Dear Aspirants, Our IBPS Guide team is providing new pattern Quantitative Aptitude Questions for IBPS Clerk Mains 2019 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
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Question 1 of 10
1. Question
Data interpretation
Directions (1 – 5): Study the following information carefully and answer the given questions:
The following bar graph shows the production of mobiles (In thousands) of different companies in two different years.
The average number of mobiles exported by company D and F in 2017 is 35000 while the mobiles exported by company D in 2016 is twice the export in 2017 then find the percentage of export by company F out of total production of company F in 2017?
Correct
Answer: b)
Total mobiles exported by company D and F= 35000*2 = 70000
Mobile exported by company D in 2016= (30/100)*35000 = 10500
Mobile exported by company D in 2017 = 10500/2 = 5250
Mobile exported by company F = 70000 – 5250 = 64750
Percentage of production exported by company F in 2017
= > 64750/90000* 100 = 72%
Incorrect
Answer: b)
Total mobiles exported by company D and F= 35000*2 = 70000
Mobile exported by company D in 2016= (30/100)*35000 = 10500
Mobile exported by company D in 2017 = 10500/2 = 5250
Mobile exported by company F = 70000 – 5250 = 64750
Percentage of production exported by company F in 2017
= > 64750/90000* 100 = 72%
Question 2 of 10
2. Question
Data interpretation
Directions (1 – 5): Study the following information carefully and answer the given questions:
The following bar graph shows the production of mobiles (In thousands) of different companies in two different years.
If company E exported a total of 50000 mobiles in the year 2016 and 2017, then find the percentage of mobiles exported by company E in 2016?
Correct
Answer: b)
Mobile exported by company E in 2017 = 40000*(70/100) = 28000
Mobile exported by company E in 2016 = 50000 – 28000 = 22000
Required % = (22000/80000)*100 = 27.5 %
Incorrect
Answer: b)
Mobile exported by company E in 2017 = 40000*(70/100) = 28000
Mobile exported by company E in 2016 = 50000 – 28000 = 22000
Required % = (22000/80000)*100 = 27.5 %
Question 3 of 10
3. Question
Data interpretation
Directions (1 – 5): Study the following information carefully and answer the given questions:
The following bar graph shows the production of mobiles (In thousands) of different companies in two different years.
The total number of mobiles exported by company A in 2016 and 2017 is 2/3 of the mobiles exported by company C in these years then find the percentage of mobiles that were exported by company C out of total production in 2017 ?
Correct
Answer: d)
Total number of mobiles exported by company A in 2016 and 2017
= > (40/100)*20000 + (60/100)*50000
= > 8000 + 30000 = 38000
Mobile exported by company C in 2016 and 2017
= > 38000*(3/2) = 57000
Mobile exported by company C in 2017
= > 57000 – 26000*(20/100)
= > 51800
Percentage of export by company C = (51800/80000)*100 = 64.75 %
Incorrect
Answer: d)
Total number of mobiles exported by company A in 2016 and 2017
= > (40/100)*20000 + (60/100)*50000
= > 8000 + 30000 = 38000
Mobile exported by company C in 2016 and 2017
= > 38000*(3/2) = 57000
Mobile exported by company C in 2017
= > 57000 – 26000*(20/100)
= > 51800
Percentage of export by company C = (51800/80000)*100 = 64.75 %
Question 4 of 10
4. Question
Data interpretation
Directions (1 – 5): Study the following information carefully and answer the given questions:
The following bar graph shows the production of mobiles (In thousands) of different companies in two different years.
The 20% of the mobiles exported by company B in 2016 are defective while the ratio between the defective mobiles exported by company B in the year 2016 and 2017 is 7 : 5 and the percentage of defective mobiles out of total export by company B in 2017 is 13.5% then find the percentage of mobile exported by company B out of total production?
