‘D’ as Batsman in  the team. Then what is the total amount spent by School X on selected players for forming the team?

  1. Rs. 7500
  2. Rs. 8000
  3. Rs. 8500
  4. Rs.9000
  5. Cannot be determined

Q2. If it is known that stadium II is favorable to fast bowling, School X decide to compose the team with two fast bowlers. Then what is the least amount that can be spent by School X on selected players for forming the team satisfying all the above conditions?

  1. Rs.7500
  2. Rs. 8000
  3. Rs.8500
  4. Rs.9000
  5. Rs. 9500

Q3. School X decided to compose the team with one fast bowler and one spinner to play in stadium I. If School X is having a budget of only Rs.7000 to form a team for that match then who among the following is not a member of that team satisfying all the above conditions?

  1. A
  2. B
  3. F
  4. E
  5. G

Q4. School X decided to compose the team with one fast bowler and one spinner to play in stadium I. Then who among the following will be definitely member of that team satisfying all the above conditions?

  1. A
  2. B
  3. C
  4. E
  5. Cannot be determined

Q5.If the School X decides to include D as Batsman in the team for the match to be played in Stadium II. Then who among the following will be definitely a member of that formed team satisfying all the conditions?

  1. A
  2. C
  3. D
  4. E
  5. Cannot be determined

Direction (6-10) Study the given information and answer the following questions

Seven  persons – A, B, C, D, E, F, and G ate different number of sweets. Person who ate second highest ate 23 sweets. F ate even number of sweets. Difference between number of sweets eaten by A and D is 5. A ate even number of sweets. E ate more than A but less than B. E didn’t eat highest number of sweets. Difference between number of sweets eaten by E and F is 5. G ate more than F. C ate even number of sweets but not the lowest. Person who ate lowest ate 15 sweets. G ate more sweets than C but less than A.

Q6. How many sweets does E eat?

  1. 23
  2. 19
  3. 18
  4. 16
  5. Cannot be determined

Q7. If all together they eat 135 sweets then how many sweets does B eat?

  1. 23
  2. 24
  3. 25
  4. 26
  5. Cannot be determined

Q8. How many persons ate even number of sweets?

  1. One
  2. Two
  3. Three
  4. Four
  5. Cannot be determined

Q9. Who among the following ate the lowest number of sweets?

  1. G
  2. A
  3. D
  4. F
  5. Cannot be determined

Q10. How many sweets does A eat?

  1. 16
  2. 17
  3. 19
  4. 20
  5. Cannot be determined

Q 11.If the code for the word ‘life’ is ‘xra’ then which of the following statements is sufficient to deduce that code?

  1. ‘life sky moon star’ is written as ‘jop omt xra pne’
  2. ‘moon sky heart wind’ is written as ‘omt krs pne iol’
  3. ‘heart wind think right ’ is written as ‘iol tam nso krs’
  4. ‘wind moon think time’ is written as ‘tam pjr pne iol ’
  5. ‘play cold life heavy’ is written as ‘eam xra luk krt’
  6. ‘cold heavy water year’ is written as ‘luk qix zon krt’
  1. Only I and V is sufficient
  2. Only I, III and IV is sufficient
  3. Only I, IV and V are sufficient
  4. I, III, IV and V are necessary
  5. All are necessary

Q12. If the word ‘heavy ’ is coded is as ‘krt ’ then which of the following statements is sufficient to deduce that code?

  1. ‘life sky moon star’ is written as ‘jop omt xra pne’
  2. ‘moon sky heart wind’ is written as ‘omt krs pne iol’
  3. ‘heart wind think right ’ is written as ‘iol tam nso krs’
  4. ‘wind moon think time’ is written as ‘tam pjr pne iol ’
  5. ‘play cold life heavy’ is written as ‘eam xra luk krt’
  6. ‘cold heavy water year’ is written as ‘luk qix zon krt’
  1. Only V and VI are sufficient
  2. Only IV and V are sufficient
  3. I, V, and VI are necessary
  4. Either A or B
  5. None is sufficient

Q13. If ‘wind’ is coded as ‘iol’ then which of the following statement is sufficient to deduce that code?

  1. ‘life sky moon star’ is written as ‘jop omt xra pne’
  2. ‘moon sky heart wind’ is written as ‘omt krs pne iol’
  3.  ‘heart wind think right ’ is written as ‘iol tam nso krs’
  4. ‘wind moon think time’ is written as ‘tam pjr pne iol ’
  5. ‘play cold life heavy’ is written as ‘eam xra luk krt’
  6. ‘cold heavy water year’ is written as ‘luk qix zon krt’
  1. I, II and III are sufficient
  2. II,III and IV are sufficient
  3. I, III and IV are sufficient
  4. I, II and IV are sufficient
  5. Either A or D

Q14. If ‘right’ is coded as ‘nso’ then which of the following statement is sufficient to deduce that code?

  1. ‘life sky moon star’ is written as ‘jop omt xra pne’
  2. ‘moon sky heart wind’ is written as ‘omt krs pne iol’
  3.  ‘heart wind think right ’ is written as ‘iol tam nso krs’
  4. ‘wind moon think time’ is written as ‘tam pjr pne iol ’
  5. ‘play cold life heavy’ is written as ‘eam xra luk krt’
  6. ‘cold heavy water year’ is written as ‘luk qix zon krt’
  1. I, II, and III are sufficient
  2. II, III and IV are sufficient
  3. Only III and IV are sufficient
  4. Only I and IV are sufficient
  5. I, II and III are necessary

Q15. In the above question what will be the code for the word ‘time’?

  1. ‘life sky moon star’ is written as ‘jop omt xra pne’
  2. ‘moon sky heart wind’ is written as ‘omt krs pne iol’
  3.  ‘heart wind think right ’ is written as ‘iol tam nso krs’
  4. ‘wind moon think time’ is written as ‘tam pjr pne iol ’
  5. ‘play cold life heavy’ is written as ‘eam xra luk krt’
  6. ‘cold heavy water year’ is written as ‘luk qix zon krt’
  1. tam
  2. pjr
  3. pne
  4. iol
  5. Cannot be determined

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