IBPS PO Mains 2018 – Quantitative Aptitude Questions Day-20
Dear Readers, Bank Exam Race for the Year 2018 is already started, To enrich your preparation here we have providing new series of Practice Questions on Quantitative Aptitude – Section. Candidates those who are preparing for IBPS PO Mains 2018 Exams can practice these questions daily and make your preparation effective.
IBPS PO Mains 2018- Quantitative Aptitude Questions Day – 20
You have to finish following quiz, to start this quiz:
1
2
3
4
5
6
7
8
9
10
Answered
Review
Question 1 of 10
Directions (Q. 1 - 5) Each question below contains a statement followed by Quantity I and Quantity II. Find the relationship among them and mark your answer accordingly.
1.
Quantity I: Simple interest earned on a certain sum of money after 4 years is Rs. 5760 at the rate of 8%, then find the principal?
Quantity II: Money invested by Ramesh is Rs. x while the money invested by Silambu is (x - 5000). The total interest received by Ramesh and Silambu is Rs. 6000 at a simple interest rate of 4% after 6 years, then find the value of x?
Explanation:
Answer: a)
Quantity I:
Principal = (5760*100)/(4*8) = Rs. 18000
Quantity II:
(x *4*6)/100 + [(x – 5000)*4*6]/100 = 6000
24x/100 + (x – 5000)*(24/100) = 6000
X + x – 5000 = 6000*(100/24)
2x – 5000 = 25000
2x = 30000
X = Rs. 15000
Quantity I > Quantity II
Explanation:
Answer: a)
Quantity I:
Principal = (5760*100)/(4*8) = Rs. 18000
Quantity II:
(x *4*6)/100 + [(x – 5000)*4*6]/100 = 6000
24x/100 + (x – 5000)*(24/100) = 6000
X + x – 5000 = 6000*(100/24)
2x – 5000 = 25000
2x = 30000
X = Rs. 15000
Quantity I > Quantity II
Question 2 of 10
Directions (Q. 1 - 5) Each question below contains a statement followed by Quantity I and Quantity II. Find the relationship among them and mark your answer accordingly.
2.
A sum of Rs. 2385 was divided among A, B and C in such a way that the amount received by A is 20% more than that of C and the amount received by C is 25% less than the amount received by B.
Quantity I: Amount received by A?
Quantity II: Amount received by B?
Explanation:
Answer: c)
Let the amount received by B be 100,
C’s share= 75
A’s share= 90
Ratio between the share of A, B and C = 90 : 100 : 75 = 18 : 20 : 15
Quantity I: The share of A = 18*(2385/53) = Rs. 810
Quantity II: The share of B = 20*(2385/53) = Rs. 900
Quantity II > Quantity I
Explanation:
Answer: c)
Let the amount received by B be 100,
C’s share= 75
A’s share= 90
Ratio between the share of A, B and C = 90 : 100 : 75 = 18 : 20 : 15
Quantity I: The share of A = 18*(2385/53) = Rs. 810
Quantity II: The share of B = 20*(2385/53) = Rs. 900
Quantity II > Quantity I
Question 3 of 10
Directions (Q. 1 - 5) Each question below contains a statement followed by Quantity I and Quantity II. Find the relationship among them and mark your answer accordingly.
3.
Quantity I: The average age of five members in a family, six years ago was 35 years while the present average age of 6 members in a family is 39 years, daughter-in- law being the new member, then find the age of the daughter-in-law?
Quantity II: The ratio of ages of A and B at present is 2:3. Five years hence, their ages will be in the ratio 5 : 7, then find the present age of A?