Correct
Answer: d)
Number of defective mobile exported by B in 2016
= > 45000*(42/100)*(20/100) = 3780
Number of defective mobile exported by company B in 2017
= > (3780/7)*5 = 2700
Number of mobiles exported by company B
= > (2700/13.5)*100 = 20000
Percentage of mobile exported by company B in 2017
= > (20000/30000)*100 = 66.66 %
Incorrect
Answer: d)
Number of defective mobile exported by B in 2016
= > 45000*(42/100)*(20/100) = 3780
Number of defective mobile exported by company B in 2017
= > (3780/7)*5 = 2700
Number of mobiles exported by company B
= > (2700/13.5)*100 = 20000
Percentage of mobile exported by company B in 2017
= > (20000/30000)*100 = 66.66 %
Question 5 of 10
5. Question
Data interpretation
Directions (1 – 5): Study the following information carefully and answer the given questions:
The following bar graph shows the production of mobiles (In thousands) of different companies in two different years.
Find the difference between the mobiles exported by company A, B and D in 2016 to that of the mobiles exported by company A and E in 2017?
Directions (6 – 10): In the following questions, two quantities are given as Quantity I and Quantity II. By finding these quantities gives corresponding answer.
Quantity I: ‘x’: 4x^{2}+24x= -27
Quantity II: ‘y’: 4y^{2}+33y+35=0
Correct
Answer: e)
Quantity I:
4x^{2}+24x= -27
4x^{2}+24x+27=0
4x^{2}+18x+6x+27=0
2x(2x+9)+3(2x+9)=0
X= – 3/2, – 9/2 = -1.5, -4.5
Quantity II:
4y^{2}+33y+35=0
4y^{2}+28y+5y+35=0
4y(y+7)+5(y+7)=0
y= – 5/4, – 7 = -1.2, -7
No Relation
Incorrect
Answer: e)
Quantity I:
4x^{2}+24x= -27
4x^{2}+24x+27=0
4x^{2}+18x+6x+27=0
2x(2x+9)+3(2x+9)=0
X= – 3/2, – 9/2 = -1.5, -4.5
Quantity II:
4y^{2}+33y+35=0
4y^{2}+28y+5y+35=0
4y(y+7)+5(y+7)=0
y= – 5/4, – 7 = -1.2, -7
No Relation
Question 7 of 10
7. Question
Inequality
Directions (6 – 10): In the following questions, two quantities are given as Quantity I and Quantity II. By finding these quantities gives corresponding answer.
Quantity I: A circle and a rectangle have the same area. Length and breadth of the rectangle is 77cm and 50cm respectively. What is the circumference of circle?
Quantity II: Diameter of a circle is 56 cm and perimeter of a rectangle is same as circumference of the circle. Find out the area of the rectangle, if the length of the rectangle is three times the breadth of the rectangle.
Correct
Answer: a)
Quantity I:
Area of circle= Area of Rectangle
πr^{2}= (l × b)
22/7× r^{2}= 77×50
r^{2}= 25×49
r=35 cm
Circumference of circle= 2πr
= 2 × 22/7 × 35
= 220 cm
Quantity II:
Perimeter of rectangle= Circumference of circle
2(l + b) = 2πr
2(l + b) = 2 × 22/7 × 56/2
l + b= 88cm
According to the question,
3b+b= 88
b=22
Area of rectangle= l × b = 22×66= 1452cm^{2}
Quantity II> Quantity I
Incorrect
Answer: a)
Quantity I:
Area of circle= Area of Rectangle
πr^{2}= (l × b)
22/7× r^{2}= 77×50
r^{2}= 25×49
r=35 cm
Circumference of circle= 2πr
= 2 × 22/7 × 35
= 220 cm
Quantity II:
Perimeter of rectangle= Circumference of circle
2(l + b) = 2πr
2(l + b) = 2 × 22/7 × 56/2
l + b= 88cm
According to the question,
3b+b= 88
b=22
Area of rectangle= l × b = 22×66= 1452cm^{2}
Quantity II> Quantity I
Question 8 of 10
8. Question
Inequality
Directions (6 – 10): In the following questions, two quantities are given as Quantity I and Quantity II. By finding these quantities gives corresponding answer.
