# Quantitative Aptitude Questions (Time and work) for SBI Clerk 2018 Day-19

## Quantitative Aptitude Questions (Time and work) for SBI Clerk 2018 Day-19:

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination ofย SBI Clerkย was scheduled fromย March 2018. Toย enrichย your preparation here we have providing new series of Time and work –ย Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

Practice Aptitude Questions (Time and work) Day-19

maximum of 10 points

Click โStart Quizโ to attend these Questions and view Solutions

## Daily Practice Test Schedule | Good Luck

 Topic Daily Publishing Time Daily News Papers & Editorials 8.00 AM Current Affairs Quiz 9.00 AM Logical Reasoning 10.00 AM Quantitative Aptitude โ20-20โ 11.00 AM Vocabulary (Based on The Hindu) 12.00 PM Static GK Quiz 1.00 PM English Language โ20-20โ 2.00 PM Banking Awareness Quiz 3.00 PM Reasoning Puzzles & Seating 4.00 PM Daily Current Affairs Updates 5.00 PM Data Interpretation / Application Sums (Topic Wise) 6.00 PM Reasoning Ability โ20-20โ 7.00 PM English Language (New Pattern Questions) 8.00 PM General / Financial Awareness Quiz 9.00 PM

Q.1) A alone can do a piece of work with 50% of its efficiency in 30 days, which is two times of the no of days taken by C alone can complete the whole work and five times of the no of days taken by B and C together can complete the whole work. Then find the no of days required by A and B together working 75% of their efficiency

1. 6
2. 7
3. 8
4. 4
5. 5

Q.2) P alone can do a piece of work in 15 days. Q alone can do the same work in 10 days. P and R together can do the same work in 6 2/3 days. P and Q started working on first day and Q and R together working on second day. This process continues until the work was completed. How many days required to complete the whole work?

1. 5 4/5
2. 5 8/11
3. 6 4/5
4. 7 5/6
5. 5 ยพ

Q.3) A is two times efficient as B and they together can do a piece of work in 4 days. C takes three days more than B. If A and B started working together, after 2 days C joins with them and leaves one day before the work was completed, then find the total no of days

1. 3 15/19
2. 3 11/15
3. 4 13/19
4. 3 13/17
5. 4 11/17

Q.4) Arun alone can do a piece of work in x days and Shaalu alone can do the same work in x+5 days. If Arun and Shaalu together can complete the same work in 11 1/9 days, then find the number of days completed by Arun alone

1. 25
2. 15
3. 10
4. 20
5. 24

Q.5) A and B together can do a piece of work in 8 days. B and C together can do the same work in 9ย  3/5ย  days. A and C together can do the same work in 6ย  6/7ย  days. If A and B started working together after every two days C joins with them for one day, then find the number of days required to complete the whole work

1. 7 3/4
2. 8 4/5
3. 9 1/3
4. 8 1/2
5. 9 1/2

Q.6) A alone can build up a wall in 20 days and B alone can break down the same wall in 5 days more than A.ย  A is two times more efficient as C (build up). A, B and C together can build the wall in how many days?

1. 26 4/5
2. 24 3/4
3. 28 4/7
4. 25 5/7
5. 28 5/7

Q.7) Swathi is 50% more efficient than Priya and together can do a piece of work in 6 days. Rathi alone can do the same work in 5 days more than Priya. If Swathi gets a share of Rs.1800, then find the total share of Swathi, Priya and Rathi working together

1. Rs.3600
2. Rs.3900
3. Rs.3200
4. Rs.3000
5. Rs.2800

Q.8) 15 men can do a piece of work in 20 days. 20 men started working together, after 5 days 20 women completed the remaining work in 20 days, and then find the number of days required to complete the whole work by 30 women alone

1. 30
2. 15
3. 25
4. 20
5. 24

Q.9) 15 boys alone can do a piece of work in 20 days. 30 boys and 30 girls working alternatively starting with 30 boys, then find the total number of days taken to complete the whole work if one boy is equal to two girls

1. 12
2. 11
3. 15
4. 17
5. 13

Q.10) 20 men and 20 women can complete half of the work in 20 days working with alternatively. If 10 men and 20 boys together can complete the whole work in 10 days, then find the number of days required by 20 boys alone complete the Remaining work?

1. 12 days
2. 11 days
3. 10 days
4. 12 days
5. 13 days

Aโs one day work with 100% efficiency = 1/15

Cโs one day work = 1/15

B and Cโs one day work = 1/6

Bโs one day work = 1/6-1/15=1/10

Required no of days = 1/20+3/40=5/40=1/8

Rโs one day work = 3/20-1/15=5/60=1/12

P and Qโs one day work = 1/15+1/10=5/30=10/60

Q and R’s one day work = 1/10+1/12=11/60

1 cycle (2 days) = 21 units completed

2 cycles (4 days) = 42 units completed

Next cycle will be P and Q,

So, 52 units get completed.

Remaining work completed by Q and R = 8/11

Required number of days =5 8/11 days

Efficiency ratio of A and B =2:1

1/2x+1/x=1/4

2x=12=>x=6

C = 12+3=15 days

Given,

Let take total number of days be x

x/4+(x-3)/15=1

Simplify the above equation we get x= 3 15/19 days

Given,

1/x+1/(x+5)=9/100

Simplify the above equation we get x=20 days

Given,

2(A+B+C)=1/8+7/48+5/48=18/48=3/8

A+B+C=3/16

Aโs one day work = 3/16-5/48=4/48=1/12

Bโs one day work=3/16-7/48=2/48=1/24

Cโs one day work = 3/16-1/8=1/16

1 cycle (3 days) =2/12+2/24+1/16=5/16

3 cycles (9 days) =15/16

Remaining =1- 15/16=1/16

Remaining work completed by A and B = (1/16)/(1/12+1/24)=1/2

Total number of days =9+ 1/2=9 1/2 days

Given,

=>1/20+1/40-1/25

=>(15-8)/200=28 4/7ย  days

Given,

Efficiency ratio of Swathi and Priya = 3:2

1/3x+1/2x=1/6

=>x=5

Efficiency ratio of Swathi, Priya and Rathi = 1/10:1/15:1/20

=>6:4:3

Total share = 1800/6ร13=Rs.3900

20 men 5 days output = (20ร5)/(15ร20)=1/3

Remaining =1- 1/3=2/3

Two-third of the total work completed in 20 days then total work completed in 30 days.

Required number of days = 30/(30ร20)=1/20

30 women alone complete the whole work in 20 days.

1 cycle (2 days) =30/(15ร20)+30/((30ร20) )=3/20

6th cycle (12 days) =18/20

Remaining =1- 18/20=2/20

Remaining work completed by 30 boys = (2/20)/(30/(15ร20))=1

Total number of days =12+1=13 days

20 men completes the whole work in 20 days

10 men 10 days work = (10ร10)/(20ร20)=1/4

Remaining =1- 1/4=3/4

20 boys can complete the whole work in 40/3 days, therefore remaining work completed by 20 boys in,

=> (40/3) *(3/4) =10 days