Explanation:
Answer: a)
Quantity I:
Total age of the family, six years ago = 35*5 = 175 years
Total ages of the family at present without daughter- in-law
= > 175 + 5*6 = 205 years
Total ages of the family now including daughter in law
= > 39*6 = 234 years
Age of the daughter in law = 234 – 205 = 29 years
Quantity II:
Let the ratio be 2x and 3x,
So,
(2x+5)/(3x+5) = 5/7
14x + 35 = 15x + 25
X = 10
Present age of A is 20 years
Quantity I > Quantity II
Explanation:
Answer: a)
Quantity I:
Total age of the family, six years ago = 35*5 = 175 years
Total ages of the family at present without daughter- in-law
= > 175 + 5*6 = 205 years
Total ages of the family now including daughter in law
= > 39*6 = 234 years
Age of the daughter in law = 234 – 205 = 29 years
Quantity II:
Let the ratio be 2x and 3x,
So,
(2x+5)/(3x+5) = 5/7
14x + 35 = 15x + 25
X = 10
Present age of A is 20 years
Quantity I > Quantity II
Question 4 of 10
Directions (Q. 1 - 5) Each question below contains a statement followed by Quantity I and Quantity II. Find the relationship among them and mark your answer accordingly.
4. Quantity I: 180 m long train crosses an electric pole in 12 seconds, then find the time taken by the same train to crosses a platform of length 230 m?
Quantity II: The train of length 150 m crosses a man walking at a speed of 8 km/hr in the opposite direction of the train in 9 seconds, then find the time taken by the train to cross a bridge of length 266 m?
Explanation:
Answer: c)
Quantity I:
Let the speed of the train be x,
12 = 180/x
X = 15 m/s
Time taken to cross a platform
= > (180 + 230)/15
= > 410/15
= > 27 1/3 seconds
Quantity II:
Speed of man = 8 km/hr
Let the speed of the train be x,
9 = 150/[(x+8)*(5/18)]
9*(5/18) = 150/(x + 8)
X + 8 = 150/[9*(5/18)]
X + 8 = 60
X = 52 km/hr
Time taken to cross a bridge= (150 + 266)/[52*(5/18)] = 144/5 = 28 4/5 seconds
Quantity II > Quantity I
Explanation:
Answer: c)
Quantity I:
Let the speed of the train be x,
12 = 180/x
X = 15 m/s
Time taken to cross a platform
= > (180 + 230)/15
= > 410/15
= > 27 1/3 seconds
Quantity II:
Speed of man = 8 km/hr
Let the speed of the train be x,
9 = 150/[(x+8)*(5/18)]
9*(5/18) = 150/(x + 8)
X + 8 = 150/[9*(5/18)]
X + 8 = 60
X = 52 km/hr
Time taken to cross a bridge= (150 + 266)/[52*(5/18)] = 144/5 = 28 4/5 seconds
Quantity II > Quantity I
Question 5 of 10
Directions (Q. 1 - 5) Each question below contains a statement followed by Quantity I and Quantity II. Find the relationship among them and mark your answer accordingly.
5.
Quantity I: The area of rectangular garden is 2080 Sq m. The length of the rectangular garden is 30 % more than the breadth. Find the perimeter of the garden?
Quantity II: The area of a square park is 2304 Sq m. Find the perimeter of the park?
Explanation:
Answer: c)
Quantity I:
The area of rectangular garden = 2080 Sq m
Length = (130/100)*breadth
l/b = 13/10 = > l : b = 13 : 10
13x*10x = 2080
130x2 = 2080
X2 = (2080/130) = 16
X = 4
Length = 52 m, Breadth = 40 m
Perimeter of the garden = 2*(l + b) = 2*(52 + 40) =2*92 = 184 m
Quantity II:
The area of a square park = 2304 Sq m
Area (a2) = 2304
Side (a) = 48
Perimeter of the park = 4a = 4*48 = 192 m
Quantity II > Quantity I
Explanation:
Answer: c)
Quantity I:
The area of rectangular garden = 2080 Sq m
Length = (130/100)*breadth
l/b = 13/10 = > l : b = 13 : 10
13x*10x = 2080
130x2 = 2080
X2 = (2080/130) = 16
X = 4
Length = 52 m, Breadth = 40 m
Perimeter of the garden = 2*(l + b) = 2*(52 + 40) =2*92 = 184 m
Quantity II:
The area of a square park = 2304 Sq m
Area (a2) = 2304
Side (a) = 48
Perimeter of the park = 4a = 4*48 = 192 m
Quantity II > Quantity I
Question 6 of 10
Directions (Q. 6 – 10) Study the following information carefully and answer the given questions.