Quantity I: ‘X’: 5, 9, 36, X, 404, 525
Quantity II: ‘Y’: 11, 20, Y, 224, 1115, 6684
Correct
Answer: b)
Quantity I:
5, 9, 36, X, 404, 525
5 + 2^{2 }= 9
9 + 3^{3} = 36 ^{ }
36 + 5^{2 }= 61
61 + 7^{3} = 404
404 + 11^{2} = 525
Quantity II:
11, 20, Y, 224, 1115, 6684
11 * 2 – 2 = 20
20 * 3 – 3 = 57
57 * 4 – 4 = 224
224 * 5 – 5 = 1115
1115 * 6 – 6 = 6684
Quantity II < Quantity I
Incorrect
Answer: b)
Quantity I:
5, 9, 36, X, 404, 525
5 + 2^{2 }= 9
9 + 3^{3} = 36 ^{ }
36 + 5^{2 }= 61
61 + 7^{3} = 404
404 + 11^{2} = 525
Quantity II:
11, 20, Y, 224, 1115, 6684
11 * 2 – 2 = 20
20 * 3 – 3 = 57
57 * 4 – 4 = 224
224 * 5 – 5 = 1115
1115 * 6 – 6 = 6684
Quantity II < Quantity I
Question 9 of 10
9. Question
Inequality
Directions (6 – 10): In the following questions, two quantities are given as Quantity I and Quantity II. By finding these quantities gives corresponding answer.
Quantity I: ‘X’: The cost of 5 bags and 12 notes is Rs. 3100 and the cost of 7 bags and 18 notes is Rs. 4400. What is the cost of 3 notes?
Quantity II: ‘Y’: Y^{2}= 22500
Correct
Answer: c)
Quantity I:
According to the question:
5b + 12n = 3100—– (i)
7b + 18n = 4400 —– (ii)
After solving equation (i) and (ii),
We get, b= 500 and n= 50
Cost of 3 notes = 50×3= 150
Quantity II:
Y^{2}= 22500
Y= ±150
Quantity I ≥ Quantity II
Incorrect
Answer: c)
Quantity I:
According to the question:
5b + 12n = 3100—– (i)
7b + 18n = 4400 —– (ii)
After solving equation (i) and (ii),
We get, b= 500 and n= 50
Cost of 3 notes = 50×3= 150
Quantity II:
Y^{2}= 22500
Y= ±150
Quantity I ≥ Quantity II
Question 10 of 10
10. Question
Inequality
Directions (6 – 10): In the following questions, two quantities are given as Quantity I and Quantity II. By finding these quantities gives corresponding answer.
Quantity I: “A”: X, Y, and Z can finish a work in 5, 6, and 10 Days respectively. They start working together. If Y stops after 2 days, how long would it take X and Z to finish the remaining work.
Quantity II: “B”: B^{3}= 27/1331
Correct
Answer: a)
Quantity I:
According to the question,
X + Y + Z= 1/5 + 1/6 + 1/10
= (12+10+6)/60 = 28/60 = 7/15
Their work for 2 Days= 14/15
Remaining work = 1 – 14/15 = 1/15
Required Time to finish the work by X and Z
= (1/15)/(1/5 + 1/10) = 1/15 × 10/3 = 2/9 Days
Quantity II:
B^{3} = 27/1331 => B =3/11
Quantity II > Quantity I
Incorrect
Answer: a)
Quantity I:
According to the question,
X + Y + Z= 1/5 + 1/6 + 1/10
= (12+10+6)/60 = 28/60 = 7/15
Their work for 2 Days= 14/15
Remaining work = 1 – 14/15 = 1/15
Required Time to finish the work by X and Z
= (1/15)/(1/5 + 1/10) = 1/15 × 10/3 = 2/9 Days
Quantity II:
B^{3} = 27/1331 => B =3/11
Quantity II > Quantity I
Data interpretation
Directions (1 – 5): Study the following information carefully and answer the given questions:
The following bar graph shows the production of mobiles (In thousands) of different companies in two different years.
1) The average number of mobiles exported by company D and F in 2017 is 35000 while the mobiles exported by company D in 2016 is twice the export in 2017 then find the percentage of export by company F out of total production of company F in 2017?
a) 65 %
b) 72 %
c) 80 %
d) 85 %
e) 92 %
2) If company E exported a total of 50000 mobiles in the year 2016 and 2017, then find the percentage of mobiles exported by company E in 2016?
a) 35 %
b) 27.5 %
c) 20 %
d) 17.5 %
e) None of these
3) The total number of mobiles exported by company A in 2016 and 2017 is 2/3 of the mobiles exported by company C in these years then find the percentage of mobiles that were exported by company C out of total production in 2017 ?
