# Quantitative Aptitude Questions (Problem on Trains) Day-47

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination ofย SBI Clerkย was scheduled fromย June/July.ย Toย enrichย your preparation here we have providing new series of Problem on Trains-ย Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

Practice Aptitude Questions (Problem on Trains) Day-47

maximum of 10 points

Click โStart Quizโ to attend these Questions and view Solutions

1) A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The otherย one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speedย of the train if both the persons are walking in the same direction as the train?

1. 96 km/hr
2. 81 km/hr
3. 51 km/hr
4. 76 km/hr
5. None of these

2) Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completelyย passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?

1. 27 m
2. 33 m
3. 27 7/9 m
4. 23 4/9 m
5. None of these

3) Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:

1. 3 : 2
2. 1 : 3
3. 3 : 7
4. 3 : 4
5. None of these

4) A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

1. 3.6 sec
2. 18 sec
3. 36 sec
4. 72 sec
5. None of these

5) Two trains are running at 60 Kmph and 42 Kmph respectively in same direction. Fast train completely passes a man sitting in the slower train in 30sec. What is the length of the faster train?

1. 100m
2. 125m
3. 150m
4. 175m
5. None of these

6) Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 350 m and 200 m respectively. The time taken by the slower train to cross the faster train in seconds is:

1. 16.8 sec
2. 15.4 sec
3. 13.2 sec
4. 19.6 sec
5. None of these

7) The distance between Meerut and Allahabad is 700 km. Sangamnagri express starts from Allahabad to Meerut at 60 kmph. 50 minutes later Ganga express leaves Meerut to Allahabad on the parallel tracks at 70 kmph. How far from Meerut will they cross each other?

1. 250 km
2. 360 km
3. 350 km
4. 475 km
5. None of these

8) A train covers a distance between stations R & S in 45 minutes. If the speed is reduced by 5 kmph. It will cover the same distance in 48 minutes. What is the distance between two stations R &S (in km)? Also find the speed of the train.

1. 60 km, 80 kmph
2. 65 km, 70 kmph
3. 60 km, 70 kmph
4. 65 km, 80 kmph
5. None of these

9) The length of Mumbai mail is 120 m and that of Punjab mail is 80 m. These two trains are running in the same direction with velocities of 40 kmph and 50 kmph respectively. The time taken by them to cross each other is:

1. 8 sec
2. 72 sec
3. 11.5 sec
4. 12.5 sec
5. None of these

10) A train overtakes two persons who are walking in the same directions in which the train is going, at the rate of 2kmph and 4 kmph respectively and passed them completely in 9 and 10 seconds respectively. The length of the train is?

1. 50 m
2. 60 m
3. 65 m
4. 70 m
5. None of these

4.5 km/hr = (4.5 x 5/18) m/sec = 5/4 m/sec = 1.25 m/sec, and
5.4 km/hr = (5.4 x 5/18) m/sec = 3/2 m/sec = 1.5 m/sec.
Let the speed of the train be x m/sec.
Then, (x – 1.25) x 8.4 = (x – 1.5) x 8.5
=> 8.4x – 10.5 = 8.5x – 12.75
=> 0.1x = 2.25
=> x = 22.5
Therefore Speed of the train = (22.5 x 18/5) km/hr = 81 km/hr.

Relative speed = (40 – 20) km/hr = (20 x 5/18) m/sec = 50/9 m/sec.
Therefore Length of faster train = (50/9 x 5) m = 250/9 m = 27 7/9 m.

Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
(27x + 17y)/(x + y) = 23
27x + 17y = 23x + 23y
4x = 6y
x/y = 3/2.

Speed of train relative to jogger = (45 – 9) km/hr = 36 km/hr.

= [36 x (5/18) m/sec

= 10 m/sec.

Distance to be covered = (240 + 120) m = 360 m.

Time taken = (360/10) sec = 36 sec

L = S ร T
L = 18 ร 5/18 ร 30
(in same direction Speed = first train – second train)
= 150m

Relative speed = (60+ 90) km/hr

= [150 * (5/18)] m/sec

= (125/3) m/sec.

Distance covered = (350 + 200) m = 550 m

Required time = [550 x (3/125)] sec = 13.2 sec.

In 50 minute Sangam nagri can cover 50 km.

So, the rest distance = 650 km, which will be jointly covered by both trains.

Time taken = 650/(60 + 70) = 5 h

Distance from Meerut = 5 * 70 = 350 km

When distance is kept constant then speed and time are in inverse relations.

So if speed is S then

s/(s โ 5) = 16/15 so we get

Speed = 80 kmph and

Distance = 60 km

Relative speed = 50 โ 40 = 10 kmph = 50 18 m/s

Time taken = Sum of length of the trains/Relative speed = (200 *18)/50 = 72 sec

Let the speed and length of train beโsโ and โlโ respectively.

Speed of one person = ย 2 km/hr = 2*(5/18) = 5/9 m/s

Speed of another person = 4 km/hr = 4*(5/18) = 10/9 m/s

So the equation as per the question becomes

(s โ 5/9) = l/9 ——–1)

(s โ 10/9) = l/10 ——2)

1) โ 2) we get l = 50 m

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