Following table shows the total number of employees in 3 different companies in different years and also shows the percentage of officers among them.
6. Total number of officers of company P in the year 2013 and 2015 together is approximately what percentage more/less than the total number of officers of company R in the year 2016 and 2017 together?
Explanation:
Answer: c)
Total number of officers of company P in the year 2013 and 2015 together
= > 1500*(25/100) + 1800*(35/100)
= > 375 + 630 = 1005
Total number of officers of company R in the year 2016 and 2017 together
= > 2100*(35/100) + 2150*(38/100)
= > 735 + 817 = 1552
Required % = [(1552 -1005)/1552]*100 = 35 % less
Explanation:
Answer: c)
Total number of officers of company P in the year 2013 and 2015 together
= > 1500*(25/100) + 1800*(35/100)
= > 375 + 630 = 1005
Total number of officers of company R in the year 2016 and 2017 together
= > 2100*(35/100) + 2150*(38/100)
= > 735 + 817 = 1552
Required % = [(1552 -1005)/1552]*100 = 35 % less
Question 7 of 10
Directions (Q. 6 – 10) Study the following information carefully and answer the given questions.
Following table shows the total number of employees in 3 different companies in different years and also shows the percentage of officers among them.
7. Find the respective ratio between the total number of employees of company Q to that of total number of employees of company R in all the given years together?
Explanation:
Answer: a)
The total number of employees of company Q in all the given years together
= > 1750 + 1900 + 2100 + 1650 + 2350 = 9750
The total number of employees of company R in all the given years together
= > 1250 + 1700 + 1550 + 2100 + 2150 = 8750
Required ratio = 9750 : 8750 = 39 : 35
Explanation:
Answer: a)
The total number of employees of company Q in all the given years together
= > 1750 + 1900 + 2100 + 1650 + 2350 = 9750
The total number of employees of company R in all the given years together
= > 1250 + 1700 + 1550 + 2100 + 2150 = 8750
Required ratio = 9750 : 8750 = 39 : 35
Question 8 of 10
Directions (Q. 6 – 10) Study the following information carefully and answer the given questions.
Following table shows the total number of employees in 3 different companies in different years and also shows the percentage of officers among them.
8. Find the difference between the total number of employees of other than officers in company P in the year 2014 and 2016 together to that of total number of officers of company R in the year 2013, 2014 and 2015 together?
Explanation:
Answer: d)
The total number of employees of other than officers in company P in the year 2014 and 2016 together
= > 2250*(68/100) + 1750*(72/100)
= > 1530 + 1260 = 2790
The total number of officers of company R in the year 2013, 2014 and 2015 together
= > 1250*(16/100) + 1700*(24/100) + 1550*(28/100)
= > 200 + 408 + 434 = 1042
Required difference = 2790 – 1042 = 1748
Explanation:
Answer: d)
The total number of employees of other than officers in company P in the year 2014 and 2016 together
= > 2250*(68/100) + 1750*(72/100)
= > 1530 + 1260 = 2790
The total number of officers of company R in the year 2013, 2014 and 2015 together
= > 1250*(16/100) + 1700*(24/100) + 1550*(28/100)
= > 200 + 408 + 434 = 1042
Required difference = 2790 – 1042 = 1748
Question 9 of 10
Directions (Q. 6 – 10) Study the following information carefully and answer the given questions.
Following table shows the total number of employees in 3 different companies in different years and also shows the percentage of officers among them.
9. Find the total number of employees other than officers of company Q in the year 2014, 2015 and 2016 together?
Explanation:
Answer: c)
The total number of employees other than officers of company Q in the year 2014, 2015 and 2016 together
= > 1900*(65/100) + 2100*(76/100) + 1650*(74/100)
= > 1235 + 1596 + 1221 = 4052
Explanation:
Answer: c)
The total number of employees other than officers of company Q in the year 2014, 2015 and 2016 together
= > 1900*(65/100) + 2100*(76/100) + 1650*(74/100)
= > 1235 + 1596 + 1221 = 4052
Question 10 of 10
Directions (Q. 6 – 10) Study the following information carefully and answer the given questions.