a) 72 %
b) 56.25 %
c) 45 %
d) 64.75 %
e) 75 %
4) The 20% of the mobiles exported by company B in 2016 are defective while the ratio between the defective mobiles exported by company B in the year 2016 and 2017 is 7 : 5 and the percentage of defective mobiles out of total export by company B in 2017 is 13.5% then find the percentage of mobile exported by company B out of total production?
a) 45.66 %
b) 72.77 %
c) 48.55 %
d) 66.66 %
e) 56.33 %
5) Find the difference between the mobiles exported by company A, B and D in 2016 to that of the mobiles exported by company A and E in 2017?
a) 18500
b) 24200
c) 20600
d) 19700
e) None of these
Inequality
Directions (6 – 10): In the following questions, two quantities are given as Quantity I and Quantity II. By finding these quantities gives corresponding answer.
6) Quantity I: ‘x’: 4x^{2}+24x= -27
Quantity II: ‘y’: 4y^{2}+33y+35=0
a) Quantity I > Quantity II
b) Quantity I < Quantity II
c) Quantity I ≥ Quantity II
d) Quantity I ≤ Quantity II
e) Quantity I = Quantity II or No relation
7) Quantity I: A circle and a rectangle have the same area. Length and breadth of the rectangle is 77cm and 50cm respectively. What is the circumference of circle?
Quantity II: Diameter of a circle is 56 cm and perimeter of a rectangle is same as circumference of the circle. Find out the area of the rectangle, if the length of the rectangle is three times the breadth of the rectangle.
a) Quantity II > Quantity I
b) Quantity II < Quantity I
c) Quantity I ≥ Quantity II
d) Quantity I ≤ Quantity II
e) Quantity I = Quantity II or No relation
8) Quantity I: ‘X’: 5, 9, 36, X, 404, 525
Quantity II: ‘Y’: 11, 20, Y, 224, 1115, 6684
a) Quantity II > Quantity I
b) Quantity II < Quantity I
c) Quantity I ≥ Quantity II
d) Quantity I ≤ Quantity II
e) Quantity I = Quantity II or No relation
9) Quantity I: ‘X’: The cost of 5 bags and 12 notes is Rs. 3100 and the cost of 7 bags and 18 notes is Rs. 4400. What is the cost of 3 notes?
Quantity II: ‘Y’: Y^{2}= 22500
a) Quantity II> Quantity I
b) Quantity II < Quantity I
c) Quantity I ≥ Quantity II
d) Quantity I ≤ Quantity II
e) Quantity I = Quantity II or No relation
10) Quantity I: “A”: X, Y, and Z can finish a work in 5, 6, and 10 Days respectively. They start working together. If Y stops after 2 days, how long would it take X and Z to finish the remaining work.
Quantity II: “B”: B^{3}= 27/1331
a) Quantity II> Quantity I
b) Quantity II< Quantity I
c) Quantity I ≥ Quantity II
d) Quantity I ≤ Quantity II
e) Quantity I = Quantity II or No relation
Answers :
Directions (1-5) :
1) Answer: b)
Total mobiles exported by company D and F= 35000*2 = 70000
Mobile exported by company D in 2016= (30/100)*35000 = 10500
Mobile exported by company D in 2017 = 10500/2 = 5250
Mobile exported by company F = 70000 – 5250 = 64750
Percentage of production exported by company F in 2017
= > 64750/90000* 100 = 72%
2) Answer: b)
Mobile exported by company E in 2017 = 40000*(70/100) = 28000
Mobile exported by company E in 2016 = 50000 – 28000 = 22000
Required % = (22000/80000)*100 = 27.5 %
3) Answer: d)
Total number of mobiles exported by company A in 2016 and 2017
= > (40/100)*20000 + (60/100)*50000
= > 8000 + 30000 = 38000
Mobile exported by company C in 2016 and 2017
= > 38000*(3/2) = 57000
Mobile exported by company C in 2017
= > 57000 – 26000*(20/100)
= > 51800
Percentage of export by company C = (51800/80000)*100 = 64.75 %
4) Answer: d)
Number of defective mobile exported by B in 2016
= > 45000*(42/100)*(20/100) = 3780
Number of defective mobile exported by company B in 2017
= > (3780/7)*5 = 2700
Number of mobiles exported by company B
= > (2700/13.5)*100 = 20000
Percentage of mobile exported by company B in 2017