Dear Aspirants, Quantitative Aptitude plays a crucial role in Banking and all other competitive exams. To enrich your preparation, here we have provided New Pattern Aptitude Questions that are similar to the questions asked in IBPS PO Mains 2018. Candidates those who are going to appear in upcoming bank exams like IBPS Clerk, IBPS SO, etc., can practice these questions daily and make your preparation effective.
[WpProQuiz 4513]Direction (1 – 5): Read the following information carefully and answer the given questions:
Total distance between A to B is 240km. Train P starts running with an average speed of (S) kmph from A to B while another train Q starts running after 2 hours of train A and reaches B 60 minutes before train P. If train A stops for 60 minutes at a line crossing and second train did not stop at any place, then the ratio between the speed of train P to speed of train Q is 4:5.
Prem distributed Rs.14000 between his two daughters Anu and Bharathi and both of them invested at the rate of (S-6)% SI per annum. The age of Bharathi and Anu at that time was 18 years and (S) years respectively and such that each daughter may get equal amounts, when they attain the age of 21 years. Initial amount the Anu has is (T).
The price of article increased by (S)% every year. If the difference between the price at the end of the third year and fourth years is (U) and the price at the end of second year is Rs.23200.
Prem sells his car, if profit on selling a car for (T) is thrice the loss on selling it for Rs.4500. The Cost price of Prem car is (V).
1) Find the value in the place of (S)
a) 15 kmph
b) 26 kmph
c) 16 kmph
d) 18 kmph
e) None of these
2) Find the value in the place of (V)
a) Rs.8000
b) Rs.6000
c) Rs.4000
d) Rs.5000
e) None of these
3) Quantity I: U
Quantity II: T
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
4) Find the difference between V and T?
a) Rs.1500
b) Rs.2500
c) Rs.500
d) Rs.1600
e) None of these
5) Find the value in the place of (U)
a) 4305.92
b) 4206.92
c) 4108.92
d) 4006.92
e) None of these
Directions (6 – 10): The questions below are based on the given Series-I. The series-I satisfy a certain pattern, follow the same pattern in Series-II and answer the questions given below.
6)
I. 3256, 3260, 3251, 3276, 3227, 3348
II. 1089 …… 1301. If 1301 is the nth term, then find the value of n?
a) 5
b) 6
c) 7
d) 9
e) 8
7)
I. 184, 356, 969, 2207, 4286, 7454
II. 42, 211 …. 4132. If 4132 is the nth term, what value should come in the place of (n+1)th term?
a) 2207
b) 8117
c) 9207
d) 7297
e) 7587
8)
I. 179, 195, 212, 248, 359, 807
II. 192, 211…… 922. If 922 is the nth term, then find the value of n?
a) 11
b) 10
c) 9
d) 7
e) 6
9)
I. 64, 33, 34, 52, 105, 263.5
II. 72 ….. 881.5. If 881.5 is the nth term, then what value should come in the place of (n-2)th term?
a) 117
b) 38
c) 58
d) 293.5
e) 457.5
10)
I. 722, 850, 994, 1202, 1538, 2386
II. 84, 256, 446 ….. 4230. If 4230 is the nth term, find the value of (n+1)?
a) 11
b) 10
c) 9
d) 8
e) 7
Answers:Â
Direction (1 – 5):
Let us take the original time taken to cross 240 km distance be x hours
Time taken by train P to reach B =(X+1)
Time taken by train Q to reach B=(x+1)-2-1=(x-2)
Speed of first train=240/(x+1)
Speed of second train=240/(x-2)
(240/(x+1))/(240/(x-2))=4/5
(x-2)/(x+1)=4/5
5x-10=4x+4
X=14
Time taken by train P =15 hrs
Time taken by train Q =12 hrs
Speed of first train (S) =240/15=16 kmph
Let the amount received by Anu=A
Let the amount received by Bharathi=14000-A
A+(A*5*10/100)=(14000-A)+((14000-A)*10*3/100)
A+A/2=(14000-A)+4200-3A/10
3A/2=18200-A-3A/10
3A/2+A+3A/10=18200
28A=182000
A=6500
Anu received (T)=Rs.6500
Initial amount=a
Second years=a*116/100
116a/100=23200
a=20000
Third year=a*(116/100)*(116/100)
Fourth year=a*(116/100)*(116/100)*(116/100)
Difference of fourth and third year (U)=a*(116/100)*(116/100)*(116/100-1)
U=20000*(116/100)*(116/100)*(16/100)
Difference of fourth and third year (U) = 4305.92
Cost price of car=V
6500-V=3(V-4500)
6500-V=3V-13500
4V=20000
V=5000
1) Answer: c)
Speed of first train (S) =240/15=16 kmph
2) Answer: d)
V=5000Â
3) Answer: c)
Quantity I:
Difference of fourth and third year (U) = 4305.92
Quantity II:
Anu received (T)=Rs.6500
Quantity I < Quantity II
4) Answer: a)
Anu received (T)=Rs.6500
V=5000
Required difference = 6500 – 5000 = Rs.1500
5) Answer: a)
Difference of fourth and third year (U) = 4305.92
Directions (6 – 10):
6) Answer: e)
Series –I pattern:
3256 is the 1st term
3256 + 22 = 3260
3260 – 32 = 3251
3251 + 52 = 3276
3276 – 72 = 3227
3227 + 112 = 3348 = 6th term
Series –II pattern:
1089 is the 1st term
1089 + 22 = 1093
1093 – 32 = 1084
1084 + 52 = 1109
1109 – 72 = 1060
1060 + 112 = 1181
1181 – 132 = 1012
1012 + 172 = 1301 = 8th term
7) Answer: d)
Series – I pattern:
Series –II pattern:
8) Answer: e)
Series –I pattern:
Pattern of the difference in the above series is:
16 * 1 + 1 = 17
17 * 2 +2 = 36
 36 * 3 + 3 = 111
111 * 4+ 4 = 448
807 is 6th term
Series – II pattern:
Pattern of the difference in the above series is:
19 * 1 + 1 = 20
20 * 2 + 2 = 42
42 * 3+ 3 = 129
129 * 4 + 4 = 520
922 is 6th term
9) Answer: a)
Series –I pattern:
64 is the 1st term
64 * 0.5 + 1 = 33
33 * 1 + 1 = 34
34 * 1.5 + 1 = 52
52 * 2 + 1 = 105
105 * 2.5 + 1 = 263.5 = 6th term
Series –II pattern:
72 is the 1st term
72 * 0.5 + 1 = 37
37 * 1 + 1 = 38
38 * 1.5 + 1 = 58
58 * 2 + 1 = 117 = 5th term = (n-2)th term
117 * 2.5 + 1 = 293.5 = 6th term = (n-1)th term
293.5 * 3 + 1 = 881.5 = 7th term = nth term
10) Answer: d)
Series – I pattern:
Pattern of the difference of difference in the above series is:
16 * 4 = 64
64 * 2 = 128
128 * 4 = 512
2386 is the 6th term
Series –II pattern:
Pattern of the difference of difference in the above series is:
18 * 4 = 72
72 * 2 = 144
144 * 4 = 576
576 * 2 = 1152
4230 is the 7th term = nth term
(n +1) = 7 +1 = 8