Following table shows the total number of employees in 3 different companies in different years and also shows the percentage of officers among them.
10. Total number of employees of company Q in the year 2014 and 2015 together is approximately what percentage of total number of employees of company R in the year 2014 and 2016 together?
Explanation:
Answer: b)
Total number of employees of company Q in the year 2014 and 2015 together
= > 1900 + 2100 = 4000
Total number of employees of company R in the year 2014 and 2016 together
= > 1700 + 2100 = 3800
Required % = (4000/3800)*100 = 105 %
Explanation:
Answer: b)
Total number of employees of company Q in the year 2014 and 2015 together
= > 1900 + 2100 = 4000
Total number of employees of company R in the year 2014 and 2016 together
Directions (Q. 1 – 5) Each question below contains a statement followed by Quantity I and Quantity II. Find the relationship among them and mark your answer accordingly.
1) Quantity I: Simple interest earned on a certain sum of money after 4 years is Rs. 5760 at the rate of 8%, then find the principal?
Quantity II: Money invested by Ramesh is Rs. x while the money invested by Silambu is (x – 5000). The total interest received by Ramesh and Silambu is Rs. 6000 at a simple interest rate of 4% after 6 years, then find the value of x?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
2) A sum of Rs. 2385 was divided among A, B and C in such a way that the amount received by A is 20% more than that of C and the amount received by C is 25% less than the amount received by B.
Quantity I: Amount received by A?
Quantity II: Amount received by B?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
3) Quantity I: The average age of five members in a family, six years ago was 35 years while the present average age of 6 members in a family is 39 years, daughter-in- law being the new member, then find the age of the daughter-in-law?
Quantity II: The ratio of ages of A and B at present is 2:3. Five years hence, their ages will be in the ratio 5 : 7, then find the present age of A?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
4) Quantity I: 180 m long train crosses an electric pole in 12 seconds, then find the time taken by the same train to crosses a platform of length 230 m?
Quantity II: The train of length 150 m crosses a man walking at a speed of 8 km/hr in the opposite direction of the train in 9 seconds, then find the time taken by the train to cross a bridge of length 266 m?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
5) Quantity I: The area of rectangular garden is 2080 Sq m. The length of the rectangular garden is 30 % more than the breadth. Find the perimeter of the garden?
Quantity II: The area of a square park is 2304 Sq m. Find the perimeter of the park?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Directions (Q. 6 – 10) Study the following information carefully and answer the given questions.
Following table shows the total number of employees in 3 different companies in different years and also shows the percentage of officers among them.
6) Total number of officers of company P in the year 2013 and 2015 together is approximately what percentage more/less than the total number of officers of company R in the year 2016 and 2017 together?
a) 25 % more
b) 35 % more
c) 35 % less
d) 25 % less
e) 15 % more
7) Find the respective ratio between the total number of employees of company Q to that of total number of employees of company R in all the given years together?
a) 39 : 35
b) 41 : 37
c) 23 : 19
d) 15 : 11
e) None of these
8) Find the difference between the total number of employees of other than officers in company P in the year 2014 and 2016 together to that of total number of officers of company R in the year 2013, 2014 and 2015 together?
a) 1536
b) 1924
c) 2152
d) 1748
e) None of these
9) Find the total number of employees other than officers of company Q in the year 2014, 2015 and 2016 together?
a) 3598
b) 3756
c) 4052
d) 4234
e) None of these
10) Total number of employees of company Q in the year 2014 and 2015 together is approximately what percentage of total number of employees of company R in the year 2014 and 2016 together?
a) 90 %
b) 105 %
c) 120 %
d) 135 %
e) 75 %
Answers :
Direction (1-5) :
1) Answer: a)
Quantity I:
Principal = (5760*100)/(4*8) = Rs. 18000
Quantity II:
(x *4*6)/100 + [(x – 5000)*4*6]/100 = 6000
24x/100 + (x – 5000)*(24/100) = 6000
X + x – 5000 = 6000*(100/24)
2x – 5000 = 25000
2x = 30000
X = Rs. 15000
Quantity I > Quantity II
2) Answer: c)
Let the amount received by B be 100,
C’s share= 75
A’s share= 90
Ratio between the share of A, B and C = 90 : 100 : 75 = 18 : 20 : 15
Quantity I: The share of A = 18*(2385/53) = Rs. 810
Quantity II: The share of B = 20*(2385/53) = Rs. 900
Quantity II > Quantity I
3) Answer: a)
Quantity I:
Total age of the family, six years ago = 35*5 = 175 years
Total ages of the family at present without daughter- in-law
= > 175 + 5*6 = 205 years
Total ages of the family now including daughter in law
= > 39*6 = 234 years
Age of the daughter in law = 234 – 205 = 29 years
Quantity II:
Let the ratio be 2x and 3x,
So,
(2x+5)/(3x+5) = 5/7
14x + 35 = 15x + 25
X = 10
Present age of A is 20 years
Quantity I > Quantity II
4) Answer: c)
Quantity I:
Let the speed of the train be x,
12 = 180/x
X = 15 m/s
Time taken to cross a platform
= > (180 + 230)/15
= > 410/15
= > 27 1/3 seconds
Quantity II:
Speed of man = 8 km/hr
Let the speed of the train be x,
9 = 150/[(x+8)*(5/18)]
9*(5/18) = 150/(x + 8)
X + 8 = 150/[9*(5/18)]
X + 8 = 60
X = 52 km/hr
Time taken to cross a bridge= (150 + 266)/[52*(5/18)] = 144/5 = 28 4/5 seconds
Quantity II > Quantity I
5) Answer: c)
Quantity I:
The area of rectangular garden = 2080 Sq m
Length = (130/100)*breadth
l/b = 13/10 = > l : b = 13 : 10
13x*10x = 2080
130x2 = 2080
X2 = (2080/130) = 16
X = 4
Length = 52 m, Breadth = 40 m
Perimeter of the garden = 2*(l + b) = 2*(52 + 40) =2*92 = 184 m
Quantity II:
The area of a square park = 2304 Sq m
Area (a2) = 2304
Side (a) = 48
Perimeter of the park = 4a = 4*48 = 192 m
Quantity II > Quantity I
Direction (6-10) :
6) Answer: c)
Total number of officers of company P in the year 2013 and 2015 together
= > 1500*(25/100) + 1800*(35/100)
= > 375 + 630 = 1005
Total number of officers of company R in the year 2016 and 2017 together
= > 2100*(35/100) + 2150*(38/100)
= > 735 + 817 = 1552
Required % = [(1552 -1005)/1552]*100 = 35 % less
7) Answer: a)
The total number of employees of company Q in all the given years together
= > 1750 + 1900 + 2100 + 1650 + 2350 = 9750
The total number of employees of company R in all the given years together
= > 1250 + 1700 + 1550 + 2100 + 2150 = 8750
Required ratio = 9750 : 8750 = 39 : 35
8) Answer: d)
The total number of employees of other than officers in company P in the year 2014 and 2016 together
= > 2250*(68/100) + 1750*(72/100)
= > 1530 + 1260 = 2790
The total number of officers of company R in the year 2013, 2014 and 2015 together
= > 1250*(16/100) + 1700*(24/100) + 1550*(28/100)
= > 200 + 408 + 434 = 1042
Required difference = 2790 – 1042 = 1748
9) Answer: c)
The total number of employees other than officers of company Q in the year 2014, 2015 and 2016 together
= > 1900*(65/100) + 2100*(76/100) + 1650*(74/100)
= > 1235 + 1596 + 1221 = 4052
10) Answer: b)
Total number of employees of company Q in the year 2014 and 2015 together
= > 1900 + 2100 = 4000
Total number of employees of company R in the year 2014 and 2016 together
= > 1700 + 2100 = 3800
Required % = (4000/3800)*100 = 105 %
Kindly watch this video to know about Important Table Based Data Interpretation Questions
